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Fruits were purchased for Rs 350. 9 boys ate 3/5th of them in 2 hours. 6 boys feel their stomach as full so do not eat further. In how many hours the remaining fruits will get finished by remaining boys?- a)2 hours
- b)3 hours
- c)5 hours
- d)4 hours
- e)6 hours
Correct answer is option 'D'. Can you explain this answer?
Fruits were purchased for Rs 350. 9 boys ate 3/5th of them in 2 hours. 6 boys feel their stomach as full so do not eat further. In how many hours the remaining fruits will get finished by remaining boys?
a)
2 hours
b)
3 hours
c)
5 hours
d)
4 hours
e)
6 hours
|
Anaya Patel answered |
D) 4 hours Explanation: Remaining boys = 3, remaining fruits = 2/5th Eating is work here. So M1*H1*W2 = M2*H2*W1
9*2*(2/5) = 3*H2*(3/5)
Solve, H2 = 4
9*2*(2/5) = 3*H2*(3/5)
Solve, H2 = 4
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In a dairy farm, 20 horses eat 40 bags of husk in 40 days. In how many days 10 horses will eat 30 bags of husks?- a)30
- b)60
- c)80
- d)100
- e)None of these
Correct answer is option 'B'. Can you explain this answer?
In a dairy farm, 20 horses eat 40 bags of husk in 40 days. In how many days 10 horses will eat 30 bags of husks?
a)
30
b)
60
c)
80
d)
100
e)
None of these
|
Nikita Singh answered |
Answer – b) 60 Explanation : Horse*Days = Bags 20*40 = 40 and 10*D = 30 (20*40)/(10*D) = 40/30
We get D = 60 days
We get D = 60 days
10 machines can wash 20 cars in 6 hours. In how many hours can 15 machines wash 40 cars?- a)8
- b)7
- c)15
- d)12
- e)6
Correct answer is option 'A'. Can you explain this answer?
10 machines can wash 20 cars in 6 hours. In how many hours can 15 machines wash 40 cars?
a)
8
b)
7
c)
15
d)
12
e)
6
|
|
Nikita Singh answered |
A) 8
Explanation: Washing cars is a work, so M1*H1*W2 = M2*H2*W1
10*6*40 = 15*H2*20
Solve, H2 = 8 hrs
Explanation: Washing cars is a work, so M1*H1*W2 = M2*H2*W1
10*6*40 = 15*H2*20
Solve, H2 = 8 hrs
A contractor employed 60 men to do a piece of work in 76 days. After 50 days, he employed 10 more men and the work was finished 2 day earlier. How many days he would have been behind, if he had not employed additional men?- a)1 day
- b)2 days
- c)3 days
- d)4 days
- e)None of these
Correct answer is option 'B'. Can you explain this answer?
A contractor employed 60 men to do a piece of work in 76 days. After 50 days, he employed 10 more men and the work was finished 2 day earlier. How many days he would have been behind, if he had not employed additional men?
a)
1 day
b)
2 days
c)
3 days
d)
4 days
e)
None of these
|
Kavya Saxena answered |
Answer –b) 2 days Explanation : Total work = 60*50 + 70*24 Now days = D D*60 = 60*50 + 70*24
We get D = 78, so 2 more days
We get D = 78, so 2 more days
To do a certain work in 9 days, some men were employed. All came on the first day, but after seeing that there is too much labor for the work, 6 men left the work after 1 day. If the work is now completed in 6 days more than the scheduled time, how many men were initially employed?- a)14
- b)15
- c)20
- d)18
- e)12
Correct answer is option 'A'. Can you explain this answer?
To do a certain work in 9 days, some men were employed. All came on the first day, but after seeing that there is too much labor for the work, 6 men left the work after 1 day. If the work is now completed in 6 days more than the scheduled time, how many men were initially employed?
a)
14
b)
15
c)
20
d)
18
e)
12
|
Yash Patel answered |
A) 14
Explanation: After 1 day, x men were to work for 8 days, but 6 men left, now (x-6) men will complete the same remaining work in (8+6) = 14days.
So x*8 = (x-6)*14 Solve, x = 14
Explanation: After 1 day, x men were to work for 8 days, but 6 men left, now (x-6) men will complete the same remaining work in (8+6) = 14days.
So x*8 = (x-6)*14 Solve, x = 14
A contractor undertakes to do a job in 18 days. He employees certain number of men, but 12 of them being absent from the very first day, the rest can complete the work in 30 days. The number of men originally employed?- a)20
- b)25
- c)30
- d)40
- e)None of these
Correct answer is option 'C'. Can you explain this answer?
A contractor undertakes to do a job in 18 days. He employees certain number of men, but 12 of them being absent from the very first day, the rest can complete the work in 30 days. The number of men originally employed?
a)
20
b)
25
c)
30
d)
40
e)
None of these
|
|
Yash Patel answered |
Answer – c) 30 Explanation : Let ‘m’ men are originally employed m*18 = (m -12)*30 m = 30
100 men were to complete a piece of work in 20 days. After they worked for 10 days, 60 more men were employed to complete the work on time. If additional men were not employed, then how many days behind schedule the work would be finished?- a)12
- b)8
- c)10
- d)6
- e)None of these
Correct answer is option 'D'. Can you explain this answer?
100 men were to complete a piece of work in 20 days. After they worked for 10 days, 60 more men were employed to complete the work on time. If additional men were not employed, then how many days behind schedule the work would be finished?
a)
12
b)
8
c)
10
d)
6
e)
None of these
|
|
Aarav Sharma answered |
Given:
100 men complete a piece of work in 20 days
Work started with 100 men and after 10 days 60 more men were employed
To find:
How many days behind schedule the work would be finished if additional men were not employed
Solution:
Let's assume the total work is equal to 100 units (this is just an assumption for ease of calculation)
Total work = 100 units
100 men complete 100 units of work in 20 days
So, 1 man will complete 1 unit of work in 20 * 100 = 2000 days
100 men will complete 100 units of work in 2000/100 = 20 days
Now, after 10 days, 100 men have completed 10 * 100 = 1000 units of work
Remaining work = 100 - 1000 = -900 units (negative value indicates that the work is already completed)
So, to complete the work on time, 60 more men were employed
Total men now = 100 + 60 = 160
Work remaining = -900 units (as previously calculated)
Now, 160 men will complete 900 units of work in 900/(160*10) = 0.5625 days
So, the work will be completed in a total of 10 + 0.5625 = 10.5625 days
If additional men were not employed, then the work would have been completed in 20 - 10 = 10 days
So, the work will be finished behind schedule by 10.5625 - 10 = 0.5625 days = 6/11 days ≈ 0.5 days
Therefore, the correct option is (D) 6 days.
100 men complete a piece of work in 20 days
Work started with 100 men and after 10 days 60 more men were employed
To find:
How many days behind schedule the work would be finished if additional men were not employed
Solution:
Let's assume the total work is equal to 100 units (this is just an assumption for ease of calculation)
Total work = 100 units
100 men complete 100 units of work in 20 days
So, 1 man will complete 1 unit of work in 20 * 100 = 2000 days
100 men will complete 100 units of work in 2000/100 = 20 days
Now, after 10 days, 100 men have completed 10 * 100 = 1000 units of work
Remaining work = 100 - 1000 = -900 units (negative value indicates that the work is already completed)
So, to complete the work on time, 60 more men were employed
Total men now = 100 + 60 = 160
Work remaining = -900 units (as previously calculated)
Now, 160 men will complete 900 units of work in 900/(160*10) = 0.5625 days
So, the work will be completed in a total of 10 + 0.5625 = 10.5625 days
If additional men were not employed, then the work would have been completed in 20 - 10 = 10 days
So, the work will be finished behind schedule by 10.5625 - 10 = 0.5625 days = 6/11 days ≈ 0.5 days
Therefore, the correct option is (D) 6 days.
2 men and 3 women are employed to type 100 pages on computer. They completed the work in 5 hours. If one man can do twice work in one hour as compared to one woman, find the number of hours to type 200 pages by 10 women.- a)12
- b)7
- c)6
- d)8.5
- e)10
Correct answer is option 'B'. Can you explain this answer?
2 men and 3 women are employed to type 100 pages on computer. They completed the work in 5 hours. If one man can do twice work in one hour as compared to one woman, find the number of hours to type 200 pages by 10 women.
a)
12
b)
7
c)
6
d)
8.5
e)
10
|
|
Anaya Patel answered |
B) 7
Explanation: Given 1 m = 2 w. So 2 m = 4w 2m+3w 100 pages in 5 hrs, so 4w+3w = 7 women 100 pages in 5 hours. So M1*H1*W2 = M2*D2*H2*W1
7*5*200 = 10*H2*100
Solve H2 = 7
Explanation: Given 1 m = 2 w. So 2 m = 4w 2m+3w 100 pages in 5 hrs, so 4w+3w = 7 women 100 pages in 5 hours. So M1*H1*W2 = M2*D2*H2*W1
7*5*200 = 10*H2*100
Solve H2 = 7
A work is to completed. 10 men started the work and completed 1/6th of the work in 5 days working 3 hrs each day. 2 more men are employed. In how many days will the total number of men complete four times work as before working 5 hours each day?- a)12
- b)18
- c)10
- d)20
- e)15
Correct answer is option 'C'. Can you explain this answer?
A work is to completed. 10 men started the work and completed 1/6th of the work in 5 days working 3 hrs each day. 2 more men are employed. In how many days will the total number of men complete four times work as before working 5 hours each day?
a)
12
b)
18
c)
10
d)
20
e)
15
|
|
Aarav Sharma answered |
Given information:
- 10 men started the work and completed 1/6th of the work in 5 days, working 3 hours each day.
- 2 more men are employed.
- They will work for 5 hours each day.
- We need to find the number of days required for the total number of men to complete four times the previous work.
Calculating the work done by 10 men in 5 days:
- Work done by 1 man in 1 day = 1/(10*5*3) = 1/150
- Work done by 10 men in 1 day = 10 * (1/150) = 1/15
- Work done by 10 men in 5 days = (1/15) * 5 = 1/3
Calculating the work done by 12 men in 1 day:
- Work done by 1 man in 1 day = 1/(12*5*5) = 1/300
- Work done by 12 men in 1 day = 12 * (1/300) = 1/25
Calculating the number of days required for 12 men to complete four times the previous work:
- Work done by 12 men in 1 day = 1/25
- Work to be done = 4 * (1/3) = 4/3
- Number of days required = (4/3) / (1/25) = (4/3) * (25/1) = 100/3 = 33.33 days
Rounding up to the nearest whole number, it will take approximately 34 days for 12 men working 5 hours each day to complete four times the previous work.
Therefore, the correct answer is option 'C' (10 days).
- 10 men started the work and completed 1/6th of the work in 5 days, working 3 hours each day.
- 2 more men are employed.
- They will work for 5 hours each day.
- We need to find the number of days required for the total number of men to complete four times the previous work.
Calculating the work done by 10 men in 5 days:
- Work done by 1 man in 1 day = 1/(10*5*3) = 1/150
- Work done by 10 men in 1 day = 10 * (1/150) = 1/15
- Work done by 10 men in 5 days = (1/15) * 5 = 1/3
Calculating the work done by 12 men in 1 day:
- Work done by 1 man in 1 day = 1/(12*5*5) = 1/300
- Work done by 12 men in 1 day = 12 * (1/300) = 1/25
Calculating the number of days required for 12 men to complete four times the previous work:
- Work done by 12 men in 1 day = 1/25
- Work to be done = 4 * (1/3) = 4/3
- Number of days required = (4/3) / (1/25) = (4/3) * (25/1) = 100/3 = 33.33 days
Rounding up to the nearest whole number, it will take approximately 34 days for 12 men working 5 hours each day to complete four times the previous work.
Therefore, the correct answer is option 'C' (10 days).
2 men or 3 boys can do a piece of work in 14 days working 6 hours each day. In how many days 6 men and 9 boys will complete a work twice as large working together 2 hours each day?- a)12 days
- b)14 days
- c)16 days
- d)15 days
- e)10 days
Correct answer is option 'B'. Can you explain this answer?
2 men or 3 boys can do a piece of work in 14 days working 6 hours each day. In how many days 6 men and 9 boys will complete a work twice as large working together 2 hours each day?
a)
12 days
b)
14 days
c)
16 days
d)
15 days
e)
10 days
|
Preeti Khanna answered |
B) 14 days Explanation: 2 m = 3 b So 1m = 3/2 b 6m + 8b = 6 * (3/2) b + 9b = 18 b So we have to find the number of days for 18 boys 3 boys do 1 work in 14 days working 6 hours, let 18 boys do twice work in x days working 2 hrs each day, then B1*D1*H1*W2 = B2*D2*H2*W1
3*14*6*2 = 18*x*2*1 Solve x = 14 days
3*14*6*2 = 18*x*2*1 Solve x = 14 days
There is sufficient food for 40 men for a 15 days picnic. If after 6 days 4 men leave, how many more days can the remaining men intake food?- a)8
- b)5
- c)10
- d)1
- e)3
Correct answer is option 'D'. Can you explain this answer?
There is sufficient food for 40 men for a 15 days picnic. If after 6 days 4 men leave, how many more days can the remaining men intake food?
a)
8
b)
5
c)
10
d)
1
e)
3
|
Rhea Reddy answered |
D) 1
Explanation: After 6 days, now food is left for 40 men for (15-6) = 9 days, now same food is eaten by (40-4) = 36 men, let it last for x days, so 40*9 = 36*x Solve, x = 10 The food which was to last for 9 days for 40 men, now will last for 10 days for 36 men, so extra 1 day.
Explanation: After 6 days, now food is left for 40 men for (15-6) = 9 days, now same food is eaten by (40-4) = 36 men, let it last for x days, so 40*9 = 36*x Solve, x = 10 The food which was to last for 9 days for 40 men, now will last for 10 days for 36 men, so extra 1 day.
20 men can complete 2/5th of work in 10 days working 6 hours each day. In how many days the remaining work will be completed by 20 women working 4 hours each day such that 4 women do as much work as is done by 2 men?- a)20
- b)42
- c)35
- d)45
- e)None of these
Correct answer is option 'D'. Can you explain this answer?
20 men can complete 2/5th of work in 10 days working 6 hours each day. In how many days the remaining work will be completed by 20 women working 4 hours each day such that 4 women do as much work as is done by 2 men?
a)
20
b)
42
c)
35
d)
45
e)
None of these
|
|
Preeti Khanna answered |
D) 45
Explanation: 4 w = 2m, so 1w = 1/2 m And then 20 w = 10 m, so we have to find the number of days for 10 men to complete remaining work (1 – 2/5) = 3/5th .
M1*D1*H1*W2 = M2*D2*H2*W1
20*10*6*(3/5) = 10*D2*4*(2/5)
Solve, D2 = 45 days
Explanation: 4 w = 2m, so 1w = 1/2 m And then 20 w = 10 m, so we have to find the number of days for 10 men to complete remaining work (1 – 2/5) = 3/5th .
M1*D1*H1*W2 = M2*D2*H2*W1
20*10*6*(3/5) = 10*D2*4*(2/5)
Solve, D2 = 45 days
If 2 men or 5 women can complete a work in 15 days, then in how many days 4 men and 5 women will complete the same work?- a)7
- b)12
- c)8
- d)5
- e)10
Correct answer is option 'D'. Can you explain this answer?
If 2 men or 5 women can complete a work in 15 days, then in how many days 4 men and 5 women will complete the same work?
a)
7
b)
12
c)
8
d)
5
e)
10
|
|
Aarav Sharma answered |
Let's assume that the work to be completed is represented by the variable "W".
Given:
2 men can complete the work in 15 days.
So, in 1 day, 2 men can complete 1/15th of the work.
Therefore, the work done by 1 man in 1 day is 1/(2*15) = 1/30th of the work.
Similarly,
5 women can complete the work in 15 days.
So, in 1 day, 5 women can complete 1/15th of the work.
Therefore, the work done by 1 woman in 1 day is 1/(5*15) = 1/75th of the work.
To find the number of days required for 4 men and 5 women to complete the work, we need to calculate the combined work done by them in 1 day.
Let's calculate the work done by 4 men in 1 day:
Work done by 1 man in 1 day = 1/30th of the work
Work done by 4 men in 1 day = 4 * (1/30) = 2/15th of the work
Now, let's calculate the work done by 5 women in 1 day:
Work done by 1 woman in 1 day = 1/75th of the work
Work done by 5 women in 1 day = 5 * (1/75) = 1/15th of the work
Therefore, the combined work done by 4 men and 5 women in 1 day is:
(2/15) + (1/15) = 3/15 = 1/5th of the work.
So, in 1 day, 4 men and 5 women can complete 1/5th of the work.
To find the number of days required to complete the entire work, we can set up the following equation:
(1/5) * D = 1
Where D represents the number of days required.
Simplifying the equation, we get:
D = 5
Therefore, 4 men and 5 women will complete the same work in 5 days.
Hence, the correct answer is option D.
Given:
2 men can complete the work in 15 days.
So, in 1 day, 2 men can complete 1/15th of the work.
Therefore, the work done by 1 man in 1 day is 1/(2*15) = 1/30th of the work.
Similarly,
5 women can complete the work in 15 days.
So, in 1 day, 5 women can complete 1/15th of the work.
Therefore, the work done by 1 woman in 1 day is 1/(5*15) = 1/75th of the work.
To find the number of days required for 4 men and 5 women to complete the work, we need to calculate the combined work done by them in 1 day.
Let's calculate the work done by 4 men in 1 day:
Work done by 1 man in 1 day = 1/30th of the work
Work done by 4 men in 1 day = 4 * (1/30) = 2/15th of the work
Now, let's calculate the work done by 5 women in 1 day:
Work done by 1 woman in 1 day = 1/75th of the work
Work done by 5 women in 1 day = 5 * (1/75) = 1/15th of the work
Therefore, the combined work done by 4 men and 5 women in 1 day is:
(2/15) + (1/15) = 3/15 = 1/5th of the work.
So, in 1 day, 4 men and 5 women can complete 1/5th of the work.
To find the number of days required to complete the entire work, we can set up the following equation:
(1/5) * D = 1
Where D represents the number of days required.
Simplifying the equation, we get:
D = 5
Therefore, 4 men and 5 women will complete the same work in 5 days.
Hence, the correct answer is option D.
An army camp of 6600 men had provisions for 64 days, when given at the rate of 850 grams per head. At the end of 14 days, a troop arrives and it was found that the provisions will last 34 days more, when given 825 grams per head.What is the strength of new troop?- a)2200
- b)2400
- c)2800
- d)3200
- e)3400 e) None of these
Correct answer is option 'E'. Can you explain this answer?
An army camp of 6600 men had provisions for 64 days, when given at the rate of 850 grams per head. At the end of 14 days, a troop arrives and it was found that the provisions will last 34 days more, when given 825 grams per head.What is the strength of new troop?
a)
2200
b)
2400
c)
2800
d)
3200
e)
3400 e) None of these
|
|
Aarav Sharma answered |
Given data:
- Initially, there were 6600 men in the army camp and provisions for 64 days at the rate of 850 grams per head.
- After 14 days, a troop arrives and the provisions will last for 34 more days when given at the rate of 825 grams per head.
To find: The strength of the new troop.
Solution:
Let's assume that the strength of the new troop is x.
Initial provisions:
- Total provisions = 6600 * 850 * 64 grams
- The provisions are given at the rate of 850 grams per head for 6600 men.
- So, the total provisions = 6600 * 850 * 64 grams
- We can simplify this as 6600 * 54,400 grams.
Provisions after 14 days:
- The provisions have to last for 64 - 14 = 50 days.
- So, the total provisions required = 6600 * 850 * 50 grams
- We can simplify this as 6600 * 42,500 grams.
Provisions after the new troop arrives:
- After the new troop arrives, the provisions last for 34 more days.
- So, the total provisions required = (6600 + x) * 825 * 34 grams
- We can simplify this as (6600 + x) * 28,050 grams.
Equating the provisions:
- The initial provisions = The provisions after 14 days + The provisions after the new troop arrives
- 6600 * 54,400 = 6600 * 42,500 + (6600 + x) * 28,050
- Simplifying this, we get x = 3400.
Therefore, the strength of the new troop is 3400.
Answer: Option (e)
- Initially, there were 6600 men in the army camp and provisions for 64 days at the rate of 850 grams per head.
- After 14 days, a troop arrives and the provisions will last for 34 more days when given at the rate of 825 grams per head.
To find: The strength of the new troop.
Solution:
Let's assume that the strength of the new troop is x.
Initial provisions:
- Total provisions = 6600 * 850 * 64 grams
- The provisions are given at the rate of 850 grams per head for 6600 men.
- So, the total provisions = 6600 * 850 * 64 grams
- We can simplify this as 6600 * 54,400 grams.
Provisions after 14 days:
- The provisions have to last for 64 - 14 = 50 days.
- So, the total provisions required = 6600 * 850 * 50 grams
- We can simplify this as 6600 * 42,500 grams.
Provisions after the new troop arrives:
- After the new troop arrives, the provisions last for 34 more days.
- So, the total provisions required = (6600 + x) * 825 * 34 grams
- We can simplify this as (6600 + x) * 28,050 grams.
Equating the provisions:
- The initial provisions = The provisions after 14 days + The provisions after the new troop arrives
- 6600 * 54,400 = 6600 * 42,500 + (6600 + x) * 28,050
- Simplifying this, we get x = 3400.
Therefore, the strength of the new troop is 3400.
Answer: Option (e)
If 12 pumps can raise 4800 tonnes of oil in 10 days, working 8 hours a day, in how many days will 16 pumps raise 6000 tonnes of oil, working 12 hours a day?- a)4.75 days
- b)5.75 days
- c)6.25 days
- d)6.75 days
- e)None of these
Correct answer is option 'C'. Can you explain this answer?
If 12 pumps can raise 4800 tonnes of oil in 10 days, working 8 hours a day, in how many days will 16 pumps raise 6000 tonnes of oil, working 12 hours a day?
a)
4.75 days
b)
5.75 days
c)
6.25 days
d)
6.75 days
e)
None of these
|
|
Yash Patel answered |
Answer – c) 6.25 days Explanation : (12*10*8)/(16*D*12) = 4800/6000
D = 25/4 days = 6.25 days
D = 25/4 days = 6.25 days
50 people can do 1/4th of work in 20 days working 4 hrs each day. How many people need to be joined in order to complete the work in 40 days working same number of hours as before?- a)75
- b)50
- c)20
- d)25
- e)None of these
Correct answer is option 'D'. Can you explain this answer?
50 people can do 1/4th of work in 20 days working 4 hrs each day. How many people need to be joined in order to complete the work in 40 days working same number of hours as before?
a)
75
b)
50
c)
20
d)
25
e)
None of these
|
|
Preeti Khanna answered |
D) 25
Explanation: M1*D1*H1*W2 = M2*D2*H2*W1
50*20*4*(3/4) = (50+x)*40*4*(1/4) Solve x = 25
Explanation: M1*D1*H1*W2 = M2*D2*H2*W1
50*20*4*(3/4) = (50+x)*40*4*(1/4) Solve x = 25
28 pipes can empty a tank in 4 days working 8 hours a day. If 84 pipes are used to for 5 hours each day, then the same work will be completed in –- a)4.(2/15)
- b)1.(2/15)
- c)3.(2/15)
- d)2.(2/15)
- e)None of these
Correct answer is option 'D'. Can you explain this answer?
28 pipes can empty a tank in 4 days working 8 hours a day. If 84 pipes are used to for 5 hours each day, then the same work will be completed in –
a)
4.(2/15)
b)
1.(2/15)
c)
3.(2/15)
d)
2.(2/15)
e)
None of these
|
|
Alok Verma answered |
Answer – d) 2.(2/15) Explanation : 28*4*8 = 84*5*D
D = 2.2/15 days
D = 2.2/15 days
10 women completed 2/7th of work in 18 days working 6 hours each day. After this 5 women left and 2 men joined. In how many days working same number of hours, the remaining work will get completed if 1 man is equal to 2 women?- a)50
- b)55
- c)70
- d)58
- e)62
Correct answer is option 'A'. Can you explain this answer?
10 women completed 2/7th of work in 18 days working 6 hours each day. After this 5 women left and 2 men joined. In how many days working same number of hours, the remaining work will get completed if 1 man is equal to 2 women?
a)
50
b)
55
c)
70
d)
58
e)
62
|
|
Nikita Singh answered |
A) 50
Explanation: Remaining work = 1 – 2/7 = 5/7 After 18 days, 5 women left and 2 men joined so 4 women joined (1m = 2w), now number of women is 5+4 = 9, so 10*18*6*(5/7) = 9*D2*6*(2/7)
Solve, D2 = 50
Explanation: Remaining work = 1 – 2/7 = 5/7 After 18 days, 5 women left and 2 men joined so 4 women joined (1m = 2w), now number of women is 5+4 = 9, so 10*18*6*(5/7) = 9*D2*6*(2/7)
Solve, D2 = 50
2 men and 4 women can complete a job in 5 days. Also same job can be completed by 3 men and 8 women in 3 days. In how many days, twice the job can be completed by 3 men and 3 women?- a)4
- b)8
- c)10
- d)8.5
- e)13
Correct answer is option 'B'. Can you explain this answer?
2 men and 4 women can complete a job in 5 days. Also same job can be completed by 3 men and 8 women in 3 days. In how many days, twice the job can be completed by 3 men and 3 women?
a)
4
b)
8
c)
10
d)
8.5
e)
13
|
|
Aarav Sharma answered |
Given information:
- 2 men + 4 women complete a job in 5 days
- 3 men + 8 women complete the same job in 3 days
To find:
- In how many days, twice the job can be completed by 3 men and 3 women?
Approach:
Let's first calculate the efficiency of each person per day based on the given information. Efficiency is calculated as the fraction of the job completed by a person in one day.
For the first case:
- 2 men + 4 women complete the job in 5 days
- Total number of people = 2 + 4 = 6
- Total number of days = 5
- Efficiency of each person per day = 1 / (6 x 5) = 1/30
For the second case:
- 3 men + 8 women complete the job in 3 days
- Total number of people = 3 + 8 = 11
- Total number of days = 3
- Efficiency of each person per day = 1 / (11 x 3) = 1/33
Now, let's assume that twice the job can be completed in 'd' days by 3 men and 3 women. We need to find the value of 'd'.
Let's calculate the total efficiency of 3 men and 3 women per day:
- Total number of people = 3 + 3 = 6
- Efficiency of each person per day = 1 / (6 x d) = 1/6d
- Total efficiency of 3 men and 3 women per day = (3/6d) + (3/6d) = 1/2d
Now, we can equate the total efficiency of 3 men and 3 women per day to the efficiency calculated in the first case (since we need to complete twice the job):
- 1/2d = 1/30
- Solving for 'd', we get d = 60/2 = 30
Therefore, twice the job can be completed by 3 men and 3 women in 30 days.
Answer:
Option B) 8
- 2 men + 4 women complete a job in 5 days
- 3 men + 8 women complete the same job in 3 days
To find:
- In how many days, twice the job can be completed by 3 men and 3 women?
Approach:
Let's first calculate the efficiency of each person per day based on the given information. Efficiency is calculated as the fraction of the job completed by a person in one day.
For the first case:
- 2 men + 4 women complete the job in 5 days
- Total number of people = 2 + 4 = 6
- Total number of days = 5
- Efficiency of each person per day = 1 / (6 x 5) = 1/30
For the second case:
- 3 men + 8 women complete the job in 3 days
- Total number of people = 3 + 8 = 11
- Total number of days = 3
- Efficiency of each person per day = 1 / (11 x 3) = 1/33
Now, let's assume that twice the job can be completed in 'd' days by 3 men and 3 women. We need to find the value of 'd'.
Let's calculate the total efficiency of 3 men and 3 women per day:
- Total number of people = 3 + 3 = 6
- Efficiency of each person per day = 1 / (6 x d) = 1/6d
- Total efficiency of 3 men and 3 women per day = (3/6d) + (3/6d) = 1/2d
Now, we can equate the total efficiency of 3 men and 3 women per day to the efficiency calculated in the first case (since we need to complete twice the job):
- 1/2d = 1/30
- Solving for 'd', we get d = 60/2 = 30
Therefore, twice the job can be completed by 3 men and 3 women in 30 days.
Answer:
Option B) 8
20 carpets are to weave by 40 women in 50 days working 8 hours per day. After 20 days, order of 6 more carpets came. To complete the total work on time, how many more hours per day they will have to work?- a)2
- b)4
- c)5
- d)10
- e)12
Correct answer is option 'B'. Can you explain this answer?
20 carpets are to weave by 40 women in 50 days working 8 hours per day. After 20 days, order of 6 more carpets came. To complete the total work on time, how many more hours per day they will have to work?
a)
2
b)
4
c)
5
d)
10
e)
12
|
|
Aisha Gupta answered |
B) 4
Explanation: First find the number of carpets weave in first 20 days, after which order of more carpets came. So, In 50 days, 20 carpets, so in 20 days 20*20/50 = 8 carpets So in remaining 30 days, (20-8) = 12 carpets can be weave working 8 hrs each day Now number of carpets is (12+6) = 18, let no of hours is x, so H1*W2 = H2*W1
8*18 = x*12 Solve, x = 12 hrs So more hrs = 12-8 = 4 hrs
Explanation: First find the number of carpets weave in first 20 days, after which order of more carpets came. So, In 50 days, 20 carpets, so in 20 days 20*20/50 = 8 carpets So in remaining 30 days, (20-8) = 12 carpets can be weave working 8 hrs each day Now number of carpets is (12+6) = 18, let no of hours is x, so H1*W2 = H2*W1
8*18 = x*12 Solve, x = 12 hrs So more hrs = 12-8 = 4 hrs
A job is completed by 5 men or 7 women in 40 days, then in how many days thrice the job as previous will be completed by 5 men and 3 women?- a)27
- b)28
- c)38
- d)84
- e)90
Correct answer is option 'D'. Can you explain this answer?
A job is completed by 5 men or 7 women in 40 days, then in how many days thrice the job as previous will be completed by 5 men and 3 women?
a)
27
b)
28
c)
38
d)
84
e)
90
|
|
Anaya Patel answered |
D) 84
Explanation: 5 m or 7 w 5m + 3w Cross multiply and put in denominator Days = 40*5*7/ [5*3 +7*5] = 28 so for thrice work, days = 28*3
Explanation: 5 m or 7 w 5m + 3w Cross multiply and put in denominator Days = 40*5*7/ [5*3 +7*5] = 28 so for thrice work, days = 28*3
50 people went on picnic along with taking food for 10 days. After 4 days 10 people left the picnic. For how many days the food will last now?- a)7 1/2
- b)15 1/2
- c)8
- d)6
- e)6 1/2
Correct answer is option 'A'. Can you explain this answer?
50 people went on picnic along with taking food for 10 days. After 4 days 10 people left the picnic. For how many days the food will last now?
a)
7 1/2
b)
15 1/2
c)
8
d)
6
e)
6 1/2
|
Gowri Chakraborty answered |
After 4 days, there is (10-4) = 6 days food for 50 people. But 10 people left, so there are 40 people left, and let now the same food is for x days for 40 people. So
M1*D1 = M2*D2
50*6 = 40*x
Solve, x = 15/2
In a school there is a meal for 60 girls and 100 boys. If 50 boys have taken their meal, how many girls will be catered with the remaining meal?- a)15
- b)30
- c)45
- d)60
- e)None of these
Correct answer is option 'B'. Can you explain this answer?
In a school there is a meal for 60 girls and 100 boys. If 50 boys have taken their meal, how many girls will be catered with the remaining meal?
a)
15
b)
30
c)
45
d)
60
e)
None of these
|
|
Preeti Khanna answered |
Answer – b) 30 Explananion : 50 boys taken the meal means only 1/2 meal is remaining So, G/60 = 1/2, we get G =30
A job that can be completed by 2 men and 6 women in 10 days will be completed by 4 men and 12 women in how many days?- a)2
- b)3
- c)4
- d)5
- e)None of these
Correct answer is option 'D'. Can you explain this answer?
A job that can be completed by 2 men and 6 women in 10 days will be completed by 4 men and 12 women in how many days?
a)
2
b)
3
c)
4
d)
5
e)
None of these
|
|
Aarav Sharma answered |
Answer – d) 5 Explanation : 2m + 6w = 1/10, m + 3w = 1/20 D is the days required We have to find 4m + 12w = 1/d, 4*(m +3w) = 1/d 4*1/20 = 1/d We get d = 5
10 people complete 2/5th of work in 8 days working 5 hours each day. How many additional men are needed to complete the work in a total of 14 days working same number of hours each day as earlier?- a)12
- b)10
- c)30
- d)20
- e)15
Correct answer is option 'B'. Can you explain this answer?
10 people complete 2/5th of work in 8 days working 5 hours each day. How many additional men are needed to complete the work in a total of 14 days working same number of hours each day as earlier?
a)
12
b)
10
c)
30
d)
20
e)
15
|
|
Aarav Sharma answered |
B) 10
Explanation: Total work to be completed in 14 days, so (additional men+10 men already employed) will have to complete remaining work (1 – 2/5 ) = 3/5 of work in (14-8) = 6 days.. let x is additional men M1*D1*H1*W2 = M2*D2*H2*W1
10*8*5*(3/5) = (10+x)*6*5*(2/5) Solve x = 10
Explanation: Total work to be completed in 14 days, so (additional men+10 men already employed) will have to complete remaining work (1 – 2/5 ) = 3/5 of work in (14-8) = 6 days.. let x is additional men M1*D1*H1*W2 = M2*D2*H2*W1
10*8*5*(3/5) = (10+x)*6*5*(2/5) Solve x = 10
100 books can be bind by 50 students in 4 hours. How many books will be bind by 150 students in 2 hours?- a)150
- b)250
- c)200
- d)180
- e)120
Correct answer is option 'A'. Can you explain this answer?
100 books can be bind by 50 students in 4 hours. How many books will be bind by 150 students in 2 hours?
a)
150
b)
250
c)
200
d)
180
e)
120
|
|
Kavya Saxena answered |
A) 150
Explanation: Binding books is a work, so W2*S1*H1 = W1*S2*H2
W2*50*4 = 100*150*2
Solve W2 = 150 books
Explanation: Binding books is a work, so W2*S1*H1 = W1*S2*H2
W2*50*4 = 100*150*2
Solve W2 = 150 books
A job that can be completed by 2 men and 6 women in 10 days will be completed by 5 men and 15 women in how many days?- a)2
- b)3
- c)5
- d)4
- e)Cannot be determined
Correct answer is option 'D'. Can you explain this answer?
A job that can be completed by 2 men and 6 women in 10 days will be completed by 5 men and 15 women in how many days?
a)
2
b)
3
c)
5
d)
4
e)
Cannot be determined
|
|
Aisha Gupta answered |
D) 4
Explanation: 2m + 6w = 10 D Or 2(1m + 3w) = 10D Or 1m + 3w = 20D So 5(1m + 3w) = 20/5 Or 5m + 15w = 4D
Explanation: 2m + 6w = 10 D Or 2(1m + 3w) = 10D Or 1m + 3w = 20D So 5(1m + 3w) = 20/5 Or 5m + 15w = 4D
2 men or 4 women or 5 children can complete a piece of work in 38 days. In how many days will 1 man, 1 woman and 1 child complete the same work?- a)20
- b)40
- c)36
- d)42
- e)None of these
Correct answer is option 'B'. Can you explain this answer?
2 men or 4 women or 5 children can complete a piece of work in 38 days. In how many days will 1 man, 1 woman and 1 child complete the same work?
a)
20
b)
40
c)
36
d)
42
e)
None of these
|
|
Aarav Sharma answered |
To solve this problem, we need to find the ratio of work done by each individual, and then use that ratio to determine the time taken by one man, one woman, and one child to complete the work.
Let's assume that the work done by 1 man in 1 day is M units, the work done by 1 woman in 1 day is W units, and the work done by 1 child in 1 day is C units.
According to the given information, 2 men, or 4 women, or 5 children can complete the work in 38 days. This means that the work done by these groups combined in 38 days is equal to the total work.
So, we can write the following equations:
2M * 38 = Total work
4W * 38 = Total work
5C * 38 = Total work
Now, we need to find the ratios of M, W, and C:
M = (Total work) / (2 * 38)
W = (Total work) / (4 * 38)
C = (Total work) / (5 * 38)
Now, we can find the work done by one man, one woman, and one child in 1 day:
1 man = (Total work) / (2 * 38)
1 woman = (Total work) / (4 * 38)
1 child = (Total work) / (5 * 38)
To find the time taken by one man, one woman, and one child to complete the work, we need to divide the total work by the work done by each individual in 1 day:
Time = Total work / [(Total work) / (2 * 38) + (Total work) / (4 * 38) + (Total work) / (5 * 38)]
Simplifying the expression:
Time = (2 * 38 * 4 * 38 * 5 * 38) / [(2 * 38) + (4 * 38) + (5 * 38)]
The common factor of 38 in the numerator and denominator can be canceled out:
Time = (2 * 4 * 5 * 38) / (2 + 4 + 5)
Time = (40 * 38) / 11
Time = 40 * 3.45
Time ≈ 138
Therefore, 1 man, 1 woman, and 1 child will take approximately 138 days to complete the work.
Since none of the given options match this value, the correct answer is None of these.
Let's assume that the work done by 1 man in 1 day is M units, the work done by 1 woman in 1 day is W units, and the work done by 1 child in 1 day is C units.
According to the given information, 2 men, or 4 women, or 5 children can complete the work in 38 days. This means that the work done by these groups combined in 38 days is equal to the total work.
So, we can write the following equations:
2M * 38 = Total work
4W * 38 = Total work
5C * 38 = Total work
Now, we need to find the ratios of M, W, and C:
M = (Total work) / (2 * 38)
W = (Total work) / (4 * 38)
C = (Total work) / (5 * 38)
Now, we can find the work done by one man, one woman, and one child in 1 day:
1 man = (Total work) / (2 * 38)
1 woman = (Total work) / (4 * 38)
1 child = (Total work) / (5 * 38)
To find the time taken by one man, one woman, and one child to complete the work, we need to divide the total work by the work done by each individual in 1 day:
Time = Total work / [(Total work) / (2 * 38) + (Total work) / (4 * 38) + (Total work) / (5 * 38)]
Simplifying the expression:
Time = (2 * 38 * 4 * 38 * 5 * 38) / [(2 * 38) + (4 * 38) + (5 * 38)]
The common factor of 38 in the numerator and denominator can be canceled out:
Time = (2 * 4 * 5 * 38) / (2 + 4 + 5)
Time = (40 * 38) / 11
Time = 40 * 3.45
Time ≈ 138
Therefore, 1 man, 1 woman, and 1 child will take approximately 138 days to complete the work.
Since none of the given options match this value, the correct answer is None of these.
30 women complete the 2/5th work in 40 days working 6 hours each day. If 10 women leave, in how many days the remaining work will get completed if now they work for 10 hours each day?- a)62
- b)58
- c)54
- d)70
- e)45
Correct answer is option 'C'. Can you explain this answer?
30 women complete the 2/5th work in 40 days working 6 hours each day. If 10 women leave, in how many days the remaining work will get completed if now they work for 10 hours each day?
a)
62
b)
58
c)
54
d)
70
e)
45
|
|
Aarav Sharma answered |
Let's break down the problem into smaller steps to solve it easily:
Step 1: Calculate the total work
Since 30 women complete 2/5th of the work in 40 days, we can find the total work as follows:
Total work = (30 women) * (2/5) = 12 women
Step 2: Calculate the work done per day
Since the 30 women work for 40 days, we can calculate the work done per day as follows:
Work done per day = Total work / Number of days
Work done per day = 12 women / 40 days = 3/10 women per day
Step 3: Calculate the work done in 1 hour
Since the women work for 6 hours each day, we can calculate the work done in 1 hour as follows:
Work done in 1 hour = Work done per day / Number of hours
Work done in 1 hour = (3/10) women per day / 6 hours = 1/20 women per hour
Step 4: Calculate the remaining work
Since 10 women leave, the remaining work is given by:
Remaining work = Total work - Work done by the 20 women
Remaining work = 12 women - (20 women * 1/20 women per hour * 6 hours per day)
Remaining work = 12 women - (20/20) women
Remaining work = 12 - 1 = 11 women
Step 5: Calculate the number of days needed to complete the remaining work
Since the remaining work is 11 women and the 20 women work for 10 hours each day, we can calculate the number of days needed to complete the remaining work as follows:
Number of days = Remaining work / (Work done in 1 hour * Number of hours per day)
Number of days = 11 women / (1/20 women per hour * 10 hours per day)
Number of days = 11 women / (1/2 women per day)
Number of days = 11 women * 2 women per day
Number of days = 22 days
Therefore, the remaining work will get completed in 22 days if the women work for 10 hours each day.
Step 1: Calculate the total work
Since 30 women complete 2/5th of the work in 40 days, we can find the total work as follows:
Total work = (30 women) * (2/5) = 12 women
Step 2: Calculate the work done per day
Since the 30 women work for 40 days, we can calculate the work done per day as follows:
Work done per day = Total work / Number of days
Work done per day = 12 women / 40 days = 3/10 women per day
Step 3: Calculate the work done in 1 hour
Since the women work for 6 hours each day, we can calculate the work done in 1 hour as follows:
Work done in 1 hour = Work done per day / Number of hours
Work done in 1 hour = (3/10) women per day / 6 hours = 1/20 women per hour
Step 4: Calculate the remaining work
Since 10 women leave, the remaining work is given by:
Remaining work = Total work - Work done by the 20 women
Remaining work = 12 women - (20 women * 1/20 women per hour * 6 hours per day)
Remaining work = 12 women - (20/20) women
Remaining work = 12 - 1 = 11 women
Step 5: Calculate the number of days needed to complete the remaining work
Since the remaining work is 11 women and the 20 women work for 10 hours each day, we can calculate the number of days needed to complete the remaining work as follows:
Number of days = Remaining work / (Work done in 1 hour * Number of hours per day)
Number of days = 11 women / (1/20 women per hour * 10 hours per day)
Number of days = 11 women / (1/2 women per day)
Number of days = 11 women * 2 women per day
Number of days = 22 days
Therefore, the remaining work will get completed in 22 days if the women work for 10 hours each day.
A certain number of answer sheets can be checked in 12 days working 5 hours each day by 9 examiners. For how many hours a day should 4 examiners work to check twice the number of answer sheets in 30 days?- a)4 hours
- b)8 hours
- c)7 hours
- d)9 hours
- e)6 hours
Correct answer is option 'D'. Can you explain this answer?
A certain number of answer sheets can be checked in 12 days working 5 hours each day by 9 examiners. For how many hours a day should 4 examiners work to check twice the number of answer sheets in 30 days?
a)
4 hours
b)
8 hours
c)
7 hours
d)
9 hours
e)
6 hours
|
|
Rhea Reddy answered |
D) 9 hours Explanation: Answer sheets are work here. So M1*D1*H1*W2 = M2*D2*H2*W1
9*12*5*2 = 4*30*H2*1
Solve, H2 = 9
9*12*5*2 = 4*30*H2*1
Solve, H2 = 9
A certain piece of work was to be completed in 50 days for which 200 men were employed. After working for 40 days, additional 100 men were employed to complete the work on time. Had additional men were not employed, how many days behind schedule the work would be finished?- a)12
- b)8
- c)10
- d)5
- e)None of these
Correct answer is option 'D'. Can you explain this answer?
A certain piece of work was to be completed in 50 days for which 200 men were employed. After working for 40 days, additional 100 men were employed to complete the work on time. Had additional men were not employed, how many days behind schedule the work would be finished?
a)
12
b)
8
c)
10
d)
5
e)
None of these
|
|
Anaya Patel answered |
D) 5
Explanation: Let 200 men complete x work in 40 days after which (200+100) = 300 men complete the remaining (1-x) work in remaining 10 days [Total work to be completed in 50 days] So, M1*D1*W2 = M2*D2*W1 200*40*(1-x) = 300*10*x Solve, x= 8/11 This means that initially employed 200 men can finish 8/11th of work in 40 days, so let they will complete 1 whole work in x days.
M1*D1*W2 = M2*D2*W1
200*40*1 = 200*x*(8/11) Solve, x = 55 This means extra (55-50) = 5 days will be required if additional men are not employed after 40 days.
Explanation: Let 200 men complete x work in 40 days after which (200+100) = 300 men complete the remaining (1-x) work in remaining 10 days [Total work to be completed in 50 days] So, M1*D1*W2 = M2*D2*W1 200*40*(1-x) = 300*10*x Solve, x= 8/11 This means that initially employed 200 men can finish 8/11th of work in 40 days, so let they will complete 1 whole work in x days.
M1*D1*W2 = M2*D2*W1
200*40*1 = 200*x*(8/11) Solve, x = 55 This means extra (55-50) = 5 days will be required if additional men are not employed after 40 days.
A pipe filled 4/5th of a cistern in 10 minutes. How much more time will it take to fill the rest?- a)2 minutes
- b)2.5 minutes
- c)3 minutes
- d)3.5 minutes
- e)None of these
Correct answer is option 'B'. Can you explain this answer?
A pipe filled 4/5th of a cistern in 10 minutes. How much more time will it take to fill the rest?
a)
2 minutes
b)
2.5 minutes
c)
3 minutes
d)
3.5 minutes
e)
None of these
|
|
Aisha Gupta answered |
B) 2.5 minutes Explanation: 1/5 * 10 = (4/5) * x x = 5/2
In a refugee camp, 20 people are provided food which was given for 5 days. 10 people left this group after 2 days, and it was found that the remaining food lasted for 3 days for remaining people. If the people would not have left, how many days the food would have been lasted?- a)4 days
- b)3.5 days
- c)3 days
- d)4.5 days
- e)None of these
Correct answer is option 'B'. Can you explain this answer?
In a refugee camp, 20 people are provided food which was given for 5 days. 10 people left this group after 2 days, and it was found that the remaining food lasted for 3 days for remaining people. If the people would not have left, how many days the food would have been lasted?
a)
4 days
b)
3.5 days
c)
3 days
d)
4.5 days
e)
None of these
|
|
Aarav Sharma answered |
Let's break down the problem step by step:
Given:
- 20 people in a refugee camp are provided food for 5 days.
- 10 people left after 2 days.
- The remaining food lasted for 3 days for the remaining people.
To find:
- How many days the food would have lasted if the 10 people had not left.
Solution:
1. Calculate the total amount of food initially provided:
- 20 people * 5 days = 100 people-days of food
2. Calculate the total amount of food consumed by the initial group in 2 days:
- 20 people * 2 days = 40 people-days of food
3. Calculate the remaining amount of food for the remaining people:
- 100 people-days of food - 40 people-days of food = 60 people-days of food
4. Calculate the number of people remaining after 10 people left:
- 20 people - 10 people = 10 people
5. Calculate the number of days the remaining food lasted for the remaining people:
- 60 people-days of food / 10 people = 6 days
Therefore, if the 10 people had not left, the food would have lasted for 6 days.
But the answer options provided do not include 6 days. Let's analyze the given options:
a) 4 days - This is less than the 6 days calculated, so it cannot be the answer.
b) 3.5 days - This is also less than the 6 days calculated, so it cannot be the answer.
c) 3 days - This is less than the 6 days calculated, so it cannot be the answer.
d) 4.5 days - This is less than the 6 days calculated, so it cannot be the answer.
e) None of these - This option is incorrect because the correct answer is option b.
Therefore, the correct answer is option b) 3.5 days.
Given:
- 20 people in a refugee camp are provided food for 5 days.
- 10 people left after 2 days.
- The remaining food lasted for 3 days for the remaining people.
To find:
- How many days the food would have lasted if the 10 people had not left.
Solution:
1. Calculate the total amount of food initially provided:
- 20 people * 5 days = 100 people-days of food
2. Calculate the total amount of food consumed by the initial group in 2 days:
- 20 people * 2 days = 40 people-days of food
3. Calculate the remaining amount of food for the remaining people:
- 100 people-days of food - 40 people-days of food = 60 people-days of food
4. Calculate the number of people remaining after 10 people left:
- 20 people - 10 people = 10 people
5. Calculate the number of days the remaining food lasted for the remaining people:
- 60 people-days of food / 10 people = 6 days
Therefore, if the 10 people had not left, the food would have lasted for 6 days.
But the answer options provided do not include 6 days. Let's analyze the given options:
a) 4 days - This is less than the 6 days calculated, so it cannot be the answer.
b) 3.5 days - This is also less than the 6 days calculated, so it cannot be the answer.
c) 3 days - This is less than the 6 days calculated, so it cannot be the answer.
d) 4.5 days - This is less than the 6 days calculated, so it cannot be the answer.
e) None of these - This option is incorrect because the correct answer is option b.
Therefore, the correct answer is option b) 3.5 days.
If 10 men can reap 40 hectares of a field in 5 days then how many hectares of field can 30 men reap in 10 days?- a)180
- b)200
- c)240
- d)280
- e)None of these
Correct answer is option 'C'. Can you explain this answer?
If 10 men can reap 40 hectares of a field in 5 days then how many hectares of field can 30 men reap in 10 days?
a)
180
b)
200
c)
240
d)
280
e)
None of these
|
|
Yash Patel answered |
Answer – c) 240 Explanation : 10*5 = 40…….(1)
30*10 = H…….(2)
Divide both equations to get H We get h = 240
30*10 = H…….(2)
Divide both equations to get H We get h = 240
To build a house, 5 men take 60 days working 8 hours each day. In how many days 2 such houses can be built by 8 men working 10 hours each day?- a)75
- b)50
- c)20
- d)60
- e)None of these
Correct answer is option 'D'. Can you explain this answer?
To build a house, 5 men take 60 days working 8 hours each day. In how many days 2 such houses can be built by 8 men working 10 hours each day?
a)
75
b)
50
c)
20
d)
60
e)
None of these
|
|
Alok Verma answered |
D) 60
Explanation: Building 1 house is 1, 2 houses is 2, so M1*D1*H1*W2 = M2*D2*H2*W1
5*60*8*(2) = 8*D2*10*(1)
Solve, D2 = 60
Explanation: Building 1 house is 1, 2 houses is 2, so M1*D1*H1*W2 = M2*D2*H2*W1
5*60*8*(2) = 8*D2*10*(1)
Solve, D2 = 60
If 10 labourers can dig a well 40 m deep in 18 days, working 9 hours a day, how many additional labourers should be engaged to dig a similar well 80 m deep in 6 days, each labourer working 9 hours a day?- a)30
- b)40
- c)50
- d)60
- e)None of these
Correct answer is option 'C'. Can you explain this answer?
If 10 labourers can dig a well 40 m deep in 18 days, working 9 hours a day, how many additional labourers should be engaged to dig a similar well 80 m deep in 6 days, each labourer working 9 hours a day?
a)
30
b)
40
c)
50
d)
60
e)
None of these
|
Faizan Khan answered |
Answer – c) 50 Explanation : 10*18*9 = 40 ……..(1)
L*9*6 = 40 ……..(2)
Divide both equations We get L = 60, so additional 50 men must be employed
L*9*6 = 40 ……..(2)
Divide both equations We get L = 60, so additional 50 men must be employed
If 20 people can complete 2/5th of a work in 6 days working 4 hours each day, then how much work will be completed by 30 people in 2 days working 8 hours each day?- a)1
- b)4/5
- c)3/5
- d)2/5
- e)2/3
Correct answer is option 'D'. Can you explain this answer?
If 20 people can complete 2/5th of a work in 6 days working 4 hours each day, then how much work will be completed by 30 people in 2 days working 8 hours each day?
a)
1
b)
4/5
c)
3/5
d)
2/5
e)
2/3
|
|
Nikita Singh answered |
D) 2/5
Explanation: M1*D1*H1*W2 = M2*D2*H2*W1
20*6*4*W2 = 30*2*8*(2/5)
Solve W2 = 2/5
Explanation: M1*D1*H1*W2 = M2*D2*H2*W1
20*6*4*W2 = 30*2*8*(2/5)
Solve W2 = 2/5
If 4 people can do a piece of work in 16 days working 5 hours each day. In how many the same work will be completed by 20 people working 4 hours each day?- a)10
- b)8
- c)4
- d)6
- e)7
Correct answer is option 'C'. Can you explain this answer?
If 4 people can do a piece of work in 16 days working 5 hours each day. In how many the same work will be completed by 20 people working 4 hours each day?
a)
10
b)
8
c)
4
d)
6
e)
7
|
|
Faizan Khan answered |
C) 4
Explanation: M1*H1*D1 = M2*H2*D2
4*5*16 = 20*4*D2
Solve D2 = 4
Explanation: M1*H1*D1 = M2*H2*D2
4*5*16 = 20*4*D2
Solve D2 = 4
A camp can provide food to 150 men for 45 days. After 10 days, 25 left the camp. What is the number of days for which the remaining food will last now?- a)42
- b)48
- c)40
- d)30
- e)36
Correct answer is option 'A'. Can you explain this answer?
A camp can provide food to 150 men for 45 days. After 10 days, 25 left the camp. What is the number of days for which the remaining food will last now?
a)
42
b)
48
c)
40
d)
30
e)
36
|
|
Yash Patel answered |
A) 42
Explanation: After 10 days, there is (45-10) = 35 days food for 150 men. But 25 men left, so there are 125 men left, and let now the same food is for x days for 125 men. So M1*D1 = M2*D2
150*35 = 125*x Solve, x = 42
Explanation: After 10 days, there is (45-10) = 35 days food for 150 men. But 25 men left, so there are 125 men left, and let now the same food is for x days for 125 men. So M1*D1 = M2*D2
150*35 = 125*x Solve, x = 42
20 people can eat 100 burgers in 2 hours. In how many hours 200 burgers will be eaten by 10 people?- a)5 hours
- b)8 hours
- c)7 hours
- d)4 hours
- e)6 hours
Correct answer is option 'B'. Can you explain this answer?
20 people can eat 100 burgers in 2 hours. In how many hours 200 burgers will be eaten by 10 people?
a)
5 hours
b)
8 hours
c)
7 hours
d)
4 hours
e)
6 hours
|
|
Anaya Patel answered |
B) 8 hours Explanation: Eating burgers will be considered as a work. So M1*H1*W2 = M2*H2*W1
20*2*200 = 10*H2*100
Solve H2 = 8
20*2*200 = 10*H2*100
Solve H2 = 8
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Quantitative Aptitude for Competitive Examinations
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