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All questions of Averages for GMAT Exam

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There are 7 members in a family whose average age is 25 years. Ram who is 12 years old is the second youngest in the family. Find the average age of the family in years just before Ram was born?
  • a)
    15.167
  • b)
    18.2
  • c)
    13
  • d)
    Cannot be determined
Correct answer is option 'D'. Can you explain this answer?

Rajeev Kumar answered
In order to find the average age of the family before Ram was born, we need to know the age of the youngest member of the family. 
Since, we do not know the age of the youngest member, we can not calculate the total age of the family before Ram was born.
Hence, we can not calculate the answer with the given conditions.
Thus, D is the right choice.

Can you explain the answer of this question below:
The average of 20 numbers is zero. Of them, How many of them may be greater than zero , at the most?
  • A:1
  • B:20
  • C:0
  • D:19

The answer is D.

Ishita Das answered
Average of 20 numbers = 0.
 Sum of 20 numbers (0 x 20) = 0.
It is quite possible that 19 of these numbers may be positive and if their sum is a then 20th number is (-a).

Can you explain the answer of this question below:
 A car owner buys diesel at Rs.7.50, Rs. 8 and Rs. 8.50 per litre for three successive years. What approximately is the average cost per litre of diesel if he spends Rs. 4000 each year?
  • A:Rs. 8
  • B:Rs. 7.98
  • C:Rs. 6.2
  • D:Rs. 8.1

The answer is B.

Ishani Rane answered
Average cost per litre of petrol = Total amount / Total quantity of petrol

Re. 4000 is spent each year, so total amount spent = 3 * Rs. 4000 = Rs. 12,000

Total quantity of petrol consumed in 3 years = (4000/7.50) + (4000/8) + (4000/8.50) litres

= 533.3 + 500 + 470.6 = 1505

Average cost = Total amount / Total quantity

= 12000/1504 = 7.98

To find quickly, you can take cube root of (7.50 * 8 * 8.50), and it will be slightly less than 8.

The correct option is B.

A batsman makes a score of 87 runs in the 17th inning and thus increases his averages by 3. What is his average after 17th inning?
  • a)
    39
  • b)
    35
  • c)
    42
  • d)
    40.5
Correct answer is option 'A'. Can you explain this answer?

Manoj Ghosh answered
Let the average after 17 innings = x
Total runs scored in 17 innings = 17x
then average after 16 innings = (x-3)
Total runs scored in 16 innings = 16(x-3)
We know that Total runs scored in 16 innings + 87 = Total runs scored in 17 innings
=> 16(x-3) + 87 = 17x
=> 16x - 48 + 87 = 17x
=> x = 39

If the average marks of three batches of 55, 60 and 45 students respectively is 50, 55, 60, what is the average marks of all the students?
  • a)
    53.23
  • b)
    54.68
  • c)
    51.33
  • d)
    50
Correct answer is 'B'. Can you explain this answer?

Manoj Ghosh answered
Total marks of first batch(55) is= 55*50=2750
Total marks of second batch (60) is= 60*55=3300
Total marks of third batch(45)= 45*60=2700

Total marks of second batch= 2750+3300+2700 = 8750
Total number of Students= 55+60+45 =160
Avg= 8750/160= 54.68

The average monthly income of P and Q is Rs. 5050. The average monthly income of Q and R is Rs. 6250 and the average monthly income of P and R is Rs. 5200. The monthly income of P is:
  • a)
    3500
  • b)
    4000
  • c)
    4050
  • d)
    5000
Correct answer is 'B'. Can you explain this answer?

Arya Roy answered
Let monthly income of A = a
monthly income of B = b 
monthly income of C = c
a + b = 2 * 5050 .... (Equation 1)
b + c = 2 * 6250 .... (Equation 2)
a + c = 2 * 5200 .... (Equation 3)
(Equation 1) + (Equation 3) - (Equation 2)
= a + b + a + c - (b + c) = (2 * 5050) + (2 * 5200) - (2 * 6250)
= 2a = 2(5050 + 5200 - 6250)
= a = 4000
i.e., Monthly income of A = 4000

The average number of runs scored by Virat Kohli in four matches is 48. In the fifth match, Kohli scores some runs such that his average now becomes 60. In the 6th innings he scores 12 runs more than his fifth innings and now the average of his last five innings becomes 78. How many runs did he score in his first innings? (He does not remain not out in any of the innings)
  • a)
    30
  • b)
    50
  • c)
    70
  • d)
    90
Correct answer is option 'A'. Can you explain this answer?

Quantronics answered
Runs scored by Kohli in first 4 innings = 48*4 = 192
Average of 5 innings is 60, so total runs scored after 5 innings = 60*5 = 300
Hence runs scored by Kohli in fifth inning = 300 – 192 = 108
It is given that in 6th innings he scores 12 runs more than this, so he must score 120 in the sixth inning. Hence total runs scored in 6 innings = 300+120 = 420
Now average of last five innings is 78, so runs scored in last innings = 390
Hence runs scored in first inning = 420 – 390 = 30.

The captain of a cricket team of 11 members is 26 years old and the wicket keeper is 3 years older. If the ages of these two are excluded, the average age of the remaining players is one year less than the average age of the whole team. Find out the average age of the team.
  • a)
    23 years
  • b)
    20 years
  • c)
    24 years
  • d)
    21 years
Correct answer is option 'A'. Can you explain this answer?

Pallabi Deshpande answered
Number of members in the team = 11
Let the average age of of the team = x
=> Sum of the ages of all the 11 members of the team / 11 = x
=> Sum of the ages of all the 11 members of the team = 11 x
Age of the captain = 26
Age of the wicket keeper = 26 + 3 = 29
Sum of the ages of 9 members of the team excluding captain and wicket keeper 
= 11x − 26 − 29 =11x − 55
Average age of 9 members of the team excluding captain and wicket keeper
= 11x−55 / 9
Given that
11x−55 / 9 =(x−1)
⇒11x−55=9(x−1)
⇒11x−55=9x−9
⇒2x=46
⇒x = 46/2 = 23 years

The average age of husband, wife and their child 3 years ago was 27 years and that of wife and the child 5 years ago was 20 years. What is the present age of the husband?
  • a)
    40
  • b)
    32
  • c)
    28
  • d)
    30
Correct answer is option 'A'. Can you explain this answer?

Arya Roy answered
Sum of the present ages of husband, wife and child = (27 x 3 + 3 x 3) years = 90 years.
Sum of the present ages of wife and child (20 x 2 + 5 x 2) years  = 50 years.
Husband's present age = (90 - 50) years = 40 years.

The average weight of A, B and C is 45 kg. If the average weight of A and B be 40 kg and that of B and C be 43 kg, what is the weight of B?
  • a)
    31 kg
  • b)
    28 kg
  • c)
    32 kg
  • d)
    30 kg
Correct answer is option 'A'. Can you explain this answer?

Kavya Saxena answered
Let A, B, C represent their respective weights. Then, we have:
A + B + C = (45 x 3) = 135 .... (i)
A + B = (40 x 2) = 80 .... (ii)
B + C = (43 x 2) = 86 ....(iii)
Adding (ii) and (iii), we get: A + 2B + C = 166 .... (iv)
Subtracting (i) from (iv), we get : B = 31.
 B's weight = 31 kg.

The average weight of a class of 10 students is increased by 2 kg when one student of 30kg left and another student joined. After a few months, this new student left and another student joined whose weight was 10 less than the student who left now. What is the difference between the final and initial averages?
  • a)
    11
  • b)
    1
  • c)
    111
  • d)
    121
Correct answer is option 'B'. Can you explain this answer?

Rajeev Kumar answered
Change in total weight of 10 students = difference in weight of the student who joined and the student
=> weigth of first student who left = 30 + (10×2) = 50
weight of the student who joined last = 50 – 10 = 40...
Thus change in average weight = (40 – 30)/10 = 1...
 

The average of 20 numbers is zero. Of them, How many of them may be greater than zero , at the most?
  • a)
    1
  • b)
    20
  • c)
    0
  • d)
    19
Correct answer is 'D'. Can you explain this answer?

Priyanka Datta answered
Average of 20 numbers = 0.
 Sum of 20 numbers (0 x 20) = 0.
It is quite possible that 19 of these numbers may be positive and if their sum is a then 20th number is (-a).

The average age of a family of 5 members is 20 years. If the age of the youngest member is 10 years, what was the average age of the family at the birth of the youngest member?
  • a)
    12.50
  • b)
    15.25
  • c)
    21.25 
  • d)
    18.75 
Correct answer is option 'D'. Can you explain this answer?

Rajeev Kumar answered
At present the total age of the family = 5 × 20 =100
The total age of the family at the time of the birth of the youngest member,
= 100 - 10 - (10 × 4)
= 50
Therefore, average age of the family at the time of birth of the youngest member,
= 50/4 =12.5

Practice Quiz or MCQ (Multiple Choice Questions) with solution are available for Practice, which would help you prepare for "Average" under Quantitative Aptitude. You can practice these practice quizzes as per your speed and improvise the topic. The same topic is covered under various competitive examinations like - CAT, GMAT, Bank PO, SSC and other competitive examinations.
 
Q. In the first 10 overs of a cricket game, the run rate was only 3.2. What should be the run rate in the remaining 40 overs to reach the target of 282 runs?
  • a)
    6.25
  • b)
    5.5
  • c)
    7.4
  • d)
    5
Correct answer is option 'A'. Can you explain this answer?

Arya Roy answered
Runs scored in the first 10 overs = 10 * 3.2 = 32
Total runs = 282
Remaining runs to be scored = 282 - 32 = 250
Remaining overs = 40
Run rate needed =250/40 = 6.25

An analysis of the monthly incentives received by 5 salesmen : The mean and median of the incentives is $7000. The only mode among the observations is $12,000. Incentives paid to each salesman were in full thousands. What is the difference between the highest and the lowest incentive received by the 5 salesmen in the month?
  • a)
    $4000
  • b)
    $13,000
  • c)
    $9000
  • d)
    $5000
  • e)
    $11,000
Correct answer is option 'E'. Can you explain this answer?

Yash Rane answered
The arithmetic mean of the incentives is $7000.
The median of the incentives is also $7000.
There is only one mode and the mode is $12,000.
Let their incentives be a, b, c, d, and e such that a ≤ b ≤ c ≤ d ≤ e
Therefore, the median of these values is 'c'.
So, c = $7000.
The sum of their incentives a + b + c + d + e = 5 * 7000 = $35,000
There is only one mode amongst these 5 observations.
The mode is that value that appears with the maximum frequency.
Hence, $12,000 is the incentive received by the most number of salesmen.
The incentive that c has got is $7000
So, the incentive received by d and e has to be greater than or equal to $7000
But the mode is $12,000
So, d and e should have got $12,000 each.
Therefore, c + d + e = 7000 + 12,000 + 12,000 = $31,000
Hence, a + b = 35,000 - 31,000 = $4000
As there is only one mode, the incentives received by a and b have to be different
So, a received $1000 and b received $3000.
Maximum incentive : $12,000
Minimum incentive : $1000
Difference between maximum and minimum incentive : $11,000

The average weight of a group of 30 friends increases by 1 kg when the weight of their football coach was added. If average weight of the group after including the weight of the football coach is 31 kg, what is the weight of their football coach?
  • a)
    31 kg
  • b)
    61 kg
  • c)
    60 kg
  • d)
    62 kg
  • e)
    91 kg
Correct answer is option 'B'. Can you explain this answer?

Yash Rane answered
The new average weight of the group after including the football coach = 31 kg.
As the new average is 1 kg more than the old average, old average without including the football coach = 30 kg.

The total weight of the 30 friends without including the football coach = 30 * 30 = 900.
After including the football coach, the number people in the group increases to 31 and the average weight of the group increases by 1 kg.
Therefore, the total weight of the group after including the weight of the football coach = 31 * 31 = 961 kg.
Therefore, the weight of the football coach = 961 - 900 = 61 kg.
Choice B is the correct answer.

The average of 20 numbers is zero. Of them, How many of them may be greater than zero , at the most?
  • a)
    1
  • b)
    20
  • c)
    0
  • d)
    19
Correct answer is option 'D'. Can you explain this answer?

Sagar Sharma answered
Problem:
The average of 20 numbers is zero. How many of them may be greater than zero, at the most?

Solution:
To find the maximum number of numbers that can be greater than zero, we need to understand the concept of average and the properties of numbers.

Understanding the Average:
The average of a set of numbers is found by summing all the numbers in the set and then dividing the sum by the total number of numbers.

Properties of Numbers:
1. The sum of positive numbers is always greater than zero.
2. The sum of negative numbers is always less than zero.
3. The sum of positive and negative numbers can be zero if the sum of positive numbers equals the sum of negative numbers.

Explanation:
Given that the average of 20 numbers is zero, we can conclude that the sum of these 20 numbers is also zero.

Let's assume that there are 'x' numbers greater than zero and 'y' numbers less than or equal to zero.

Since the sum of these 20 numbers is zero, we can write the equation:
(x * positive number) + (y * non-positive number) = 0

To maximize the number of numbers greater than zero, we need to minimize the number of non-positive numbers. The smallest non-positive number is zero. Therefore, we can rewrite the equation as:
(x * positive number) + (y * 0) = 0

Simplifying the equation, we get:
x * positive number = 0

In order for this equation to be true, the value of 'x' must be zero. This means that there can be zero numbers greater than zero in the set of 20 numbers.

Therefore, the maximum number of numbers that can be greater than zero is 0.

Hence, the correct answer is option 'C' - 0.

The average weight of a class is 54 kg. A student, whose weight is 145 kg, joined the class and the average weight of the class now becomes a prime number less than 72. Find the total number of students in the class now.
  • a)
    7
  • b)
    13
  • c)
    15
  • d)
    Cannot be determined
Correct answer is option 'D'. Can you explain this answer?

Rajeev Kumar answered
Let the original number of students in the class be N.
Total weight of the class = 54N
New total weight of the class = 54N + 145
New average weight of the class = (54N + 145)/(N+1) = (54N + 54)/(N+1) + 91/(N+1) = 54 + 91/(N+1).
Since the new average is an integer, (N+1) should be a factor of 91.
If N+1 = 7, the new average becomes 54 + 91/7 = 54 + 13 = 67
and if N+1 = 13, then the new average becomes 54 + 91/13 = 54 + 7 = 61
Both 67 and 61 are prime numbers less than 72. So, we cannot uniquely determine the number of students in the class.

The arithmetic mean of the 5 consecutive integers starting with 's' is 'a'. What is the arithmetic mean of 9 consecutive integers that start with s + 2?
  • a)
    2 + s + a
  • b)
    22 + a
  • c)
    2s
  • d)
    2a + 2
  • e)
    4 + a
Correct answer is option 'E'. Can you explain this answer?

Amar Chakraborty answered
The sequence starts with 's' and its mean is 'a'
The mean of 5 consecutive numbers is the 3rd term - the middle term.
Hence, 'a'
the mean is the middle (3rd) term.The terms of the sequence are s, s + 1, s + 2, s + 3, and s + 4
The middle term is s + 2
Therefore, a = s + 2
The second series starts from s + 2
The terms will therefore, be s + 2, s + 3, s + 4, s + 5, s + 6, s + 7, s + 8, s + 9, and s + 10
The middle term of the second series is the 5th term = s + 6
If a = s + 2, then s + 6 will be a + 4
The average of the second sequence is a + 4

 A car owner buys diesel at Rs.7.50, Rs. 8 and Rs. 8.50 per litre for three successive years. What approximately is the average cost per litre of diesel if he spends Rs. 4000 each year?
  • a)
    Rs. 8
  • b)
    Rs. 7.98
  • c)
    Rs. 6.2
  • d)
    Rs. 8.1
Correct answer is option 'B'. Can you explain this answer?

Ishani Rane answered
Total quantity of petrol consumed in 3 years =(4000/7.50+4000/8+4000/8.50)  liters
= 4000(2/15+1/8+2/17) liters                                                   
= 76700/51 liters
Total amount spent = Rs. (3 x 4000) = Rs. 12000.
Average cost = Rs. (12000*51/76700) = Rs. 7.98.

There are n weights in a bag measuring 1kg, 2kg and so on till n kg. These weights are divided into 3 parts. The first part contains the weights 1kg, 4kg, 7kg, and so on. The second part contains the weights 2kg, 5kg, 8kg and so on. The third part contains the remaining weights. The average weights any two of the three parts is equal to the weight present in those parts but the average weight of the remaining one part is not equal to the weight present in that part. Which of the following can be a possible value of n?
  • a)
    90
  • b)
    93
  • c)
    96
  • d)
    88
Correct answer is option 'D'. Can you explain this answer?

Rajeev Kumar answered
We know that if in an AP the number of terms in a series is odd, the average of the terms of the series is equal to the middle term of the series. However if the number of terms in the series is even, the average of all the terms of the series is not equal to one of the terms of the series. Hence the three part contain terms 2x+1, 2x+1, 2x or 2x-1, 2x-1, 2x
Hence the total number of parts = 2x+1+2x+1+2x or 2x-1+2x-1+2x = 6x+2 or 6x-2
Among the options, the only number of the form 6x+2 or 6x-2 is 88. Hence 88 can be the required value of n.

Consider a class of 40 students whose average weight is 40 kgs. m new students join this class whose average weight is n kgs. If it is known that m + n = 50, what is the maximum possible average weight of the class now?
  • a)
    40.18 Kgs
  • b)
    40.56 Kgs
  • c)
    40.67 Kgs
  • d)
    40.49 Kgs
Correct answer is option 'B'. Can you explain this answer?

Rajeev Kumar answered
If the overall average weight has to increase after the new people are added, the average weight of the new entrants has to be higher than 40.
So, n > 40
Consequently, m has to be < 10 (as n + m = 50)
Working with the “differences"? approach, we know that the total additional weight added by “m"? students would be (n - 40) each, above the already existing average of 40. m(n - 40) is the total extra additional weight added, which is shared amongst 40 + m students.
So, m * (n−40)(m+40)(n−40)(m+40) has to be maximum for the overall average to be maximum.

At this point, use the trial and error approach (or else, go with the answer options) to arrive at the answer.
The maximum average occurs when m = 5, and n = 45

And the average is 40 + (45 – 40) * 545545 = 40 + 5959 = 40.56 kgs
The question is "what is the maximum possible average weight of the class now?"
Hence, the answer is "40.56 kgs".

The average wages of a worker during a fortnight comprising 15 consecutive working days was $90 per day. During the first 7 days, his average wages was $87/day and the average wages during the last 7 days was $92 /day. What was his wage on the 8th day?
  • a)
    $83
  • b)
    $92
  • c)
    $90
  • d)
    $97
  • e)
    $104
Correct answer is option 'D'. Can you explain this answer?

Pranav Das answered
Fill in the data given in the question in the standard framework as shown below. Most questions in averages can be solved by completing this standard framework. The sum of wages is computed as the product of the number of days and the average wage earned per day.

The total wages earned during the 15 days that the worker worked = 15 * 90 = $ 1350.
The total wages earned during the first 7 days = 7 * 87 = $ 609.
The total wages earned during the last 7 days = 7 * 92 = $ 644.
Total wages earned during the 15 days = wages during first 7 days + wage on 8th day + wages during the last 7 days.
Or 1350 = 609 + wage on 8th day + 644
Wage on 8th day = 1350 - 609 - 644 = $ 97.
Choice D is the correct answer.

Positive integers from 1 to 45, inclusive are placed in 5 groups of 9 each. What is the highest possible average of the medians of these 5 groups?
  • a)
    25
  • b)
    31
  • c)
    15
  • d)
    26
  • e)
    23
Correct answer is option 'B'. Can you explain this answer?

Hridoy Desai answered
Step 1: Arrange the integers
- To find the highest possible average of the medians, we need to arrange the integers in a way that maximizes the medians.
- First, we arrange the integers in ascending order: 1, 2, 3, ..., 45.

Step 2: Find the medians of the groups
- Since each group contains 9 integers, the medians will be the 5th number in each group.
- The medians of the 5 groups will be: 5, 14, 23, 32, and 41.

Step 3: Calculate the average of the medians
- The average of the medians is calculated by adding all the medians and dividing by the number of groups.
- (5 + 14 + 23 + 32 + 41) / 5 = 31.
Therefore, the highest possible average of the medians of these 5 groups is 31, which corresponds to option B.

If the average of 5 positive integers is 40 and the difference between the largest and the smallest of these 5 numbers is 10, what is the maximum value possible for the largest of these 5 integers?
  • a)
    50
  • b)
    52
  • c)
    49
  • d)
    48
  • e)
    44
Correct answer is option 'D'. Can you explain this answer?

Nandita Yadav answered
The average of 5 positive integers is 40. i.e., the sum of these integers = 5 * 40 = 200
Let the least of these 5 numbers be x.
Because the range of the set is 10, the largest of these 5 numbers will be x + 10.
If we have to maximize the largest of these numbers, we have to minimize all the other numbers.
That is 4 of these numbers are all at the least value possible = x.
So, x + x + x + x + x + 10 = 200
Or x = 38.
So, the maximum value possible for the largest of these 5 integers is 48.
Choice D is the correct answer.

A car owner buys petrol at Rs.7.50, Rs. 8 and Rs. 8.50 per litre for three successive years. What approximately is the average cost per litre of petrol if he spends Rs. 4000 each year?
  • a)
    Rs. 8
  • b)
    Rs. 7.98
  • c)
    Rs. 6.2
  • d)
    Rs. 8.1
Correct answer is option 'B'. Can you explain this answer?

Arya Roy answered
Average cost per litre of petrol = Total amount / Total quantity of petrol

Re. 4000 is spent each year, so total amount spent = 3 * Rs. 4000 = Rs. 12,000

Total quantity of petrol consumed in 3 years = (4000/7.50) + (4000/8) + (4000/8.50) litres

= 533.3 + 500 + 470.6 = 1505

Average cost = Total amount / Total quantity

= 12000/1504 = 7.98

To find quickly, you can take cube root of (7.50 * 8 * 8.50), and it will be slightly less than 8.

The average monthly income of P and Q is Rs. 5050. The average monthly income of Q and R is Rs. 6250 and the average monthly income of P and R is Rs. 5200. The monthly income of P is:
  • a)
    3500
  • b)
    4000
  • c)
    4050
  • d)
    5000
Correct answer is option 'B'. Can you explain this answer?

Sameer Rane answered
Let monthly income of A = a
monthly income of B = b 
monthly income of C = c

a + b = 2 x 5050 .... (Equation 1)
b + c = 2 x 6250 .... (Equation 2)
a + c = 2 x 5200 .... (Equation 3)

(Equation 1) + (Equation 3) - (Equation 2)
=> a + b + a + c - (b + c) = (2 x 5050) + (2 x 5200) - (2 x 6250)
=> 2a = 2(5050 + 5200 - 6250)
=> a = 4000

i.e., Monthly income of A = 4000

The average age of a group of 10 students was 20. The average age increased by 2 years when two new students joined the group. What is the average age of the two new students who joined the group?
  • a)
    22 years
  • b)
    0 years
  • c)
    44 years
  • d)
    32 years
  • e)
    None of these
Correct answer is option 'D'. Can you explain this answer?

Devansh Chawla answered

The average age of a group of 10 students is 20.
Therefore, the sum of the ages of all 10 of them = 10 * 20 = 200
When two new students join the group, the average age increases by 2. New average = 22.
Now, there are 12 students.
Therefore, the sum of the ages of all 12 of them = 12 * 22 = 264
Therefore, the sum of the ages of the two new students who joined = 264 - 200 = 64
And the average age of each of the two new students = 64/2 = 32 years
Choice D is the correct answer.

The average of 5 quantities is 6. The average of 3 of them is 8. What is the average of the remaining two numbers?
  • a)
    4
  • b)
    5
  • c)
    3
  • d)
    3.5
  • e)
    0.5
Correct answer is option 'C'. Can you explain this answer?

Pranav Das answered
The average of 5 quantities is 6.
Therefore, the sum of the 5 quantities is 5 * 6 = 30.
The average of three of these 5 quantities is 8.
Therefore, the sum of these three quantities = 3 * 8 = 24
The sum of the remaining two quantities = (Sum of all 5 - Sum of 3 quantities) = 30 - 24 = 6.
Average of these two quantities = 6/2 = 3
Choice C is the correct answer.

Is 'b' the median of 3 numbers a, b, and c?
Statement 1: 
Statement 2: ab < 0
  • a)
    Statement ( 1 ) ALONE is sufficient but statement ( 2 ) alone is not sufficient.
  • b)
    Statemrnt ( 2 ) ALONE is sufficient but statement ( 1 ) is not sufficient
  • c)
    Both Stement TOGETHER are sufficient, but Neither statement  ALONE is sufficient
  • d)
    EACH stetement ALONE is sufficient
  • e)
    Statement ( 1 ) and ( 2 ) TOGETHER are NOT Sufficient.
Correct answer is option 'C'. Can you explain this answer?

Palak Saha answered
If either statement 1 alone or statement 2 alone had provided us with a definitive answer, we should never venture to combine the two statements.
Because neither statements provided us with a definitive answer, let us combine the two statements.
For the 3 numbers a, b, and c from the two statement we know that and ab < 0
 
We know from statement 1 that b is the geometric mean of a, b and c.
We know from statement 2 that one of a or b is negative.
Therefore, we can conclude that the three numbers - a, b and c are not all positive nor all negative.
We can further conclude that the common ratio of the geometric sequence is negative.
'b' will be median only if the common ratio of the geometric progression is positive.
We can therefore, answer conclusively using the two statements that 'b' is not the median.
The information given in the two statements taken together is sufficient to answer the question.
Choice C is the correct answer.

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