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All questions of Binary Operations for JAMB Exam

If the binary operation ∗ is defined as a ∗ b = a^2 + b^2, what is the value of (−3) ∗ 2?
  • a)
    1
  • b)
    4
  • c)
    13
  • d)
    18
Correct answer is option 'C'. Can you explain this answer?

Understanding the Operation
The binary operation defined here is a ∗ b = a^2 + b^2. This means that when we perform the operation between two numbers, we square each number and then add the results together.
Applying the Operation
To find the value of (-3) ∗ 2, we will substitute -3 for 'a' and 2 for 'b' in the operation:
- a = -3
- b = 2
Now we calculate:
Step 1: Square the Values
- (-3)^2 = 9
- (2)^2 = 4
Step 2: Add the Squares
Now we sum the squared values:
- 9 + 4 = 13
Final Result
Thus, (-3) ∗ 2 = 13.
Conclusion
The value of (-3) ∗ 2 is 13, which corresponds to option 'C'. This demonstrates how the defined operation works by utilizing the properties of squaring and addition.

The set of real numbers under the operation ∗, defined as a ∗ b = a2 − b2, is closed. Which property does the operation satisfy?
  • a)
    Associative
  • b)
    Commutative
  • c)
    Identity
  • d)
    Inverse
Correct answer is option 'A'. Can you explain this answer?

The operation ∗ is closed under the set of real numbers, which means for any real numbers a and b, a ∗ b is also a real number. Therefore, the operation satisfies the closure property.

Let ⊗ be a binary operation on the set of rational numbers defined by a ⊗ b = ab + a. What is the identity element for this operation?
  • a)
    0
  • b)
    1
  • c)
    -1
  • d)
    2
Correct answer is option 'B'. Can you explain this answer?

For an element e to be an identity element, it should satisfy a ⊗ e = a for all elements a. By substituting a = 1 and e = 1 into the given expression, we get 1 ⊗ 1 = 1(1) + 1 = 1 + 1 = 2 ≠ 1. Hence, there is no identity element for this operation.

What is the result of the binary operation ⊕ on the set {1, 2, 3}, defined as a ⊕ b = a + b − ab?
  • a)
    {0, 1, 2}
  • b)
    {−2, −1, 0}
  • c)
    {0, 1, 3}
  • d)
    {−2, 0, 2}
Correct answer is option 'C'. Can you explain this answer?

Substituting the values, we get the following results:
1 ⊕ 1 = 1 + 1 − 1(1) = 1
1 ⊕ 2 = 1 + 2 − 1(2) = 1
1 ⊕ 3 = 1 + 3 − 1(3) = 0
2 ⊕ 1 = 2 + 1 − 2(1) = 1
2 ⊕ 2 = 2 + 2 − 2(2) = 0
2 ⊕ 3 = 2 + 3 − 2(3) = −1
3 ⊕ 1 = 3 + 1 − 3(1) = 0
3 ⊕ 2 = 3 + 2 − 3(2) = −1
3 ⊕ 3 = 3 + 3 − 3(3) = 3
Therefore, the result of the operation ⊕ is {0, 1, 3}.

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