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20 men can complete 2/5th of work in 10 days working 6 hours each day. In how many days the remaining work will be completed by 20 women working 4 hours each day such that 4 women do as much work as is done by 2 men?
- a)20
- b)42
- c)35
- d)45
- e)None of these
Correct answer is option 'D'. Can you explain this answer?
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Verified Answer
20 men can complete 2/5th of work in 10 days working 6 hours each day....
D) 45
Explanation: 4 w = 2m, so 1w = 1/2 m And then 20 w = 10 m, so we have to find the number of days for 10 men to complete remaining work (1 – 2/5) = 3/5th .
M1*D1*H1*W2 = M2*D2*H2*W1
20*10*6*(3/5) = 10*D2*4*(2/5)
Solve, D2 = 45 days
Explanation: 4 w = 2m, so 1w = 1/2 m And then 20 w = 10 m, so we have to find the number of days for 10 men to complete remaining work (1 – 2/5) = 3/5th .
M1*D1*H1*W2 = M2*D2*H2*W1
20*10*6*(3/5) = 10*D2*4*(2/5)
Solve, D2 = 45 days
Most Upvoted Answer
20 men can complete 2/5th of work in 10 days working 6 hours each day....
Given:
- 20 men can complete 2/5th of work in 10 days working 6 hours each day.
- Work to be completed = 1 - 2/5 = 3/5th
- 4 women do as much work as is done by 2 men.
To find:
- In how many days the remaining work will be completed by 20 women working 4 hours each day.
Solution:
Step 1: Calculate the total work
- Let the total work be W
- 20 men can complete 2/5th of work in 10 days working 6 hours each day
- Therefore, the total hours worked by 20 men = 20 x 10 x 6 = 1200 hours
- Let the efficiency of each man be E
- Therefore, the total work done by 20 men = 20E x 1200
- It is given that 20 men can complete 2/5th of work
- Therefore, 20E x 1200 = 2/5 W
- Simplifying, E = W/12000
- Therefore, the total work = 12000E = 1000W
Step 2: Calculate the efficiency of each woman
- It is given that 4 women do as much work as is done by 2 men
- Let the efficiency of each woman be e
- Therefore, 4e = 2E
- Simplifying, e = E/2 = W/24000
Step 3: Calculate the number of days required
- Let the number of days required be d
- 20 women working 4 hours each day can complete the work
- Therefore, 20 x 4 x d x e = 3/5 W
- Substituting the value of e, we get:
- 20 x 4 x d x W/24000 = 3/5 W
- Simplifying, d = 45
Therefore, the remaining work will be completed by 20 women working 4 hours each day in 45 days.
Hence, option D is the correct answer.
- 20 men can complete 2/5th of work in 10 days working 6 hours each day.
- Work to be completed = 1 - 2/5 = 3/5th
- 4 women do as much work as is done by 2 men.
To find:
- In how many days the remaining work will be completed by 20 women working 4 hours each day.
Solution:
Step 1: Calculate the total work
- Let the total work be W
- 20 men can complete 2/5th of work in 10 days working 6 hours each day
- Therefore, the total hours worked by 20 men = 20 x 10 x 6 = 1200 hours
- Let the efficiency of each man be E
- Therefore, the total work done by 20 men = 20E x 1200
- It is given that 20 men can complete 2/5th of work
- Therefore, 20E x 1200 = 2/5 W
- Simplifying, E = W/12000
- Therefore, the total work = 12000E = 1000W
Step 2: Calculate the efficiency of each woman
- It is given that 4 women do as much work as is done by 2 men
- Let the efficiency of each woman be e
- Therefore, 4e = 2E
- Simplifying, e = E/2 = W/24000
Step 3: Calculate the number of days required
- Let the number of days required be d
- 20 women working 4 hours each day can complete the work
- Therefore, 20 x 4 x d x e = 3/5 W
- Substituting the value of e, we get:
- 20 x 4 x d x W/24000 = 3/5 W
- Simplifying, d = 45
Therefore, the remaining work will be completed by 20 women working 4 hours each day in 45 days.
Hence, option D is the correct answer.
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Community Answer
20 men can complete 2/5th of work in 10 days working 6 hours each day....
D) 45
Explanation: 4 w = 2m, so 1w = 1/2 m And then 20 w = 10 m, so we have to find the number of days for 10 men to complete remaining work (1 – 2/5) = 3/5th .
M1*D1*H1*W2 = M2*D2*H2*W1
20*10*6*(3/5) = 10*D2*4*(2/5)
Solve, D2 = 45 days
Explanation: 4 w = 2m, so 1w = 1/2 m And then 20 w = 10 m, so we have to find the number of days for 10 men to complete remaining work (1 – 2/5) = 3/5th .
M1*D1*H1*W2 = M2*D2*H2*W1
20*10*6*(3/5) = 10*D2*4*(2/5)
Solve, D2 = 45 days
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