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Test: Combination of Capacitors & Energy Stored in a Capacitor (November 20) - NEET MCQ


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10 Questions MCQ Test Daily Test for NEET Preparation - Test: Combination of Capacitors & Energy Stored in a Capacitor (November 20)

Test: Combination of Capacitors & Energy Stored in a Capacitor (November 20) for NEET 2024 is part of Daily Test for NEET Preparation preparation. The Test: Combination of Capacitors & Energy Stored in a Capacitor (November 20) questions and answers have been prepared according to the NEET exam syllabus.The Test: Combination of Capacitors & Energy Stored in a Capacitor (November 20) MCQs are made for NEET 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Combination of Capacitors & Energy Stored in a Capacitor (November 20) below.
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Test: Combination of Capacitors & Energy Stored in a Capacitor (November 20) - Question 1
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Here is a combination of three identical capacitors. If resultant capacitance is 1 μƒ, calculate capacitance of each capacitor.

Detailed Solution for Test: Combination of Capacitors & Energy Stored in a Capacitor (November 20) - Question 1

Combination of Capacitors in Series
C(effective) = C/3 = 1

Test: Combination of Capacitors & Energy Stored in a Capacitor (November 20) - Question 2
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If two spheres of different radii have equal charge, then the potential will be

Detailed Solution for Test: Combination of Capacitors & Energy Stored in a Capacitor (November 20) - Question 2

When equal charges are given to two spheres of different radii, the potential will be more or the smaller sphere as per the equation, Potential = Charge / Radius.
Since potential is inversely proportional to radius, the smaller radius will have higher potential and vice versa.

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Test: Combination of Capacitors & Energy Stored in a Capacitor (November 20) - Question 3
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Three different capacitors are connected in series, then:

Detailed Solution for Test: Combination of Capacitors & Energy Stored in a Capacitor (November 20) - Question 3

C = Q/V
series connection splits the battery potential, hence....
V = V1 + V2
V1 = Q/C1 & V2 = Q/C2
Therefore, both have equal charge
 

Test: Combination of Capacitors & Energy Stored in a Capacitor (November 20) - Question 4
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There are three capacitors with equal capacitance. In series combination, they have a net capacitance of C1 and in parallel combination, a net capacitance of C2.What will be the value of C1 C2?​
Detailed Solution for Test: Combination of Capacitors & Energy Stored in a Capacitor (November 20) - Question 4

For series combination,
1/C1=(1/C)+(1/C)+(1/C) [ Since all capacitors have equal capacitances]=3/C Or
C1=C/3−−−(i)
For parallel combination,
C2=C+C+C=3C−−−(ii)
Now,C1/C2=(C/3)/3C=(C/3)×(1/3C)=1/9

Test: Combination of Capacitors & Energy Stored in a Capacitor (November 20) - Question 5
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A parallel plate capacitor is connected across a 2V battery and charged. The battery is then disconnected and a glass slab is introduced between plates. Which of the following pairs of quantities decreases?
Detailed Solution for Test: Combination of Capacitors & Energy Stored in a Capacitor (November 20) - Question 5

When battery is disconnected, charge remains constant. On introducing glass slab, capacity increases, Potential difference and energy stored decreases.

Test: Combination of Capacitors & Energy Stored in a Capacitor (November 20) - Question 6
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A 16 pF capacitor is connected to 70 V supply. The amount of electric energy stored in the capacitor is
Detailed Solution for Test: Combination of Capacitors & Energy Stored in a Capacitor (November 20) - Question 6

Here C = 16pF = 16 × 10−12FV = 80V

Test: Combination of Capacitors & Energy Stored in a Capacitor (November 20) - Question 7
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A parallel plate capacitor has a uniform electric field E in the space between the plates. If the distance between the plates is d and area of each plate is A, the energy stored in the capacitor is
Detailed Solution for Test: Combination of Capacitors & Energy Stored in a Capacitor (November 20) - Question 7

Capacitance of a parallel plate capacitor is C = ε0A/d ………(i)
Potential difference between the plates is
V = Ed
The energy stored in the capacitor is

Test: Combination of Capacitors & Energy Stored in a Capacitor (November 20) - Question 8
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Two condensers, one of capacity C and other of capacity C/2 are connected to a V-volt battery, as shown in the figure. The work done in charging fully both the condensers is
Detailed Solution for Test: Combination of Capacitors & Energy Stored in a Capacitor (November 20) - Question 8

As the capacitors are connected in parallel, therefore potential difference across both the condensors remains the same.


Work done in charging fully both the condensors is given by

Test: Combination of Capacitors & Energy Stored in a Capacitor (November 20) - Question 9
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Energy stored in a capacitor and dissipated during charging a capacitor bear a ratio.
Detailed Solution for Test: Combination of Capacitors & Energy Stored in a Capacitor (November 20) - Question 9

Half of the energy is dissipated during charging a capacitor.

Test: Combination of Capacitors & Energy Stored in a Capacitor (November 20) - Question 10
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A series combination of n1, capacitors, each of value C1, is charged by a source of potential difference 4V. When another parallel combination of n2, capacitors, each of value C2, is charged by a source of potential difference V, it has the same (total) energy stored in it, as the first combination has. The value of C2, in terms of C1 is then
Detailed Solution for Test: Combination of Capacitors & Energy Stored in a Capacitor (November 20) - Question 10


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