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Test: Physics Minor Mock Test- 2 (March 20) - NEET MCQ


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30 Questions MCQ Test Daily Test for NEET Preparation - Test: Physics Minor Mock Test- 2 (March 20)

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Test: Physics Minor Mock Test- 2 (March 20) - Question 1

The kinetic energy of one mole of an ideal gas is E=3/2 RT. Then Cρ will be

Detailed Solution for Test: Physics Minor Mock Test- 2 (March 20) - Question 1

We know that,
Cp=cv+R
E=3Rt/2
also,
E=Cv
cp=R+3RT/2
=5/2 RT
=2.5R

Test: Physics Minor Mock Test- 2 (March 20) - Question 2

An open-ended U-tube of uniform cross-sectional area contains water (density 1.0 gram/centimeter3) standing initially 20 centimeters from the bottom in each arm. An immiscible liquid of density 4.0 grams/centimeter3 is added to one arm until a layer 5 centimeters high forms, as shown in the figure above. What is the ratio h2/h1 of the heights of the liquid in the two arms ?

                   

Detailed Solution for Test: Physics Minor Mock Test- 2 (March 20) - Question 2

5 × 4 × 10 + (h1 - 5) × 10 = h2 × 1 × 10
200 + 10h1 – 50 = 10h2
10h2 - 10h1 = 150
h2 - h1 = 15
h2 + h1 = 20 + 20 + 5 = 45
2h2 = 60
h2 = 30
h1 = 15
h2/h1 = 30/15
h2/h1 = 2/1

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Test: Physics Minor Mock Test- 2 (March 20) - Question 3

If the acceleration due to gravity inside the earth is to be kept constant, then the relation between the density d and the distance r from the centre of earth will be -

Detailed Solution for Test: Physics Minor Mock Test- 2 (March 20) - Question 3

If M is the mass of the Earth and m is the mass of a sphere of radius r and you want the force of gravity to be the same at both the surface of the sphere and the surface of the earth then mg = Mg and m = M. This means that the mass of the sphere would have to be the same as the mass of the Earth no matter what r is. This is impossible since a sub-sphere cannot have the same mass as its parent.
For a sphere of radius r to have force g at its surface, d = (De *Re)/r where De is the density of the entire Earth and Re is the radius of the Earth, d is the density of the sphere of radius r. So there is a radius and a density which will produce a gravitational force of g for any d, r >0 but one cannot be a subset of another.

= d μ 1/r

Test: Physics Minor Mock Test- 2 (March 20) - Question 4

The perfect gas equation is PV = nRT where n is the

Detailed Solution for Test: Physics Minor Mock Test- 2 (March 20) - Question 4

n is the number of moles.

Test: Physics Minor Mock Test- 2 (March 20) - Question 5

The height above surface of earth where the value of gravitational acceleration is one fourth of that at surface, will be

Test: Physics Minor Mock Test- 2 (March 20) - Question 6

A light semi cylindrical gate of radius R is piovted at its mid point O, of the diameter as shown in the figure holding liquid of density r. The force F required to prevent the rotation of the gate is equal to

Detailed Solution for Test: Physics Minor Mock Test- 2 (March 20) - Question 6

The force is normal to the surface of the cylinder and hence will pass through the centre. And since the forces pass through the centre it means that the net torque will be zero.

Test: Physics Minor Mock Test- 2 (March 20) - Question 7

What diameter should a 10-m-long steel wire have if we do not want it to stretch more than 0.5 cm under a tension of 940 N? Take Young's modulus of steel as 20 × 1010 Pa

Detailed Solution for Test: Physics Minor Mock Test- 2 (March 20) - Question 7

Y=F x l/A x Δ l
Δ l=0.5cm=0.5x10-2m, l=10M, F=940N
Y=20x1010pa
20x1010=940x10/πr2x0.5x10-10
πr2=94x100/5x10-3x2x1011=94x102/10x108
r2=94/π x 10-7 =2.99 x 10-6
r2 ≅3x10-6
r=1.13x10-10 m
diameter=2r=3.6mm

Test: Physics Minor Mock Test- 2 (March 20) - Question 8

A steel rod 2.0 m long has a cross-sectional area of 0.30 cm2. It is hung by one end from a support, and a 550-kg milling machine is hung from its other end. Determine the elongation. Take Young's modulus of steel as 20 × 1010 Pa

Detailed Solution for Test: Physics Minor Mock Test- 2 (March 20) - Question 8

σ=Stress and ε=strain
σ=F/A= (550kg) × (9.81m/s2)3×10-5m2/=0.18GPA
ε=Δl/l0=σ/Υ​=0.18×109/200×109​=9×10-4
Δl=εl0= (9×10-4) (2m) = 0.0018m=1.8mm

Test: Physics Minor Mock Test- 2 (March 20) - Question 9

Which of the given relation is true for molar heat capacity of a substance?

Test: Physics Minor Mock Test- 2 (March 20) - Question 10

Two identical rectangular strips, one of copper and the other of steel, are riveted as shown to form a bi-metal strip. On heating, the bi-metal strip will

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Detailed Solution for Test: Physics Minor Mock Test- 2 (March 20) - Question 10

On heating, the copper strip will suffer greater elongation and hence the bimetal strip will bend with the steel strip on the concave side. 

[Bimetal strips are widely used in thermal switching applications such as automatic electric iron].

Test: Physics Minor Mock Test- 2 (March 20) - Question 11

Value of gas constant, R for one mole of a gas is independent of the

Detailed Solution for Test: Physics Minor Mock Test- 2 (March 20) - Question 11

We know that PV=nRT also PM=dRT
So in the equation The value of R depends on P , V , n , T , d , M
except atomicity 
 so the ans is A

Test: Physics Minor Mock Test- 2 (March 20) - Question 12

On doubling the distance between two masses the gravitational force between them will -

Test: Physics Minor Mock Test- 2 (March 20) - Question 13

A piece of copper having a rectangular cross-section of 15.2 mm × 19.1 mm is pulled in tension with 44,500 N force, producing only elastic deformation. Calculate the resulting strain? Take Young's modulus of copper as 42 × 109Pa

Detailed Solution for Test: Physics Minor Mock Test- 2 (March 20) - Question 13

Given Data,
Length of the piece of copper = l = 19.1 mm = 19.1 × 10-3m
Breadth of the piece of copper = b = 15.2 mm = 15.2× 10-3m
Tension force applied on the piece of cooper, F = 44500N
Area of rectangular cross section of copper piece,
Area = l× b
⇒ Area = (19.1 × 10-3m) × (15.2× 10-3m)
⇒ Area = 2.9 × 10-4 m2
Modulus of elasticity of copper from standard list, η = 42× 109 N/m2
By definition, Modulus of elasticity, η = stress/strain

⇒ Strain = F/Aη

⇒ Strain = 3.65 × 10-3
Hence, the resulting strain is 3.65 × 10-3

Test: Physics Minor Mock Test- 2 (March 20) - Question 14

To complete one revolution around Earth, communication satellites take

Detailed Solution for Test: Physics Minor Mock Test- 2 (March 20) - Question 14

A communications satellite is in a GEO (geostationary equatorial orbit) with a period of 24 hours. The spin rate ωs about its axis of symmetry is 1 revolution per minute, and the moment of inertia about the spin axis is 550 kg · m2.

Test: Physics Minor Mock Test- 2 (March 20) - Question 15

 A body is just floating in a liquid (their densities are equal) If the body is slightly pressed down and released it will -

Detailed Solution for Test: Physics Minor Mock Test- 2 (March 20) - Question 15

The body will sink to the bottom as it gains a downward velocity and has no force to bring it back up. The weight becomes greater than upwards thrust.
 

As body is just floating, its density is same as that of the liquid.
If pressed below, it will gain momentum downwards, and continue to sink till bottom.
When the body is slightly pressed, the contraction in volume decreases upthrust, so weight becomes greater than upthrust, body moves down. The upthrust further decreases, since more and more contraction occurs as the body moves down. The body thus, sinks to the bottom.

Test: Physics Minor Mock Test- 2 (March 20) - Question 16

According to kinetic theory of gases, 0K is that temperature at which for an ideal gas

Detailed Solution for Test: Physics Minor Mock Test- 2 (March 20) - Question 16

According to kinetic theory of gases, 0K is that temperature at which for an ideal gas the internal energy is zero because at 0K nearly all molecular motion stops.

Test: Physics Minor Mock Test- 2 (March 20) - Question 17

A steel tape is calibrated at 20° C. A piece of wood is being measured by steel tape at 10°C and reading is 30 cm on the tape. The real length of the wood is:

Detailed Solution for Test: Physics Minor Mock Test- 2 (March 20) - Question 17

When heated the length between adjacent markings increases. Hence the actual length will be less than
30 cm.

Test: Physics Minor Mock Test- 2 (March 20) - Question 18

Elasticity is the property of a body, by virtue of which

Detailed Solution for Test: Physics Minor Mock Test- 2 (March 20) - Question 18

Explanation:When external force is applied on the solid bodies, the solid bodies get deformed. The atoms or molecules are displaced from their equilibrium positions causing a change in the interatomic ( or intermolicular ) distances. When the deforming foce is removed, the interatomic forces tend to drive them back to their original postions. Thus the body regains its original shape and size.

Test: Physics Minor Mock Test- 2 (March 20) - Question 19

The temperature for which the reading on Celsius and Fahrenheit scales are identical is

Detailed Solution for Test: Physics Minor Mock Test- 2 (March 20) - Question 19

The Celsius and Fahrenheit are two important temperature scales. The Fahrenheit scale is used primarily in the United States, while Celsius is used throughout the world. The two scales have different zero points and the Celsius degree is bigger than the Fahrenheit one. There is one point on the Fahrenheit and Celsius scales where the temperatures in degrees are equal. This is -40 degree C and -40 degree F.

Test: Physics Minor Mock Test- 2 (March 20) - Question 20

The area of cross-section of the wider tube shown in figure is 800 cm2. If a mass of 12 kg is placed on the massless piston, the difference in heights h in the level of water in the two tubes is :

                         

Detailed Solution for Test: Physics Minor Mock Test- 2 (March 20) - Question 20

h × ρ × 10 = 120/800 × 10-4 
h × ρ = 12/8 × 10
h × ρ = 150m
h × 1000 = 150m
h = 15cm

Test: Physics Minor Mock Test- 2 (March 20) - Question 21

A U-tube having horizontal arm of length 20 cm, has uniform cross-sectional area = 1 cm2. It is filled with water of volume 60 cc. What volume of a liquid of density 4 g/cc should be poured from one side into the U-tube so that no water is left in the horizontal arm of the tube?

Detailed Solution for Test: Physics Minor Mock Test- 2 (March 20) - Question 21

Test: Physics Minor Mock Test- 2 (March 20) - Question 22

At what altitude will the acceleration due to gravity be 25% of that at the earth's surface (given radius of earth is R) ?

Detailed Solution for Test: Physics Minor Mock Test- 2 (March 20) - Question 22

Force on the body placed on Earth's surface is
F = GMm/R2
But, F=mg hence,
mg = GMm​/R2
where, variables have their usual meanings.
gR= GM
Now, force on the body at geo-potential height say h (altitude) where the acceleration due to gravity is 25% of that at the earth's surface i.e.
25//100g ​= g/4​
Hence, we can write
g/4​ = GM/(R+h)2

g/4​ = gR2/(R+h)2

(R+h)= 4R2

Taking roots for both sides we get
R+h = 2R
h = R

Test: Physics Minor Mock Test- 2 (March 20) - Question 23

When water is heated from 0° C to 20° C its volume:

Detailed Solution for Test: Physics Minor Mock Test- 2 (March 20) - Question 23

When water is heated from 0°C, its volume decreases because its density increases and you can see this effect upto 4°C. Since the density of ice is maximum at 4°C, afterwards as the density decreases the volume increases. The main reason for this is hydrogen bond in ice gets cleaved due to the melting of ice.

Test: Physics Minor Mock Test- 2 (March 20) - Question 24

A perfectly rigid body is one

Detailed Solution for Test: Physics Minor Mock Test- 2 (March 20) - Question 24

Explanation:A perfectly rigid body is hypothetical in nature but for some phenomena ( in rotational bodies ) we assume bodies are perfectly rigid i.e. the intermolecular forces are always in equilibrium irrespective of the external forces due to which their shape and size are constant.

Test: Physics Minor Mock Test- 2 (March 20) - Question 25

Relationship for converting the Fahrenheit and Celsius scales is

Detailed Solution for Test: Physics Minor Mock Test- 2 (March 20) - Question 25

Test: Physics Minor Mock Test- 2 (March 20) - Question 26

The importance of the elastic behavior of materials is

Detailed Solution for Test: Physics Minor Mock Test- 2 (March 20) - Question 26

Explanation:More the elastic a material is , more it has the property to regain its original position which is required in construction works.

Test: Physics Minor Mock Test- 2 (March 20) - Question 27

Pressure exerted by an ideal gas molecule is given by the expression

Test: Physics Minor Mock Test- 2 (March 20) - Question 28

Equal masses of three liquids of specific heats C1, C2 and C3 at temperatures t1, tand t3 respectively are mixed. If there is no change of state, the temperature of the mixture is

Detailed Solution for Test: Physics Minor Mock Test- 2 (March 20) - Question 28

For the composite system, energy conservation yields no net energy flow in or out of the system.
Let final temperature be T
Then, heat absorbed by A+heat absorbed by B+heat absorbed by C=0

Here in the question m1=m2=m3

Test: Physics Minor Mock Test- 2 (March 20) - Question 29

If the radius of the earth be increased by a factor of 5, by what factor its density be changed to keep the value of g the same ?

Detailed Solution for Test: Physics Minor Mock Test- 2 (March 20) - Question 29

The acceleration due to gravity on surface of earth is
g=GM​/ R2
 
g=GρV​/R2
where, G is the gravitational constant, M  is mass of earth, R  is radius of earth, ρ is the density and V is the volume of earth.
∴g=Gρ(4/3)​πR3​/ R2
 
∴g=(4/3)​GρπR
⇒g∝ρR
since, all other quantities are constant.
Hence, if the radius of the earth be increased by a factor of 5, density will decrease by 51​  to keep the value of g the same.

Test: Physics Minor Mock Test- 2 (March 20) - Question 30

A bucket contains water filled upto a height = 15 cm. The bucket is tied to a rope which is passed over a frictionless light pulley and the other end of the rope is tied to a weight of mass which is half of that of the (bucket + water). The water pressure above atmosphere pressure at the bottom is :

Detailed Solution for Test: Physics Minor Mock Test- 2 (March 20) - Question 30

Consider the mass of the block be m, thus we get a mass of bucket + water is 2m. Now if we consider it as a two mass pulley, we get  the net acceleration a by which the bucket is going down can be found by - 
2mg - mg = 3ma
Thus we get a = g/3
Now we know that the bucket is accelerating with acceleration g/3 downwards hence to treat it as an inertial system we need to apply pseudo force upon it in upward direction. Thus we get in reference to the bucket net acceleration is 2g/3 downwards. Thus the pressure at the bottom is P + x 0.15 x 2g/3 = P + 1 kPa
 

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