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All questions of Angles and lines for JAMB Exam

If two angles are supplementary then the sum of their measures is ___________ .
  • a)
    45°
  • b)
    180°
  • c)
    90°
  • d)
    360°
Correct answer is option 'B'. Can you explain this answer?

Shilpa Das answered
Supplementary angles are two angles whose sum is equal to 180∘. In other words when you add the measure of one angle in the pair with the other angle in the pair, they equal 180 degrees.

These two angles are supplementary because together they form a straight line. You can also tell that they are supplementary because when you add their angle measures the sum is equal to 180 degrees.

120+60=180degree

Practice Quiz or MCQ (Multiple Choice Questions) with solutions are available for Practice, which would help you prepare for chapter Lines and Angles, Class 7, Mathematics . You can practice these practice quizzes as per your speed and improvise the topic. 
Q.
If two lines intersect at a point, then the vertically opposite angles are always ________
  • a)
    supplementary
  • b)
    equal
  • c)
    unequal
  • d)
    none of these
Correct answer is option 'B'. Can you explain this answer?



Given two lines AB and CD intersect each other at the point O.
To prove: ∠1 = ∠3 and ∠2 = ∠4
Proof:
From the figure, ∠1 + ∠2 = 180 deg [Linear pair]  → (1)
∠2 + ∠3 = 180 deg [Linear pair]  → (2)
From (1) and (2), we get
∠1 + ∠2 = ∠2 + ∠3
∴ ∠1 = ∠3
Similarly, we can prove ∠2 = ∠4 also.

If two adjacent angles are supplementary, then they form _________ .
  • a)
    a linear pair of angles
  • b)
    vertically opposite angles
  • c)
    Corresponding angles
  • d)
    a ray
Correct answer is 'A'. Can you explain this answer?

Shilpa Das answered
A linear pair is two angles that are adjacent and whose non-common sides form a straight line. If two angles are a linear pair, then they are supplementary.

Find the measure of an angle, if 7 times its complement is 10 less than 3 times its supplement
  • a)
    15°    
  • b)
    10°
  • c)
    25°
  • d)
Correct answer is option 'C'. Can you explain this answer?

Ananya Das answered
Let the angle be x
measure of its complement = (90-x)
measure of its supplement= (180-x)
7(90-x) =3(180-x)-10
630 - 7x=540x-3x -10
-7x+3x= 530-630
-4x=-100
x= 100/4
x=25

In figure pair of alternate interior angles are :
  • a)
    ∠2, ∠5
  • b)
    ∠1, ∠2
  • c)
    ∠2, ∠3
  • d)
    None of these
Correct answer is option 'C'. Can you explain this answer?

Geetika Shah answered
Alternate interior angles are formed when a transversal passes through two lines. The angles that are formed on opposite sides of the transversal and inside the two lines are alternate interior angles. The theorem says that when the lines are parallel, that the alternate interior angles are equal.
So in the given figure ∠2, ∠3 are alternate interior angles
Alternate angle form Z shape

Two angles forming a linear pair are ________________.
  • a)
    complimentary
  • b)
    equal
  • c)
    supplementary
  • d)
    None of these
Correct answer is 'C'. Can you explain this answer?

Meera Reddy answered
Supplementary angles are two angles whose sum is 180 degree. A linear pair (two angles that form a line) will always be supplementary. The two angles can be adjacent or non-adjacent.

A line that intersects two or more lines at distinct points is called
  • a)
    parallel
  • b)
    transversal
  • c)
    intersecting
  • d)
    None of these
Correct answer is option 'B'. Can you explain this answer?

Meera Reddy answered
Parallel Lines and a Transversal. A line which intersects two or more given lines at distinct points is called a 'transversal' of the given lines.

If two angles are complementary, then the sum of their measures is __________.
  • a)
    360°
  • b)
    90°
  • c)
    180°
  • d)
    45°
Correct answer is option 'B'. Can you explain this answer?

Kashvi Verma answered
If two angles are Complementary - means when we add both the angles the Answer will always be '90 degree'.

Sum of their measures is -
We do not know the value of the angles so we can take them as 'x' and as we know that these angles are complementary meaning 90 degree each so their sum will be 180 degree

So the equation will be =
x+x=180
2x=180
x=180/2
x=90
Therefore the Answer will be 'Option [b] 90 degrees'

The complement angle of 80° is
  • a)
    18 / π radian
  • b)
    5π / 9 radian
  • c)
    π / 18 radian
  • d)
    9 / 5π radian
Correct answer is option 'C'. Can you explain this answer?

Rahul Kapoor answered
Complementary angles: Complementary angles are angle pairs whose measures sum to one right angle (90°).
So, the required angle will be 10°
180° = π radian
1º = (π / 180)
∴ 10º = {(π × 10) / 180} = (π / 18)
Hence, option C is correct.

In the given figure AB || CD, ∠A = 128°, ∠E = 144°. Then, ∠FCD is equal to :
  • a)
    72°
  • b)
    64°
  • c)
    136°
  • d)
    92°
Correct answer is option 'D'. Can you explain this answer?

As per the given figure,
Through E draw EE’ || AB || CD.
Then, ∠AEE’ = 180° ‒ ∠BAE = (180° ‒ 128°) = 52°.
(Interior angles on the same side of the transversal are supplementary.)
Now, ∠E’EC = (144° ‒ 52°) = 92°.
∠FCD = ∠E’EC = 92° (Corr. ∠s).
Hence, option D is correct.

If one arm of an angle is respectively parallel to the arm of another angle formed with a common line between them, then the two angles are
  • a)
    Neither equal nor supplementary
  • b)
    not equal but supplementary
  • c)
    equal but not supplementary
  • d)
    Either equal or supplementary
Correct answer is option 'B'. Can you explain this answer?

Rahul Kapoor answered
If one arm of an angle is respectively parallel to the arm of another angle formed with a common line between them, then the two angles are not equal but supplementary.

If l1 || l2 ⇒ ∠1 + ∠2 = 180°
(Supplementary)
Hence, option B is correct.

In the figure given below, ABC is a triangle. BC is parallel to AE. If BC = AC, then what is the value of ∠CAE?
  • a)
    20°
  • b)
    30°
  • c)
    40°
  • d)
    50°
Correct answer is option 'D'. Can you explain this answer?

Given that, BC || AE
∠CBA + ∠EAB = 180°
⇒ ∠EAB = 180° – 65° = 115°
∵   BC = AC
Hence, ΔABC is an isosceles triangle. 

⇒ ∠CBA = ∠CAB = 65°
Now,  ∠EAB = ∠EAC + ∠CAB
⇒ 115° = x + 65° ⇒ x = 50°.
Hence, option D is correct.

In the trapezium PQRS, QR || PS, ∠Q = 90°, PQ = QR and ∠PRS = 20°. If ∠TSR = θ, then the value of θ is:
  • a)
    75°
  • b)
    55°
  • c)
    65°
  • d)
    45°
Correct answer is option 'C'. Can you explain this answer?

BT Educators answered
In the given figure, 
PQ = QR and ∠PQR = 90° ⇒ ∠QPR = ∠QRP = 45°.
∴ ∠QRS = (45° + 20°) = 65°.
∴ θ = ∠QRS = 65° (alt. ∠s)
Hence, option C is correct.

In the given figure, AB || CD, m∠ABF = 45° and m∠CFC = 110°. Then, m∠FDC is:
  • a)
    25°
  • b)
    45°
  • c)
    35°
  • d)
    30°
Correct answer is option 'A'. Can you explain this answer?

As in the given figure,
∠FCD = ∠FBA = 45° (alt. ∠s)
∴ ∠FDC = 180° ‒ (110° + 45°) = 25°.
Hence, option A is correct.

Consider the following statements
I. The locus of points which are equidistant from two parallel lines is a line parallel to both of them and drawn mid way between them.
II. The perpendicular distance of any point on this locus line from two original parallel lines are equal. Further, no point outside this locus line has this property.
Which of the above statements is/are correct?
  • a)
    Only I
  • b)
    Only II
  • c)
    Both I and II
  • d)
    Neither I nor II
Correct answer is option 'C'. Can you explain this answer?

Rahul Kapoor answered
Statements I and II are both true, because the locus of points which are equidistant from two parallel lines is a line parallel to both of them and draw mid way between them.

Also, it is true that the perpendicular distances of any point on this locus line from two original parallel lines are equal. Further, no point outside this locus line has this property.

Hence, option C is correct.


In the figure given above LOM is a straight line. What is the value of x°?
  • a)
    45°
  • b)
    60°
  • c)
    70°
  • d)
    80°
Correct answer is option 'B'. Can you explain this answer?

From the given figure,
∠LOQ + ∠QOP + ∠POM = 180°
(straight line)
∴   (x° + 20°) + 50° + (x° – 10°) = 180°
⇒   2x° + 60° = 180° ⇒ 2x° = 120°
∴   x° = 60°
Hence, optuion B is correct.

In the given figure, line CE is drawn parallel to DB. If ∠BAD = 110°, ∠ABD = 30°, ∠ADC = 75° and ∠BCD = 60°, then the value of x° is:
  • a)
    45°
  • b)
    75°
  • c)
    85°
  • d)
    120°
Correct answer is option 'C'. Can you explain this answer?

EduRev GMAT answered
As in the given figure,
∠ADB = 180° ‒ (110° + 30°) = 40°.
So, ∠BDC = (75° ‒ 40°) = 35°.
∴ ∠DBC = 180° ‒ (60° + 35°) = 85°.
∴ ∠BCE = ∠DBC = 85° (alt. ∠s).
So, x = 85°.
Hence, option C is correct.

In the given figure AB || CD, ∠ALC = 60° and EC is the bisector of ∠LCD. If EF || AB then the value of ∠CEF is
  • a)
    120°
  • b)
    140°
  • c)
    150°
  • d)
    None of these
Correct answer is option 'C'. Can you explain this answer?

Notes Wala answered

∠ALC = ∠LCD = 60°
[∵  Alternate angles]
EC is the bisector of ∠LCD
∴ ∠ ECD = (1 / 2) × ∠ LCD
= (1 / 2) × 60º = 30º
∠CEF + ∠ECD = 180°
[∵  Pair of interior angles]
∠CEF + 30° = 180°
∠CEF = 180° – 30° = 150°
Hence, option C is correct.

In the adjoining figure, ∠ABC = 100°, ∠EDC = 120° and AB || DE. Then, ∠BCD is equal to:
  • a)
    80°
  • b)
    60°
  • c)
    40°
  • d)
    20°
Correct answer is option 'C'. Can you explain this answer?

In the given figure,
Produce AB to meet CD at F.
∠BFD = ∠EDF = 120° (alt. ∠s)
∠BFC = (180° ‒ 120°) = 60°.
∠CBF = (180° ‒ 100°) = 80°.
∴ ∠BCF = 180° ‒ (60° + 80°) = 40°.
Hence, option C is correct.

If two supplementary angles differ by 44°, then one of the angle is:
  • a)
    72°
  • b)
    102°
  • c)
    65°
  • d)
    68°
Correct answer is option 'D'. Can you explain this answer?

Hridoy Desai answered
If two supplementary angles differ by 44 degrees, we can set up the equation:

x + (x + 44) = 180

Simplifying this equation, we have:

2x + 44 = 180

Subtracting 44 from both sides, we get:

2x = 136

Dividing both sides by 2, we find:

x = 68

So, one angle is 68 degrees, and the other angle (which differs by 44 degrees) is 112 degrees.

In a Δ ABC, (1 / 2) ∠A + (1 / 3) ∠C + (1 / 2) ∠B = 80°, then what is the value of ∠C?
  • a)
    35°
  • b)
    40°
  • c)
    60°
  • d)
    70°
Correct answer is option 'C'. Can you explain this answer?

Rahul Kapoor answered
Given that,
(1 / 2) ∠A + (1 / 3) ∠C + (1 / 2) ∠B = 80�
⇒   3∠A + 2∠C + 3∠B = 480�
⇒   3(∠A + ∠B) + 2∠C = 480� ....(i)
Also, in ΔABC,
∠A + ∠B + ∠C = 180�
On multiplying both sides L.H.S. & R.H.S. by 3, we get
3(∠A + ∠B) + 3∠C = 540�  ..... (ii)
On subtracting Eq. (i) from Eq. (ii), we get
∠C = 60�.
Hence, option C is correct.

Which of the following statements is false?
  • a)
    When a transversal cuts two parallel lines, each pair of corresponding angles are equal.
  • b)
    When a transversal cuts two parallel lines, each pair of alternate interior angles are equal.
  • c)
    When a transversal cuts two parallel lines, each pair of interior angles on the same side of the transversal are supplementary.
  • d)
    A transversal cuts two parallel lines in three points.
Correct answer is option 'D'. Can you explain this answer?

Kds Coaching answered
  • (a) This is true.
    By the property of parallel lines and transversals, corresponding angles are always equal.
  • (b) This is true.
    Alternate interior angles are equal when a transversal cuts two parallel lines.
  • (c) This is true.
    Interior angles on the same side of the transversal are supplementary, meaning their sum is 180°.
  • (d) This is false.
    A transversal intersects two parallel lines at exactly two points, not three.

In the figure given below, AB is parallel to CD. ∠ABC = 65°, ∠CDE = 15° and AB = AE. What is the value of ∠AEF?
  • a)
    30°
  • b)
    35°
  • c)
    40°
  • d)
    45°
Correct answer is option 'B'. Can you explain this answer?

Rahul Kapoor answered
Given that,
∠ABC = 65° and ∠CDE = 15°
Here, ∠ABC + ∠TCB = 180°
(∵   AB || CD)
∠TCB = 180° – ∠ABC
∴ ∠TCB = 180° – 65° = 115°
∵ ∠TCB + ∠DCB = 180°
(Linear pair)
∴ ∠DCB = 65°
Now, in ΔCDE
∠CED = 180° – (∠ECD + ∠EDC)
(∵ ∠ECD = ∠BCD)
= 180° – (– 65° + 15° ) = 100°

∵ ∠DEC + ∠FEC = 180°
⇒ ∠FEC = 180° – 100° = 80°
Given that, AB = AE.
i.e. ΔABE an isosceles triangle.
∴ ∠ABE = ∠AEB = 65°
∵ ∠AEB + ∠AEF + ∠FEC = 180°
(straight line)
⇒ 65° + x° + 80° = 180°
∴ x° = 180° – 145° = 35°.
Hence, option B is correct.

In the given figure, AB || CD, ∠ABO = 40° and ∠CDO = 30°. If ∠DOB = x°, then the value of x is:
  • a)
    35°
  • b)
    110°
  • c)
    70°
  • d)
    140°
Correct answer is option 'C'. Can you explain this answer?

Notes Wala answered
In the given figure,

Through O draw EOF parallel to AB & so to CD.
∴ ∠BOF = ∠ABO = 40° (alt. ∠s)
Similarly, ∠FOD = ∠CDO = 30° (alt. ∠s)
∴ ∠BOD = (40° + 30°) = 70°.
So, x = 70°.
Hence, option C is correct.

The sum of all angles around a point is
  • a)
    0deg
  • b)
    180deg
  • c)
    360deg
  • d)
    90deg
Correct answer is option 'C'. Can you explain this answer?

Partho Basu answered
The sum of all angles around a point is 360 degrees.

Explanation:


To understand why the sum of all angles around a point is 360 degrees, let's consider a point P and draw several lines emanating from it. Each of these lines creates an angle with its adjacent line. We can number these angles as shown below:

```
__1__
| |
2| P |3
|_____|
__4__
| |
5| |6
|_____|
__7__
| |
8| |9
|_____|
```

Angles formed by the lines:


- Angle 1 is formed between line 1 and line 2.
- Angle 2 is formed between line 2 and line 3.
- Angle 3 is formed between line 3 and line 4.
- Angle 4 is formed between line 4 and line 5.
- Angle 5 is formed between line 5 and line 6.
- Angle 6 is formed between line 6 and line 7.
- Angle 7 is formed between line 7 and line 8.
- Angle 8 is formed between line 8 and line 9.
- Angle 9 is formed between line 9 and line 1.

Sum of all angles:


If we add up all these angles, we get:

Angle 1 + Angle 2 + Angle 3 + Angle 4 + Angle 5 + Angle 6 + Angle 7 + Angle 8 + Angle 9

This can be rewritten as:

Angle 1 + (Angle 2 + Angle 3) + (Angle 4 + Angle 5) + (Angle 6 + Angle 7) + (Angle 8 + Angle 9)

Notice that the sum of the adjacent angles (Angle 2 + Angle 3, Angle 4 + Angle 5, etc.) gives us a straight line. And since a straight line forms a 180-degree angle, we can simplify the expression further:

Angle 1 + 180 degrees + 180 degrees + 180 degrees + 180 degrees

Simplifying the expression, we get:

Angle 1 + 4 * 180 degrees

Since angle 1 is formed by two adjacent lines, it is a straight angle and measures 180 degrees. Therefore:

180 degrees + 4 * 180 degrees = 180 degrees + 720 degrees = 900 degrees

Thus, the sum of all angles around a point is 900 degrees. However, we know that a full rotation around a point is 360 degrees. Therefore, we subtract one full rotation (360 degrees) from the sum to get the final answer:

900 degrees - 360 degrees = 540 degrees

So, the sum of all angles around a point is 540 degrees.

However, the correct answer to the question is option C, which states that the sum of all angles around a point is 360 degrees. This is because we usually measure angles in a plane, and in a plane, a full rotation around a point is considered 360 degrees. Therefore, the sum of all angles around a point is 360 degrees.

In the figure given above, EC is parallel to AB, ∠ECD = 70° and ∠BDO = 20°. What is the value of ∠OBD?
  • a)
    20°
  • b)
    30°
  • c)
    40°
  • d)
    50°
Correct answer is option 'D'. Can you explain this answer?

Notes Wala answered
Given that, EC || AB
∴    ∠ECO + ∠AOC = 180°

⇒   ∠AOC = 180° – 70° = 110°
∴    ∠BOD = ∠AOC = 110°
(alternate angle)
Now, in ΔOBD
∠BOD + ∠ODB + ∠DBO = 180°
∴   110° + 20° + x° = 180° ⇒ x° = 50°.
Hence, option D is correct.

The angles x°, a°, c° and (π – b)° are indicated in the figure given below. Which one of the following is correct?
  • a)
    x° = a° + c° – b°
  • b)
    x° = b° – a° – c°
  • c)
    x° = a° + b° + c°
  • d)
    x° = a° – b° + c°
Correct answer is option 'C'. Can you explain this answer?

Rahul Kapoor answered
∠PCT + ∠PCB = π
(Linear pair)
∠PCB = π – (π – b°) = b° ..... (i)

In ΔBPC,
∠PCB + ∠BPC + ∠PBC = π
∠PBC = π – ∠PCB – ∠BPC  =  π – b° – a° ..... (ii)
∵ ∠ABE + ∠EBC = π
(∵ ∠PBC = ∠EBC)      (linear pair)
∠ABE = π – ∠PBC = π – (π – b° – a°)  =  a° + b° ...(iii)
Now, in ΔABE
Sum of two interior angles = Exterior angle
∠EAB + ∠ABE = ∠BES ⇒ c° + b° + a° = x°
∴   x° = a° + b° + c°.
Hence, option C is correct.

A wheel makes 12 revolutions per min. The angle in radian described by a spoke of the wheel in 1 s is:
  • a)
    5π/2
  • b)
    2π/5
  • c)
    3π/5
  • d)
    4π/5
Correct answer is option 'B'. Can you explain this answer?

Advait Roy answered
To find the angle described by a spoke of the wheel in 1 second, we need to find the angle described by the wheel in 1 second and then divide it by the number of spokes on the wheel.

The wheel makes 12 revolutions per minute, so it makes 12 * 2π radians per minute.

To find the angle described by the wheel in 1 second, we divide by 60 (since there are 60 seconds in a minute): (12 * 2π) / 60 = 2π/5 radians per second.

Since there are typically 4 spokes on a wheel, we divide the angle described by the wheel in 1 second by 4 to find the angle described by a spoke in 1 second: (2π/5) / 4 = π/10 radians per second.

Therefore, the angle described by a spoke of the wheel in 1 second is π/10 radians.

In the given figure lines AP and OQ intersect at G. If ∠AGO + ∠PGF = 70° and ∠PGQ = 40°. Find the angle value of ∠PGF.
  • a)
    31°
  • b)
    35°
  • c)
    30°
  • d)
    20°
Correct answer is option 'C'. Can you explain this answer?

Notes Wala answered
As AP is a straight line and rays GO and GF stands on it.
∴ ∠AGO + ∠OGF + ∠PGF = 180°
⇒ (∠AGO + ∠PGF) + ∠OGF = 180°
⇒ 70° + ∠OGF = 180°
⇒ ∠OGF = 180° – 70° 
⇒ ∠OGF = 110°
As, OQ is a straight line, rays GF and GP stands on it.
∠OGF + ∠PGF + ∠PGQ = 180°
Putting the value of ∠OGF & ∠PGQ 
110° + ∠PGF + 40° = 180°
∠PGF = 180° – 150° = 30°
Hence, option C is correct.

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