All Exams >
Physics >
Topic wise Tests for IIT JAM Physics >
All Questions
All questions of Logic Gates for Physics Exam
Choose the correct options :- a)The boolean expression of an AND gate followed by an inverter is same as the boolean expression for a NAND gate.
- b)The boolean expression for an OR gate followed by a NOT gate is same as that for a NOR gate
- c)No two basic logic gates have the same boolean expression
- d)None of the above
Correct answer is option 'A,B,C'. Can you explain this answer?
Choose the correct options :
a)
The boolean expression of an AND gate followed by an inverter is same as the boolean expression for a NAND gate.
b)
The boolean expression for an OR gate followed by a NOT gate is same as that for a NOR gate
c)
No two basic logic gates have the same boolean expression
d)
None of the above
|
Ipsita Chopra answered |
The correct answers are: The boolean expression of an AND gate followed by an inverter is same as the boolean expression for a NAND gate., The boolean expression for an OR gate followed by a NOT gate is same as that for a NOR gate, No two basic logic gates have the same boolean expression
When simplified with boolean algebra, the expression (x + y)(x + z) simplies to :- a)x(1 + yz)
- b)x + yz
- c)x
- d)x + x(y+z)
Correct answer is option 'B'. Can you explain this answer?
When simplified with boolean algebra, the expression (x + y)(x + z) simplies to :
a)
x(1 + yz)
b)
x + yz
c)
x
d)
x + x(y+z)
|
Vanshika Patel answered |
Simplifying the expression (x y)(x z) using Boolean algebra:
Step 1: Expand the expression using the distributive property of multiplication over addition.
(x y)(x z) = x(x z) + y(x z)
Step 2: Simplify each term separately.
Simplifying x(x z):
Using the distributive property, x(x z) can be expanded as x * x + x * z.
x * x is equal to x, and x * z is equal to xz.
Therefore, x(x z) simplifies to x + xz.
Simplifying y(x z):
Using the distributive property, y(x z) can be expanded as y * x + y * z.
y * x is equal to xy, and y * z is equal to yz.
Therefore, y(x z) simplifies to xy + yz.
Step 3: Combine the simplified terms.
x + xz + xy + yz
Step 4: Group the terms with common factors.
(x + xy) + (xz + yz)
Step 5: Factor out the common factor from each group.
x(1 + y) + z(x + y)
Step 6: Simplify the expression further.
Since (1 + y) is always equal to 1 (since y can only be 0 or 1), we can simplify x(1 + y) to just x.
Similarly, we can simplify z(x + y) to just zx.
The simplified expression is:
x + zx
Since zx is equivalent to xz, the final simplified expression is:
x + xz
Therefore, the correct answer is option B: x + xz.
Step 1: Expand the expression using the distributive property of multiplication over addition.
(x y)(x z) = x(x z) + y(x z)
Step 2: Simplify each term separately.
Simplifying x(x z):
Using the distributive property, x(x z) can be expanded as x * x + x * z.
x * x is equal to x, and x * z is equal to xz.
Therefore, x(x z) simplifies to x + xz.
Simplifying y(x z):
Using the distributive property, y(x z) can be expanded as y * x + y * z.
y * x is equal to xy, and y * z is equal to yz.
Therefore, y(x z) simplifies to xy + yz.
Step 3: Combine the simplified terms.
x + xz + xy + yz
Step 4: Group the terms with common factors.
(x + xy) + (xz + yz)
Step 5: Factor out the common factor from each group.
x(1 + y) + z(x + y)
Step 6: Simplify the expression further.
Since (1 + y) is always equal to 1 (since y can only be 0 or 1), we can simplify x(1 + y) to just x.
Similarly, we can simplify z(x + y) to just zx.
The simplified expression is:
x + zx
Since zx is equivalent to xz, the final simplified expression is:
x + xz
Therefore, the correct answer is option B: x + xz.
The boolean expression of an OR gate is _______ - a)A.B
- b)A’B + AB’
- c)A + B
- d)A’B’
Correct answer is option 'C'. Can you explain this answer?
The boolean expression of an OR gate is _______
a)
A.B
b)
A’B + AB’
c)
A + B
d)
A’B’
|
|
Vedika Singh answered |
An OR gate gives the result as 1 if any one of the inputs is one.
Its expression is A + B.
An OR gate gives a 0 only if both the inputs are 0.
Its expression is A + B.
An OR gate gives a 0 only if both the inputs are 0.
The output of which of the following logic gate is high when one or both of the input is low :- a)NAND
- b)NOR
- c)AND
- d)XOR
Correct answer is option 'A,D'. Can you explain this answer?
The output of which of the following logic gate is high when one or both of the input is low :
a)
NAND
b)
NOR
c)
AND
d)
XOR
|
Oviya Kapoor answered |
Understanding the NAND Gate
The NAND gate is a fundamental digital logic gate that has a specific behavior based on its inputs. It is crucial to understand how it operates to answer the question correctly.
Function of the NAND Gate
- The NAND gate stands for "NOT AND," meaning it performs the AND operation followed by a NOT operation.
- It has two inputs and one output.
Truth Table for the NAND Gate
- The truth table for the NAND gate is as follows:
| Input A | Input B | Output (A NAND B) |
|---------|---------|-------------------|
| 0 | 0 | 1 |
| 0 | 1 | 1 |
| 1 | 0 | 1 |
| 1 | 1 | 0 |
Key Observations
- The output is high (1) when one or both inputs are low (0).
- The only time the output is low (0) is when both inputs are high (1).
Comparison with Other Gates
- NOR Gate: Outputs high only when both inputs are low.
- AND Gate: Outputs high only when both inputs are high.
- XOR Gate: Outputs high when exactly one input is high.
Conclusion
Thus, the correct answer to the question is option B (NAND) because its output is high (1) when one or both of the inputs are low (0).
The NAND gate is a fundamental digital logic gate that has a specific behavior based on its inputs. It is crucial to understand how it operates to answer the question correctly.
Function of the NAND Gate
- The NAND gate stands for "NOT AND," meaning it performs the AND operation followed by a NOT operation.
- It has two inputs and one output.
Truth Table for the NAND Gate
- The truth table for the NAND gate is as follows:
| Input A | Input B | Output (A NAND B) |
|---------|---------|-------------------|
| 0 | 0 | 1 |
| 0 | 1 | 1 |
| 1 | 0 | 1 |
| 1 | 1 | 0 |
Key Observations
- The output is high (1) when one or both inputs are low (0).
- The only time the output is low (0) is when both inputs are high (1).
Comparison with Other Gates
- NOR Gate: Outputs high only when both inputs are low.
- AND Gate: Outputs high only when both inputs are high.
- XOR Gate: Outputs high when exactly one input is high.
Conclusion
Thus, the correct answer to the question is option B (NAND) because its output is high (1) when one or both of the inputs are low (0).
The boolean expression 
is equivalent to :- a)
- b)
- c)
- d)
Correct answer is option 'C,D'. Can you explain this answer?
The boolean expression is equivalent to :
is equivalent to :a)
b)
c)
d)
|
|
Sahana Sharma answered |
The correct answers are: 
The output of a logic gate is high when all its inputs are at logic 0. The gate can be :
- a)NAND
- b)OR
- c)XNOR
- d)NOR
Correct answer is option 'A,C,D'. Can you explain this answer?
The output of a logic gate is high when all its inputs are at logic 0. The gate can be :
a)
NAND
b)
OR
c)
XNOR
d)
NOR
|
Chirag Nambiar answered |
The Truth table for NAND gate is given below
The Truth table for XNOR gate is given below
The Truth table for NOR gate is given below
It is clear from the tables that when all the inputs are zero the output is high for NAND, XNOR and NOR. Hence correct answers are a, c and d.
Which gates are required to build an exclusive OR (XOR) gate?- a)OR
- b)AND
- c)NOT
- d)None of the above
Correct answer is option 'A,B,C'. Can you explain this answer?
Which gates are required to build an exclusive OR (XOR) gate?
a)
OR
b)
AND
c)
NOT
d)
None of the above
|
|
Milan Majumdar answered |
The correct answers are: OR, AND, NOT
If a 3-input OR gate has eight input possibilities, how many of those possibilities will result in a HIGH output?
- a)8
- b)1
- c)2
- d)7
Correct answer is option 'D'. Can you explain this answer?
If a 3-input OR gate has eight input possibilities, how many of those possibilities will result in a HIGH output?
a)
8
b)
1
c)
2
d)
7
|
Xena Bhatia answered |
Answer:
To determine the number of input possibilities for a 3-input AND gate that result in a HIGH output, we need to consider all the possible combinations of input values.
Truth table for a 3-input AND gate:
The truth table for a 3-input AND gate consists of 8 rows, representing all possible combinations of input values. Each row corresponds to a specific combination of input values, and the output column indicates whether the output is HIGH or LOW for that particular combination.
To analyze the truth table, we need to understand the behavior of an AND gate:
- An AND gate produces a HIGH output only when all of its inputs are HIGH.
- If any of the inputs are LOW, the output will be LOW.
Analysis of the truth table:
In the truth table for a 3-input AND gate, there are 8 rows, representing all possible combinations of input values (0 or 1). The output column indicates whether the output is HIGH (1) or LOW (0) for each combination.
We can observe that there is only one row in the truth table where all three inputs are HIGH (1), and the output is also HIGH (1). This means that there is only one input possibility that results in a HIGH output.
Therefore, the correct answer is option 'D', which states that there is only 1 input possibility for a 3-input AND gate that will result in a HIGH output.
Summary:
- The truth table for a 3-input AND gate consists of 8 rows representing all possible combinations of input values.
- An AND gate produces a HIGH output only when all of its inputs are HIGH.
- In the truth table, there is only one row where all three inputs are HIGH, resulting in a HIGH output.
- Therefore, there is only 1 input possibility for a 3-input AND gate that will result in a HIGH output.
To determine the number of input possibilities for a 3-input AND gate that result in a HIGH output, we need to consider all the possible combinations of input values.
Truth table for a 3-input AND gate:
The truth table for a 3-input AND gate consists of 8 rows, representing all possible combinations of input values. Each row corresponds to a specific combination of input values, and the output column indicates whether the output is HIGH or LOW for that particular combination.
To analyze the truth table, we need to understand the behavior of an AND gate:
- An AND gate produces a HIGH output only when all of its inputs are HIGH.
- If any of the inputs are LOW, the output will be LOW.
Analysis of the truth table:
In the truth table for a 3-input AND gate, there are 8 rows, representing all possible combinations of input values (0 or 1). The output column indicates whether the output is HIGH (1) or LOW (0) for each combination.
We can observe that there is only one row in the truth table where all three inputs are HIGH (1), and the output is also HIGH (1). This means that there is only one input possibility that results in a HIGH output.
Therefore, the correct answer is option 'D', which states that there is only 1 input possibility for a 3-input AND gate that will result in a HIGH output.
Summary:
- The truth table for a 3-input AND gate consists of 8 rows representing all possible combinations of input values.
- An AND gate produces a HIGH output only when all of its inputs are HIGH.
- In the truth table, there is only one row where all three inputs are HIGH, resulting in a HIGH output.
- Therefore, there is only 1 input possibility for a 3-input AND gate that will result in a HIGH output.
is equivalent to :
Which of the following is true for an exclusive OR gate?- a)
- b)
- c)
- d)
Correct answer is option 'C'. Can you explain this answer?
Which of the following is true for an exclusive OR gate?
a)
b)
c)
d)
|
Pie Academy answered |
The exclusive OR (XOR) gate is a digital logic gate that outputs true or high only when the inputs are unequal.
- If one input is true (1) and the other is false (0), the output is true (1).
- If both inputs are the same (either true or both false), the output is false (0).
This behaviour is captured by the truth table of an XOR gate.
The correct answer is: 
What gate corresponds to the logic gate shown above :- a)XOR
- b)NOR
- c)NAND
- d)OR
Correct answer is option 'C'. Can you explain this answer?
What gate corresponds to the logic gate shown above :
a)
XOR
b)
NOR
c)
NAND
d)
OR
|
|
Pie Academy answered |
This logic gate is a combination of AND and NOT gates. It outputs false only when all inputs are true. For any other input combination, the output is true.
The output of an AND gate with 3 inputs A, B and C is high when :- a)A = 1 ,B = 1 ,C = 0
- b)A = 1,B = 0, C=1
- c)A = 0, B = 0, C = 0
- d)A= 1, B= 1, C= 1
Correct answer is option 'D'. Can you explain this answer?
The output of an AND gate with 3 inputs A, B and C is high when :
a)
A = 1 ,B = 1 ,C = 0
b)
A = 1,B = 0, C=1
c)
A = 0, B = 0, C = 0
d)
A= 1, B= 1, C= 1
|
|
Pie Academy answered |
The output of an AND gate with three inputs is high only when all inputs are high.
- Inputs A, B, and C must all be 1 for the output to be high.
- In this scenario: A = 1, B = 1, C = 1.
Therefore, the correct condition is A = 1, B = 1, C = 1.
If a signal passing through a gate is inhibited by sending a LOW into one of the inputs and the output is HIGH, the gate is a(n)- a)NAND
- b)AND
- c)NOR
- d)OR
Correct answer is option 'A'. Can you explain this answer?
If a signal passing through a gate is inhibited by sending a LOW into one of the inputs and the output is HIGH, the gate is a(n)
a)
NAND
b)
AND
c)
NOR
d)
OR
|
|
Pie Academy answered |
The NAND gate is a type of digital logic gate. When one input is LOW, the output is HIGH. This behaviour is characteristic of the NAND gate. The gate inhibits signals with a LOW input, ensuring the output remains HIGH.
If a 3 input NOR gate has eight input possibilities how many of them will result in a high output?- a)7
- b)8
- c)2
- d)1
Correct answer is option 'D'. Can you explain this answer?
If a 3 input NOR gate has eight input possibilities how many of them will result in a high output?
a)
7
b)
8
c)
2
d)
1
|
|
Pie Academy answered |
A 3-input NOR gate produces a high output only when all its inputs are low.
- There are 8 possible input combinations for a 3-input gate.
- These combinations include all permutations of high and low inputs.
- For a NOR gate, only the combination where all inputs are 0 results in a high output.
Therefore, there is 1 combination that gives a high output.
It is required to change a logic 1 to logic 0 and vice versa the logic gate required to do this is :- a)buffer
- b)XOR
- c)inverter
- d)XNOR
Correct answer is option 'C'. Can you explain this answer?
It is required to change a logic 1 to logic 0 and vice versa the logic gate required to do this is :
a)
buffer
b)
XOR
c)
inverter
d)
XNOR
|
|
Pie Academy answered |
The solution involves changing a logic 1 to logic 0 and vice versa.
The correct logic gate for this operation is an inverter.
What is the expression for a 4 input OR gate?- a)Y = A + B + C + D
- b)A . B . C . D
- c)Y = A + B . C + D
- d)Y = A + B + C . D
Correct answer is option 'A'. Can you explain this answer?
What is the expression for a 4 input OR gate?
a)
Y = A + B + C + D
b)
A . B . C . D
c)
Y = A + B . C + D
d)
Y = A + B
+
C . D|
|
Pie Academy answered |
The correct expression for a 4-input OR gate is:
- Y = A + B + C + D
This means that the output Y will be 1 (true) if at least one of the inputs, A, B, C, or D, is 1.
What gate corresponds to the above logic gate?- a)NOR gate
- b)Exclusive OR gate
- c)NAND gate
- d)AND gate
Correct answer is option 'A'. Can you explain this answer?
What gate corresponds to the above logic gate?
a)
NOR gate
b)
Exclusive OR gate
c)
NAND gate
d)
AND gate
|
|
Pie Academy answered |
The logic gate shown corresponds to the NOR gate. A NOR gate is a combination of an OR gate followed by a NOT gate. It outputs false when at least one of its inputs is true.
When all inputs are false, the output is true.
Chapter doubts & questions for Logic Gates - Topic wise Tests for IIT JAM Physics 2025 is part of Physics exam preparation. The chapters have been prepared according to the Physics exam syllabus. The Chapter doubts & questions, notes, tests & MCQs are made for Physics 2025 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests here.
Chapter doubts & questions of Logic Gates - Topic wise Tests for IIT JAM Physics in English & Hindi are available as part of Physics exam.
Download more important topics, notes, lectures and mock test series for Physics Exam by signing up for free.
|
© EduRev
|
Education Revolution
|
|
Signup on EduRev and stay on top of your study goals
10M+ students crushing their study goals daily