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All questions of Mechanical Properties of Fluids for NEET Exam
A fluid is in streamline flow across a horizontal pipe of variable area of cross section. For this which of the following statements is correct? [NEET Kar. 2013]- a)The velocity is minimum at the narrowest part of the pipe and the pressure is minimum at the widest part of the pipe
- b)The velocity is maximum at the narrowest part of the pipe and pressure is maximum at the widest part of the pipe
- c)Velocity and pressure both are maximum at the narrowest part of the pipe
- d)Velocity and pressure both are maximum at the widest part of the pipe
Correct answer is option 'B'. Can you explain this answer?
A fluid is in streamline flow across a horizontal pipe of variable area of cross section. For this which of the following statements is correct? [NEET Kar. 2013]
a)
The velocity is minimum at the narrowest part of the pipe and the pressure is minimum at the widest part of the pipe
b)
The velocity is maximum at the narrowest part of the pipe and pressure is maximum at the widest part of the pipe
c)
Velocity and pressure both are maximum at the narrowest part of the pipe
d)
Velocity and pressure both are maximum at the widest part of the pipe
|
Srishti Sen answered |
According to Bernoulli’s theorem,
= constant and Av = constantIf A is minimum, v is maximum, P is minimum.
The wetability of a surface by a liquid depends primarily on [NEET 2013]- a)surface tension
- b)density
- c)angle of contact between the surface and the liquid
- d)viscosity
Correct answer is option 'C'. Can you explain this answer?
The wetability of a surface by a liquid depends primarily on [NEET 2013]
a)
surface tension
b)
density
c)
angle of contact between the surface and the liquid
d)
viscosity
|
|
Srishti Sen answered |
Wetability of a surface by a liquid primarily depends on angle of contact between the surface and liquid.
If angle of contact is acute liquids wet the solid and vice-versa.
If angle of contact is acute liquids wet the solid and vice-versa.
In rising from the bottom of a lake, to the top, the temperature of an air bubble remains unchanged, but its diameter gets doubled. If h is the barometric height (expressed in m of mercury of relative densityρ) at the surface of the lake, the depth of the lake is [1994]- a)8ρh m
- b)7ρh m
- c)9ρh m
- d)12ρh m
Correct answer is option 'B'. Can you explain this answer?
In rising from the bottom of a lake, to the top, the temperature of an air bubble remains unchanged, but its diameter gets doubled. If h is the barometric height (expressed in m of mercury of relative densityρ) at the surface of the lake, the depth of the lake is [1994]
a)
8ρh m
b)
7ρh m
c)
9ρh m
d)
12ρh m
|
Ishani Nambiar answered |
This gives H = 7hρ
The angle of contact between pure water and pure glass, is [1996]- a)0º
- b)45º
- c)90º
- d)135º
Correct answer is option 'A'. Can you explain this answer?
The angle of contact between pure water and pure glass, is [1996]
a)
0º
b)
45º
c)
90º
d)
135º
|
|
Srishti Sen answered |
We know that angle of contact is the angle between the tangent to liquid surface at the point of contact and solid surface inside the liquid. In case of pure water and pure glass, the angle of contact is zero.
A rectangular block of mass m and area of crosssection A floats in a liquid of density ρ. If it is given a small vertical displacement from equilibrium it undergoes oscillation with a time period T. Then [2006]- a)
- b)
- c)
- d)
Correct answer is option 'A'. Can you explain this answer?
A rectangular block of mass m and area of crosssection A floats in a liquid of density ρ. If it is given a small vertical displacement from equilibrium it undergoes oscillation with a time period T. Then [2006]
a)
b)
c)
d)
|
|
Srishti Sen answered |
Let the body be depressed by distance x from its equilibrium position. The extra upthrust created is xρAg which applies to whole body.
If a be acceleration created then,
If a be acceleration created then,
Since, acceleration αx, so, it is equation of S.H.M.
The terminal velocity vr of a small steel ball of radius r falling under gravity through a column of a viscous liquid of coefficient of viscosity η depends on mass of the ball m, acceleration due to gravity g, coefficient of viscosity η and radius r. Which of the following relations is dimensionally correct ? [1992]- a)
- b)
- c)
- d)
Correct answer is option 'C'. Can you explain this answer?
The terminal velocity vr of a small steel ball of radius r falling under gravity through a column of a viscous liquid of coefficient of viscosity η depends on mass of the ball m, acceleration due to gravity g, coefficient of viscosity η and radius r. Which of the following relations is dimensionally correct ? [1992]
a)
b)
c)
d)
|
|
Srishti Sen answered |
Note that according to Stoke's law 6πrvr = mg
Hence, the valid relation is vr = mg /rη
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