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In Jonathan’s pen there are 300 sheep’s. 5/6 of the sheep’s are white, 2/3 of the sheep’s have soft wool. What can’t be the number of white sheep’s that also have soft wool in the pen?a) 150b) 200c) 190d) 180e) 160Correct answer is option 'A'. Can you explain this answer?
|
Yeshwanth Varma answered |
Answer can't be 200, it can be 150 but not 200
There are 40 students in a classroom, 9/20 of them are boys and 4/5 of them are right-handed. How many right-handed boys are there in the classroom?- a)Between 10 and 32.
- b)Between 14 and 32.
- c)Between 10 and 18.
- d)Between 14 and 18.
- e)Between 18 and 36
Correct answer is option 'C'. Can you explain this answer?
There are 40 students in a classroom, 9/20 of them are boys and 4/5 of them are right-handed. How many right-handed boys are there in the classroom?
a)
Between 10 and 32.
b)
Between 14 and 32.
c)
Between 10 and 18.
d)
Between 14 and 18.
e)
Between 18 and 36
|
Meera Rana answered |
Given that there are 18 boys (9/20*40=18) and 22 girls in the class. Also we know that out of 40 students 32 are right-handed (4/5*40=32).
Maximum number of right-handed boys possible is if ALL 18 boys are right-handed;
Minimum number of right-handed boys possible is if ALL 22 girls are right-handed, so in this case 32-22=10 boys would be right-handed.
Maximum number of right-handed boys possible is if ALL 18 boys are right-handed;
Minimum number of right-handed boys possible is if ALL 22 girls are right-handed, so in this case 32-22=10 boys would be right-handed.
There are 200 cats in Cat-City. Out of the 200, 70 are street cats and the rest are domestic cats. 110 cats are gray, 30 out of the gray cats are street ones. How many domestic cats are there which are not gray in Cat-City?
a) 90b) 80c) 50d) 40e) 25Correct answer is option 'C'. Can you explain this answer?
|
Devansh Shah answered |
Out of 200 cats, 130 are domestic ones. Out of 110 gray cats, 30 are street cats therefore 80 are grey and domestic ones.
Altogether there are 130 domestic cats, 80 are grey so (130 – 80) = 50 are not grey.
Altogether there are 130 domestic cats, 80 are grey so (130 – 80) = 50 are not grey.
If A2 + B2 = 15 and AB = 10, what is the value of the expression (A – B)2 + (A + B)2 ?- a)10
- b)20
- c)30
- d)60
- e)70
Correct answer is option 'C'. Can you explain this answer?
If A2 + B2 = 15 and AB = 10, what is the value of the expression (A – B)2 + (A + B)2 ?
a)
10
b)
20
c)
30
d)
60
e)
70
|
Kirti Roy answered |
The best answer is C.
(A – B)2 + (A + B)2 = A2 – 2AB + B2 + A2 + 2AB + B2 = 2(A2 + B2) = 30.
(A – B)2 + (A + B)2 = A2 – 2AB + B2 + A2 + 2AB + B2 = 2(A2 + B2) = 30.
There are 40 students in a classroom, 9/20 of them are boys and 4/5 of them are right-handed. How many right-handed boys are there in the classroom?- a)Between 10 and 32.
- b)Between 14 and 32.
- c)Between 10 and 18.
- d)Between 14 and 18.
- e)Between 18 and 36
Correct answer is option 'C'. Can you explain this answer?
There are 40 students in a classroom, 9/20 of them are boys and 4/5 of them are right-handed. How many right-handed boys are there in the classroom?
a)
Between 10 and 32.
b)
Between 14 and 32.
c)
Between 10 and 18.
d)
Between 14 and 18.
e)
Between 18 and 36
|
|
Sounak Iyer answered |
There are (9/20 x 40 = 18) boys in the class. 80% of them are right-handed, meaning that (4/5 x 18 = 14.4). Answer C is the best answer.
In the Kan film festival, 50 movies were presented. 3/5 of the movies are action movies and 4/5 is science fiction movies. How many of the movies were science fiction action movies?- a)10
- b)15
- c)20
- d)30
- e)35
Correct answer is option 'C'. Can you explain this answer?
In the Kan film festival, 50 movies were presented. 3/5 of the movies are action movies and 4/5 is science fiction movies. How many of the movies were science fiction action movies?
a)
10
b)
15
c)
20
d)
30
e)
35
|
|
Nitya Kumar answered |
There were (3/5 x 50 = 30) action movies.
There were (4/5 x 50 = 40) science fiction movies.
Exact overlapping is calculated by minimum overlapping method.
Therefore there are (40 + 30 – 50 = 20) movies that belong to both categories.
There were (4/5 x 50 = 40) science fiction movies.
Exact overlapping is calculated by minimum overlapping method.
Therefore there are (40 + 30 – 50 = 20) movies that belong to both categories.
A certain airline’s fleet consisted of 60 type A planes at the beginning of 1980. At the end of each year, starting with 1980, the airline retired 3 of the type A planes and acquired 4 new type B planes. How many years did it take before the number of type A planes left in the airline’s fleet was less than 50 percent of the fleet?- a)6
- b)7
- c)8
- d)9
- e)10
Correct answer is option 'D'. Can you explain this answer?
A certain airline’s fleet consisted of 60 type A planes at the beginning of 1980. At the end of each year, starting with 1980, the airline retired 3 of the type A planes and acquired 4 new type B planes. How many years did it take before the number of type A planes left in the airline’s fleet was less than 50 percent of the fleet?
a)
6
b)
7
c)
8
d)
9
e)
10
|
|
Niharika Sen answered |
Understanding the problem:
The airline starts with 60 type A planes and at the end of each year, it retires 3 type A planes and acquires 4 new type B planes.
Calculating the number of type A planes over the years:
- Year 1980: 60 type A planes
- Year 1981: 60 - 3 = 57 type A planes
- Year 1982: 57 - 3 = 54 type A planes
- Year 1983: 54 - 3 = 51 type A planes
- Year 1984: 51 - 3 = 48 type A planes
Finding the answer:
After 5 years (by the end of 1984), the number of type A planes is 48, which is less than 50% of the fleet (60/2 = 30). Therefore, it took 5 years for the number of type A planes left in the airline's fleet to be less than 50%.
Conclusion:
The correct answer is option D - 9 years.
The airline starts with 60 type A planes and at the end of each year, it retires 3 type A planes and acquires 4 new type B planes.
Calculating the number of type A planes over the years:
- Year 1980: 60 type A planes
- Year 1981: 60 - 3 = 57 type A planes
- Year 1982: 57 - 3 = 54 type A planes
- Year 1983: 54 - 3 = 51 type A planes
- Year 1984: 51 - 3 = 48 type A planes
Finding the answer:
After 5 years (by the end of 1984), the number of type A planes is 48, which is less than 50% of the fleet (60/2 = 30). Therefore, it took 5 years for the number of type A planes left in the airline's fleet to be less than 50%.
Conclusion:
The correct answer is option D - 9 years.
Rates for having a manuscript typed at a certain typing service are $5 per page for the first time a page is typed and $3 per page each time a page is revised. If a certain manuscript has 100 pages, of which 40 were revised only once, 10 were revised twice, and the rest required no revisions, what was the total cost of having the manuscript typed?- a)$430
- b)$620
- c)$650
- d)$680
- e)$770
Correct answer is option 'D'. Can you explain this answer?
Rates for having a manuscript typed at a certain typing service are $5 per page for the first time a page is typed and $3 per page each time a page is revised. If a certain manuscript has 100 pages, of which 40 were revised only once, 10 were revised twice, and the rest required no revisions, what was the total cost of having the manuscript typed?
a)
$430
b)
$620
c)
$650
d)
$680
e)
$770
|
EduRev GMAT answered |
This problem has been circulating in the official practice tests for over a decade. It is amazing how many smart, high-scoring students miss it! There is no hard math present and you just need to follow specific instructions, but people are far too casual on these types of “reading comprehension” math questions. When you are performing well on this exam, there is something hard about every question, so always try to identify where that difficulty is coming from. In this example, the key is to carefully note that the question says, “40 were revised only once.” The “sucker” incorrect answer on this question is calculated as follows:
100 x $5 = $500
40 x $3 = $120
10 x $3 = $30 (incorrectly assuming that you have accounted for the first charge of $3 in the first revision category)
The last calculation is wrong because the ones revised “only once” and “twice” are two completely separate categories—there is no overlap. So, the pages revised twice will cost $6 for each page and the correct charge for those is $6 x 10 = $60. Correct answer is thus $680, not $650.
When I review an official practice test with a student who misses this question, I literally yell: “You cannot miss this question!” Never be casual with any question regardless of how simple it seems and always find the trap; otherwise, you are surely falling for it. I always emphasize that the “soft skills” on the quant side—reading carefully, critical thinking, strategy—are just as important as hard quant skills, if not more.
The overwhelming majority of our clients are admitted to one of their target schools. We help applicants to select schools that are in line with their qualifications and don’t hesitate to recommend against particular schools (or even against an MBA). We’re happy to help you apply to a stretch school if you understand the odds and do so in the context of a balanced list of schools.
Having said that, we recommend against using success rate as the main way to select a consultant because this metric is easily manipulated by either a) taking only perfect candidates, or b) convincing applicants to apply to easy schools. Furthermore, there is no satisfying way for applicants to verify claimed success rates.
100 x $5 = $500
40 x $3 = $120
10 x $3 = $30 (incorrectly assuming that you have accounted for the first charge of $3 in the first revision category)
The last calculation is wrong because the ones revised “only once” and “twice” are two completely separate categories—there is no overlap. So, the pages revised twice will cost $6 for each page and the correct charge for those is $6 x 10 = $60. Correct answer is thus $680, not $650.
When I review an official practice test with a student who misses this question, I literally yell: “You cannot miss this question!” Never be casual with any question regardless of how simple it seems and always find the trap; otherwise, you are surely falling for it. I always emphasize that the “soft skills” on the quant side—reading carefully, critical thinking, strategy—are just as important as hard quant skills, if not more.
The overwhelming majority of our clients are admitted to one of their target schools. We help applicants to select schools that are in line with their qualifications and don’t hesitate to recommend against particular schools (or even against an MBA). We’re happy to help you apply to a stretch school if you understand the odds and do so in the context of a balanced list of schools.
Having said that, we recommend against using success rate as the main way to select a consultant because this metric is easily manipulated by either a) taking only perfect candidates, or b) convincing applicants to apply to easy schools. Furthermore, there is no satisfying way for applicants to verify claimed success rates.
If X ~ Y = X2 + XY, then what is the value of -1 ~ 2 ?- a)1
- b)-1
- c)3
- d)4
- e)2
Correct answer is option 'B'. Can you explain this answer?
If X ~ Y = X2 + XY, then what is the value of -1 ~ 2 ?
a)
1
b)
-1
c)
3
d)
4
e)
2
|
|
Nitya Kumar answered |
The best answer is B.-1 ~ 2 = (-1)2 + (-1)2 = -1.
An Ameba is an organic life form that divides into two Amebas each round hour. If at a certain round hour, two Amebas were placed in a jar, how many Amebas will be in the jar in N hours?- a)2N
- b)22N
- c)2N+1
- d)2N-1
- e)2N
Correct answer is option 'C'. Can you explain this answer?
An Ameba is an organic life form that divides into two Amebas each round hour. If at a certain round hour, two Amebas were placed in a jar, how many Amebas will be in the jar in N hours?
a)
2N
b)
22N
c)
2N+1
d)
2N-1
e)
2N
|
|
Sounak Iyer answered |
Let’s find the number of Amebas in the first hours.
After one hour (N=1) there will be 4 Amebas.
After two hours (N=2) there will be 8 Amebas.
After three hours (N=3) there will be 16 amebas.
Therefore the formula that fits this series is 2N+1.
After one hour (N=1) there will be 4 Amebas.
After two hours (N=2) there will be 8 Amebas.
After three hours (N=3) there will be 16 amebas.
Therefore the formula that fits this series is 2N+1.
The value of an “Aerosoul” stock changes according to the following method:At the end of each month her value is doubled but due to commission the stock’s value is decreases by $10. If the value at the beginning of January is $A, what would be her value at the end of February?- a)4A – 10
- b)4A – 20
- c)4A – 30
- d)4A – 40
- e)4A – 50
Correct answer is option 'C'. Can you explain this answer?
The value of an “Aerosoul” stock changes according to the following method:At the end of each month her value is doubled but due to commission the stock’s value is decreases by $10. If the value at the beginning of January is $A, what would be her value at the end of February?
a)
4A – 10
b)
4A – 20
c)
4A – 30
d)
4A – 40
e)
4A – 50
|
|
Pallavi Sharma answered |
Asset is the worth or estimated worth of that asset. This can be determined through various methods such as market value, book value, or appraisals. The value of an asset can change over time due to factors such as market conditions, demand, and supply. It is important to regularly assess the value of assets to make informed financial decisions and to ensure accurate financial reporting.
Two carpenters, working in the same pace, can build 2 desks in two hours and a half. How many desks can 4 carpenters build in 4 hours?- a)2.4
- b)3.6
- c)4.2
- d)5.5
- e)6.4
Correct answer is option 'E'. Can you explain this answer?
Two carpenters, working in the same pace, can build 2 desks in two hours and a half. How many desks can 4 carpenters build in 4 hours?
a)
2.4
b)
3.6
c)
4.2
d)
5.5
e)
6.4
|
|
Akshay Khanna answered |
2 carpenters build 2 desks in 2.5 hours ---> 4 carpenters build 4 desks in 2.5 hours ----> In 4 hours there are (4/2.5 = 1.6) time units. And (4 x 1.6) is 6.4 desks.
If A and B are positive integers, which of the following expressions is not an integer for certain?- a)(2A2 – 2B2)/(A+B).
- b)(6B + 8A)/(3B + 4A).
- c)(3A – B)/(B - 3A).
- d)(A + B)/(A2 + B2 + 2AB).
- e)(A2 – B2)/(A - B).
Correct answer is option 'D'. Can you explain this answer?
If A and B are positive integers, which of the following expressions is not an integer for certain?
a)
(2A2 – 2B2)/(A+B).
b)
(6B + 8A)/(3B + 4A).
c)
(3A – B)/(B - 3A).
d)
(A + B)/(A2 + B2 + 2AB).
e)
(A2 – B2)/(A - B).
|
|
Bhavana Kulkarni answered |
The best answer is D.
All the answers besides D are numbers after some simplification.Answer D = (A + B)/(A+B)2 = 1/(A+B), and this is a fraction of a number.
All the answers besides D are numbers after some simplification.Answer D = (A + B)/(A+B)2 = 1/(A+B), and this is a fraction of a number.
Alfa, Beta and Gamma are inner angles in a triangle. If Alfa = Beta + Gamma, what can’t be the size of Beta?- a)44 degrees.
- b)45 degrees.
- c)89 degrees.
- d)90 degrees.
- e)There isn’t enough data to determine
Correct answer is option 'D'. Can you explain this answer?
Alfa, Beta and Gamma are inner angles in a triangle. If Alfa = Beta + Gamma, what can’t be the size of Beta?
a)
44 degrees.
b)
45 degrees.
c)
89 degrees.
d)
90 degrees.
e)
There isn’t enough data to determine
|
|
Sharmila Nambiar answered |
If Beta is 90 degrees than Alfa is bigger than 90 and the sum of the angles in the triangle will be bigger than 180 degrees.
15 Java programmers, working in a constant pace, finish a web page in 3 days. If after one day, 9 programmers quit, how many more days are needed to finish the remainder of the job?
- a)5
- b)2
- c)8
- d)4
- e)6
Correct answer is option 'A'. Can you explain this answer?
15 Java programmers, working in a constant pace, finish a web page in 3 days. If after one day, 9 programmers quit, how many more days are needed to finish the remainder of the job?
a)
5
b)
2
c)
8
d)
4
e)
6
|
|
Arjun Iyer answered |
Problem Analysis
Given that 15 Java programmers can finish a web page in 3 days, we need to determine how many more days are needed to finish the remainder of the job after 9 programmers quit after the first day.
Calculation
To calculate the number of days needed to finish the remainder of the job, we can use the concept of person-days.
Initially, we have 15 programmers working for 3 days, which gives us a total of 15 x 3 = 45 person-days of work.
After the first day, 9 programmers quit, so we are left with 15 - 9 = 6 programmers.
The work completed by these 6 programmers in the first day is equivalent to 6 person-days.
Therefore, the work remaining after the first day is 45 - 6 = 39 person-days.
Since we now have 6 programmers working, we can calculate the number of days needed to complete the remaining work.
The number of days required is given by the equation:
(Number of programmers) x (Number of days) = Total person-days of work
Substituting the values, we have:
6 x (Number of days) = 39
Simplifying the equation, we find:
(Number of days) = 39 / 6 = 6.5
Since the number of days must be a whole number, we round up to the nearest whole number.
Therefore, we need 7 more days to finish the remainder of the job.
Conclusion
After 9 programmers quit, 6 programmers are left to complete the remaining work. These 6 programmers will require 7 more days to finish the job.
Therefore, the correct answer is option A) 5.
Given that 15 Java programmers can finish a web page in 3 days, we need to determine how many more days are needed to finish the remainder of the job after 9 programmers quit after the first day.
Calculation
To calculate the number of days needed to finish the remainder of the job, we can use the concept of person-days.
Initially, we have 15 programmers working for 3 days, which gives us a total of 15 x 3 = 45 person-days of work.
After the first day, 9 programmers quit, so we are left with 15 - 9 = 6 programmers.
The work completed by these 6 programmers in the first day is equivalent to 6 person-days.
Therefore, the work remaining after the first day is 45 - 6 = 39 person-days.
Since we now have 6 programmers working, we can calculate the number of days needed to complete the remaining work.
The number of days required is given by the equation:
(Number of programmers) x (Number of days) = Total person-days of work
Substituting the values, we have:
6 x (Number of days) = 39
Simplifying the equation, we find:
(Number of days) = 39 / 6 = 6.5
Since the number of days must be a whole number, we round up to the nearest whole number.
Therefore, we need 7 more days to finish the remainder of the job.
Conclusion
After 9 programmers quit, 6 programmers are left to complete the remaining work. These 6 programmers will require 7 more days to finish the job.
Therefore, the correct answer is option A) 5.
For every X, the action [X] is defined in the following matter: [X] is the greatest integer that is smaller or equal to X. For example: [8.9] = 8.What is the value of [6.5] x [2/3] + [2] x 7.2 + [8.4] – 6.6 ?- a)15.8
- b)16.2
- c)16.4
- d)14.4
- e)12.6
Correct answer is option 'A'. Can you explain this answer?
For every X, the action [X] is defined in the following matter: [X] is the greatest integer that is smaller or equal to X. For example: [8.9] = 8.
What is the value of [6.5] x [2/3] + [2] x 7.2 + [8.4] – 6.6 ?
a)
15.8
b)
16.2
c)
16.4
d)
14.4
e)
12.6
|
|
Jatin Kapoor answered |
The best answer is A.
[6.5] x [2/3] + [2] x 7.2 + [8.4] – 6.6 = 6 x 0 + 2 x 7.2 + 8 - 6.6 = 15.8.
What is the sum of all the even numbers bigger than (-10) and smaller than 12?- a)2
- b)10
- c)0
- d)8
- e)4
Correct answer is option 'B'. Can you explain this answer?
What is the sum of all the even numbers bigger than (-10) and smaller than 12?
a)
2
b)
10
c)
0
d)
8
e)
4
|
|
Aditya Gupta answered |
Sum of Even Numbers
To find the sum of all the even numbers between -10 and 12, we need to identify the even numbers within this range and then add them up.
Identifying Even Numbers
To identify the even numbers, we need to determine the numbers that are divisible by 2. We can start by listing the numbers between -10 and 12:
-10, -9, -8, -7, -6, -5, -4, -3, -2, -1, 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12
From this list, we can see that the even numbers are -10, -8, -6, -4, -2, 0, 2, 4, 6, 8, 10.
Calculating the Sum
To calculate the sum of these even numbers, we can add them up using basic arithmetic:
-10 + (-8) + (-6) + (-4) + (-2) + 0 + 2 + 4 + 6 + 8 + 10
Simplifying the expression, we get:
-10 - 8 - 6 - 4 - 2 + 0 + 2 + 4 + 6 + 8 + 10
The negative numbers can be rearranged to form a positive sum:
(-10 + 10) + (-8 + 8) + (-6 + 6) + (-4 + 4) + (-2 + 2) + 0 + 2 + 4 + 6 + 8 + 10
This simplifies to:
0 + 0 + 0 + 0 + 0 + 0 + 2 + 4 + 6 + 8 + 10
Finally, adding up all the numbers, we get:
2 + 4 + 6 + 8 + 10 = 30
Therefore, the sum of all the even numbers between -10 and 12 is 30.
Correct Answer: (b) 10
To find the sum of all the even numbers between -10 and 12, we need to identify the even numbers within this range and then add them up.
Identifying Even Numbers
To identify the even numbers, we need to determine the numbers that are divisible by 2. We can start by listing the numbers between -10 and 12:
-10, -9, -8, -7, -6, -5, -4, -3, -2, -1, 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12
From this list, we can see that the even numbers are -10, -8, -6, -4, -2, 0, 2, 4, 6, 8, 10.
Calculating the Sum
To calculate the sum of these even numbers, we can add them up using basic arithmetic:
-10 + (-8) + (-6) + (-4) + (-2) + 0 + 2 + 4 + 6 + 8 + 10
Simplifying the expression, we get:
-10 - 8 - 6 - 4 - 2 + 0 + 2 + 4 + 6 + 8 + 10
The negative numbers can be rearranged to form a positive sum:
(-10 + 10) + (-8 + 8) + (-6 + 6) + (-4 + 4) + (-2 + 2) + 0 + 2 + 4 + 6 + 8 + 10
This simplifies to:
0 + 0 + 0 + 0 + 0 + 0 + 2 + 4 + 6 + 8 + 10
Finally, adding up all the numbers, we get:
2 + 4 + 6 + 8 + 10 = 30
Therefore, the sum of all the even numbers between -10 and 12 is 30.
Correct Answer: (b) 10
In a psychology school the grade of the students is determined by the following method: At the end of the first year the grade equals to twice the age of the student. From then on, the grade is determined by twice the age of the student plus half of his grade from the previous year. If Joey’s grade at the end of the first year is 40, what will be his grade at the end of the third year?- a)75
- b)62
- c)80
- d)44
- e)56
Correct answer is option 'A'. Can you explain this answer?
In a psychology school the grade of the students is determined by the following method: At the end of the first year the grade equals to twice the age of the student. From then on, the grade is determined by twice the age of the student plus half of his grade from the previous year. If Joey’s grade at the end of the first year is 40, what will be his grade at the end of the third year?
a)
75
b)
62
c)
80
d)
44
e)
56
|
|
Aditya Sharma answered |
Understanding the Grading System
The grading system for students is defined as follows:
- At the end of the first year, the grade is determined by twice the age of the student.
- From the second year onwards, the grade is calculated using the formula:
- Grade = 2 * Age + 0.5 * Previous Grade
Initial Information
For Joey:
- At the end of the first year, his grade is 40.
Calculating Joey's Age
Since Joey's grade at the end of the first year is 40, we can find his age:
- Grade (First Year) = 2 * Age
- 40 = 2 * Age
- Age = 40 / 2 = 20 years old
Calculating the Second Year Grade
Now, to find the grade at the end of the second year, we need Joey's age in the second year:
- Age (Second Year) = 20 + 1 = 21 years old
Using the grading formula:
- Grade (Second Year) = 2 * Age (21) + 0.5 * Previous Grade (40)
- Grade (Second Year) = 2 * 21 + 0.5 * 40
- Grade (Second Year) = 42 + 20 = 62
Calculating the Third Year Grade
Now, to find the grade at the end of the third year:
- Age (Third Year) = 21 + 1 = 22 years old
Using the grading formula again:
- Grade (Third Year) = 2 * Age (22) + 0.5 * Previous Grade (62)
- Grade (Third Year) = 2 * 22 + 0.5 * 62
- Grade (Third Year) = 44 + 31 = 75
Conclusion
Thus, Joey's grade at the end of the third year will be 75, which corresponds to option A.
The grading system for students is defined as follows:
- At the end of the first year, the grade is determined by twice the age of the student.
- From the second year onwards, the grade is calculated using the formula:
- Grade = 2 * Age + 0.5 * Previous Grade
Initial Information
For Joey:
- At the end of the first year, his grade is 40.
Calculating Joey's Age
Since Joey's grade at the end of the first year is 40, we can find his age:
- Grade (First Year) = 2 * Age
- 40 = 2 * Age
- Age = 40 / 2 = 20 years old
Calculating the Second Year Grade
Now, to find the grade at the end of the second year, we need Joey's age in the second year:
- Age (Second Year) = 20 + 1 = 21 years old
Using the grading formula:
- Grade (Second Year) = 2 * Age (21) + 0.5 * Previous Grade (40)
- Grade (Second Year) = 2 * 21 + 0.5 * 40
- Grade (Second Year) = 42 + 20 = 62
Calculating the Third Year Grade
Now, to find the grade at the end of the third year:
- Age (Third Year) = 21 + 1 = 22 years old
Using the grading formula again:
- Grade (Third Year) = 2 * Age (22) + 0.5 * Previous Grade (62)
- Grade (Third Year) = 2 * 22 + 0.5 * 62
- Grade (Third Year) = 44 + 31 = 75
Conclusion
Thus, Joey's grade at the end of the third year will be 75, which corresponds to option A.
Ross has 40 shirts, ¾ of the shirts are green and 1/10 is without buttons.Therefore Ross has between ___ and ___ shirts with buttons that are not green.- a)6 ; 10.
- b)4 ; 25
- c)4 ; 10
- d)5 ; 25
- e)3 ; 10
Correct answer is option 'A'. Can you explain this answer?
Ross has 40 shirts, ¾ of the shirts are green and 1/10 is without buttons.
Therefore Ross has between ___ and ___ shirts with buttons that are not green.
a)
6 ; 10.
b)
4 ; 25
c)
4 ; 10
d)
5 ; 25
e)
3 ; 10
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Nilotpal Sen answered |
Notice that the groups that we are looking for a overlapping are the not-green shirts and the buttoned ones. The not-green shirts are a quarter of 40, 10 shirts.
The shirts with buttons are (9/10 x 40 = 36).
The maximum overlapping is the size of the smallest group: 10.
The minimum overlapping is: 36 + 10 – 40 = 6.
Therefore A is the answer.
The shirts with buttons are (9/10 x 40 = 36).
The maximum overlapping is the size of the smallest group: 10.
The minimum overlapping is: 36 + 10 – 40 = 6.
Therefore A is the answer.
Which of the following fractions is the smallest?- a)3/10
- b)6/19
- c)3/8
- d)11/30
- e)12/31
Correct answer is option 'A'. Can you explain this answer?
Which of the following fractions is the smallest?
a)
3/10
b)
6/19
c)
3/8
d)
11/30
e)
12/31
|
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Kalyan Nair answered |
The best answer is A
.Compare all of the answers to
(a) 3/10.
(b) 3/10 x 2 = 6/20 which is smaller than 6/19.
(c) 3/10 is smaller.
(d) 3/10 = 9/30, and this is smaller than 11/30.
(e) 3/10 = 12/40 and that is smaller than 12/31.
The smallest fraction is A.
.Compare all of the answers to
(a) 3/10.
(b) 3/10 x 2 = 6/20 which is smaller than 6/19.
(c) 3/10 is smaller.
(d) 3/10 = 9/30, and this is smaller than 11/30.
(e) 3/10 = 12/40 and that is smaller than 12/31.
The smallest fraction is A.
Which of the following fractions is the largest?- a)2/7
- b)2/3
- c)7/9
- d)7/12
- e)3/5
Correct answer is option 'C'. Can you explain this answer?
Which of the following fractions is the largest?
a)
2/7
b)
2/3
c)
7/9
d)
7/12
e)
3/5
|
|
Akshay Khanna answered |
The best answer is C.
Lets compare all the answers to 2/7, unless we find a larger fraction.
(b) 2/3 is larger than 2/7. For now, this is the right answer.
(c) 2/3 is also 6/9 and that is smaller than 7/9. For now this is the right answer.
(d) 7/9 is bigger than 7/12
(e) Bring this answer and (c) to a common denominator.7/9 = 35/45 and 3/5 = 27/45.
7/9 is the largest fraction.
Lets compare all the answers to 2/7, unless we find a larger fraction.
(b) 2/3 is larger than 2/7. For now, this is the right answer.
(c) 2/3 is also 6/9 and that is smaller than 7/9. For now this is the right answer.
(d) 7/9 is bigger than 7/12
(e) Bring this answer and (c) to a common denominator.7/9 = 35/45 and 3/5 = 27/45.
7/9 is the largest fraction.
If (1 < A < 3 < B), then which of the following expressions is the largest?- a)(B+2)/(A-1)
- b)(B-2)/(A+1)
- c)A/B
- d)(B-2)/(A-1)
- e)B/A
Correct answer is option 'A'. Can you explain this answer?
If (1 < A < 3 < B), then which of the following expressions is the largest?
a)
(B+2)/(A-1)
b)
(B-2)/(A+1)
c)
A/B
d)
(B-2)/(A-1)
e)
B/A
|
|
Mihir Nambiar answered |
The best answer is A.
Try some numbers and check the answers. A=2, B=4.
(a) 6/1 = 6
(b) 2/3
(c) 1/2
(d) 2
(e) 2
Try some numbers and check the answers. A=2, B=4.
(a) 6/1 = 6
(b) 2/3
(c) 1/2
(d) 2
(e) 2
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