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All questions of Electrostatic Force for EmSAT Achieve Exam
- a)48 × 10 8 N
- b)4.8 × 10 9 N
- c)48 × 10 4 N
- d)4.8 × 10 10 N
Correct answer is 'D'. Can you explain this answer?
|
Ritika Sengupta answered |
The force between two small charged spheres having charges 3 x 10-6C and 4 x 10-6C placed 40 cm apart in air is- a)67.5 x 10-3 N
- b)67.5 x 10-2 N
- c)6.75 x 10-1 N
- d)none
Correct answer is option 'C'. Can you explain this answer?
The force between two small charged spheres having charges 3 x 10-6C and 4 x 10-6C placed 40 cm apart in air is
a)
67.5 x 10-3 N
b)
67.5 x 10-2 N
c)
6.75 x 10-1 N
d)
none
|
Siddharth Tiwari answered |
**Explanation:**
When two charges are placed in close proximity to each other, they exert a force on each other. This force is known as the electrostatic force. The electrostatic force between two charges is governed by Coulomb's Law, which states that the force is directly proportional to the product of the charges and inversely proportional to the square of the distance between them.
In this case, we have a positive charge of 1C and a negative charge of -4C. According to Coulomb's Law, the force between these two charges will be attractive because one charge is positive and the other is negative. The force will act along the line connecting the two charges, from the positive charge to the negative charge.
To determine the direction of the force, we can use a simple mnemonic: "like charges repel, opposite charges attract." Since the charges in this scenario are opposite (positive and negative), they will attract each other. Therefore, the force will act from the positive charge (1C) towards the negative charge (-4C).
Hence, the correct answer is option C: "From 1C to -4C."
When two charges are placed in close proximity to each other, they exert a force on each other. This force is known as the electrostatic force. The electrostatic force between two charges is governed by Coulomb's Law, which states that the force is directly proportional to the product of the charges and inversely proportional to the square of the distance between them.
In this case, we have a positive charge of 1C and a negative charge of -4C. According to Coulomb's Law, the force between these two charges will be attractive because one charge is positive and the other is negative. The force will act along the line connecting the two charges, from the positive charge to the negative charge.
To determine the direction of the force, we can use a simple mnemonic: "like charges repel, opposite charges attract." Since the charges in this scenario are opposite (positive and negative), they will attract each other. Therefore, the force will act from the positive charge (1C) towards the negative charge (-4C).
Hence, the correct answer is option C: "From 1C to -4C."
Two insulated charged copper spheres A and B have their centers separated by a distance of 50 cm. What is the mutual force of electrostatic repulsion if the charge on each is 6.5×10−7 C? The radii of A and B are negligible compared to the distance of separation.- a)4.5×10−2N
- b)2.5×10−2 N
- c)1.5×10−2 N
- d)3.5×10−2 N
Correct answer is option 'C'. Can you explain this answer?
Two insulated charged copper spheres A and B have their centers separated by a distance of 50 cm. What is the mutual force of electrostatic repulsion if the charge on each is 6.5×10−7 C? The radii of A and B are negligible compared to the distance of separation.
a)
4.5×10−2N
b)
2.5×10−2 N
c)
1.5×10−2 N
d)
3.5×10−2 N
|
Om Desai answered |
A uniform line charge with linear density λ lies along the y-axis. What flux crosses a spherical surface cantered at the origin with r = R- a)2Rλ/ε0
- b)Rλ/ε0
- c)λ/ε0
- d)none of the above
Correct answer is option 'A'. Can you explain this answer?
A uniform line charge with linear density λ lies along the y-axis. What flux crosses a spherical surface cantered at the origin with r = R
a)
2Rλ/ε0
b)
Rλ/ε0
c)
λ/ε0
d)
none of the above
|
Neha Chauhan answered |
Total charge inside the spherical surface =2Rλ
∫E.dS = qin/ε0
So flux = 2Rλ/ε0
Hence answer is (a)
∫E.dS = qin/ε0
So flux = 2Rλ/ε0
Hence answer is (a)
Ratio of the permittivity of medium to the permittivity of free space is known as
- a)Dielectric ratio
- b)Dielectric permittivity
- c)Dielectric constant
- d)Dielectric medium
Correct answer is option 'C'. Can you explain this answer?
Ratio of the permittivity of medium to the permittivity of free space is known as
a)
Dielectric ratio
b)
Dielectric permittivity
c)
Dielectric constant
d)
Dielectric medium
|
Hansa Sharma answered |
The ratio of a medium's permittivity to the permittivity of free space is known as the dielectric constant or relative permittivity. The equation for relative permittivity is κ = ϵ/ϵ0, where ϵ is the permittivity of the medium and ϵ0 is the permittivity of free space. Both permittivity and the permittivity of free space have the same unit, farads per meter (F/m), so the dielectric constant is dimensionless.
The force between two charges is 120 N. If the distance between the charges is doubled, the force will be- a)60 N
- b)30 N
- c)40 N
- d)15 N
Correct answer is option 'B'. Can you explain this answer?
The force between two charges is 120 N. If the distance between the charges is doubled, the force will be
a)
60 N
b)
30 N
c)
40 N
d)
15 N
|
Gaurav Kumar answered |
Coulombs law states the force between two charged particles is directly proportional to the product of charges and inversely proportional to the square of distance between them.
So if the distance is doubled then the force would decrease 4 times.
So the new force would be 120/4=30 Newton.
So if the distance is doubled then the force would decrease 4 times.
So the new force would be 120/4=30 Newton.
Two positive charges - a)repel each other
- b)attract each other at times and repel at other times
- c)attract each other
- d)always attract each other
Correct answer is option 'A'. Can you explain this answer?
Two positive charges
a)
repel each other
b)
attract each other at times and repel at other times
c)
attract each other
d)
always attract each other
|
Ramesh Chand answered |
In contrast to the attractive force between 2 objects with opposite charges , two objects that are of like charge will repel eachother. That is , a positively charged object will exert a repulsive force upon a second positively charged object. This repulsive force will push the two object apart.
An infinite number of charges, each equal to 4C, are placed along the x-axis at x = 1 m, x = 2 m, x = 4 m, x = 8 m and so on. The total force on a charge of 1C placed at the origin is- a)48 × 10 8 N
- b)4.8 × 10 9 N
- c)48 × 10 4 N
- d)4.8 × 10 10 N
Correct answer is 'D'. Can you explain this answer?
An infinite number of charges, each equal to 4C, are placed along the x-axis at x = 1 m, x = 2 m, x = 4 m, x = 8 m and so on. The total force on a charge of 1C placed at the origin is
a)
48 × 10 8 N
b)
4.8 × 10 9 N
c)
48 × 10 4 N
d)
4.8 × 10 10 N
|
Nabanita Sen answered |
An infinite number of charges, each equal to 4C, are placed along the x-axis at x = 1 m, x = 2 m, x = 4 m, x = 8 m and so on. The total force on a charge of 1C placed at the origin is- a)48 × 10 8 N
- b)4.8 × 10 9 N
- c)48 × 10 4 N
- d)4.8 × 10 10 N
Correct answer is option 'D'. Can you explain this answer?
An infinite number of charges, each equal to 4C, are placed along the x-axis at x = 1 m, x = 2 m, x = 4 m, x = 8 m and so on. The total force on a charge of 1C placed at the origin is
a)
48 × 10 8 N
b)
4.8 × 10 9 N
c)
48 × 10 4 N
d)
4.8 × 10 10 N
|
Knowledge Hub answered |
Electrostatic force is - a)force exerted by an electron on a neutron
- b)force exerted by one charge on another when the two are at rest in a given frame of reference
- c)force exerted by one charge on another when the two are moving in a given frame of reference
- d)force exerted by one charge on another when the two are accelerating in a given frame of reference
Correct answer is option 'B'. Can you explain this answer?
Electrostatic force is
a)
force exerted by an electron on a neutron
b)
force exerted by one charge on another when the two are at rest in a given frame of reference
c)
force exerted by one charge on another when the two are moving in a given frame of reference
d)
force exerted by one charge on another when the two are accelerating in a given frame of reference
|
|
Rhea Iyer answered |
Electrostatics means charges at rest, or relatively at rest so this force can be applicable only when charge produce electric field which is constant which is possible only when charges at rest or relatively at rest.
Under the influence of the coulomb field of charge +Q, a charge −q is moving around it in an elliptical orbit. Find out the correct statement(s). - a)The linear momentum of the charge −q is constant
- b)The angular velocity of the charge −q is constant
- c)The angular momentum of the charge −q is constant
- d)The linear speed of the charge −q is constant
Correct answer is option 'C'. Can you explain this answer?
Under the influence of the coulomb field of charge +Q, a charge −q is moving around it in an elliptical orbit. Find out the correct statement(s).
a)
The linear momentum of the charge −q is constant
b)
The angular velocity of the charge −q is constant
c)
The angular momentum of the charge −q is constant
d)
The linear speed of the charge −q is constant
|
|
Shraddha Dey answered |
Since the charge –q is moving in elliptical orbit so to make its motion stable the total angular momentum of the charge is constant since it experience a centripetal force from the charge +Q so it follow the motion as the motion of earth around sun.
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