All Exams  >   JAMB  >   Mathematics for JAMB  >   All Questions

All questions of Matrices and Determinants for JAMB Exam

  • a)
  • b)
  • c)
  • d)
Correct answer is option 'D'. Can you explain this answer?

Sushil Kumar answered
 P(n) : An = {(1+2n, -4n), (n,(1 - 2n))}
= P(k + 1) = {(1+2(k+1), -4(k+1)), (k+1, (1 - 2(k+1)}
= {(1+2k+2, -4k-4) (k+1, 1-2k-2)}
= {(2k+3, -4k-4), (k+1, -2k-1)}

If   and  , then AB=?
  • a)
    [7]
  • b)
    [1 - 12]
  • c)
  • d)
    [18]
Correct answer is option 'A'. Can you explain this answer?

Ritu Singh answered
A = [2, 3, 4]  
Therefore AXB = {(2*1) + (3*(-1)) + (4*2)}
AXB = {2 + (-3) + 8}
AXB = 7

For a skew symmetric even ordered matrix A of integers, which of the following will not hold true:
  • a)
    det(A) = 9
  • b)
    det(A) = 81
  • c)
    det(A) = 7
  • d)
    det(A) = 4
Correct answer is option 'C'. Can you explain this answer?

Skew Symmetric Even Ordered Matrix and Determinant

Skew Symmetric Matrix:
A skew symmetric matrix is a square matrix whose transpose is equal to its negative. In other words, if A is a skew symmetric matrix, then A^T = -A.
Example:
[0 -3 4]
[3 0 -5]
[-4 5 0]
This is a 3x3 skew symmetric matrix because A^T = -A.

Even Ordered Matrix:
An even ordered matrix is a square matrix whose order is even. In other words, if A is an even ordered matrix, then the order of A is 2n, where n is a positive integer.
Example:
[2 1 5 3]
[4 6 8 2]
[9 7 1 5]
[3 4 2 6]
This is a 4x4 even ordered matrix because the order of A is 2n=4.

Determinant of a Skew Symmetric Even Ordered Matrix:
The determinant of a skew symmetric even ordered matrix is always equal to zero. This is because the determinant of a skew symmetric matrix of odd order is always equal to zero and the determinant of any even ordered matrix can be expressed as a sum of permutations of the determinants of its n x n submatrices. Since the submatrices of a skew symmetric matrix are also skew symmetric, their determinants are equal to zero. Therefore, the determinant of a skew symmetric even ordered matrix is also equal to zero.

Solution:

a) det(A) = 9
Since the determinant of a skew symmetric even ordered matrix is always equal to zero, this statement is false. Therefore, option 'a' is not true.

b) det(A) = 81
Since the determinant of a skew symmetric even ordered matrix is always equal to zero, this statement is false. Therefore, option 'b' is not true.

c) det(A) = 7
This statement is false because the determinant of a skew symmetric even ordered matrix is always equal to zero.

d) det(A) = 4
Since the determinant of a skew symmetric even ordered matrix is always equal to zero, this statement is false. Therefore, option 'd' is not true.

Therefore, the correct answer is option 'c'.

If  and  , then AB = ?
  • a)
  • b)
  • c)
  • d)
Correct answer is option 'B'. Can you explain this answer?

Tanoy Rudra answered
Always check out for the new order and compatability of the order of both the matrices A & B. Then, multiply first Row element of A i.e. 2 with B's first column i.e [-1 2 -2] and then 2nd row element of A i.e 3 with [-1 2 -2].Resulting order will be of {2x 1(A) & 1x 3(B) } is 2 x 3.Hence , the given option B.

If  and  then AB = ?
  • a)
    [0]
  • b)
    B
  • c)
  • d)
    A
Correct answer is option 'D'. Can you explain this answer?

By using multiplication of matrices, we know that no of columns of A should be equal to no of rows of B. so the order of matrix AB is1*1. here B is a identity matrix . and any matrix multiplied to identity matrix I is the matrix itself. hence AB=A.

If A, B are, respectively m × n, k × l matrices, then both AB and BA are defined if and only if​
 
  • a)
    n = m , k = m
  • b)
    m = l , n= l
  • c)
    m = n, k = l
  • d)
    n = k and l = m.
Correct answer is option 'D'. Can you explain this answer?

Nikita Singh answered
If A, B are, respectively m × n, k × l matrices, then both AB and BA are defined if and only if n = k and l = m. In particular, if both A and B are square matrices of the same order, then both AB and BA are defined.

Value of determinant is computed by adding multiples of one row to
  • a)
    another dimension
  • b)
    another row
  • c)
    another column
  • d)
    another matrix
Correct answer is option 'B'. Can you explain this answer?

Lalit Yadav answered
Value of Determinant remains unchanged if we add equal multiples of all the elements of row (column) to corresponding elements of another row (column) If, we have a given matrix A.

Chapter doubts & questions for Matrices and Determinants - Mathematics for JAMB 2025 is part of JAMB exam preparation. The chapters have been prepared according to the JAMB exam syllabus. The Chapter doubts & questions, notes, tests & MCQs are made for JAMB 2025 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests here.

Chapter doubts & questions of Matrices and Determinants - Mathematics for JAMB in English & Hindi are available as part of JAMB exam. Download more important topics, notes, lectures and mock test series for JAMB Exam by signing up for free.

Mathematics for JAMB

139 videos|82 docs|101 tests

Signup to see your scores go up within 7 days!

Study with 1000+ FREE Docs, Videos & Tests
10M+ students study on EduRev