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All questions of Perimeter of Various Shapes & Area of Rectangle and Square for Class 5 Exam
The perimeter of a square is 20 cm. What is the length of each side of the square?- a)80 cm
- b)18 cm
- c)5 cm
- d)4 cm
Correct answer is option 'C'. Can you explain this answer?
The perimeter of a square is 20 cm. What is the length of each side of the square?
a)
80 cm
b)
18 cm
c)
5 cm
d)
4 cm
|
Gunjan Lakhani answered |
To find the length of each side of the square:
- The perimeter of a square is calculated using the formula: Perimeter = 4 × side length.
- Given that the perimeter is 20 cm, set up the equation:
- 4 × side length = 20 cm
- To find the side length, divide both sides by 4:
- side length = 20 cm / 4
- Thus, the length of each side is 5 cm.
A square has an area of 64 cm2. What is the length of each side?- a)8 cm
- b)16 cm
- c)32 cm
- d)60 cm
Correct answer is option 'A'. Can you explain this answer?
A square has an area of 64 cm2. What is the length of each side?
a)
8 cm
b)
16 cm
c)
32 cm
d)
60 cm
|
Shubham mishra answered |
The area of a square is given by the formula A = s^2, where A is the area and s is the length of each side. We are given that the area of the square is 64 cm^2, so we can set up the equation 64 = s^2. Solving for s, we get s = 8 cm. Therefore, the length of each side of the square is 8 cm.
The area of the figure above is _____
m2.
- a)42
- b)88
- c)108
- d)123
Correct answer is option 'B'. Can you explain this answer?
The area of the figure above is _____
m2.
m2.
a)
42
b)
88
c)
108
d)
123
|
Stoneridge Institute answered |
first break it into a rectangle and square
rectangle of LxB=9x7
square of side=5
so area of rectangle = 9x7 =63
area of square = 5x5 = 25
so total area = 63 +25
= 88
Find the area of the triangle shown.
- a)2.5 cm2
- b)32.5 cm2
- c)65 cm2
- d)71.5 cm2
Correct answer is option 'B'. Can you explain this answer?
Find the area of the triangle shown.
a)
2.5 cm2
b)
32.5 cm2
c)
65 cm2
d)
71.5 cm2
|
Kunal Desai answered |
Area of triangle = 1/2 (b*h)
= 1/2 (13*5)
= 65/2
= 32.5 cm2
The figure below is made up of three squares. Find the perimeter of the figure.
- a)48 cm
- b)60 cm
- c)72 cm
- d)144 cm
Correct answer is option 'A'. Can you explain this answer?
The figure below is made up of three squares. Find the perimeter of the figure.
a)
48 cm
b)
60 cm
c)
72 cm
d)
144 cm
|
|
Gunjan Lakhani answered |
there are 8 boundry lines so 8 * a = 8*6 = 48
Calculate the area of rectangle if one square represents an area of 1 cm2 .
- a)2 cm2
- b)9 cm2
- c)50 cm2
- d)24 cm2
Correct answer is option 'D'. Can you explain this answer?
Calculate the area of rectangle if one square represents an area of 1 cm2 .
a)
2 cm2
b)
9 cm2
c)
50 cm2
d)
24 cm2
|
Edu Impact answered |
There are 6×4=24 squares and each square has an area of = 1cm2. So, the area of rectangle = 6×4×1=24cm2.
Which one of the following rectangles had the biggest perimeter?- a)
- b)
- c)
- d)
Correct answer is option 'B'. Can you explain this answer?
Which one of the following rectangles had the biggest perimeter?
a)
b)
c)
d)
|
Saikat Chavan answered |
A) Area = 96m2
Breadth = 8m
Area = l*b
96 = l*8
l =12
Perimeter = 2(l+b)
= 2(12+8) = 40
B) Area = 110m2
Breadth = 10cm = 0.1m
Area = l*b
110 = l*0.1
l =1100
Perimeter = 2(l+b)
= 2(1100+0.1) = 2200.2
C) Area = 90m2
Length = 15cm = 0.15m
Area = l*b
90 = 0.15*b
b = 600m
Perimeter = 2(l+b)
= 2(0.15+600) = 1200.3
D) Area = 100m2
Length = 25cm = 0.25m
Area = l*b
100 = 0.25*b
b = 400m
Perimeter = 2(l+b)
= 2(0.25+400) = 800.5
A rectangular garden measures 25 m by 20 m. What is the cost of erecting a wooden fence around it if every 5 metres of wooden fencing cost $ 27?
- a)$ 486
- b)$ 500
- c)$ 2430
- d)$ 2700
Correct answer is option 'A'. Can you explain this answer?
A rectangular garden measures 25 m by 20 m. What is the cost of erecting a wooden fence around it if every 5 metres of wooden fencing cost $ 27?
a)
$ 486
b)
$ 500
c)
$ 2430
d)
$ 2700
|
|
Divyansh Basu answered |
Let's take perimeter of recatngular garden=
2(20m+25m)= 90m
Cost of fencing every 5 m= Rs 27
Cost of fencing 90 m= $ 27/5 ×90
= $ 27× 18= $ 486
2(20m+25m)= 90m
Cost of fencing every 5 m= Rs 27
Cost of fencing 90 m= $ 27/5 ×90
= $ 27× 18= $ 486
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