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Test: Pressure & Its Measurements, Reciprocating Pumps, Flow Around Submerged Bodies - Drag & Lift - 2 - Mechanical Engineering MCQ


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30 Questions MCQ Test GATE Mechanical (ME) Mock Test Series 2025 - Test: Pressure & Its Measurements, Reciprocating Pumps, Flow Around Submerged Bodies - Drag & Lift - 2

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Test: Pressure & Its Measurements, Reciprocating Pumps, Flow Around Submerged Bodies - Drag & Lift - 2 - Question 1

In an open U tube containing mercury, kerosene of specificgravity 0·8 is poured into one of its limbs so that the length ofcolumn of kerosene is about 40 cm. The level of mercury columnin that limb is lowered approximately by how much? 

Detailed Solution for Test: Pressure & Its Measurements, Reciprocating Pumps, Flow Around Submerged Bodies - Drag & Lift - 2 - Question 1

Ans. (b) 0.8 x 40 = 13.6 x (2h) ⇒ h = 1.2 cm

Test: Pressure & Its Measurements, Reciprocating Pumps, Flow Around Submerged Bodies - Drag & Lift - 2 - Question 2

The standard atmospheric pressure is 762 mm of Hg. At aspecific location, the barometer reads 700 mm of Hg. At this place, what does at absolute pressure of 380 mm of Hg correspond to?  

Detailed Solution for Test: Pressure & Its Measurements, Reciprocating Pumps, Flow Around Submerged Bodies - Drag & Lift - 2 - Question 2

Ans. (a)

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Test: Pressure & Its Measurements, Reciprocating Pumps, Flow Around Submerged Bodies - Drag & Lift - 2 - Question 3

Assertion (A): U-tube manometer connected to a venturimeterfitted in a pipeline can measure the velocity through the pipe.
Reason (R): U-tube manometer directly measures dynamic and static heads.

Detailed Solution for Test: Pressure & Its Measurements, Reciprocating Pumps, Flow Around Submerged Bodies - Drag & Lift - 2 - Question 3

Ans. (a)

Test: Pressure & Its Measurements, Reciprocating Pumps, Flow Around Submerged Bodies - Drag & Lift - 2 - Question 4

When can a piezometer be not used for pressure measurement inpipes?

Detailed Solution for Test: Pressure & Its Measurements, Reciprocating Pumps, Flow Around Submerged Bodies - Drag & Lift - 2 - Question 4

Ans. (c)

Test: Pressure & Its Measurements, Reciprocating Pumps, Flow Around Submerged Bodies - Drag & Lift - 2 - Question 5

Which of following are the beneficial effects of air vessel fitted to delivery side of a reciprocating pump?  
1. Constant rate of discharge can be ensured
2. Power consumption can be reduced
3. Discharge can be increased
4. Constant velocity of the piston can be ensured
Select the correct answer using the codes given below:
Codes:

Detailed Solution for Test: Pressure & Its Measurements, Reciprocating Pumps, Flow Around Submerged Bodies - Drag & Lift - 2 - Question 5

Ans. (b) The function of air-vessel are:
1. On suction side
i) To reduce accelerating head. This will reduced the total vacuum head,
reducing the possibility of separation and saving in power required for supplying accelerating head.
ii) Pump can be run on higher speed.
iii) Length of suction pipe below the air vessel can be increased.
2. On delivery side
i) To reduce the accelerating head and affecting in large amount of power
consumed in supplying the accelerating head.
ii) A uniform rate of discharge is ensured.

Test: Pressure & Its Measurements, Reciprocating Pumps, Flow Around Submerged Bodies - Drag & Lift - 2 - Question 6

Why is an air vessel used in a reciprocating pump? 

Detailed Solution for Test: Pressure & Its Measurements, Reciprocating Pumps, Flow Around Submerged Bodies - Drag & Lift - 2 - Question 6

Ans. (a) An air vessel is a closed chamber containing compressed air in the upper
part and liquid being pumped in the lower part. The air vessels are used:
(i) To get continuous supply of liquid at a uniform rate,
(ii) To save the power required to drive the pump and
(iii) To run the pump at a much higher speed without any danger of separation.

Test: Pressure & Its Measurements, Reciprocating Pumps, Flow Around Submerged Bodies - Drag & Lift - 2 - Question 7

Consider the following pumps:  
1. Centrifugal pump, single-stage
2. Centrifugal pump, multi-stage
3. Reciprocating pump
4. Jet pump.
The pump (s) which can be used to lift water through a suction head of12 m from a well would include

Detailed Solution for Test: Pressure & Its Measurements, Reciprocating Pumps, Flow Around Submerged Bodies - Drag & Lift - 2 - Question 7

Ans. (c) Since suction head is 12 m, i.e. more than atmospheric pressure, only jet
pump can be used to lift water under such a situation.

Test: Pressure & Its Measurements, Reciprocating Pumps, Flow Around Submerged Bodies - Drag & Lift - 2 - Question 8

Which one of the following is correct? A turbine pump is basically a centrifugal pump equipped additionally with

Detailed Solution for Test: Pressure & Its Measurements, Reciprocating Pumps, Flow Around Submerged Bodies - Drag & Lift - 2 - Question 8

Ans. (b) A turbine pump in basically a centrifugal pump equipped additionally
with vaned diffusion casing.

Test: Pressure & Its Measurements, Reciprocating Pumps, Flow Around Submerged Bodies - Drag & Lift - 2 - Question 9

The drag force exerted by a fluid on a body immersed in the fluid is due to:  

Detailed Solution for Test: Pressure & Its Measurements, Reciprocating Pumps, Flow Around Submerged Bodies - Drag & Lift - 2 - Question 9

Ans. (a) Total drag on a body = pressure drag + friction drag

Test: Pressure & Its Measurements, Reciprocating Pumps, Flow Around Submerged Bodies - Drag & Lift - 2 - Question 10

When ever a plate is submerged at an angle with the direction of flow of liquid, it is subjected to some pressure. What is the component of this pressure in the direction of flow of liquid, known as?  

Detailed Solution for Test: Pressure & Its Measurements, Reciprocating Pumps, Flow Around Submerged Bodies - Drag & Lift - 2 - Question 10

Ans. (c)

Test: Pressure & Its Measurements, Reciprocating Pumps, Flow Around Submerged Bodies - Drag & Lift - 2 - Question 11

Which one of the following is correct? 
In the flow past bluff bodies

Detailed Solution for Test: Pressure & Its Measurements, Reciprocating Pumps, Flow Around Submerged Bodies - Drag & Lift - 2 - Question 11

Ans. (c) In the flow past bluff bodies the pressure drag occupies the major part of
total drag. During flow past bluff-bodies, the desired pressure recovery does not take place in a separated flow and the situation gives rise to pressure drag or form drag.

Test: Pressure & Its Measurements, Reciprocating Pumps, Flow Around Submerged Bodies - Drag & Lift - 2 - Question 12

Match List-I with List-II and select the correct answer using the codes given below the lists: 

 



Detailed Solution for Test: Pressure & Its Measurements, Reciprocating Pumps, Flow Around Submerged Bodies - Drag & Lift - 2 - Question 12

Ans. (c)

Test: Pressure & Its Measurements, Reciprocating Pumps, Flow Around Submerged Bodies - Drag & Lift - 2 - Question 13

The parameters for ideal fluid flow around a rotating circular cylindercan be obtained by superposition of some elementary flows. Which one of the following sets would describe the flow around a rotating circular cylinder? 

Detailed Solution for Test: Pressure & Its Measurements, Reciprocating Pumps, Flow Around Submerged Bodies - Drag & Lift - 2 - Question 13

Ans. (a)

Test: Pressure & Its Measurements, Reciprocating Pumps, Flow Around Submerged Bodies - Drag & Lift - 2 - Question 14

Match List-I (Types of flow) with List-II (Basic ideal flows) and select the correct answer:


Detailed Solution for Test: Pressure & Its Measurements, Reciprocating Pumps, Flow Around Submerged Bodies - Drag & Lift - 2 - Question 14

Ans. (d)

Test: Pressure & Its Measurements, Reciprocating Pumps, Flow Around Submerged Bodies - Drag & Lift - 2 - Question 15

Which one of the following is true of flow around a submerged body?  

Detailed Solution for Test: Pressure & Its Measurements, Reciprocating Pumps, Flow Around Submerged Bodies - Drag & Lift - 2 - Question 15

Ans. (d) Profile drag comprises two components. Surface friction drag and normal pressure drag (form drag).

Test: Pressure & Its Measurements, Reciprocating Pumps, Flow Around Submerged Bodies - Drag & Lift - 2 - Question 16

Assertion (A): Aircraft wings are slotted to control separation of boundary layer especially at large angles of attack.  
Reason (R): This helps to increase the lift and the aircraft can take off from, and land on, short runways.

Detailed Solution for Test: Pressure & Its Measurements, Reciprocating Pumps, Flow Around Submerged Bodies - Drag & Lift - 2 - Question 16

Ans. (c)

Test: Pressure & Its Measurements, Reciprocating Pumps, Flow Around Submerged Bodies - Drag & Lift - 2 - Question 17

Assertion (A): In flow over immersed bodies. 
Reason(R): Drag can be created without life. Life cannot be created without drag.

Detailed Solution for Test: Pressure & Its Measurements, Reciprocating Pumps, Flow Around Submerged Bodies - Drag & Lift - 2 - Question 17

Ans. (b). Both the statements of A and R are true, but R is not necessarily the explanation for A.

Test: Pressure & Its Measurements, Reciprocating Pumps, Flow Around Submerged Bodies - Drag & Lift - 2 - Question 18

Dead weight gauge is used for the measurement of pressure of

Test: Pressure & Its Measurements, Reciprocating Pumps, Flow Around Submerged Bodies - Drag & Lift - 2 - Question 19

For solid spheres falling vertically downwards under gravity in aviscous fluid, the terminal velocity, V1 varies with diameter 'D' of thesphere as  

Detailed Solution for Test: Pressure & Its Measurements, Reciprocating Pumps, Flow Around Submerged Bodies - Drag & Lift - 2 - Question 19

Ans. (b) Terminal velocity V1 ∞Dfor all diameters. Stokes’ formula forms the
basis for determination of viscosity of oils which consists of allowing a sphere of known diameter to fail freely in the oil. After initial acceleration. The sphere attains a constant velocity known as Terminal Velocity which is reached when the external drag on the surface and buoyancy, both acting upwards and in opposite to the motions, become equal to the downward force due to gravity.

Test: Pressure & Its Measurements, Reciprocating Pumps, Flow Around Submerged Bodies - Drag & Lift - 2 - Question 20

A cylindrical object is rotated with constant angular velocity about its symmetry axis in auniform flow field of an ideal fluid producing stream lines as shown in the figure given above.At which point(s), is the pressure on the cylinder surface maximum? 

Detailed Solution for Test: Pressure & Its Measurements, Reciprocating Pumps, Flow Around Submerged Bodies - Drag & Lift - 2 - Question 20

Ans. (d)

Test: Pressure & Its Measurements, Reciprocating Pumps, Flow Around Submerged Bodies - Drag & Lift - 2 - Question 21

Flow over a half body is studied by utilising a free stream velocity of 5m/s superimposed on a source at the origin. The body has a maximumwidth of 2 m. The co-ordinates of the stagnation point are:  

Detailed Solution for Test: Pressure & Its Measurements, Reciprocating Pumps, Flow Around Submerged Bodies - Drag & Lift - 2 - Question 21



Test: Pressure & Its Measurements, Reciprocating Pumps, Flow Around Submerged Bodies - Drag & Lift - 2 - Question 22

In given figure, if the pressure of gas in bulb A is 50 cm Hg vacuum and Patm = 76 cm Hg, then height of column H is equal to     

Detailed Solution for Test: Pressure & Its Measurements, Reciprocating Pumps, Flow Around Submerged Bodies - Drag & Lift - 2 - Question 22

Ans. (b) If the pressure of gas in bulb A is atm. H = zero.
If we create a pressure of gas in bulb A is 1 cm Hg vacuum then the vacuum will lift 1 cm liquid, H = 1 cm.
If we create a pressure of gas in bulb A is 2 cm Hg vacuum then the vacuum will lift 2 cm liquid, H = 2 cm.
If we create a pressure of gas in bulb A is 50 cm Hg vacuum then the vacuum will lift 50 cm liquid, H = 50 cm.

Test: Pressure & Its Measurements, Reciprocating Pumps, Flow Around Submerged Bodies - Drag & Lift - 2 - Question 23

The pressure gauges Gand G2 installed on the system show pressures of PG1 = 5.00 bar and PG2 = 1.00 bar. The value of unknown pressure P is? (Atmospheric pressure1.01 bars) 

Detailed Solution for Test: Pressure & Its Measurements, Reciprocating Pumps, Flow Around Submerged Bodies - Drag & Lift - 2 - Question 23

Ans. (d) Pressure in the right cell = PG2 + Atmospheric pressure = 1.01 + 1.0 = 2.01 bar
Therefore P = PG1 + Pressure on right cell = 5 + 2.01 = 7.01 bar

Test: Pressure & Its Measurements, Reciprocating Pumps, Flow Around Submerged Bodies - Drag & Lift - 2 - Question 24

Refer to Figure, the absolute pressure ofgas A in the bulb is:  

Detailed Solution for Test: Pressure & Its Measurements, Reciprocating Pumps, Flow Around Submerged Bodies - Drag & Lift - 2 - Question 24

Ans. (a) Use ‘hs’ formula;

Test: Pressure & Its Measurements, Reciprocating Pumps, Flow Around Submerged Bodies - Drag & Lift - 2 - Question 25

Hydrostatic law of pressure is given as 

Detailed Solution for Test: Pressure & Its Measurements, Reciprocating Pumps, Flow Around Submerged Bodies - Drag & Lift - 2 - Question 25

Ans. (a)

Test: Pressure & Its Measurements, Reciprocating Pumps, Flow Around Submerged Bodies - Drag & Lift - 2 - Question 26

A mercury-water manometer has a gauge difference of 500 mm(difference in elevation of menisci). What will be the difference in pressure? 

Detailed Solution for Test: Pressure & Its Measurements, Reciprocating Pumps, Flow Around Submerged Bodies - Drag & Lift - 2 - Question 26

Ans. (b)

m of light fluid or h = 0.5

= 6.3m of water.

Test: Pressure & Its Measurements, Reciprocating Pumps, Flow Around Submerged Bodies - Drag & Lift - 2 - Question 27

Pressure drop of flowing through a pipe (density 1000 kg/m3) between two points is measured by using a vertical U-tube manometer. Manometer uses a liquid with density 2000 kg/m3.The difference in height of manometric liquid in the two limbs of the manometer is observed to be 10 cm. The pressure drop between the two points is: 

Detailed Solution for Test: Pressure & Its Measurements, Reciprocating Pumps, Flow Around Submerged Bodies - Drag & Lift - 2 - Question 27

Ans. (b)

of light fluid or h = 0.1

= 0.1m of light fluid

The pressure dropbetween the two points is = hρg = 0.1 x 9.81 x 1000 = 981N/m2

Test: Pressure & Its Measurements, Reciprocating Pumps, Flow Around Submerged Bodies - Drag & Lift - 2 - Question 28

Differential pressure head measured by mercury oil differential manometer (specific gravity of oil is 0.9) equivalent to a 600 mm difference of mercury levels will nearly be:  

Detailed Solution for Test: Pressure & Its Measurements, Reciprocating Pumps, Flow Around Submerged Bodies - Drag & Lift - 2 - Question 28

Ans. (d)

m of light fluid or h = 0.600

= 8.47m of oil

Test: Pressure & Its Measurements, Reciprocating Pumps, Flow Around Submerged Bodies - Drag & Lift - 2 - Question 29

Pressure drop of water flowing through a pipe (density 1000kg/m3) between two points is measured by using a vertical Utube manometer. Manometer uses a liquid with density 2000 kg /m3. The difference in height of manometric liquid in the two limbs of the manometer is observed to be 10 cm. The pressure drop between the two points is: 

Detailed Solution for Test: Pressure & Its Measurements, Reciprocating Pumps, Flow Around Submerged Bodies - Drag & Lift - 2 - Question 29

Ans. (b)

Test: Pressure & Its Measurements, Reciprocating Pumps, Flow Around Submerged Bodies - Drag & Lift - 2 - Question 30

A U-tube manometer is connected to a pipeline conveying water as shown in the Figure. The pressure head of water in the pipeline is    

Detailed Solution for Test: Pressure & Its Measurements, Reciprocating Pumps, Flow Around Submerged Bodies - Drag & Lift - 2 - Question 30

Ans. (c) Use ‘hs’ formula;

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