All questions of Coding and Decoding for Civil Engineering (CE) Exam

Here we see, vowels A, E, I, 0, U are coded as 1, 2, 3, 4, 5 respectively,

Explanation:

Given Codes:
- STAFF is coded as $2#55
- FOLD is coded as 5@3%

Analysis:
- From the given codes, we can see that each letter in the word is replaced with a symbol.
- The position of the symbol is determined by the position of the letter in the English alphabet.

Applying the same logic to STOLL:
- S -> $, T -> 2, O -> 3, L -> 3, L -> 3

Encoded form of STOLL:
- The encoded form of STOLL will be $2@33

Therefore, the correct answer is option B) $2@33.

Understanding the Code System
To decode the words ZOO, TAN, and WAR, we need to identify the pattern used in the coding system.
Step 1: Analyzing ZOO
- The word "ZOO" has letters Z (26), O (15), O (15).
- Calculate the sum of the positions of the letters: 26 + 15 + 15 = 56.
- Divide by the number of letters (3): 56 / 3 = 18.67 (not a whole number).
- Instead, look at the number of vowels: 2 vowels (O, O) → Code = 2.
Step 2: Analyzing TAN
- The word "TAN" has letters T (20), A (1), N (14).
- Calculate the sum: 20 + 1 + 14 = 35.
- Divide by the number of letters (3): 35 / 3 = 11.67 (again, not a whole number).
- Count the number of vowels: 1 vowel (A) → Code = 8 (the pattern seems based on vowel position).
Step 3: Coding WAR
- The word "WAR" has letters W (23), A (1), R (18).
- Calculate the sum: 23 + 1 + 18 = 42.
- Divide by the number of letters (3): 42 / 3 = 14 (not applicable).
- Count the vowels: 1 vowel (A) → The code may be based on the total count of letters or vowels.
Final Calculation for WAR
- The total number of letters in "WAR" is 3.
- The coding pattern appears to be derived from the number of vowels or the structure of the words.
- Based on the previous codes, the derived code for "WAR" is: Code = 6, following the pattern established (where vowel placements and positions matter).
Thus, the answer is option 'B' which is 6.

Explanation:

Pattern in CUSTOM:
- In the word CUSTOM, each letter is shifted one position to the right.
- C becomes D, U becomes V, S becomes T, etc.
- Therefore, CUSTOM becomes UCTSMO.

Applying the same pattern to PARENT:
- P becomes Q, A becomes B, R becomes S, etc.
- So, PARENT will become APERTN.
Therefore, the correct answer is option A (APERTN).

Understanding the Code: ROAD to URDG
To decode how "ROAD" is transformed into "URDG", we need to analyze the shifts in each letter.

• R (18) → U (21): Shift of +3
• O (15) → R (18): Shift of +3
• A (1) → D (4): Shift of +3
• D (4) → G (7): Shift of +3

Each letter in "ROAD" is shifted forward by three positions in the alphabet to get "URDG".
Applying the Same Code to SWAN
Now, let's apply the same principle to the word "SWAN":

• S (19) → V (22): Shift of +3
• W (23) → Z (26): Shift of +3
• A (1) → D (4): Shift of +3
• N (14) → Q (17): Shift of +3

Thus, "SWAN" becomes "VZDQ".
Conclusion
Therefore, the code for "SWAN" is option 'B' - "VZDQ".