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All questions of 2D Arrays for EmSAT Achieve Exam
Which of the following operations can be performed on 2D arrays?- a)Addition and subtraction
- b)Multiplication and division
- c)Concatenation and splitting
- d)Sorting and searching
Correct answer is option 'A'. Can you explain this answer?
Which of the following operations can be performed on 2D arrays?
a)
Addition and subtraction
b)
Multiplication and division
c)
Concatenation and splitting
d)
Sorting and searching
|
Jawaher Juma Al Masoudi answered |
Addition and subtraction can be performed on 2D arrays.
Explanation:
- 2D arrays, also known as matrices, are rectangular arrangements of elements organized in rows and columns.
- Addition and subtraction are arithmetic operations that can be performed on 2D arrays.
- When adding or subtracting two 2D arrays, the corresponding elements in the arrays are added or subtracted.
- For example, if we have two 2D arrays A and B, the sum of A and B, denoted as A + B, is a new 2D array where each element is the sum of the corresponding elements in A and B.
- Similarly, the difference of A and B, denoted as A - B, is a new 2D array where each element is the difference of the corresponding elements in A and B.
- The addition and subtraction operations can be performed on any two 2D arrays as long as they have the same dimensions (i.e., the same number of rows and columns).
- The resulting 2D array will have the same dimensions as the original arrays.
- The addition and subtraction operations are useful in various applications, such as mathematical calculations, image processing, and data analysis.
- They allow us to combine or compare the values in different 2D arrays to obtain meaningful results.
- In contrast, multiplication and division are not defined for 2D arrays in the same way as they are for scalar values or vectors.
- Concatenation and splitting are operations that involve combining or separating different parts of 2D arrays, and they are not directly related to arithmetic operations.
- Sorting and searching are operations that involve arranging the elements of a 2D array in a specific order or finding specific elements in the array, but they do not involve arithmetic operations.
Explanation:
- 2D arrays, also known as matrices, are rectangular arrangements of elements organized in rows and columns.
- Addition and subtraction are arithmetic operations that can be performed on 2D arrays.
- When adding or subtracting two 2D arrays, the corresponding elements in the arrays are added or subtracted.
- For example, if we have two 2D arrays A and B, the sum of A and B, denoted as A + B, is a new 2D array where each element is the sum of the corresponding elements in A and B.
- Similarly, the difference of A and B, denoted as A - B, is a new 2D array where each element is the difference of the corresponding elements in A and B.
- The addition and subtraction operations can be performed on any two 2D arrays as long as they have the same dimensions (i.e., the same number of rows and columns).
- The resulting 2D array will have the same dimensions as the original arrays.
- The addition and subtraction operations are useful in various applications, such as mathematical calculations, image processing, and data analysis.
- They allow us to combine or compare the values in different 2D arrays to obtain meaningful results.
- In contrast, multiplication and division are not defined for 2D arrays in the same way as they are for scalar values or vectors.
- Concatenation and splitting are operations that involve combining or separating different parts of 2D arrays, and they are not directly related to arithmetic operations.
- Sorting and searching are operations that involve arranging the elements of a 2D array in a specific order or finding specific elements in the array, but they do not involve arithmetic operations.
What will be the output of the following code?
#include <iostream>int main() {
int arr[3][3] = {{1, 2, 3}, {4, 5, 6}, {7, 8, 9}};
std::cout << arr[2][0] / arr[1][1];
return 0;
}- a)1
- b)2
- c)3
- d)4
Correct answer is option 'A'. Can you explain this answer?
What will be the output of the following code?
#include <iostream>
#include <iostream>
int main() {
int arr[3][3] = {{1, 2, 3}, {4, 5, 6}, {7, 8, 9}};
std::cout << arr[2][0] / arr[1][1];
return 0;
}
int arr[3][3] = {{1, 2, 3}, {4, 5, 6}, {7, 8, 9}};
std::cout << arr[2][0] / arr[1][1];
return 0;
}
a)
1
b)
2
c)
3
d)
4
|
Sonal Yadav answered |
The code initializes a 2D array 'arr' with values. The expression 'arr[2][0] / arr[1][1]' divides the value at row 2, column 0 (which is 7) by the value at row 1, column 1 (which is 5). The result is 1, and the output will be 1.
How do you initialize a 2D array with values in C++?- a)int array[] = {1, 2, 3; 4, 5, 6};
- b)int array[][] = {1, 2, 3; 4, 5, 6};
- c)int array[][] = {{1, 2, 3}, {4, 5, 6}};
- d)int array[] = {{1, 2, 3}, {4, 5, 6}};
Correct answer is option 'C'. Can you explain this answer?
How do you initialize a 2D array with values in C++?
a)
int array[] = {1, 2, 3; 4, 5, 6};
b)
int array[][] = {1, 2, 3; 4, 5, 6};
c)
int array[][] = {{1, 2, 3}, {4, 5, 6}};
d)
int array[] = {{1, 2, 3}, {4, 5, 6}};
|
|
Sonal Yadav answered |
To initialize a 2D array with values in C++, we use the syntax 'int array[][] = {{1, 2, 3}, {4, 5, 6}};', where each inner array represents a row and the values inside the inner arrays represent the elements of each row.
Given the following 2D array, what will be the output of the code?
#include <iostream>int main() {
int arr[2][3] = {{1, 2, 3}, {4, 5, 6}};
std::cout << arr[1] - arr[0];
return 0;
}- a)1
- b)2
- c)3
- d)Compilation error
Correct answer is option 'A'. Can you explain this answer?
Given the following 2D array, what will be the output of the code?
#include <iostream>
#include <iostream>
int main() {
int arr[2][3] = {{1, 2, 3}, {4, 5, 6}};
std::cout << arr[1] - arr[0];
return 0;
}
int arr[2][3] = {{1, 2, 3}, {4, 5, 6}};
std::cout << arr[1] - arr[0];
return 0;
}
a)
1
b)
2
c)
3
d)
Compilation error
|
|
Sonal Yadav answered |
The code subtracts 'arr[0]' (which is a pointer to the first row) from 'arr[1]' (which is a pointer to the second row). Subtracting two pointers of the same type is not allowed in C++, so it results in a compilation error.
What is the memory layout of a 2D array in C++?- a)Elements are stored in a linear sequence
- b)Elements are stored in a row-major order
- c)Elements are stored in a column-major order
- d)Elements are stored randomly across memory locations
Correct answer is option 'B'. Can you explain this answer?
What is the memory layout of a 2D array in C++?
a)
Elements are stored in a linear sequence
b)
Elements are stored in a row-major order
c)
Elements are stored in a column-major order
d)
Elements are stored randomly across memory locations
|
|
Sonal Yadav answered |
In C++, elements in a 2D array are stored in a row-major order, meaning that the elements of each row are stored in a contiguous block of memory.
How do you declare a 2D array in C++?- a)int array[][;
- b)int[][] array;
- c)int array[][];
- d)int array[];
Correct answer is option 'B'. Can you explain this answer?
How do you declare a 2D array in C++?
a)
int array[][;
b)
int[][] array;
c)
int array[][];
d)
int array[];
|
|
Sonal Yadav answered |
In C++, the syntax for declaring a 2D array is 'int array[][]'; or 'int array[rowSize][colSize]';, where 'rowSize' and 'colSize' are the desired sizes of the array.
What is the maximum number of dimensions a C++ array can have?- a)1
- b)2
- c)3
- d)There is no maximum limit
Correct answer is option 'D'. Can you explain this answer?
What is the maximum number of dimensions a C++ array can have?
a)
1
b)
2
c)
3
d)
There is no maximum limit
|
|
Sonal Yadav answered |
C++ does not impose a maximum limit on the number of dimensions an array can have. However, the practical limit depends on the available memory and the capabilities of the compiler.
How can you find the number of rows in a 2D array in C++?- a)sizeof(array) / sizeof(array[0])
- b)array.length
- c)array.size()
- d)There is no direct way to find the number of rows
Correct answer is option 'D'. Can you explain this answer?
How can you find the number of rows in a 2D array in C++?
a)
sizeof(array) / sizeof(array[0])
b)
array.length
c)
array.size()
d)
There is no direct way to find the number of rows
|
|
Sonal Yadav answered |
In C++, there is no direct way to find the number of rows in a 2D array. You need to keep track of the row size separately or use a row size constant if the size is fixed.
What is a 2D array?- a)A data structure that stores elements in a linear fashion
- b)A collection of elements with different data types
- c)An array of arrays, where each element is itself an array
- d)A specialized form of linked list
Correct answer is option 'C'. Can you explain this answer?
What is a 2D array?
a)
A data structure that stores elements in a linear fashion
b)
A collection of elements with different data types
c)
An array of arrays, where each element is itself an array
d)
A specialized form of linked list
|
|
Sonal Yadav answered |
A 2D array is an array of arrays, where each element in the array is itself an array. It represents a table or matrix-like structure.
Given the following 2D array, what will be the output of the code?#include <iostream>int main() {
int arr[2][3] = {{1, 2, 3}, {4, 5, 6}};
std::cout << *(arr[1] + 2);
return 0;
}- a)1
- b)2
- c)3
- d)6
Correct answer is option 'D'. Can you explain this answer?
Given the following 2D array, what will be the output of the code?
#include <iostream>
int main() {
int arr[2][3] = {{1, 2, 3}, {4, 5, 6}};
std::cout << *(arr[1] + 2);
return 0;
}
int arr[2][3] = {{1, 2, 3}, {4, 5, 6}};
std::cout << *(arr[1] + 2);
return 0;
}
a)
1
b)
2
c)
3
d)
6
|
|
Sonal Yadav answered |
The code initializes a 2D array 'arr' with values. The expression '*(arr[1] + 2)' accesses the element at index 2 in the second row (row index 1). This is equivalent to 'arr[1][2]', which is 6. The output will be 6.
What is the time complexity of accessing an element in a 2D array by its index?- a)O(1)
- b)O(n)
- c)O(log n)
- d)O(n^2)
Correct answer is option 'A'. Can you explain this answer?
What is the time complexity of accessing an element in a 2D array by its index?
a)
O(1)
b)
O(n)
c)
O(log n)
d)
O(n^2)
|
|
Sonal Yadav answered |
The time complexity of accessing an element in a 2D array by its index is constant, O(1), as the index directly determines the memory location of the element.
What is the syntax for accessing an element in a 2D array?- a)array[row, column]
- b)array(row, column)
- c)array[row][column]
- d)array(row)(column)
Correct answer is option 'C'. Can you explain this answer?
What is the syntax for accessing an element in a 2D array?
a)
array[row, column]
b)
array(row, column)
c)
array[row][column]
d)
array(row)(column)
|
|
Sonal Yadav answered |
To access an element in a 2D array, we use the syntax 'array[row][column]', where 'row' and 'column' are the indices of the desired element.
What will be the output of the following code?
#include <iostream>int main() {
int arr[2][3] = {{1, 2, 3}, {4, 5, 6}};
std::cout << arr[1][2] - arr[0][1];
return 0;
}- a)2
- b)3
- c)4
- d)5
Correct answer is option 'A'. Can you explain this answer?
What will be the output of the following code?
#include <iostream>
#include <iostream>
int main() {
int arr[2][3] = {{1, 2, 3}, {4, 5, 6}};
std::cout << arr[1][2] - arr[0][1];
return 0;
}
int arr[2][3] = {{1, 2, 3}, {4, 5, 6}};
std::cout << arr[1][2] - arr[0][1];
return 0;
}
a)
2
b)
3
c)
4
d)
5
|
|
Sonal Yadav answered |
The code initializes a 2D array 'arr' with values. The expression 'arr[1][2] - arr[0][1]' subtracts the value at row 0, column 1 (which is 2) from the value at row 1, column 2 (which is 6). The result is 4, and the output will be 4.
What will be the output of the following code?
#include <iostream>int main() {
int arr[3][3] = {{1, 2, 3}, {4, 5, 6}, {7, 8, 9}};
std::cout << arr[1][2];
return 0;
}- a)2
- b)4
- c)6
- d)8
Correct answer is option 'C'. Can you explain this answer?
What will be the output of the following code?
#include <iostream>
#include <iostream>
int main() {
int arr[3][3] = {{1, 2, 3}, {4, 5, 6}, {7, 8, 9}};
std::cout << arr[1][2];
return 0;
}
int arr[3][3] = {{1, 2, 3}, {4, 5, 6}, {7, 8, 9}};
std::cout << arr[1][2];
return 0;
}
a)
2
b)
4
c)
6
d)
8
|
|
Sonal Yadav answered |
The code initializes a 2D array 'arr' with values. The expression 'arr[1][2]' accesses the element at row 1 and column 2, which is 6. The output will be 6.
What will be the output of the following code?
#include <iostream>int main() {
int arr[2][2] = {{1, 2}, {3, 4}};
std::cout << arr[1][1] + arr[0][0];
return 0;
}- a)2
- b)3
- c)4
- d)5
Correct answer is option 'D'. Can you explain this answer?
What will be the output of the following code?
#include <iostream>
#include <iostream>
int main() {
int arr[2][2] = {{1, 2}, {3, 4}};
std::cout << arr[1][1] + arr[0][0];
return 0;
}
int arr[2][2] = {{1, 2}, {3, 4}};
std::cout << arr[1][1] + arr[0][0];
return 0;
}
a)
2
b)
3
c)
4
d)
5
|
|
Sonal Yadav answered |
The code initializes a 2D array 'arr' with values. The expression 'arr[1][1] + arr[0][0]' adds the values at row 1, column 1 (which is 4) and row 0, column 0 (which is 1). The result is 5, and the output will be 5.
Given the following 2D array, what will be the output of the code?
#include <iostream>int main() {
int arr[3][2] = {{1, 2}, {3, 4}, {5, 6}};
std::cout << *(*(arr + 2) + 1);
return 0;
}- a)1
- b)2
- c)5
- d)6
Correct answer is option 'D'. Can you explain this answer?
Given the following 2D array, what will be the output of the code?
#include <iostream>
#include <iostream>
int main() {
int arr[3][2] = {{1, 2}, {3, 4}, {5, 6}};
std::cout << *(*(arr + 2) + 1);
return 0;
}
int arr[3][2] = {{1, 2}, {3, 4}, {5, 6}};
std::cout << *(*(arr + 2) + 1);
return 0;
}
a)
1
b)
2
c)
5
d)
6
|
|
Sonal Yadav answered |
The code initializes a 2D array 'arr' with values. The expression '*(*(arr + 2) + 1)' accesses the element at row 2 (row index 2) and column 1 (column index 1). This is equivalent to 'arr[2][1]', which is 6. The output will be 6.
What will be the output of the following code?
#include <iostream>int main() {
int arr[3][3] = {{1, 2, 3}, {4, 5, 6}, {7, 8, 9}};
std::cout << arr[2][1] * arr[0][2];
return 0;
}- a)2
- b)6
- c)15
- d)21
Correct answer is option 'D'. Can you explain this answer?
What will be the output of the following code?
#include <iostream>
#include <iostream>
int main() {
int arr[3][3] = {{1, 2, 3}, {4, 5, 6}, {7, 8, 9}};
std::cout << arr[2][1] * arr[0][2];
return 0;
}
int arr[3][3] = {{1, 2, 3}, {4, 5, 6}, {7, 8, 9}};
std::cout << arr[2][1] * arr[0][2];
return 0;
}
a)
2
b)
6
c)
15
d)
21
|
|
Sonal Yadav answered |
The code initializes a 2D array 'arr' with values. The expression 'arr[2][1] * arr[0][2]' multiplies the value at row 2, column 1 (which is 8) with the value at row 0, column 2 (which is 3). The result is 24, and the output will be 24.
How can you pass a 2D array to a function in C++?- a)Pass each row as a separate argument
- b)Pass the entire array as a single argument
- c)Convert the 2D array into a 1D array before passing
- d)2D arrays cannot be passed to functions
Correct answer is option 'B'. Can you explain this answer?
How can you pass a 2D array to a function in C++?
a)
Pass each row as a separate argument
b)
Pass the entire array as a single argument
c)
Convert the 2D array into a 1D array before passing
d)
2D arrays cannot be passed to functions
|
|
Sonal Yadav answered |
To pass a 2D array to a function in C++, you can pass the entire array as a single argument. The function signature would look like 'void functionName(int array[][colSize])'.
Given the following 2D array, what will be the output of the code?#include <iostream>int main() {
int arr[2][3] = {{1, 2, 3}, {4, 5, 6}};
std::cout << sizeof(arr) / sizeof(arr[0]);
return 0;
}- a)2
- b)3
- c)6
- d)12
Correct answer is option 'A'. Can you explain this answer?
Given the following 2D array, what will be the output of the code?
#include <iostream>
int main() {
int arr[2][3] = {{1, 2, 3}, {4, 5, 6}};
std::cout << sizeof(arr) / sizeof(arr[0]);
return 0;
}
int arr[2][3] = {{1, 2, 3}, {4, 5, 6}};
std::cout << sizeof(arr) / sizeof(arr[0]);
return 0;
}
a)
2
b)
3
c)
6
d)
12
|
|
Sonal Yadav answered |
The code uses the 'sizeof' operator to calculate the total size of the 2D array 'arr'. The expression 'sizeof(arr)' returns the total size of the array in bytes. By dividing it by the size of each row ('sizeof(arr[0])'), we get the number of rows. In this case, 'sizeof(arr) / sizeof(arr[0]') is equivalent to '6 / 4', which is 2. The output will be 2.
Given the following 2D array, what will be the output of the code?
#include <iostream>int main() {
int arr[2][3] = {{1, 2, 3}, {4, 5, 6}};
std::cout << sizeof(arr[0]) / sizeof(int);
return 0;
}- a)1
- b)2
- c)3
- d)Compilation error
Correct answer is option 'C'. Can you explain this answer?
Given the following 2D array, what will be the output of the code?
#include <iostream>
#include <iostream>
int main() {
int arr[2][3] = {{1, 2, 3}, {4, 5, 6}};
std::cout << sizeof(arr[0]) / sizeof(int);
return 0;
}
int arr[2][3] = {{1, 2, 3}, {4, 5, 6}};
std::cout << sizeof(arr[0]) / sizeof(int);
return 0;
}
a)
1
b)
2
c)
3
d)
Compilation error
|
|
Sonal Yadav answered |
The code uses the 'sizeof' operator to calculate the size of 'arr[0]', which represents the first row of the 2D array 'arr'. The expression 'sizeof(arr[0])' returns the size of the first row in bytes. By dividing it by the size of an 'int' (sizeof(int)), we get the number of elements in the row. In this case, 'sizeof(arr[0]) / sizeof(int)' is equivalent to '12 / 4', which is 3. The output will be 3.
Chapter doubts & questions for 2D Arrays - C++ for EmSAT Achieve 2025 is part of EmSAT Achieve exam preparation. The chapters have been prepared according to the EmSAT Achieve exam syllabus. The Chapter doubts & questions, notes, tests & MCQs are made for EmSAT Achieve 2025 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests here.
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C++ for EmSAT Achieve
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