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All questions of Locus for JAMB Exam
What is the locus of points equidistant from two intersecting lines?- a)Circle
- b)Line
- c)Parabola
- d)Hyperbola
Correct answer is option 'B'. Can you explain this answer?
What is the locus of points equidistant from two intersecting lines?
a)
Circle
b)
Line
c)
Parabola
d)
Hyperbola
|
Sun Ray Institute answered |
The locus of points equidistant from two intersecting lines is a line that is perpendicular to the lines at their point of intersection.
What is the locus of points that are equidistant from two intersecting perpendicular lines?- a)Line
- b)Parabola
- c)Hyperbola
- d)Circle
Correct answer is option 'D'. Can you explain this answer?
What is the locus of points that are equidistant from two intersecting perpendicular lines?
a)
Line
b)
Parabola
c)
Hyperbola
d)
Circle
|
|
Sun Ray Institute answered |
The locus of points equidistant from two intersecting perpendicular lines is a circle with the point of intersection as its center.
The locus of points that are equidistant from two intersecting lines l1 and l2 is:- a)The angle bisector of the angle between l1 and l2
- b)The perpendicular bisector of the angle between l1 and l2
- c)A circle passing through the intersection of l1 and l2
- d)A parabola with the focus at the intersection of l1 and l2
Correct answer is option 'A'. Can you explain this answer?
The locus of points that are equidistant from two intersecting lines l1 and l2 is:
a)
The angle bisector of the angle between l1 and l2
b)
The perpendicular bisector of the angle between l1 and l2
c)
A circle passing through the intersection of l1 and l2
d)
A parabola with the focus at the intersection of l1 and l2
|
|
Sun Ray Institute answered |
The locus of points that are equidistant from two intersecting lines l1 and l2 is the angle bisector of the angle between them. The angle bisector is a line that divides the angle formed by the intersecting lines into two equal angles. Any point on the angle bisector is equidistant from both lines, as the distances to the lines are equal due to the symmetry of the angle bisector.
A point moves in a plane such that the sum of its distances from two fixed points A and B is constant. The locus of this point is:- a)A straight line
- b)A circle
- c)An ellipse
- d)A hyperbola
Correct answer is option 'C'. Can you explain this answer?
A point moves in a plane such that the sum of its distances from two fixed points A and B is constant. The locus of this point is:
a)
A straight line
b)
A circle
c)
An ellipse
d)
A hyperbola
|
|
Sun Ray Institute answered |
If a point moves in a plane such that the sum of its distances from two fixed points A and B is constant, the locus of this point is an ellipse. An ellipse is defined as the set of points in a plane where the sum of the distances from any point on the ellipse to two fixed points (foci) is constant. In this case, the sum of distances from the moving point to fixed points A and B remains constant, resulting in an elliptical locus.
The locus of points whose distances from two fixed points A and B are in the ratio 2:3 is:- a)A circle centered at the midpoint of AB
- b)A straight line parallel to AB
- c)An ellipse with foci at A and B
- d)A hyperbola with foci at A and B
Correct answer is option 'D'. Can you explain this answer?
The locus of points whose distances from two fixed points A and B are in the ratio 2:3 is:
a)
A circle centered at the midpoint of AB
b)
A straight line parallel to AB
c)
An ellipse with foci at A and B
d)
A hyperbola with foci at A and B
|
|
Sun Ray Institute answered |
The locus of points whose distances from two fixed points A and B are in a constant ratio is a hyperbola. In this case, the hyperbola has foci at points A and B. The ratio of 2:3 indicates that the difference of distances from any point on the hyperbola to focus A and focus B will always be in the ratio of 2:3.
What is the locus of points that are equidistant from the vertex and the base of an isosceles triangle?- a)Perpendicular bisector
- b)Median
- c)Angle bisector
- d)Circumcircle
Correct answer is option 'A'. Can you explain this answer?
What is the locus of points that are equidistant from the vertex and the base of an isosceles triangle?
a)
Perpendicular bisector
b)
Median
c)
Angle bisector
d)
Circumcircle
|
|
Sun Ray Institute answered |
The locus of points equidistant from the vertex and the base of an isosceles triangle is the perpendicular bisector of the base.
The locus of points equidistant from two given points A and B is:- a)The perpendicular bisector of AB
- b)The angle bisector of AB
- c)A circle with AB as its diameter
- d)A straight line passing through A and B
Correct answer is option 'A'. Can you explain this answer?
The locus of points equidistant from two given points A and B is:
a)
The perpendicular bisector of AB
b)
The angle bisector of AB
c)
A circle with AB as its diameter
d)
A straight line passing through A and B
|
|
Sun Ray Institute answered |
The locus of points equidistant from two given points A and B is the perpendicular bisector of the line segment AB. The perpendicular bisector is a line that intersects AB at its midpoint and forms right angles with it. Any point on the perpendicular bisector is equidistant from both A and B because it lies at an equal distance from the endpoints of the segment.
Consider a triangle ABC. What is the locus of points that are equidistant from the three sides of the triangle?- a)Incenter
- b)Circumcenter
- c)Centroid
- d)Orthocenter
Correct answer is option 'B'. Can you explain this answer?
Consider a triangle ABC. What is the locus of points that are equidistant from the three sides of the triangle?
a)
Incenter
b)
Circumcenter
c)
Centroid
d)
Orthocenter
|
|
Sun Ray Institute answered |
The circumcenter of a triangle is the point equidistant from the three sides of the triangle. Hence, the locus of points is the circumcenter.
The locus of points equidistant from the endpoints of a line segment AB is:- a)The perpendicular bisector of AB
- b)The angle bisector of AB
- c)A circle with AB as its diameter
- d)A straight line passing through A and B
Correct answer is option 'A'. Can you explain this answer?
The locus of points equidistant from the endpoints of a line segment AB is:
a)
The perpendicular bisector of AB
b)
The angle bisector of AB
c)
A circle with AB as its diameter
d)
A straight line passing through A and B
|
|
Sun Ray Institute answered |
The locus of points equidistant from the endpoints of a line segment AB is the perpendicular bisector of AB. The perpendicular bisector is a line that intersects AB at its midpoint and forms right angles with it. Any point on the perpendicular bisector is equidistant from both endpoints of the line segment because it lies at an equal distance from each.
What is the locus of points that are equidistant from the endpoints of a line segment AB?- a)Line
- b)Parabola
- c)Circle
- d)Ellipse
Correct answer is option 'C'. Can you explain this answer?
What is the locus of points that are equidistant from the endpoints of a line segment AB?
a)
Line
b)
Parabola
c)
Circle
d)
Ellipse
|
|
Sun Ray Institute answered |
The locus of points equidistant from the endpoints of a line segment AB is a circle with AB as its diameter.
What is the locus of points that are equidistant from two intersecting non-perpendicular lines?- a)Line
- b)Parabola
- c)Hyperbola
- d)Circle
Correct answer is option 'C'. Can you explain this answer?
What is the locus of points that are equidistant from two intersecting non-perpendicular lines?
a)
Line
b)
Parabola
c)
Hyperbola
d)
Circle
|
|
Sun Ray Institute answered |
The locus of points equidistant from two intersecting non-perpendicular lines is a hyperbola with the point of intersection as its center.
If a point moves such that its distance from a fixed point is always constant, its locus is:- a)A straight line
- b)A circle
- c)A parabola
- d)An ellipse
Correct answer is option 'B'. Can you explain this answer?
If a point moves such that its distance from a fixed point is always constant, its locus is:
a)
A straight line
b)
A circle
c)
A parabola
d)
An ellipse
|
|
Sun Ray Institute answered |
If a point moves such that its distance from a fixed point (center) is always constant, its locus is a circle. The locus of points equidistant from a fixed point forms a circle with the fixed point as its center and the constant distance as its radius. All points on the circle are at an equal distance from the fixed point.
The locus of points equidistant from two parallel lines l1 and l2 is:- a)A point
- b)A straight line parallel to l1 and l2
- c)A circle
- d)A parabola
Correct answer is option 'B'. Can you explain this answer?
The locus of points equidistant from two parallel lines l1 and l2 is:
a)
A point
b)
A straight line parallel to l1 and l2
c)
A circle
d)
A parabola
|
|
Sun Ray Institute answered |
When two parallel lines are given, any point equidistant from both lines will lie on a line that is parallel to the given lines. This can be understood by considering the definition of parallel lines, which states that they never intersect and always maintain the same distance between them. Therefore, the locus of points equidistant from two parallel lines is a straight line parallel to those lines.
The locus of the midpoint of a chord of a circle with center O and radius r, which subtends a constant angle at the center, is:- a)A circle with radius r/2
- b)A circle with radius r
- c)A circle with radius 2r
- d)An ellipse
Correct answer is option 'D'. Can you explain this answer?
The locus of the midpoint of a chord of a circle with center O and radius r, which subtends a constant angle at the center, is:
a)
A circle with radius r/2
b)
A circle with radius r
c)
A circle with radius 2r
d)
An ellipse
|
|
Sun Ray Institute answered |
The locus of the midpoint of a chord of a circle with center O and radius r, which subtends a constant angle at the center, is an ellipse. As the chord rotates around the circle, the midpoint of the chord traces out an ellipse. The major axis of the ellipse coincides with the diameter of the circle that subtends the constant angle at the center.
What is the locus of points that are equidistant from the vertex and the base of a right-angled triangle?- a)Perpendicular bisector
- b)Median
- c)Angle bisector
- d)Circumcircle
Correct answer is option 'A'. Can you explain this answer?
What is the locus of points that are equidistant from the vertex and the base of a right-angled triangle?
a)
Perpendicular bisector
b)
Median
c)
Angle bisector
d)
Circumcircle
|
|
Sun Ray Institute answered |
The locus of points equidistant from the vertex and the base of a right-angled triangle is the perpendicular bisector of the base.
The locus of points that are equidistant from a fixed line l and a fixed point P not on line l is:- a)A circle
- b)A parabola
- c)An ellipse
- d)A hyperbola
Correct answer is option 'D'. Can you explain this answer?
The locus of points that are equidistant from a fixed line l and a fixed point P not on line l is:
a)
A circle
b)
A parabola
c)
An ellipse
d)
A hyperbola
|
|
Sun Ray Institute answered |
The locus of points that are equidistant from a fixed line l and a fixed point P not on line l is a hyperbola. A hyperbola is defined as the set of points in a plane such that the difference of the distances from any point on the hyperbola to the fixed point (focus) and the fixed line (directrix) is constant. In this case, the fixed point P acts as the focus and the fixed line l acts as the directrix.
What is the locus of points that are equidistant from two parallel lines?- a)Line
- b)Parabola
- c)Hyperbola
- d)Circle
Correct answer is option 'A'. Can you explain this answer?
What is the locus of points that are equidistant from two parallel lines?
a)
Line
b)
Parabola
c)
Hyperbola
d)
Circle
|
|
Sun Ray Institute answered |
The locus of points equidistant from two parallel lines is a line that is equidistant from the two lines.
What is the locus of points that are equidistant from the sides of an equilateral triangle?- a)Incenter
- b)Circumcenter
- c)Centroid
- d)Orthocenter
Correct answer is option 'B'. Can you explain this answer?
What is the locus of points that are equidistant from the sides of an equilateral triangle?
a)
Incenter
b)
Circumcenter
c)
Centroid
d)
Orthocenter
|
|
Sun Ray Institute answered |
The circumcenter of an equilateral triangle is the point equidistant from the sides of the triangle. Hence, the locus of points is the circumcenter.
What is the locus of points that are equidistant from the endpoints of a line segment and lie on the same side of the segment?- a)Line
- b)Parabola
- c)Circle
- d)Ellipse
Correct answer is option 'A'. Can you explain this answer?
What is the locus of points that are equidistant from the endpoints of a line segment and lie on the same side of the segment?
a)
Line
b)
Parabola
c)
Circle
d)
Ellipse
|
|
Sun Ray Institute answered |
The locus of points equidistant from the endpoints of a line segment and lying on the same side of the segment is a line parallel to the segment.
The locus of points that are equidistant from the x-axis and the y-axis is:- a)A straight line with a slope of 1
- b)A straight line with a slope of -1
- c)A circle with the center at the origin
- d)A parabola with the vertex at the origin
Correct answer is option 'C'. Can you explain this answer?
The locus of points that are equidistant from the x-axis and the y-axis is:
a)
A straight line with a slope of 1
b)
A straight line with a slope of -1
c)
A circle with the center at the origin
d)
A parabola with the vertex at the origin
|
|
Sun Ray Institute answered |
The locus of points that are equidistant from the x-axis and the y-axis is a circle with the center at the origin. The points on the circle will have equal distances from both the x-axis and the y-axis. Since the origin is equidistant from the x-axis and the y-axis, it serves as the center of the circle.
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Mathematics for JAMB
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