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All questions of Gravitation for NEET Exam
A satellite A of mass m is at a distance of r from the surface of the earth. Another satellite B of mass 2m is at a distance of 2r from the earth’s centre. Their time periods are in the ratio of [1993]- a)1 : 2
- b)1 : 16
- c)1 : 32
- d)
Correct answer is option 'D'. Can you explain this answer?
A satellite A of mass m is at a distance of r from the surface of the earth. Another satellite B of mass 2m is at a distance of 2r from the earth’s centre. Their time periods are in the ratio of [1993]
a)
1 : 2
b)
1 : 16
c)
1 : 32
d)
|
Abhishek Desai answered |
Time period does not depend on the mass.
Also, T2 ∝ r3 .
Also, T2 ∝ r3 .
A particle of mass M is situated at the centre of a spherical shell of same mass and radius a. The gravitational potential at a point situated at 
distance from the centre, will be: [2010]- a)
- b)
- c)
- d)
Correct answer is option 'A'. Can you explain this answer?
A particle of mass M is situated at the centre of a spherical shell of same mass and radius a. The gravitational potential at a point situated at distance from the centre, will be: [2010]
distance from the centre, will be: [2010]a)
b)
c)
d)
|
Pankaj Kulkarni answered |
Potential at the given point = Potential at the point due to the shell + Potential due to the particle
Assuming earth to be a sphere of uniform density, what is the value of ‘g’ in a mine 100 km below the earth’s surface? (Given, R = 6400 km) [2001]- a)9.65 m/s2
- b)7.65 m/s2
- c)5.06 m/s2
- d)3.10 m/s2
Correct answer is option 'A'. Can you explain this answer?
Assuming earth to be a sphere of uniform density, what is the value of ‘g’ in a mine 100 km below the earth’s surface? (Given, R = 6400 km) [2001]
a)
9.65 m/s2
b)
7.65 m/s2
c)
5.06 m/s2
d)
3.10 m/s2
|
Jatin Chakraborty answered |
We know that effective gravity g' at depth below earth surface is given by
Here, d = 100 km, R = 6400 km,
The mean radius of earth is R, its angular speed on its own axis is ω and the acceleration due to gravity at earth's surface is g. What will be the radius of the orbit of a geostationary satellite ? [1992]- a)( R2g/ω2)1/3
- b)( Rg/ω2)1/3
- c)( R2ω2/g)1/3
- d)( R 2g /ω)1/3
Correct answer is option 'A'. Can you explain this answer?
The mean radius of earth is R, its angular speed on its own axis is ω and the acceleration due to gravity at earth's surface is g. What will be the radius of the orbit of a geostationary satellite ? [1992]
a)
( R2g/ω2)1/3
b)
( Rg/ω2)1/3
c)
( R2ω2/g)1/3
d)
( R 2g /ω)1/3
|
Sarthak Saini answered |
Hence, 
Infinite number of bodies, each of mass 2 kg are situated on x-axis at distances 1m, 2m, 4m, 8m, ..... respectively, from the origin. The resulting gravitational potential due to this system at the origin will be [NEET 2013]- a)
- b)
- c)– 4 G
- d)– G
Correct answer is option 'C'. Can you explain this answer?
Infinite number of bodies, each of mass 2 kg are situated on x-axis at distances 1m, 2m, 4m, 8m, ..... respectively, from the origin. The resulting gravitational potential due to this system at the origin will be [NEET 2013]
a)
b)
c)
– 4 G
d)
– G
|
Pioneer Academy answered |
Gravitational potential 
A ball is dropped from a satellite revolving around the earth at a height of 120 km. The ball will [1996]- a)continue to move with same speed along a straight line tangentially to the satellite at that time
- b)continue to move with the same speed along the original orbit of satellite
- c)fall down to earth gradually
- d)go far away in space
Correct answer is option 'B'. Can you explain this answer?
A ball is dropped from a satellite revolving around the earth at a height of 120 km. The ball will [1996]
a)
continue to move with same speed along a straight line tangentially to the satellite at that time
b)
continue to move with the same speed along the original orbit of satellite
c)
fall down to earth gradually
d)
go far away in space
|
Sonal Kulkarni answered |
The orbital speed of satellite is independent of mass of satellite, so the ball will behave as a satellite and will continue to move with the same speed in the original orbit.
Which one of the following plots represents the variation of gravitational field on a particle with distance r due to a thin spherical shell of radius R ? (r is measured from the centre of the spherical shell) [2012M]- a)
- b)
- c)
- d)
Correct answer is option 'B'. Can you explain this answer?
Which one of the following plots represents the variation of gravitational field on a particle with distance r due to a thin spherical shell of radius R ? (r is measured from the centre of the spherical shell) [2012M]
a)
b)
c)
d)
|
|
Shristi Sharya answered |
Inside cell electric field zero.
on surface maximum but inversely proportion to Radius2...
on outer surface inversely proportion to r2.. but decrease continuesly.
on surface maximum but inversely proportion to Radius2...
on outer surface inversely proportion to r2.. but decrease continuesly.
A satellite in force free space sweeps stationary interplanetary dust at a rate dM/dt = αv where M is the mass and v is the velocity of the satellite and α is a constant. What is the deceleration of the satellite? [1994]- a)-αv2
- b)-αv2/2M
- c)-αv2/M
- d)-2αv2/M
Correct answer is option 'C'. Can you explain this answer?
A satellite in force free space sweeps stationary interplanetary dust at a rate dM/dt = αv where M is the mass and v is the velocity of the satellite and α is a constant. What is the deceleration of the satellite? [1994]
a)
-αv2
b)
-αv2/2M
c)
-αv2/M
d)
-2αv2/M
|
|
Jatin Chakraborty answered |
A roller coaster is designed such that riders experience “weightlesness” as they go round the top of a hill whose radius of curvature is 20 m.The speed of the car at the top of the hill is between: [2008]- a)14 m/s and 15 m/s
- b)15 m/s and 16 m/s
- c)16 m/s and 17 m/s
- d)13 m/s and 14 m/s
Correct answer is option 'A'. Can you explain this answer?
A roller coaster is designed such that riders experience “weightlesness” as they go round the top of a hill whose radius of curvature is 20 m.The speed of the car at the top of the hill is between: [2008]
a)
14 m/s and 15 m/s
b)
15 m/s and 16 m/s
c)
16 m/s and 17 m/s
d)
13 m/s and 14 m/s
|
Prashanth Dasgupta answered |
For the riders to experience weightlessness at the top of the hill, the weight of the radius must be balanced by the centripetal force.
Hence, the speed of the car should be between 14 ms–1 and 15 ms–1.
Two spheres of masses m and M are situated in air and the gravitational force between them is F.The space around the masses is now filled with a liquid of specific gravity 3. The gravitational force will now be [2003]- a)
- b)3F
- c)F
- d)
Correct answer is option 'C'. Can you explain this answer?
Two spheres of masses m and M are situated in air and the gravitational force between them is F.The space around the masses is now filled with a liquid of specific gravity 3. The gravitational force will now be [2003]
a)
b)
3F
c)
F
d)
|
Lekshmi Banerjee answered |
Gravitational force is independent of medium, Hence, this will remain same.
The potential energy of a satellite, having mass m and rotating at a height of 6.4 × 106m from the earth surface, is [2001]- a)– mgRe
- b)– 0.67 mgRe
- c)– 0.5 mgRe
- d)– 0.33 mgRe
Correct answer is option 'C'. Can you explain this answer?
The potential energy of a satellite, having mass m and rotating at a height of 6.4 × 106m from the earth surface, is [2001]
a)
– mgRe
b)
– 0.67 mgRe
c)
– 0.5 mgRe
d)
– 0.33 mgRe
|
Sreemoyee Chopra answered |
The potential energy of a satellite can be calculated using the formula:
Potential Energy = mgh
Where:
m = mass of the satellite
g = acceleration due to gravity
h = height of the satellite
In this case, the height of the satellite is given as 6.4. We need to know the units of the height (e.g. meters, kilometers) in order to calculate the potential energy accurately.
Potential Energy = mgh
Where:
m = mass of the satellite
g = acceleration due to gravity
h = height of the satellite
In this case, the height of the satellite is given as 6.4. We need to know the units of the height (e.g. meters, kilometers) in order to calculate the potential energy accurately.
The density of a newly discovered planet is twice that of earth. The acceleration due to gravity at the surface of the planet is equal to that at the surface of the earth. If the radius of the earth is R, the radius of the planet would be- a)½ R
- b)2 R [2004]
- c)4 R
- d)1/4 R
Correct answer is option 'A'. Can you explain this answer?
The density of a newly discovered planet is twice that of earth. The acceleration due to gravity at the surface of the planet is equal to that at the surface of the earth. If the radius of the earth is R, the radius of the planet would be
a)
½ R
b)
2 R [2004]
c)
4 R
d)
1/4 R
|
Muskaan Basak answered |
At the surface of planet, 
At the surface of the earth 
The escape velocity from the surface of the earth is ve.The escape velocity from the surface of a planet whose mass and radius are three times those of the earth, will be [1995]- a)ve
- b)3ve
- c)9ve
- d)1/3ve
Correct answer is option 'A'. Can you explain this answer?
The escape velocity from the surface of the earth is ve.The escape velocity from the surface of a planet whose mass and radius are three times those of the earth, will be [1995]
a)
ve
b)
3ve
c)
9ve
d)
1/3ve
|
Nayanika Dasgupta answered |
Escape velocity on surface of earth
or, vP= ve.
If the gravitational force between two objects were proportional to 1/R (and not as 1/R2) where R is separation between them, then a particle in circular orbit under such a force would have its orbital speed v proportional to [1989]- a)1/R2
- b)R0
- c)R1
- d)1/R
Correct answer is option 'B'. Can you explain this answer?
If the gravitational force between two objects were proportional to 1/R (and not as 1/R2) where R is separation between them, then a particle in circular orbit under such a force would have its orbital speed v proportional to [1989]
a)
1/R2
b)
R0
c)
R1
d)
1/R
|
Pallabi Reddy answered |
Hence v ∝ R0A planet is moving in an elliptical orbit around the sun. If T, V, E and L stand respectively for its kinetic energy, gravitational potential energy, total energy and magnitude of angular momentum about the centre of force, which of the following is correct ? [1990]- a)T is conserved
- b)V is always positive
- c)E is always negative
- d)L is conserved but direction of vector L changes continuously
Correct answer is option 'C'. Can you explain this answer?
A planet is moving in an elliptical orbit around the sun. If T, V, E and L stand respectively for its kinetic energy, gravitational potential energy, total energy and magnitude of angular momentum about the centre of force, which of the following is correct ? [1990]
a)
T is conserved
b)
V is always positive
c)
E is always negative
d)
L is conserved but direction of vector L changes continuously
|
Aashna Mukherjee answered |
In a circular or elliptical orbital motion, torque is always acting parallel to displacement or velocity. So, angular momentum is conserved.
In attractive field, potential energy is negative.
Kinetic energy changes as velocity increase when distance is less. So, option (c) is correct.
In attractive field, potential energy is negative.
Kinetic energy changes as velocity increase when distance is less. So, option (c) is correct.
Imagine a new planet having the same density as that of earth but it is 3 times bigger than the earth in size. If the acceleration due to gravity on the surface of earth is g and that on the surface of the new planet is g’, then [2005]- a)g’ = g/9
- b)g’ = 27g
- c)g’=9g
- d)g’=3g
Correct answer is option 'D'. Can you explain this answer?
Imagine a new planet having the same density as that of earth but it is 3 times bigger than the earth in size. If the acceleration due to gravity on the surface of earth is g and that on the surface of the new planet is g’, then [2005]
a)
g’ = g/9
b)
g’ = 27g
c)
g’=9g
d)
g’=3g
|
|
Sarthak Saini answered |
We know that
∴ g ' = 3g
A planet moving along an elliptical orbit is closest to the sun at a distance r1 and farthest away at a distance of r2. If v1 and v2 are the linear velocities at these points respectively, then the ratio 
is[2011]- a)(r1/r2)2
- b)r2/r1
- c)(r2/r1)2
- d)r1/r2
Correct answer is option 'B'. Can you explain this answer?
A planet moving along an elliptical orbit is closest to the sun at a distance r1 and farthest away at a distance of r2. If v1 and v2 are the linear velocities at these points respectively, then the ratio is[2011]
is[2011]a)
(r1/r2)2
b)
r2/r1
c)
(r2/r1)2
d)
r1/r2
|
Tejas Chavan answered |
Angular momentum is conserved
Assuming the radius of the earth as R, the change in gravitational potential energy of a body of mass m, when it is taken from the earth's surface to a height 3R above its surface, is [2002]- a)3 mg R
- b)
- c)1 mg R
- d)
Correct answer is option 'B'. Can you explain this answer?
Assuming the radius of the earth as R, the change in gravitational potential energy of a body of mass m, when it is taken from the earth's surface to a height 3R above its surface, is [2002]
a)
3 mg R
b)
c)
1 mg R
d)
|
Shruti Chauhan answered |
Gravitational potential energy (GPE) on the surface of earth,
GPE at 3R, 
∴ Change in GPE
The radius of a planet is twice the radius of earth.Both have almost equal average mass-densities.If VP and VE are escape velocities of the planet and the earth, respectively, then [NEET Kar. 2013]- a)VE = 1.5VP
- b)VP = 1.5VE
- c)VP = 2VE
- d)VE = 3VP
Correct answer is option 'C'. Can you explain this answer?
The radius of a planet is twice the radius of earth.Both have almost equal average mass-densities.If VP and VE are escape velocities of the planet and the earth, respectively, then [NEET Kar. 2013]
a)
VE = 1.5VP
b)
VP = 1.5VE
c)
VP = 2VE
d)
VE = 3VP
|
Yash Saha answered |
Escape velocity, 
A spherical planet has a mass MP and diameter DP. A particle of mass m falling freely near the surface of this planet will experience an acceleration due to gravity, equal to : [2012]- a)4GMP/DP2
- b)GMPm/DP2
- c)GMP/DP2
- d)4GMPm/DP2
Correct answer is option 'A'. Can you explain this answer?
A spherical planet has a mass MP and diameter DP. A particle of mass m falling freely near the surface of this planet will experience an acceleration due to gravity, equal to : [2012]
a)
4GMP/DP2
b)
GMPm/DP2
c)
GMP/DP2
d)
4GMPm/DP2
|
Vijay Bansal answered |
As we know g = GM/R^2
R= D/2
so,
g = GM/ (D/2)^2
= 4GM/ D^2
So as the mass of the planet = M
diameter = D
then g = 4GMp/ Dp^2
The escape velocity on the surface of earth is 11.2 km/s. What would be the escape velocity on the surface of another planet of the same mass but 1/4 times the radius of the earth? [2000]- a)22.4 km/s
- b)44.8 km/s
- c)5.6 km/s
- d)11.2 km/s
Correct answer is option 'A'. Can you explain this answer?
The escape velocity on the surface of earth is 11.2 km/s. What would be the escape velocity on the surface of another planet of the same mass but 1/4 times the radius of the earth? [2000]
a)
22.4 km/s
b)
44.8 km/s
c)
5.6 km/s
d)
11.2 km/s
|
Dipika Das answered |
The distance of Neptune and Saturn from the sun is nearly 1013 and 1012 meter respectively.Assuming that they move in circular orbits, their periodic times will be in the ratio [1994]- a)10
- b)100
- c)
- d)1000
Correct answer is option 'C'. Can you explain this answer?
The distance of Neptune and Saturn from the sun is nearly 1013 and 1012 meter respectively.Assuming that they move in circular orbits, their periodic times will be in the ratio [1994]
a)
10
b)
100
c)
d)
1000
|
|
Dipika Das answered |
T2 ∝ R3 (According to Kepler ’s law)
For a satellite escape velocity is 11 km/s. If the satellite is launched at an angle of 60° with the vertical, then escape velocity will be [1989]- a)11 km/s
- b)
- c)
- d)33 km/s
Correct answer is option 'A'. Can you explain this answer?
For a satellite escape velocity is 11 km/s. If the satellite is launched at an angle of 60° with the vertical, then escape velocity will be [1989]
a)
11 km/s
b)
c)
d)
33 km/s
|
|
Krish Khanna answered |
Since, escape velocity 
is independent of angle of projection, so it will not change.
is independent of angle of projection, so it will not change.A body weighs 72 N on the surface of the earth.What is the gravitational force on it due to earth at a height equal to half the radius of the earth from the surface? [2000]- a)32 N
- b)28 N
- c)16 N
- d)72 N
Correct answer is option 'A'. Can you explain this answer?
A body weighs 72 N on the surface of the earth.What is the gravitational force on it due to earth at a height equal to half the radius of the earth from the surface? [2000]
a)
32 N
b)
28 N
c)
16 N
d)
72 N
|
Arya Khanna answered |
mg = 72 N (body weight on the surface)
At a height 
Body weight at height 
A particle of mass ‘m’ is kept at rest at a height 3R from the surface of earth, where ‘R’ is radius of earth and ‘M’ is mass of earth. The minimum speed with which it should be projected, so that it does not return back, is (g is acceleration due to gravity on the surface of earth) [NEET Kar. 2013]- a)
- b)
- c)
- d)
Correct answer is option 'B'. Can you explain this answer?
A particle of mass ‘m’ is kept at rest at a height 3R from the surface of earth, where ‘R’ is radius of earth and ‘M’ is mass of earth. The minimum speed with which it should be projected, so that it does not return back, is (g is acceleration due to gravity on the surface of earth) [NEET Kar. 2013]
a)
b)
c)
d)
|
|
Pankaj Kulkarni answered |
As we know, the minimum speed with which a body is projected so that it does not return back is called escape speed.
Two satellites of earth, S1 and S2 are moving in the same orbit. The mass of S1 is four times the mass of S2. Which one of the following statements is true? [2007]- a)The potential energies of earth satellites in the two cases are equal.
- b)S1 and S2 are moving with the same speed.
- c)The kinetic energies of the two satellites are equal.
- d)The time period of S1 is four times that of S2.
Correct answer is option 'B'. Can you explain this answer?
Two satellites of earth, S1 and S2 are moving in the same orbit. The mass of S1 is four times the mass of S2. Which one of the following statements is true? [2007]
a)
The potential energies of earth satellites in the two cases are equal.
b)
S1 and S2 are moving with the same speed.
c)
The kinetic energies of the two satellites are equal.
d)
The time period of S1 is four times that of S2.
|
Nilanjan Chakraborty answered |
Since orbital velocity of satellite is
it does not depend upon the mass of the satellite.Therefore, both satellites will move with same speed.
The Earth is assumed to be a sphere of radius R.
A platform is arranged at a height R from the surface of the Earth. The escape velocity of a body from this platform is fv, where v is its escape velocity from the surface of the Earth.
The value of f is [2006]- a)
- b)
- c)
- d)
Correct answer is option 'A'. Can you explain this answer?
The Earth is assumed to be a sphere of radius R.
A platform is arranged at a height R from the surface of the Earth. The escape velocity of a body from this platform is fv, where v is its escape velocity from the surface of the Earth.
The value of f is [2006]
A platform is arranged at a height R from the surface of the Earth. The escape velocity of a body from this platform is fv, where v is its escape velocity from the surface of the Earth.
The value of f is [2006]
a)
b)
c)
d)
|
Ruchi Chopra answered |
Potential energy at height
If m be the mass of a body which is thrown with velocity ve so that it goes out of gravitational field from distance R, then
Comparing it with given equation, 
The acceleration due to gravity on the planet A is 9 times the acceleration due to gravity on planet B. A man jumps to a height of 2m on the surface of A. What is the height of jump by the same person on the planet B? [2003]- a)
- b)
- c)18 m
- d)6 m
Correct answer is option 'C'. Can you explain this answer?
The acceleration due to gravity on the planet A is 9 times the acceleration due to gravity on planet B. A man jumps to a height of 2m on the surface of A. What is the height of jump by the same person on the planet B? [2003]
a)
b)
c)
18 m
d)
6 m
|
|
Krish Khanna answered |
Applying conservation of total mechanical energy principle
The largest and the shortest distance of the earth from the sun are r1 and r2. Its distance from the sun when it is at perpendicular to the major-axis of the orbit drawn from the sun is [1988]- a)
- b)
- c)
- d)
Correct answer is option 'C'. Can you explain this answer?
The largest and the shortest distance of the earth from the sun are r1 and r2. Its distance from the sun when it is at perpendicular to the major-axis of the orbit drawn from the sun is [1988]
a)
b)
c)
d)
|
Surbhi Das answered |
Applying the properties of ellipse, we have
The figure shows elliptical or bit of a planet m about the sun S. The shaded area SCD is twice the shaded area SAB. If t1 is the time for the planet to move from C to D and t2 is the time to move from A to B then : [2009]
- a)t1 = 4t2
- b)t1 = 2t2
- c)t1 = t2
- d)t1 > t2
Correct answer is option 'B'. Can you explain this answer?
The figure shows elliptical or bit of a planet m about the sun S. The shaded area SCD is twice the shaded area SAB. If t1 is the time for the planet to move from C to D and t2 is the time to move from A to B then : [2009]
a)
t1 = 4t2
b)
t1 = 2t2
c)
t1 = t2
d)
t1 > t2
|
Harshitha Chavan answered |
According to Kepler ’s law, the areal velocity of a planet around the sun always remains constant.
SCD : A1– t1 (areal velocity constant)
SAB : A2 – t2
SCD : A1– t1 (areal velocity constant)
SAB : A2 – t2
∴ t1 = 2t2
A geostationary satellite is orbiting the earth at a height of 5R above that surface of the earth, R being the radius of the earth. The time period of another satellite in hours at a height of 2R from the surface of the earth is : [2012]- a)5
- b)10
- c)
- d)
Correct answer is option 'C'. Can you explain this answer?
A geostationary satellite is orbiting the earth at a height of 5R above that surface of the earth, R being the radius of the earth. The time period of another satellite in hours at a height of 2R from the surface of the earth is : [2012]
a)
5
b)
10
c)
d)
|
|
Ayeshashreya Mishra answered |
A particle of mass m is thrown upwards from the surface of the earth, with a velocity u. The mass and the radius of the earth are, respectively, M and R. G is gravitational constant and g is acceleration due to gravity on the surface of the earth. The minimum value of u so that the particle does not return back to earth, is [2011M]
- a)
- b)
- c)
- d)
Correct answer is option 'A'. Can you explain this answer?
A particle of mass m is thrown upwards from the surface of the earth, with a velocity u. The mass and the radius of the earth are, respectively, M and R. G is gravitational constant and g is acceleration due to gravity on the surface of the earth. The minimum value of u so that the particle does not return back to earth, is [2011M]
a)
b)
c)
d)
|
Mahesh Saini answered |
Particle will not return if it is thrown upwards with escape velocity. Conserving mechanical energy between the instants the particle is at the surface of the earth and at a very large distance
Ui+Ki=Uf+Kf
Ui+Ki=Uf+Kf
A seconds pendulum is mounted in a rocket. Its period of oscillation decreases when the rocket [1991]- a)comes down with uniform acceleration
- b)moves round the earth in a geostationary orbit
- c)moves up with a uniform velocity
- d)moves up with uniform acceleration
Correct answer is option 'D'. Can you explain this answer?
A seconds pendulum is mounted in a rocket. Its period of oscillation decreases when the rocket [1991]
a)
comes down with uniform acceleration
b)
moves round the earth in a geostationary orbit
c)
moves up with a uniform velocity
d)
moves up with uniform acceleration
|
|
Muskaan Basak answered |
. When the rocket accelerates upwards g increases to ( g + a).The escape velocity from earth is 11.2 km/s. If a body is to be projected in a direction making an angle 45° to the vertical, then the escape velocity is[1993]- a)11.2 × 2 km/s
- b)11.2 km/s
- c)
- d)
Correct answer is option 'B'. Can you explain this answer?
The escape velocity from earth is 11.2 km/s. If a body is to be projected in a direction making an angle 45° to the vertical, then the escape velocity is[1993]
a)
11.2 × 2 km/s
b)
11.2 km/s
c)
d)
|
Priyanka Iyer answered |
Escape velocity does not depend on the angle of projection.
The escape velocity of a sphere of mass m is given by (G = Universal gravitational constant; M = Mass of the earth and Re = Radius of the earth) [1999]- a)
- b)
- c)
- d)
Correct answer is option 'B'. Can you explain this answer?
The escape velocity of a sphere of mass m is given by (G = Universal gravitational constant; M = Mass of the earth and Re = Radius of the earth) [1999]
a)
b)
c)
d)
|
|
Abhishek Desai answered |
Escape velocity is the minimum velocity with which a body is projected to escape from earth's gravitational field
For a satellite moving in an or bit ar ound the earth, the ratio of kinetic energy to potential energy is [2005]- a)
- b)
- c)2
- d)
Correct answer is option 'A'. Can you explain this answer?
For a satellite moving in an or bit ar ound the earth, the ratio of kinetic energy to potential energy is [2005]
a)
b)
c)
2
d)
|
Ayush Sengupta answered |
K.E. of satellite moving in an orbit around the earth is
P.E. of satellite and earth system is
The escape velocity of a body on the surface of the earth is 11.2 km/s. If the earth’s mass increases to twice its present value and the radius of the earth becomes half, the escape velocity would become [1997]- a)44.8 km/s
- b)22.4 km/s
- c)11.2 km/s (remains unchanged)
- d)5.6 km/s
Correct answer is option 'B'. Can you explain this answer?
The escape velocity of a body on the surface of the earth is 11.2 km/s. If the earth’s mass increases to twice its present value and the radius of the earth becomes half, the escape velocity would become [1997]
a)
44.8 km/s
b)
22.4 km/s
c)
11.2 km/s (remains unchanged)
d)
5.6 km/s
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Pallabi Reddy answered |
Escape velcocity
v 'e = 2ve = 2 x 11.2 = 22.4 km/s
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