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Test: Bohrs Model of Atom (April 28) - NEET MCQ


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10 Questions MCQ Test Daily Test for NEET Preparation - Test: Bohrs Model of Atom (April 28)

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Test: Bohrs Model of Atom (April 28) - Question 1

Which of the following is correct?

Detailed Solution for Test: Bohrs Model of Atom (April 28) - Question 1

Because isotones means the same number of neutron, So, from the question, option c is right, number of neutron in k is,39-19= 20,and,the number of neutron in ca is also 40-20=20 so it is isotones. 

Test: Bohrs Model of Atom (April 28) - Question 2

‘Hartree’ is the atomic unit of energy and is equal to

Detailed Solution for Test: Bohrs Model of Atom (April 28) - Question 2

The potential energy of an electron in the first Bohr’s orbit in the H-atom is

This energy is defined as an atomic unit of energy called HARTREE.

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Test: Bohrs Model of Atom (April 28) - Question 3

Wave number of a spectral line for a given transition is x cm-1 for He+, then its value for Be3+ (isoelectronic of He+)for the same transition is

Detailed Solution for Test: Bohrs Model of Atom (April 28) - Question 3



Test: Bohrs Model of Atom (April 28) - Question 4

Which of the following electronic transitions requires that the greatest quantity of energy be absorbed by a hydrogen atom ?

Detailed Solution for Test: Bohrs Model of Atom (April 28) - Question 4







Therefore, electronic transition (a) requires greatest quantity of energy.

Test: Bohrs Model of Atom (April 28) - Question 5

An electron in H-atom in its ground state absorbs 1.5 times as much as energy as the minimum required for its escape from the atom

Q.

Thus, kinetic energy given to the emitted electron is

Detailed Solution for Test: Bohrs Model of Atom (April 28) - Question 5

E1 = Energy of H-atom in the ground state = 13.6 eV 

Energy absorbed = (13.6 x 1.5) = 20.4 eV
E2 = Energy of the excited state
= 13.6+ 20.4= 34.0 eV
ΔE = KE = (E2 - E1)
= 34.0 - 13.6 = 20.4 eV

Test: Bohrs Model of Atom (April 28) - Question 6

Ionisation energy of He+ is 19.6x10-18 J atom -1. The energy of the first stationary state (n = 1)of Li2+ is

Detailed Solution for Test: Bohrs Model of Atom (April 28) - Question 6

Ionisation energy = - Energy of the electron






Test: Bohrs Model of Atom (April 28) - Question 7

The kinetic energy of an electron in the second Bohr orbit of a hydrogen atom is (a0 is Bohr radius)

[AIEEE 2012]

Detailed Solution for Test: Bohrs Model of Atom (April 28) - Question 7


Also, angular momentum is quantised








Test: Bohrs Model of Atom (April 28) - Question 8

Energy of the electron in nth orbit is given by E   Wavelength of light required to excite an electron in an H-atom from level n = 1 to n = 2 will be (h = 6.62 x 10-34 J s ; c = 3.0 x 108ms -1)

[AIEEE 2012]

Detailed Solution for Test: Bohrs Model of Atom (April 28) - Question 8

For H - atom , Z = 1




Test: Bohrs Model of Atom (April 28) - Question 9

The potential energy of an electron in the second Bohr's orbit of the he±

Detailed Solution for Test: Bohrs Model of Atom (April 28) - Question 9

 

Test: Bohrs Model of Atom (April 28) - Question 10

In Lyman series, shortest wavelength of H-atom appears at x m, then longest wavelength in Balmer series of He+ appear at

Detailed Solution for Test: Bohrs Model of Atom (April 28) - Question 10

For the spectral line in H -atom and H -like species (one electron)

For Lyman series
For shortest wavelength (maximum wave number) n2 → ∞



For longest wave length (minimum wave number), n2 = (n1, + 1).
For Balmer series, n1 = 2


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