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Test: Aldol Condensation (February 14) - NEET MCQ


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10 Questions MCQ Test Daily Test for NEET Preparation - Test: Aldol Condensation (February 14)

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Test: Aldol Condensation (February 14) - Question 1

Which of the following could result as a product in the aldol condensation reaction?

Detailed Solution for Test: Aldol Condensation (February 14) - Question 1


It is an α, β-unsaturated ketone which can be formed in an aldol condensation followed by dehydration.

Test: Aldol Condensation (February 14) - Question 2

Comprehension Type

Direction (Q. Nos. 20-22) This section contains a paragraph, describing theory, experiments, data, etc.
Three questions related to the paragraph have been given. Each question has only one correct answer among the four given options (a), (b), (c) and (d).

Passage

A is optically active and C is one of the several aldol possible in the above reaction.

Q. 

The structure of A satisfying above criteria is

Detailed Solution for Test: Aldol Condensation (February 14) - Question 2

Reversing the final product gives

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Test: Aldol Condensation (February 14) - Question 3

In a mixed aldoi condensation with ethanal as one aidehyde, which other from the following is expected to give maximum yield of cross condensation product?

Detailed Solution for Test: Aldol Condensation (February 14) - Question 3

Nucleophilic addition at carbonyl carbon of cyclopropane releases angle strain.

*Answer can only contain numeric values
Test: Aldol Condensation (February 14) - Question 4

Consider the following modified aldol condensation,

Q. 

How many ethanal, at the most, will react with one molecule of nitromethane?


Detailed Solution for Test: Aldol Condensation (February 14) - Question 4

All three hydrogen can be deprotonated from nitromethane giving

Test: Aldol Condensation (February 14) - Question 5

A is optically active and C is one of the several aldol possible in the above reaction.

Q. 

Besides C, the other six membered cyclic aldol formed in the above reaction is

Detailed Solution for Test: Aldol Condensation (February 14) - Question 5

Test: Aldol Condensation (February 14) - Question 6

A is optically active and C is one of the several aldol possible in the above reaction.

Q. 

The product B is stereomeric. If a mixture containing all stereoisomers of B is treated with excess of LiAIH4 followed by the acidification will give how many different isomeric diols ?

Detailed Solution for Test: Aldol Condensation (February 14) - Question 6

Test: Aldol Condensation (February 14) - Question 7

Statement I : When a mixture of ethanal and propanal is treated with aqueous Na2CO3, four aldol (excluding stereoisomers) are formed.
Statement II : In mixed aldol condensation, two self and two cross condensation products are always formed.

Detailed Solution for Test: Aldol Condensation (February 14) - Question 7

It would be true only if both carbonyls are capable of forming enolates, i.e. possesses α-H

*Multiple options can be correct
Test: Aldol Condensation (February 14) - Question 8

Which of the following indicated carbon-carbon bond can be formed via intramolecular aldoi condensation of a dicarbonyl compound?

Detailed Solution for Test: Aldol Condensation (February 14) - Question 8

In aldol reaction as α-β C—C bond is always formed.

Test: Aldol Condensation (February 14) - Question 9

Identify the starting reagent needed to make the following compound by mixed aldol condensation.

Detailed Solution for Test: Aldol Condensation (February 14) - Question 9


*Multiple options can be correct
Test: Aldol Condensation (February 14) - Question 10

One or More than One Options Correct Type

Direction (Q. Nos. 11-15) This section contains 5 multiple choice questions. Each question has four choices (a), (b), (c) and (d), out of which ONE or MORE THAN ONE are correct.

Q. 

Successful mixed aldol condensation will be favoured 

Detailed Solution for Test: Aldol Condensation (February 14) - Question 10

If an aldol product is continuously removed from the reaction mixture, reaction occur predominantly in direction of that product (Le-Chatelier’s principle).
Also, if a carbonyl is first treated with strong base like LDA, its role as a nucleophile can be ascertained.

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