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All questions of Magnetic Torque for EmSAT Achieve Exam
A conductor of length l, carrying current I and placed in a magnetic field B experiences a force F given by- a)
- b)
- c)
- d)
Correct answer is option 'C'. Can you explain this answer?
A conductor of length l, carrying current I and placed in a magnetic field B experiences a force F given by
a)
b)
c)
d)
|
Deepali Tripathi answered |
F=q(v x B)
=q(dl/dt x B)
=q/dt(l x B)
=i(l x B)
=q(dl/dt x B)
=q/dt(l x B)
=i(l x B)
A wire of length l, carrying current is bent into a loop and placed with its plane perpendicular to a magnetic field. In which of the following shapes, is the torque acting on the loop maximum?- a)Rectangle
- b)Circle
- c)Square
- d)Equilateral triangle
Correct answer is option 'B'. Can you explain this answer?
A wire of length l, carrying current is bent into a loop and placed with its plane perpendicular to a magnetic field. In which of the following shapes, is the torque acting on the loop maximum?
a)
Rectangle
b)
Circle
c)
Square
d)
Equilateral triangle
|
Om Desai answered |
The torque on a current loop depends upon the area of the current loop, when the magnetic field is perpendicular to the plane of the loops the torque has its maximum value,
Τ=I A B
We know I and B for all these cases but A depends upon the geometry. The circle has the greatest area so it should provide the greatest torque.
Τ=I A B
We know I and B for all these cases but A depends upon the geometry. The circle has the greatest area so it should provide the greatest torque.
A plane square loop PQRS of side ‘a’ made of thin copper wire has ‘n’ turns and it carries a direct current ‘I’ ampere in the direction shown in the adjoining figure. This wire loop is placed in a magnetic field of flux density ‘B’ tesla, which is directed perpendicularly in to the plane of the loop. What is the torque acting on the loop?
- a)nIaB
- b)Zero
- c)IaB
- d)nIa2B
Correct answer is option 'B'. Can you explain this answer?
A plane square loop PQRS of side ‘a’ made of thin copper wire has ‘n’ turns and it carries a direct current ‘I’ ampere in the direction shown in the adjoining figure. This wire loop is placed in a magnetic field of flux density ‘B’ tesla, which is directed perpendicularly in to the plane of the loop. What is the torque acting on the loop?
a)
nIaB
b)
Zero
c)
IaB
d)
nIa2B
|
|
Ram Mohith answered |
The magnetic moment of this loop is in direction perpendicular to the plane of loop and coming out of the plane. The magnetic field is also directed perpendicularly into the loop. So, magnetic moment magnetic field are antiparallel. The torque acting on the loop, which is given by the cross product of moment and field, is zero since sin 180 = 0
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