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All questions of Playing with Numbers for Class 8 Exam

Substitute digits for the letter A to make the following Addition problem true.
  • a)
    2
  • b)
    4
  • c)
    3
  • d)
    6
Correct answer is option 'B'. Can you explain this answer?

Amit Sharma answered
Correct Answer :- b
Explanation : 1+9+7 +4 + 2(power) so the answer will 23 and if we add 5+6+4+2(power) so the answer will 17.

If a number is divisible by 9, then it is also divisible by which number?
  • a)
    3
  • b)
    2
  • c)
    6
  • d)
    5
Correct answer is option 'A'. Can you explain this answer?

Mohit Gupta answered

Divisibility Rule for 9:


When a number is divisible by 9, the sum of its digits is also divisible by 9.


Explanation:


Let's take an example of a number 567.


Sum of digits of the number = 5+6+7 = 18


Since 18 is divisible by 9, the number 567 is also divisible by 9.


Divisibility Rule for 3:


When a number is divisible by 3, the sum of its digits is also divisible by 3.


Explanation:


Let's take the same example of the number 567.


Sum of digits of the number = 5+6+7 = 18


Since 18 is divisible by 3, the number 567 is also divisible by 3.


Therefore, if a number is divisible by 9, it will also be divisible by 3 since both have the same divisibility rule.


Conclusion:


If a number is divisible by 9, then it is also divisible by 3.


Therefore, the correct answer is option 'A' which is 3.

Which of these numbers is divisible by 6?
  • a)
    8964
  • b)
    6053
  • c)
    2666
  • d)
    5782
Correct answer is option 'A'. Can you explain this answer?

Nisha Nambiar answered
Divisibility Rules:
To determine if a number is divisible by another number, there are certain rules or tests that can be applied. In this case, we need to determine if the number 3116365 is divisible by 5 and 7.

Divisibility by 5:
A number is divisible by 5 if its units digit is either 0 or 5. In the given number 3116365, the units digit is 5. Therefore, the number 3116365 is divisible by 5.

Divisibility by 7:
To check if a number is divisible by 7, we can use a divisibility rule:
Step 1: Double the last digit of the number (5 * 2 = 10).
Step 2: Subtract the result from the remaining digits (311636 - 10 = 311626).
Step 3: Repeat steps 1 and 2 until a smaller number is obtained.
Step 4: If the resulting number is divisible by 7, then the original number is also divisible by 7.

Following this rule, we can continue to perform the steps:
Step 1: Double the last digit of 311626 (6 * 2 = 12).
Step 2: Subtract 12 from the remaining digits (31162 - 12 = 31150).
Step 3: Repeat the steps again.
Step 1: Double the last digit of 31150 (0 * 2 = 0).
Step 2: Subtract 0 from the remaining digits (3115 - 0 = 3115).
Step 3: Repeat the steps again.
Step 1: Double the last digit of 3115 (5 * 2 = 10).
Step 2: Subtract 10 from the remaining digits (311 - 10 = 301).
Step 3: Repeat the steps again.
Step 1: Double the last digit of 301 (1 * 2 = 2).
Step 2: Subtract 2 from the remaining digits (30 - 2 = 28).
Step 3: Repeat the steps again.
Step 1: Double the last digit of 28 (8 * 2 = 16).
Step 2: Subtract 16 from the remaining digits (2 - 16 = -14).

At this point, we have obtained a smaller number (-14), and we can determine that the original number 3116365 is not divisible by 7.

Conclusion:
The given number 3116365 is divisible by 5, but it is not divisible by 7. Therefore, the correct answer is option 'C' - Both 5 and 7.

By which of the following number 9042 is not divisible? 2, 3, 6, and 9
  • a)
    2
  • b)
    3
  • c)
    9
  • d)
    6
Correct answer is option 'C'. Can you explain this answer?

9,042 is divisible by 2 since the last digit is 2.

9,042 is divisible by 3 since the sum of the digits is 15, and 15 is divisible by 3.

9,042 is divisible by 6 since it is divisible by both 2 and 3.

9,042 is not divisible by 9 since the sum of the digits is 15, and 15 is not divisible by 9.

Solution: 9,042 is divisible by 2, 3 and 6 but not 9

Suppose that the division N ÷ 5 leaves a remainder of 4, and the division N ÷ 2 leaves a remainder of 1. What must be the one’s digit of N?
  • a)
    7
  • b)
    8
  • c)
    9
  • d)
    6
Correct answer is option 'C'. Can you explain this answer?

Amit Kumar answered
Since N leaves the remainder of 4 when divided by 5. the possible values in ones place of number N are 4 or 9.
now, since it leaves a remainder of 1 when divided by 2, the N would be an odd number. hence ones digit of N is also an odd number. which means ones digit of our number N is 9.

  • a)
    6
  • b)
    8
  • c)
    9
  • d)
    7
Correct answer is option 'A'. Can you explain this answer?

Shubham Sharma answered
We have 7+5=12, 1 is carried forward, so 1+N+8=_5, which gives N=6

By which of these numbers is the number 3116365 divisible?
  • a)
    5
  • b)
    7
  • c)
    Both 5 and 7  
  • d)
    6
Correct answer is option 'C'. Can you explain this answer?

Kavya Chopra answered
The last digit is 5, the number is divisible by 5.
Since 311636−10=311626÷7=44568,  the number is divisible by 7 also.   

Which of these numbers is divisible by 6?
  • a)
    5782
  • b)
    2666
  • c)
    6053
  • d)
    8964
Correct answer is option 'D'. Can you explain this answer?

To determine which number is divisible by 6, we need to check if the number is divisible by both 2 and 3, as 6 is a multiple of both 2 and 3. Let's check each option:

a) 5782: To check if this number is divisible by 2, we need to see if the last digit is even. In this case, the last digit is 2, which is even, so 5782 is divisible by 2. However, to check if it is divisible by 3, we need to find the sum of its digits. The sum of 5, 7, 8, and 2 is 22, which is not divisible by 3. Therefore, 5782 is not divisible by 6.

b) 2666: Again, to check if this number is divisible by 2, we look at the last digit, which is 6 (even), so 2666 is divisible by 2. To check if it is divisible by 3, we find the sum of its digits: 2 + 6 + 6 + 6 = 20. Since 20 is not divisible by 3, 2666 is not divisible by 6.

c) 6053: The last digit of this number is 3, which means it is not divisible by 2. Therefore, we can already conclude that it is not divisible by 6 without further calculations.

d) 8964: The last digit of this number is 4, which is even, so 8964 is divisible by 2. Now, let's check if it is divisible by 3. The sum of its digits is 8 + 9 + 6 + 4 = 27. Since 27 is divisible by 3, 8964 is divisible by 3.

Since 8964 is divisible by both 2 and 3, it is divisible by 6. Therefore, the correct answer is option 'D'.

Find the value of the letters in following:
  • a)
    A = 8, B = 8
  • b)
    A = 8, B = 1
  • c)
    A = 1, B = 1
  • d)
    None of these
Correct answer is option 'B'. Can you explain this answer?

Aditi Bhosale answered
Correct answer is B because in question, in one's place its given a+b, so according to option B i.e, a=8 and b=1 a+b=8+1 and the answer in one's place is nine so answer gets match and if we see in ten's place its given 2+a which is 2+8=10 and the answer in ten's place is 0 and 1 is carried on hundred's place and in hundred's place its given 1+6=A, 1+6+1=8.
This is explanation of this question

Determine if 48 is divisible by 2, 3 and 5.
  • a)
    2, 3 and 5
  • b)
    2 and 3 only
  • c)
    2 only
  • d)
    2 and 5 only
Correct answer is option 'B'. Can you explain this answer?

Divya Gauri answered
Yes, the B option is right because if you divide 48 by 2 and 3 it is easy to divide and reminder is 0 but if you divide 48 by 5 it is not divide. Thats why 48 is divisible by 2 and 3.

  • a)
    2
  • b)
    9
  • c)
    5
  • d)
    3
Correct answer is option 'A'. Can you explain this answer?

Kavya Saxena answered
Adding one’s place 5+7+8=20, 2 is carried forward.adding the ten’s place 2+3+9+8=22, this means A=2

Identify the missing digit in the number 234,4_6, if the number is divisible by 4.
  • a)
    2
  • b)
    6
  • c)
    4
  • d)
    5
Correct answer is option 'D'. Can you explain this answer?

Jatin Jain answered
To determine the missing digit in the number 234,4_6, we need to find a digit that makes the number divisible by 4.

A number is divisible by 4 if its last two digits form a number that is divisible by 4.

In this case, the last two digits are 4_6. To find the missing digit, we need to try all possible values for the missing digit and check if the resulting number is divisible by 4.

Let's try each option one by one:

a) 234,426: To check if this number is divisible by 4, we need to check if 426 is divisible by 4. Since 26 is not divisible by 4, the number is not divisible by 4.

b) 234,466: To check if this number is divisible by 4, we need to check if 466 is divisible by 4. Since 66 is divisible by 4, the number is divisible by 4.

c) 234,446: To check if this number is divisible by 4, we need to check if 446 is divisible by 4. Since 46 is not divisible by 4, the number is not divisible by 4.

d) 234,456: To check if this number is divisible by 4, we need to check if 456 is divisible by 4. Since 56 is divisible by 4, the number is divisible by 4.

Therefore, the missing digit in the number 234,4_6, if the number is divisible by 4, is 5.

If the three digit number 24x is divisible by ‘9’, what is the value of ‘x’?
  • a)
    5
  • b)
    4
  • c)
    9
  • d)
    3
Correct answer is option 'D'. Can you explain this answer?

Hans Raj answered
1. 245 = 27.222 not completely divisible by 9 2. 244=. 27.111 not completely divisible by 9 3. 249=. 27.666 not completely divisible by 9 4. 243= 27. yes completely divisible by 9

Which number is divisible by 6?
  • a)
    468
  • b)
    213
  • c)
    621
  • d)
    573
Correct answer is option 'A'. Can you explain this answer?

The no which divisible by both 2 and 3  is divisible by 6
468 is divisible by 2
4+6+8=18 divisible by 3 so it is divisible by 6 also

How many prime numbers are there between 100 and 200?
  • a)
    25
  • b)
    19
  • c)
    21
  • d)
    20
Correct answer is option 'C'. Can you explain this answer?

Raina Kapoor answered
The number of prime numbers from 100 to 200 is 21.

101, 103, 107, 109, 113, 127, 131, 137, 139, 149, 151, 157, 163, 167, 173, 179, 181, 191, 193, 197, 199.

Substitute digits for the letter A to make the following Multiplication problem true. 
  • a)
    2
  • b)
    6
  • c)
    3
  • d)
    5
Correct answer is option 'A'. Can you explain this answer?

Kavya Saxena answered
We have A*4=_8 so A can be 2 or 7.now if A is 7,then we have 2 as carried forward so 4*3+2=14_7A,when A=2, we have no carried forward so4*3=12=_2=A. Hence A=2

  • a)
    P = 5 and Q = 0
  • b)
    P = 0 and Q = 1
  • c)
    P = 0 and Q = 5
  • d)
    None of these
Correct answer is option 'A'. Can you explain this answer?

Ananya Das answered
As we see the addition part,we have 23PPQ, this means that we don’t have any carried forward for the thousand’s place this means we have only single digit by adding Q and P, so Q+P =P only when Q=0,and now seeing the multiplication we have 3*P=_P which is only possible when P=5.

Write in the usual form: 100 × a + 10 × c + b
  • a)
    abc
  • b)
    acb
  • c)
    bac
  • d)
    bca
Correct answer is option 'B'. Can you explain this answer?

Amit Sharma answered
We can write acb=100*a+10*c+b which say that a is at hundred’s place, c is at ten’s place and b is at one’s place.

What value should be given to * so that the number 653∗47 is divisible by 11?
  • a)
    1
  • b)
    6
  • c)
    2
  • d)
    9
Correct answer is option 'A'. Can you explain this answer?

Rounak Sen answered
Adding the digits at odd places of the given number 653∗ 47,we get 13. Now if the number is divisible by 11, the sum of digits at even places should also be 13, so that 13−13=0 is divisible by 11. We have 7+∗+5=13.
∴ ∗=13−12=1 is the required value.

X is the least composite number between 85 and 100. What is the value of X?
  • a)
    85                                  
  • b)
    99                  
  • c)
    100                
  • d)
    86    
Correct answer is option 'D'. Can you explain this answer?

Rutuja Reddy answered
**Answer:**

To find the least composite number between 85 and 100, we need to understand what a composite number is.

A composite number is a positive integer greater than 1 that has at least one positive divisor other than 1 and itself. In other words, a composite number can be divided evenly by numbers other than 1 and itself.

Now, let's analyze the numbers between 85 and 100 to determine the least composite number.

- 85: This number can be divided evenly by 1 and 85, but it cannot be divided evenly by any other number. Therefore, it is not a composite number.

- 86: This number can be divided evenly by 1, 2, 43, and 86. Since it has divisors other than 1 and itself, it is a composite number.

- 87: This number can be divided evenly by 1, 3, 29, and 87. Since it has divisors other than 1 and itself, it is a composite number.

- 88: This number can be divided evenly by 1, 2, 4, 8, 11, 22, 44, and 88. Since it has divisors other than 1 and itself, it is a composite number.

- 89: This number is a prime number because it can only be divided evenly by 1 and 89. Therefore, it is not a composite number.

- 90: This number can be divided evenly by 1, 2, 3, 5, 6, 9, 10, 15, 18, 30, 45, and 90. Since it has divisors other than 1 and itself, it is a composite number.

- 91: This number can be divided evenly by 1, 7, 13, and 91. Since it has divisors other than 1 and itself, it is a composite number.

- 92: This number can be divided evenly by 1, 2, 4, 23, 46, and 92. Since it has divisors other than 1 and itself, it is a composite number.

- 93: This number can be divided evenly by 1, 3, 31, and 93. Since it has divisors other than 1 and itself, it is a composite number.

- 94: This number can be divided evenly by 1, 2, 47, and 94. Since it has divisors other than 1 and itself, it is a composite number.

- 95: This number can be divided evenly by 1, 5, 19, and 95. Since it has divisors other than 1 and itself, it is a composite number.

- 96: This number can be divided evenly by 1, 2, 3, 4, 6, 8, 12, 16, 24, 32, 48, and 96. Since it has divisors other than 1 and itself, it is a composite number.

- 97: This number is a prime number because it can only be divided evenly by 1 and 97. Therefore, it is not a composite number.

- 98: This number can be divided evenly by 1, 2,

  • a)
    A = 4 and B = 4
  • b)
    A = 6 and B = 6
  • c)
    A = 4 and B = 6
  • d)
    A = 6 and B = 4
Correct answer is option 'D'. Can you explain this answer?

Ananya Das answered
Looking at the addition of the hundred’s place we have 7+7+2=_A which gives A=6. Coming back to the multiplication which is A*B=B where A=6 ,so B can be 4 or 6, but when you take B=6, we have 3 as carried forward and 7*6+3 is not equal to 0. Hence B=4 and A=6.

If the division N ÷ 5 leaves a remainder of 0, what might be the one’s digit of N?
  • a)
    5
  • b)
    7
  • c)
    2
  • d)
    Either 5 or 0
Correct answer is option 'B'. Can you explain this answer?

Since every multiple of 5 ends with either 5 or 0. Therefore, the unit digit of N must be either 0+3=3 or 5+3=8. Hence the answer is either 3 or 8.

When is a number always divisible by 90?
  • a)
    If it is divisible by both 2 and 45.
  • b)
    If it is not divisible by both 5 and 18.
  • c)
    If it is not divisible by both 9 and 10.
  • d)
    If it is divisible by 3 and 20.
Correct answer is option 'A'. Can you explain this answer?

Sarita Verma answered
A number is always divisible by 90 if it is divisible by both 2 and 45. This is because 90 is the product of 2335, so a number that is divisible by both 2 and 45 (which is the product of 33*5) is also divisible by 90.

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