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The energy of a system as a function of time t is given as E(t) = A2exp(-αt), where α = 0.2 s-1. The
measurement of A has an error of 1.25 %. If the error in the measurement of time is 1.50 %, the percentage
error in the value of E(t) at t = 5 s is
Correct answer is '4'. Can you explain this answer?
The energy of a system as a function of time t is given as E(t) = A2exp(-αt), where α = 0.2 s-1. The
measurement of A has an error of 1.25 %. If the error in the measurement of time is 1.50 %, the percentage
error in the value of E(t) at t = 5 s is
measurement of A has an error of 1.25 %. If the error in the measurement of time is 1.50 %, the percentage
error in the value of E(t) at t = 5 s is
|
Sushil Kumar answered |
Section 1Q. No. 1 - 8 Carry 4 marks eachThe answer to each question is a SINGLE DIGIT INTEGER ranging from 0 to 9, both inclusive.Q.An electron in an excited state of Li2+ ion has angular momentum 3h/2π. The de Broglie wavelength of the
electron in this state is pπa0 (where a0 is the Bohr radius). The value of p is
Correct answer is '2'. Can you explain this answer?
Section 1
Q. No. 1 - 8 Carry 4 marks each
The answer to each question is a SINGLE DIGIT INTEGER ranging from 0 to 9, both inclusive.
Q.
An electron in an excited state of Li2+ ion has angular momentum 3h/2π. The de Broglie wavelength of the
electron in this state is pπa0 (where a0 is the Bohr radius). The value of p is
electron in this state is pπa0 (where a0 is the Bohr radius). The value of p is
|
Kumari Sakshi answered |
Let the curve C be the mirror image of the parabola y2 = 4x with respect to the line x + y + 4 = 0. If A and B
are the points of intersection of C with the line y = -5, then the distance between A and B is
Correct answer is '4'. Can you explain this answer?
Let the curve C be the mirror image of the parabola y2 = 4x with respect to the line x + y + 4 = 0. If A and B
are the points of intersection of C with the line y = -5, then the distance between A and B is
are the points of intersection of C with the line y = -5, then the distance between A and B is
|
Chirag Verma answered |
Image of y = –5 about the line x + y + 4 = 0 is x = 1
Distance AB = 4
Distance AB = 4In the following circuit, the current through the resistor R (=2
) is I Amperes. The value of I is
Correct answer is '1'. Can you explain this answer?
In the following circuit, the current through the resistor R (=2) is I Amperes. The value of I is
) is I Amperes. The value of I is
|
Vikas Saini answered |
1ohm/2ohm and 2ohm/4ohm are balanced wheat stone bridge,so 8ohm R will be removed then after solvinge them 2ohm R will come.Then 6ohm/12ohm And 2ohm/4ohm are in balanced wheat stone bridge then 10ohm resistance will be removed.Reff comes 6.5 ohm.I=V/R=6.5/6.5=1ANS
Consider a hydrogen atom with its electron in the nth orbital. An electromagnetic radiation of wavelength
90 nm is used to ionize the atom. If the kinetic energy of the ejected electron is 10.4 eV, then the value of n
is (hc = 1242 eV nm)
Correct answer is '2'. Can you explain this answer?
Consider a hydrogen atom with its electron in the nth orbital. An electromagnetic radiation of wavelength
90 nm is used to ionize the atom. If the kinetic energy of the ejected electron is 10.4 eV, then the value of n
is (hc = 1242 eV nm)
90 nm is used to ionize the atom. If the kinetic energy of the ejected electron is 10.4 eV, then the value of n
is (hc = 1242 eV nm)
|
Rohit Jain answered |
The correct statement(s) regarding, (i) HClO, (ii) HClO2, (iii) HClO3 and (iv) HClO4, is (are)- a)The number of Cl = O bonds in (ii) and (iii) together is two
- b)The number of lone pairs of electrons on Cl in (ii) and (iii) together is three
- c)The hybridization of Cl in (iv) is sp3
- d)Amongst (i) to (iv), the strongest acid is (i)
Correct answer is option 'B,C'. Can you explain this answer?
The correct statement(s) regarding, (i) HClO, (ii) HClO2, (iii) HClO3 and (iv) HClO4, is (are)
a)
The number of Cl = O bonds in (ii) and (iii) together is two
b)
The number of lone pairs of electrons on Cl in (ii) and (iii) together is three
c)
The hybridization of Cl in (iv) is sp3
d)
Amongst (i) to (iv), the strongest acid is (i)
|
Nisha Kaur answered |
Statement (i): HClO
HClO is hypochlorous acid. It contains one chlorine atom, one hydrogen atom, and one oxygen atom. The chlorine atom is bonded to the oxygen through a single bond and the oxygen atom has two lone pairs of electrons. Therefore, the correct statement about HClO is that it has one Cl = O bond and two lone pairs of electrons on chlorine.
Statement (ii): HClO2
HClO2 is chlorous acid. It contains one chlorine atom, one hydrogen atom, and two oxygen atoms. The chlorine atom is bonded to one of the oxygen atoms through a single bond and to the other oxygen atom through a double bond. The oxygen atoms have a total of three lone pairs of electrons. Therefore, the correct statement about HClO2 is that it has one Cl = O bond and three lone pairs of electrons on chlorine.
Statement (iii): HClO3
HClO3 is chloric acid. It contains one chlorine atom, one hydrogen atom, and three oxygen atoms. The chlorine atom is bonded to each of the oxygen atoms through a single bond. The oxygen atoms have a total of four lone pairs of electrons. Therefore, the correct statement about HClO3 is that it has three Cl = O bonds and four lone pairs of electrons on chlorine.
Statement (iv): HClO4
HClO4 is perchloric acid. It contains one chlorine atom, one hydrogen atom, and four oxygen atoms. The chlorine atom is bonded to each of the oxygen atoms through a single bond. The oxygen atoms have a total of five lone pairs of electrons. Therefore, the correct statement about HClO4 is that it has four Cl = O bonds and five lone pairs of electrons on chlorine.
Correct Statements:
Based on the above analysis, the correct statements are:
a) The number of Cl = O bonds in (ii) and (iii) together is two.
In HClO2, there is one Cl = O bond.
In HClO3, there are three Cl = O bonds.
Therefore, the total number of Cl = O bonds in (ii) and (iii) together is two.
b) The number of lone pairs of electrons on Cl in (ii) and (iii) together is three.
In HClO2, there are three lone pairs of electrons on the chlorine atom.
In HClO3, there are four lone pairs of electrons on the chlorine atom.
Therefore, the total number of lone pairs of electrons on Cl in (ii) and (iii) together is three.
c) The hybridization of Cl in (iv) is sp3
In HClO4, there are four Cl = O bonds and five lone pairs of electrons on the chlorine atom. This indicates that the chlorine atom is sp3 hybridized.
Therefore, the correct statements are (b) and (c).
HClO is hypochlorous acid. It contains one chlorine atom, one hydrogen atom, and one oxygen atom. The chlorine atom is bonded to the oxygen through a single bond and the oxygen atom has two lone pairs of electrons. Therefore, the correct statement about HClO is that it has one Cl = O bond and two lone pairs of electrons on chlorine.
Statement (ii): HClO2
HClO2 is chlorous acid. It contains one chlorine atom, one hydrogen atom, and two oxygen atoms. The chlorine atom is bonded to one of the oxygen atoms through a single bond and to the other oxygen atom through a double bond. The oxygen atoms have a total of three lone pairs of electrons. Therefore, the correct statement about HClO2 is that it has one Cl = O bond and three lone pairs of electrons on chlorine.
Statement (iii): HClO3
HClO3 is chloric acid. It contains one chlorine atom, one hydrogen atom, and three oxygen atoms. The chlorine atom is bonded to each of the oxygen atoms through a single bond. The oxygen atoms have a total of four lone pairs of electrons. Therefore, the correct statement about HClO3 is that it has three Cl = O bonds and four lone pairs of electrons on chlorine.
Statement (iv): HClO4
HClO4 is perchloric acid. It contains one chlorine atom, one hydrogen atom, and four oxygen atoms. The chlorine atom is bonded to each of the oxygen atoms through a single bond. The oxygen atoms have a total of five lone pairs of electrons. Therefore, the correct statement about HClO4 is that it has four Cl = O bonds and five lone pairs of electrons on chlorine.
Correct Statements:
Based on the above analysis, the correct statements are:
a) The number of Cl = O bonds in (ii) and (iii) together is two.
In HClO2, there is one Cl = O bond.
In HClO3, there are three Cl = O bonds.
Therefore, the total number of Cl = O bonds in (ii) and (iii) together is two.
b) The number of lone pairs of electrons on Cl in (ii) and (iii) together is three.
In HClO2, there are three lone pairs of electrons on the chlorine atom.
In HClO3, there are four lone pairs of electrons on the chlorine atom.
Therefore, the total number of lone pairs of electrons on Cl in (ii) and (iii) together is three.
c) The hybridization of Cl in (iv) is sp3
In HClO4, there are four Cl = O bonds and five lone pairs of electrons on the chlorine atom. This indicates that the chlorine atom is sp3 hybridized.
Therefore, the correct statements are (b) and (c).
In an aluminium (Al) bar of square cross section, a square hole is drilled and is filled with iron (Fe) as
shown in the figure. The electrical resistivities of Al and Fe are 2.7 × 10–8 
m and 1.0 × 10–7 m,
respectively. The electrical resistance between the two faces P and Q of the composite bar is
- a)
- b)
- c)
- d)
Correct answer is option 'B'. Can you explain this answer?
In an aluminium (Al) bar of square cross section, a square hole is drilled and is filled with iron (Fe) as
shown in the figure. The electrical resistivities of Al and Fe are 2.7 × 10–8 m and 1.0 × 10–7 m,
respectively. The electrical resistance between the two faces P and Q of the composite bar is
shown in the figure. The electrical resistivities of Al and Fe are 2.7 × 10–8
m and 1.0 × 10–7 m,respectively. The electrical resistance between the two faces P and Q of the composite bar is
a)
b)
c)
d)
|
Krishna Iyer answered |
Two spherical stars A and B emit blackbody radiation. The radius of A is 400 times that of B and A emits
104 times the power emitted from B. The ratio (λA/λB) of their wavelengths λA and λB at which the peaks
occur in their respective radiation curves is
Correct answer is '2'. Can you explain this answer?
Two spherical stars A and B emit blackbody radiation. The radius of A is 400 times that of B and A emits
104 times the power emitted from B. The ratio (λA/λB) of their wavelengths λA and λB at which the peaks
occur in their respective radiation curves is
104 times the power emitted from B. The ratio (λA/λB) of their wavelengths λA and λB at which the peaks
occur in their respective radiation curves is
|
|
Krishna Iyer answered |
The correct statement(s) about Cr2+ and Mn3+ is(are)
[Atomic numbers of Cr = 24 and Mn = 25]- a)Cr2+ is a reducing agent
- b)Mn3+ is an oxidizing agent
- c)Both Cr2+ and Mn3+ exhibit d 4 electronic configuration
- d)When Cr2+ is used as a reducing agent, the chromium ion attains d 5 electronic configuration
Correct answer is option 'A,B,C'. Can you explain this answer?
The correct statement(s) about Cr2+ and Mn3+ is(are)
[Atomic numbers of Cr = 24 and Mn = 25]
[Atomic numbers of Cr = 24 and Mn = 25]
a)
Cr2+ is a reducing agent
b)
Mn3+ is an oxidizing agent
c)
Both Cr2+ and Mn3+ exhibit d 4 electronic configuration
d)
When Cr2+ is used as a reducing agent, the chromium ion attains d 5 electronic configuration
|
Dhruv Kulkarni answered |
(1) Cr2+ is a reducing agent because Cr3+ is more stable.
(2) Mn3+ is an oxidizing agent because Mn2+ is more stable.
(3) Cr2+ and Mn3+ exhibit d4 electronic configuration.
(2) Mn3+ is an oxidizing agent because Mn2+ is more stable.
(3) Cr2+ and Mn3+ exhibit d4 electronic configuration.
When O2 is adsorbed on a metallic surface, electron transfer occurs from the metal to O2. The TRUE
statement(s) regarding this adsorption is(are)- a)O2 is physisorbed
- b)heat is released
- c)occupancy of π*2p of O2 is increased
- d)bond length of O2 is increased
Correct answer is option 'B,C,D'. Can you explain this answer?
When O2 is adsorbed on a metallic surface, electron transfer occurs from the metal to O2. The TRUE
statement(s) regarding this adsorption is(are)
statement(s) regarding this adsorption is(are)
a)
O2 is physisorbed
b)
heat is released
c)
occupancy of π*2p of O2 is increased
d)
bond length of O2 is increased
|
|
Disha Khanna answered |
* Adsorption of O2 on metal surface is exothermic.
* During electron transfer from metal to O2 electron occupies π*2p orbital of O2.
* Due to electron transfer to O2 the bond order of O2 decreases hence bond length increases
* During electron transfer from metal to O2 electron occupies π*2p orbital of O2.
* Due to electron transfer to O2 the bond order of O2 decreases hence bond length increases
Not considering the electronic spin, the degeneracy of the second excited state( n = 3) of H atom is 9, while
the degeneracy of the second excited state of H– is
Correct answer is '3'. Can you explain this answer?
Not considering the electronic spin, the degeneracy of the second excited state( n = 3) of H atom is 9, while
the degeneracy of the second excited state of H– is
the degeneracy of the second excited state of H– is
|
Gauri Chauhan answered |
Single electron species don’t follow the 
rule but multi electron species do
rule but multi electron species do
Three moles of B2H6 are completely reacted with methanol. The number of moles of boron containing
product formed is
Correct answer is '6'. Can you explain this answer?
Three moles of B2H6 are completely reacted with methanol. The number of moles of boron containing
product formed is
product formed is
|
Meera Choudhury answered |
1 mole of B2H6 reacts with 6 mole of MeOH to give 2 moles of B(OMe)3.
3 mole of B2H6 will react with 18 mole of MeOH to give 6 moles of B(OMe)3
3 mole of B2H6 will react with 18 mole of MeOH to give 6 moles of B(OMe)3
Let n be the number of ways in which 5 boys and 5 girls can stand in a queue in such a way that all the girls
stand consecutively in the queue. Let m be the number of ways in which 5 boys and 5 girls can stand in a
queue in such a way that exactly four girls stand consecutively in the queue. Then the value of m/n is
Correct answer is '5'. Can you explain this answer?
Let n be the number of ways in which 5 boys and 5 girls can stand in a queue in such a way that all the girls
stand consecutively in the queue. Let m be the number of ways in which 5 boys and 5 girls can stand in a
queue in such a way that exactly four girls stand consecutively in the queue. Then the value of m/n is
stand consecutively in the queue. Let m be the number of ways in which 5 boys and 5 girls can stand in a
queue in such a way that exactly four girls stand consecutively in the queue. Then the value of m/n is
|
Anshu Gupta answered |
Solution:
Finding n:
To find the total number of ways in which 5 boys and 5 girls can stand in a queue such that all the girls stand consecutively, we can group the 5 girls together and treat them as a single entity. So, we have 6 entities to be arranged in a queue, which can be done in 6! ways. Also, the 5 girls can be arranged among themselves in 5! ways. Therefore, the total number of ways in which 5 boys and 5 girls can stand in a queue such that all the girls stand consecutively is:
n = 6! × 5! = 720 × 120 = 86400
Finding m:
To find the number of ways in which exactly four girls stand consecutively, we can select any four girls out of the five in 5 ways. Then, we can group these four girls together and treat them as a single entity. So, we have 6 entities to be arranged in a queue, which can be done in 6! ways. Also, the four girls can be arranged among themselves in 4! ways, and the remaining girl can be placed in any of the 5 gaps between the groups of four girls or to the left or right of the group. Therefore, the total number of ways in which 5 boys and 5 girls can stand in a queue such that exactly four girls stand consecutively is:
m = 5 × 6! × 4! × 5 = 6000
Finding m/n:
The required value is m/n:
m/n = 6000/86400 = 5/72
Therefore, the correct option is 5.
Finding n:
To find the total number of ways in which 5 boys and 5 girls can stand in a queue such that all the girls stand consecutively, we can group the 5 girls together and treat them as a single entity. So, we have 6 entities to be arranged in a queue, which can be done in 6! ways. Also, the 5 girls can be arranged among themselves in 5! ways. Therefore, the total number of ways in which 5 boys and 5 girls can stand in a queue such that all the girls stand consecutively is:
n = 6! × 5! = 720 × 120 = 86400
Finding m:
To find the number of ways in which exactly four girls stand consecutively, we can select any four girls out of the five in 5 ways. Then, we can group these four girls together and treat them as a single entity. So, we have 6 entities to be arranged in a queue, which can be done in 6! ways. Also, the four girls can be arranged among themselves in 4! ways, and the remaining girl can be placed in any of the 5 gaps between the groups of four girls or to the left or right of the group. Therefore, the total number of ways in which 5 boys and 5 girls can stand in a queue such that exactly four girls stand consecutively is:
m = 5 × 6! × 4! × 5 = 6000
Finding m/n:
The required value is m/n:
m/n = 6000/86400 = 5/72
Therefore, the correct option is 5.
number of complex
A ring of mass M and radius R is rotating with angular speed ω about a fixed vertical axis passing through its centre O with two point masses each of mass M/8 at rest at O. These masses can move radially outwards along two massless rods fixed on the ring as shown in the figure. At some instant the angular speed
of the system is 8/9 ω and one of the masses is at a distance of 3/5 R from O. At this instant the distance of the other mass from O is
- a)2/3 R
- b)1/3 R
- c)3/5 R
- d)4/5 R
Correct answer is option 'D'. Can you explain this answer?
A ring of mass M and radius R is rotating with angular speed ω about a fixed vertical axis passing through its centre O with two point masses each of mass M/8 at rest at O. These masses can move radially outwards along two massless rods fixed on the ring as shown in the figure. At some instant the angular speed
of the system is 8/9 ω and one of the masses is at a distance of 3/5 R from O. At this instant the distance of the other mass from O is
of the system is 8/9 ω and one of the masses is at a distance of 3/5 R from O. At this instant the distance of the other mass from O is
a)
2/3 R
b)
1/3 R
c)
3/5 R
d)
4/5 R
|
Anaya Patel answered |
The pair(s) of ions where BOTH the ions are precipitated upon passing H2S gas in presence of dilute HCl,
is(are)- a)Ba2+, Zn2+
- b)Bi3+, Fe3+
- c)Cu2+, Pb2+
- d)Hg2+, Bi3+
Correct answer is option 'C,D'. Can you explain this answer?
The pair(s) of ions where BOTH the ions are precipitated upon passing H2S gas in presence of dilute HCl,
is(are)
is(are)
a)
Ba2+, Zn2+
b)
Bi3+, Fe3+
c)
Cu2+, Pb2+
d)
Hg2+, Bi3+
|
|
Nitya Sarkar answered |
Cu2+ , Pb2+ , Hg2+ , Bi3+ give ppt with H2S in presence of dilute HCl.
Consider a Vernier callipers in which each 1 cm on the main scale is divided into 8 equal divisions and a
screw gauge with 100 divisions on its circular scale. In the Vernier callipers, 5 divisions of the Vernier
scale coincide with 4 divisions on the main scale and in the screw gauge, one complete rotation of the
circular scale moves it by two divisions on the linear scale. Then:- a)If the pitch of the screw gauge is twice the least count of the Vernier callipers, the least count of the screw gauge is 0.01 mm.
- b)If the pitch of the screw gauge is twice the least count of the Vernier callipers, the least count of the screw gauge is 0.005 mm.
- c)If the least count of the linear scale of the screw gauge is twice the least count of the Vernier callipers, the least count of the screw gauge is 0.01 mm.
- d)If the least count of the linear scale of the screw gauge is twice the least count of the Vernier callipers, the least count of the screw gauge is 0.005 mm.
Correct answer is option 'B,C'. Can you explain this answer?
Consider a Vernier callipers in which each 1 cm on the main scale is divided into 8 equal divisions and a
screw gauge with 100 divisions on its circular scale. In the Vernier callipers, 5 divisions of the Vernier
scale coincide with 4 divisions on the main scale and in the screw gauge, one complete rotation of the
circular scale moves it by two divisions on the linear scale. Then:
screw gauge with 100 divisions on its circular scale. In the Vernier callipers, 5 divisions of the Vernier
scale coincide with 4 divisions on the main scale and in the screw gauge, one complete rotation of the
circular scale moves it by two divisions on the linear scale. Then:
a)
If the pitch of the screw gauge is twice the least count of the Vernier callipers, the least count of the screw gauge is 0.01 mm.
b)
If the pitch of the screw gauge is twice the least count of the Vernier callipers, the least count of the screw gauge is 0.005 mm.
c)
If the least count of the linear scale of the screw gauge is twice the least count of the Vernier callipers, the least count of the screw gauge is 0.01 mm.
d)
If the least count of the linear scale of the screw gauge is twice the least count of the Vernier callipers, the least count of the screw gauge is 0.005 mm.
|
Neha Joshi answered |
For screw gauge,
pitch (p) = 2 main scale division
So least count p/100
So option (B) & (C) are correct.
pitch (p) = 2 main scale division
So least count p/100
So option (B) & (C) are correct.
For the octahedral complexes of Fe3+ in SCN– (thiocyanato-S) and in CN– ligand environments, the
difference between the spin-only magnetic moments in Bohr magnetons (When approximated to the nearest
integer) is
[Atomic number of Fe = 26]
Correct answer is '4'. Can you explain this answer?
For the octahedral complexes of Fe3+ in SCN– (thiocyanato-S) and in CN– ligand environments, the
difference between the spin-only magnetic moments in Bohr magnetons (When approximated to the nearest
integer) is
[Atomic number of Fe = 26]
difference between the spin-only magnetic moments in Bohr magnetons (When approximated to the nearest
integer) is
[Atomic number of Fe = 26]
|
Mayank Saha answered |
When 100 mL of 1.0 M HCl was mixed with 100 mL of 1.0 M NaOH in an insulated beaker at constant pressure, a temperature increase of 5.7oC was measured for the beaker and its contents (Expt. 1). Because the enthalpy of neutralization of a strong acid with a strong base is a constant (-57.0 kJ mol-1), this experiment could be used to measure the calorimeter constant. In a second experiment (Expt. 2), 100 mL of 2.0 M acetic acid (Ka = 2.0 × 10-5) was mixed with 100 mL of 1.0 M NaOH (under identical conditions to Expt. 1) where a temperature rise of 5.6oC as measured. (Consider heat capacity of all solutions as 4.2 J g-1 K-1 and density of all solutions as 1.0 g mL-1)Q.The pH of the solution after Expt. 2 is - a)2.8
- b)4.7
- c)5.0
- d)7.0
Correct answer is option 'B'. Can you explain this answer?
When 100 mL of 1.0 M HCl was mixed with 100 mL of 1.0 M NaOH in an insulated beaker at constant pressure, a temperature increase of 5.7oC was measured for the beaker and its contents (Expt. 1). Because the enthalpy of neutralization of a strong acid with a strong base is a constant (-57.0 kJ mol-1), this experiment could be used to measure the calorimeter constant. In a second experiment (Expt. 2), 100 mL of 2.0 M acetic acid (Ka = 2.0 × 10-5) was mixed with 100 mL of 1.0 M NaOH (under identical conditions to Expt. 1) where a temperature rise of 5.6oC as measured.
(Consider heat capacity of all solutions as 4.2 J g-1 K-1 and density of all solutions as 1.0 g mL-1)
Q.
The pH of the solution after Expt. 2 is
a)
2.8
b)
4.7
c)
5.0
d)
7.0
|
Avik Nair answered |
PARAGRAPH 2Let n1 and n2 be the number of red and black balls, respectively, in box I. Let n3 and n4 be the number of red and black balls, respectively, in box II.Q.One of the two boxes, box I and box II, was selected at random and a ball was drawn randomly out of this box. The ball was found to be red. If the probability that this red ball was drawn from box II is 1/3 then the correct option(s) with the possible values of n1, n2, n3 and n4 is(are)- a)n1 = 3, n2 = 3, n3 = 5, n4 = 15
- b)n1 = 3, n2 = 6, n3 = 10, n4 = 50
- c)n1 = 8, n2 = 6, n3 = 5, n4 = 20
- d)n1 = 6, n2 = 12, n3 = 5, n4 = 20
Correct answer is option 'A,B'. Can you explain this answer?
PARAGRAPH 2
Let n1 and n2 be the number of red and black balls, respectively, in box I. Let n3 and n4 be the number of red and black balls, respectively, in box II.
Q.
One of the two boxes, box I and box II, was selected at random and a ball was drawn randomly out of this box. The ball was found to be red. If the probability that this red ball was drawn from box II is 1/3 then the correct option(s) with the possible values of n1, n2, n3 and n4 is(are)
a)
n1 = 3, n2 = 3, n3 = 5, n4 = 15
b)
n1 = 3, n2 = 6, n3 = 10, n4 = 50
c)
n1 = 8, n2 = 6, n3 = 5, n4 = 20
d)
n1 = 6, n2 = 12, n3 = 5, n4 = 20
|
|
Anjali Sharma answered |
A large spherical mass M is fixed at one position and two identical point masses m are kept on a line
passing through the centre of M (see figure). The point masses are connected by a rigid massless rod of
length 
and this assembly is free to move along the line connecting them. All three masses interact only
through their mutual gravitational interaction. When the point mass nearer to M is at a distance r = 3 from
M, the tension in the rod is zero for m = k(M/288). The value of k is
Correct answer is '7'. Can you explain this answer?
A large spherical mass M is fixed at one position and two identical point masses m are kept on a line
passing through the centre of M (see figure). The point masses are connected by a rigid massless rod of
length and this assembly is free to move along the line connecting them. All three masses interact only
through their mutual gravitational interaction. When the point mass nearer to M is at a distance r = 3 from
M, the tension in the rod is zero for m = k(M/288). The value of k is
passing through the centre of M (see figure). The point masses are connected by a rigid massless rod of
length
and this assembly is free to move along the line connecting them. All three masses interact onlythrough their mutual gravitational interaction. When the point mass nearer to M is at a distance r = 3
fromM, the tension in the rod is zero for m = k(M/288). The value of k is
|
|
Krishna Iyer answered |
Let y(x) be a solution of the differential equation (1 + ex )y' + yex = 1. If y(0) = 2, then which of the
following statements is (are) true ?- a)y(-4) = 0
- b)y(-2) = 0
- c)y(x) has a critical point in the interval (-1, 0)
- d)y(x) has no critical point in the interval (-1, 0)
Correct answer is option 'A,C'. Can you explain this answer?
Let y(x) be a solution of the differential equation (1 + ex )y' + yex = 1. If y(0) = 2, then which of the
following statements is (are) true ?
following statements is (are) true ?
a)
y(-4) = 0
b)
y(-2) = 0
c)
y(x) has a critical point in the interval (-1, 0)
d)
y(x) has no critical point in the interval (-1, 0)
|
|
Diya Iyer answered |
The % yield of ammonia as a function of time in the reaction
If this reaction is conducted at (P, T2), with T2 > T1, the % yield of ammonia as a function of time is
represented by- a)
- b)
- c)
- d)
Correct answer is option 'B'. Can you explain this answer?
The % yield of ammonia as a function of time in the reaction
If this reaction is conducted at (P, T2), with T2 > T1, the % yield of ammonia as a function of time is
represented by
represented by
a)
b)
c)
d)
|
|
Krishna Iyer answered |
Increasing the temperature lowers equilibrium yield of ammonia.
However, at higher temperature the initial rate of forward reaction would be greater than at lower
temperature that is why the percentage yield of NH3 too would be more initially.
However, at higher temperature the initial rate of forward reaction would be greater than at lower
temperature that is why the percentage yield of NH3 too would be more initially.
Suppose that all the terms of an arithmetic progression (A.P.) are natural numbers. If the ratio of the sum of
the first seven terms to the sum of the first eleven terms is 6 : 11 and the seventh term lies in between 130
and 140, then the common difference of this A.P. is
Correct answer is '9'. Can you explain this answer?
Suppose that all the terms of an arithmetic progression (A.P.) are natural numbers. If the ratio of the sum of
the first seven terms to the sum of the first eleven terms is 6 : 11 and the seventh term lies in between 130
and 140, then the common difference of this A.P. is
the first seven terms to the sum of the first eleven terms is 6 : 11 and the seventh term lies in between 130
and 140, then the common difference of this A.P. is
|
Akshay Chauhan answered |
parallel plate capacitor having plates of area S and plate separation d, has capacitance C1 in air. When
two dielectrics of different relative permittivities (ε1 = 2 and ε2 = 4) are introduced between the two plates
as shown in the figure, the capacitance becomes C2. The ratio C2/C1 is
- a)6/5
- b)5/3
- c)7/5
- d)7/3
Correct answer is option 'D'. Can you explain this answer?
parallel plate capacitor having plates of area S and plate separation d, has capacitance C1 in air. When
two dielectrics of different relative permittivities (ε1 = 2 and ε2 = 4) are introduced between the two plates
as shown in the figure, the capacitance becomes C2. The ratio C2/C1 is
two dielectrics of different relative permittivities (ε1 = 2 and ε2 = 4) are introduced between the two plates
as shown in the figure, the capacitance becomes C2. The ratio C2/C1 is
a)
6/5
b)
5/3
c)
7/5
d)
7/3
|
Preeti Iyer answered |
Consider the family of all circles whose centers lie on the straight line y = x. If this family of circles is
represented by the differential equation 
where P, Q are functions of x, y and 
then which of the following statements is (are) true ?- a)P = y + x
- b)P = y- x
- c)P + Q = 1 - x + y + y' + (y')2
- d)P - Q = x + y - y' - (y')2
Correct answer is option 'B,C'. Can you explain this answer?
Consider the family of all circles whose centers lie on the straight line y = x. If this family of circles is
represented by the differential equation where P, Q are functions of x, y and then which of the following statements is (are) true ?
represented by the differential equation
where P, Q are functions of x, y and then which of the following statements is (are) true ?a)
P = y + x
b)
P = y- x
c)
P + Q = 1 - x + y + y' + (y')2
d)
P - Q = x + y - y' - (y')2
|
|
Sahil Sharma answered |
Two identical glass rods S1 and S2 (refractive index = 1.5) have one convex end of radius of
curvature 10 cm. They are placed with the curved surfaces at a distance d as shown in the figure, with their axes (shown by the dashed line) aligned. When a point source of light P is placed inside rod S1 on its axis at a distance of 50 cm from the curved face, the light rays emanating from it are found to be parallel to the axis inside S2. The distance d is
- a)60 cm
- b)70 cm
- c)80 cm
- d)90 cm
Correct answer is option 'B'. Can you explain this answer?
Two identical glass rods S1 and S2 (refractive index = 1.5) have one convex end of radius of
curvature 10 cm. They are placed with the curved surfaces at a distance d as shown in the figure, with their axes (shown by the dashed line) aligned. When a point source of light P is placed inside rod S1 on its axis at a distance of 50 cm from the curved face, the light rays emanating from it are found to be parallel to the axis inside S2. The distance d is
curvature 10 cm. They are placed with the curved surfaces at a distance d as shown in the figure, with their axes (shown by the dashed line) aligned. When a point source of light P is placed inside rod S1 on its axis at a distance of 50 cm from the curved face, the light rays emanating from it are found to be parallel to the axis inside S2. The distance d is
a)
60 cm
b)
70 cm
c)
80 cm
d)
90 cm
|
|
Kritika Sarkar answered |
A cylindrical container is to be made from certain solid material with the following constraints: It has a
fixed inner volume of V mm3, has a 2 mm thick solid wall and is open at the top. The bottom of the
container is a solid circular disc of thickness 2 mm and is of radius equal to the outer radius of the
container.
If the volume of the material used to make the container is minimum when the inner radius of the container
is 10 mm, then the value of V/250π is
Correct answer is '4'. Can you explain this answer?
A cylindrical container is to be made from certain solid material with the following constraints: It has a
fixed inner volume of V mm3, has a 2 mm thick solid wall and is open at the top. The bottom of the
container is a solid circular disc of thickness 2 mm and is of radius equal to the outer radius of the
container.
If the volume of the material used to make the container is minimum when the inner radius of the container
is 10 mm, then the value of V/250π is
fixed inner volume of V mm3, has a 2 mm thick solid wall and is open at the top. The bottom of the
container is a solid circular disc of thickness 2 mm and is of radius equal to the outer radius of the
container.
If the volume of the material used to make the container is minimum when the inner radius of the container
is 10 mm, then the value of V/250π is
|
|
Muskaan Chakraborty answered |
An infinitely long uniform line charge distribution of charge per unit length λ lies parallel to the y-axis in the
y-z plane at z =
a (see figure). If the magnitude of the flux of the electric field through the rectangular
surface ABCD lying in the x-y plane with its center at the origin is 
= permittivity of free space), then
the value of n is
Correct answer is '6'. Can you explain this answer?
An infinitely long uniform line charge distribution of charge per unit length λ lies parallel to the y-axis in the
y-z plane at z =a (see figure). If the magnitude of the flux of the electric field through the rectangular
surface ABCD lying in the x-y plane with its center at the origin is= permittivity of free space), then
the value of n is
y-z plane at z =
surface ABCD lying in the x-y plane with its center at the origin is
= permittivity of free space), thenthe value of n is
|
|
Krishna Iyer answered |
Suppose that the foci of the ellipse 
are (f1, 0) and (f2, 0) where f1 > 0 and f2 < 0. Let P1 and P2
be two parabolas with a common vertex at (0, 0) and with foci at (f1, 0) and (2f2, 0), respectively. Let T1 be
a tangent to P1 which passes through (2f2, 0) and T2 be a tangent to P2 which passes through (f1, 0). The m1
is the slope of T1 and m2 is the slope of T2, then the value of 
Correct answer is '4'. Can you explain this answer?
Suppose that the foci of the ellipse are (f1, 0) and (f2, 0) where f1 > 0 and f2 < 0. Let P1 and P2
be two parabolas with a common vertex at (0, 0) and with foci at (f1, 0) and (2f2, 0), respectively. Let T1 be
a tangent to P1 which passes through (2f2, 0) and T2 be a tangent to P2 which passes through (f1, 0). The m1
is the slope of T1 and m2 is the slope of T2, then the value of
are (f1, 0) and (f2, 0) where f1 > 0 and f2 < 0. Let P1 and P2be two parabolas with a common vertex at (0, 0) and with foci at (f1, 0) and (2f2, 0), respectively. Let T1 be
a tangent to P1 which passes through (2f2, 0) and T2 be a tangent to P2 which passes through (f1, 0). The m1
is the slope of T1 and m2 is the slope of T2, then the value of
|
|
Anaya Patel answered |
Four harmonic waves of equal frequencies and equal intensities I0 have phase angles 0, π/3, 2π/3 and π.
When they are superposed, the intensity of the resulting wave is nI0. The value of n is- a)2
- b)1
- c)3
- d)4
Correct answer is option 'C'. Can you explain this answer?
Four harmonic waves of equal frequencies and equal intensities I0 have phase angles 0, π/3, 2π/3 and π.
When they are superposed, the intensity of the resulting wave is nI0. The value of n is
When they are superposed, the intensity of the resulting wave is nI0. The value of n is
a)
2
b)
1
c)
3
d)
4
|
|
Sahana Rane answered |
First and fourth wave interfere destructively. So from the interference of 2nd and 3rd wave only,
SECTION 3Q. No. 57 - 60 carry 4 marks each and 2 mark is deducted for every wrong answer.This section contains TWO paragraphs.
Based on each paragraph, there will be TWO questions
Each question has FOUR options (A), (B), (C) and (D). ONE OR MORE THAN ONE of these four
option(s) is(are) correctPARAGRAPH 1Let 
be a thrice differentiable function. Suppose that F(1) = 0, F(3) = -4 and F'(x) < 0 for all x 
(1/2, 3). Let f (x) = xF(x) for all 
Q.The correct statement(s) is(are)- a)f'(1) < 0
- b)f (2) < 0
- c)f'(x)
0 for any x 
(1, 3) - d)f'(x) = 0 for some x (1, 3)
Correct answer is option 'A,B,C'. Can you explain this answer?
SECTION 3
Q. No. 57 - 60 carry 4 marks each and 2 mark is deducted for every wrong answer.
This section contains TWO paragraphs.
Based on each paragraph, there will be TWO questions
Each question has FOUR options (A), (B), (C) and (D). ONE OR MORE THAN ONE of these four
option(s) is(are) correct
Based on each paragraph, there will be TWO questions
Each question has FOUR options (A), (B), (C) and (D). ONE OR MORE THAN ONE of these four
option(s) is(are) correct
PARAGRAPH 1
Let be a thrice differentiable function. Suppose that F(1) = 0, F(3) = -4 and F'(x) < 0 for all x (1/2, 3). Let f (x) = xF(x) for all
be a thrice differentiable function. Suppose that F(1) = 0, F(3) = -4 and F'(x) < 0 for all x (1/2, 3). Let f (x) = xF(x) for all Q.
The correct statement(s) is(are)
a)
f'(1) < 0
b)
f (2) < 0
c)
f'(x) 0 for any x (1, 3)
0 for any x (1, 3)d)
f'(x) = 0 for some x (1, 3)
(1, 3)|
|
Krishna Iyer answered |
. The value of the expression
SECTION 1Q. No. 21 -28 carry 4 marks each.The answer to each question is a SINGLE DIGIT INTEGER ranging from 0 to 9, both inclusiveQ.In dilute aqueous H2SO4, the complex diaquodioxalatoferrate(II) is oxidized by 
. For this reaction, the ratio of the rate of change of [H+] to the rate of change of 
is
Correct answer is '8'. Can you explain this answer?
SECTION 1
Q. No. 21 -28 carry 4 marks each.
The answer to each question is a SINGLE DIGIT INTEGER ranging from 0 to 9, both inclusive
Q.
In dilute aqueous H2SO4, the complex diaquodioxalatoferrate(II) is oxidized by . For this reaction, the ratio of the rate of change of [H+] to the rate of change of is
. For this reaction, the ratio of the rate of change of [H+] to the rate of change of is
|
Hansa Sharma answered |
Under hydrolytic conditions, the compounds used for preparation of linear polymer and for chain
termination, respectively, are- a)CH3SiCl3 and Si(CH3)4
- b)(CH3)2SiCl2 and (CH3)3SiCl
- c)(CH3)2SiCl2 and CH3SiCl3
- d)SiCl4 and (CH3)3SiCl
Correct answer is option 'B'. Can you explain this answer?
Under hydrolytic conditions, the compounds used for preparation of linear polymer and for chain
termination, respectively, are
termination, respectively, are
a)
CH3SiCl3 and Si(CH3)4
b)
(CH3)2SiCl2 and (CH3)3SiCl
c)
(CH3)2SiCl2 and CH3SiCl3
d)
SiCl4 and (CH3)3SiCl
|
|
Nikhil Banerjee answered |
In 
, let L be a straight line passing through the origin. Suppose that all the points on L are at a constant
distance from the two planes P1 : x + 2y - z + 1 = 0 and P2 : 2x - y + z - 1 = 0. Let M be the locus of the
feet of the perpendiculars drawn from the points on L to the plane P1. Which of the following points lie(s)
on M ?- a)
- b)
- c)
- d)
Correct answer is option 'B,D'. Can you explain this answer?
In , let L be a straight line passing through the origin. Suppose that all the points on L are at a constant
distance from the two planes P1 : x + 2y - z + 1 = 0 and P2 : 2x - y + z - 1 = 0. Let M be the locus of the
feet of the perpendiculars drawn from the points on L to the plane P1. Which of the following points lie(s)
on M ?
, let L be a straight line passing through the origin. Suppose that all the points on L are at a constantdistance from the two planes P1 : x + 2y - z + 1 = 0 and P2 : 2x - y + z - 1 = 0. Let M be the locus of the
feet of the perpendiculars drawn from the points on L to the plane P1. Which of the following points lie(s)
on M ?
a)
b)
c)
d)
|
|
Rishika Khanna answered |
Equation of projection of line L on plane P1 is
Clearly points 
and 
satisfy the line of projection i.e. M
and satisfy the line of projection i.e. M
SECTION 2Q. No 29 - 38 carry 4 marks each and 2 marks are deducted for every wrong answer.Each question has FOUR options (A), (B), (C) and (D). ONE OR MORE THAN ONE of these four
option(s) is(are) correct.Q.If the unit cell of a mineral has cubic close packed (ccp) array of oxygen atoms with m fraction of
octahedral holes occupied by aluminium ions and n fraction of tetrahedral holes occupied by magnesium
ions, m and n, respectively, are- a)
- b)
- c)
- d)
Correct answer is option 'A'. Can you explain this answer?
SECTION 2
Q. No 29 - 38 carry 4 marks each and 2 marks are deducted for every wrong answer.
Each question has FOUR options (A), (B), (C) and (D). ONE OR MORE THAN ONE of these four
option(s) is(are) correct.
option(s) is(are) correct.
Q.
If the unit cell of a mineral has cubic close packed (ccp) array of oxygen atoms with m fraction of
octahedral holes occupied by aluminium ions and n fraction of tetrahedral holes occupied by magnesium
ions, m and n, respectively, are
octahedral holes occupied by aluminium ions and n fraction of tetrahedral holes occupied by magnesium
ions, m and n, respectively, are
a)
b)
c)
d)
|
Vijaya Kondalwade answered |
, where the inverse trigonometric functions take only the principal
SECTION – 1Q. No. - 21 - 28 carry 4 marks each.The answer to each question is a SINGLE DIGIT INTEGER ranging from 0 to 9, both inclusive Q.If the freezing point of a 0.01 molal aqueous solution of a cobalt (III) chloride-ammonia complex(which
behaves as a strong electrolyte) is – 0.05580C, the number of chloride(s) in the coordination sphere of the
complex is
[Kf of water = 1.86 K kg mol–1]
Correct answer is '1'. Can you explain this answer?
SECTION – 1
Q. No. - 21 - 28 carry 4 marks each.
The answer to each question is a SINGLE DIGIT INTEGER ranging from 0 to 9, both inclusive
Q.
If the freezing point of a 0.01 molal aqueous solution of a cobalt (III) chloride-ammonia complex(which
behaves as a strong electrolyte) is – 0.05580C, the number of chloride(s) in the coordination sphere of the
complex is
[Kf of water = 1.86 K kg mol–1]
behaves as a strong electrolyte) is – 0.05580C, the number of chloride(s) in the coordination sphere of the
complex is
[Kf of water = 1.86 K kg mol–1]
|
|
Bhavya Tiwari answered |
Chapter doubts & questions for JEE Advanced 2015 - National Level Test Series for JEE Advanced 2025 2025 is part of JEE exam preparation. The chapters have been prepared according to the JEE exam syllabus. The Chapter doubts & questions, notes, tests & MCQs are made for JEE 2025 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests here.
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