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Full Test 3 - EKT EEE - AFCAT MCQ


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30 Questions MCQ Test IAF AFCAT Mock Test Series and EKT for (ME, EEE, CSE) 2025 - Full Test 3 - EKT EEE

Full Test 3 - EKT EEE for AFCAT 2024 is part of IAF AFCAT Mock Test Series and EKT for (ME, EEE, CSE) 2025 preparation. The Full Test 3 - EKT EEE questions and answers have been prepared according to the AFCAT exam syllabus.The Full Test 3 - EKT EEE MCQs are made for AFCAT 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Full Test 3 - EKT EEE below.
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Full Test 3 - EKT EEE - Question 1

The integrating factor of equation 

Detailed Solution for Full Test 3 - EKT EEE - Question 1

Full Test 3 - EKT EEE - Question 2

Detailed Solution for Full Test 3 - EKT EEE - Question 2

Let,

Now, we know that, 
Thus the integral can also be written as

Adding the above two integral equations, we get
 

 2I = 0

∴ I = 0

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Full Test 3 - EKT EEE - Question 3

Area of parallelogram having diagonal 

Detailed Solution for Full Test 3 - EKT EEE - Question 3

From the determinant formula, vector area of parallelogram 

Full Test 3 - EKT EEE - Question 4

If ω is a cube root of unity then the value of (1−ω8)(1−ω4)(1−ω2)(1−ω) is ___

Detailed Solution for Full Test 3 - EKT EEE - Question 4

We know that 1 + ω + ω= 0 and ω3= 1 then

(1−ω8)(1−ω4)(1−ω2)(1−ω)=(1−ω2)(1−ω)(1−ω2)(1−ω)
=(1−ω2−ω+ω3)(1−ω2−ω+ω3)
=(2−(ω+ω2))(2−(ω+ω2))
=(2−(−1))(2−(−1))=9

Full Test 3 - EKT EEE - Question 5

The inverse Laplace Transform of 

Detailed Solution for Full Test 3 - EKT EEE - Question 5


Apply inverse Laplace transform we get f(t)= e−5t−5te−5t=e−5t(1−5t)

Full Test 3 - EKT EEE - Question 6

Which of the following forces have zero value of resultant?

Detailed Solution for Full Test 3 - EKT EEE - Question 6

Equilibrium is the status of the body when it is subjected to a system of forces. If the resultant force is equal to zero it implies that the net effect of the system of forces is zero this represents the state of equilibrium.

Full Test 3 - EKT EEE - Question 7

Two coils are placed close to each other. The mutual inductance of the pair of coils depends upon

Detailed Solution for Full Test 3 - EKT EEE - Question 7

Mutual inductance of the pair of coils depends on the distance between two coils and geometry of two coils. The rate of change of current impacts the emf in coil. 

Full Test 3 - EKT EEE - Question 8

Two point charges of + 2μC and + 6 μC repel each other with a force of 12 N. If each is given an additional charge of -4μC, what will be the new force?

Detailed Solution for Full Test 3 - EKT EEE - Question 8

Full Test 3 - EKT EEE - Question 9

All the magnetic materials lose their magnetic properties when they are

Detailed Solution for Full Test 3 - EKT EEE - Question 9
  • For every material, there is a temperature specific to it known as its Curie temperature
  • Above curie temperature, they lose their magnetic properties
Full Test 3 - EKT EEE - Question 10

Two capacitors, C1 = 2 μF and C2 = 8 μF are connected in series across a 300 V source. Then

Detailed Solution for Full Test 3 - EKT EEE - Question 10

In series the equivalent capacitance will be C = 1.6 μF. The charge will be same on each capacitor. Its value will be Q = CV = 1.6 × 10-6  × 300 = 4.8 × 10-4 C. The potential difference across C1 and C2 will be 240 V and 60 V respectively. The energy stored in the system will be 1/2CV2 = 7.2 × 10-2 J.

Full Test 3 - EKT EEE - Question 11

Which of the following is not electromagnetic in nature?

Detailed Solution for Full Test 3 - EKT EEE - Question 11

Cathode rays are stream of electrons observed in vacuum tubes. Rest all are electromagnetic waves in nature.

Full Test 3 - EKT EEE - Question 12

An axonometric projection in which three perpendicular edges of the project make different angles with the POP is called

Detailed Solution for Full Test 3 - EKT EEE - Question 12

In trimetric projection, trimetric scales are used in which three perpendicular edges of the object make different angles with POP

Full Test 3 - EKT EEE - Question 13

Two non - inverting amplifiers, one having unity gain another having gain of 100 are made using two identical Op - amps. As compared to unity gain amplifier the 100 gain amplifier has

i. Less negative feedback

ii. Greater input impedance

iii. Less bandwidth

iv. More sensitive to Op - amp amplification factor variances

The correct statements among them is/are

Detailed Solution for Full Test 3 - EKT EEE - Question 13

The feedback amplification factor is given by   

where A is open loop gain and βA is loop gain.

As feedback increases the gain decreases thereby bandwidth increases since gain bandwidth product of Op - amp is constant, also feedback increases input impedance while decreasing output impedance.

In this problem compared to non - inverting amplifier with unity gain the 100 gain amplifier has less negative feedback leading to leading to lesser bandwidth and input impedance

The sensitivity of feedback amplifier to Op - amp amplification factor variances is given by

Therefore compared to unity gain amplifier 100 gain amplifier is more sensitive to changes in open loop Op - amp gain.

Full Test 3 - EKT EEE - Question 14

One input terminal of high gain comparator circuit is connected to ground and a sinusoidal voltage is applied to the other input. The output of the comparator will be

Detailed Solution for Full Test 3 - EKT EEE - Question 14

In a comparator if V+ > V- then output is Vsat+ and if V+ < V- then output is Vsat-. In the question V- is set to be ground, hence when during positive cycle of input sinusoid we get output as Vsat+ and Vsat- during negative cycle. The overall output is a square wave.

Full Test 3 - EKT EEE - Question 15

For an ideal Op-amp, find the common mode input voltage of the circuit given below

Detailed Solution for Full Test 3 - EKT EEE - Question 15

We know that Vo=A(V2−V1)

−20=1000(10−V1)
∴ V1=10.02v
Common mode input voltage = 

Full Test 3 - EKT EEE - Question 16

Consider the following statements in a common collector amplifier:

1. It performs a resistance transformation from low to high resistance

2. Its current gain is close to unity

3. Its voltage gain is close to unity

4. Its frequency range is higher than of CE-Stage

Which of the following statements are correct?

Detailed Solution for Full Test 3 - EKT EEE - Question 16

In CC configuration the input resistance is high and output resistance is low.

Voltage gain is close to unity

Full Test 3 - EKT EEE - Question 17

To represent a decimal number 35 in binary, the minimum number of bits required are

Detailed Solution for Full Test 3 - EKT EEE - Question 17

To represent a decimal number 35 in binary, the minimum number of bits required are 6. Its binary representation is 100011.

Full Test 3 - EKT EEE - Question 18

Binary addition 1001 + 1101 yields

Detailed Solution for Full Test 3 - EKT EEE - Question 18

For Binary addition use the following rule:

0 + 0 = 0

0 + 1 = 1

1 + 0 = 1

1 + 1 = 0 and a carry = 1

So, using these rules the binary addition of 1001 and 1101 gives 10110.

Full Test 3 - EKT EEE - Question 19

NOR gate is logically equivalent to

Detailed Solution for Full Test 3 - EKT EEE - Question 19

NOR gate is logically equivalent to an OR gate followed by an inverter. The logic or Boolean expression given for a logic NOR gate is that for Logical Multiplication which it performs on the complements of the inputs.

Boolean expression for A NOR B which gives output Q is

Full Test 3 - EKT EEE - Question 20

The output of a logic gate is “1” when all its input are at logic “0”, the gate is either

Detailed Solution for Full Test 3 - EKT EEE - Question 20



NOR gate

XNOR gate

Full Test 3 - EKT EEE - Question 21

NAND gate is called a universals gate because 

Detailed Solution for Full Test 3 - EKT EEE - Question 21

A universal gate is a gate which can implement any Boolean function without need to use any other gate type. The NAND and NOR gates are universal gates. That means we can implement a whole logic whatever you can implement using AND, OR, Invert combination can be implement using NAND gates alone 

Full Test 3 - EKT EEE - Question 22

The normal way to turn off a SCR is by appropriate

Detailed Solution for Full Test 3 - EKT EEE - Question 22

A reverse anode to cathode voltage will tend to interrupt the normal cycle and turn off the SCR. This way is also known as forced commutation.

Full Test 3 - EKT EEE - Question 23

A SCR is a ……. Switch.

Detailed Solution for Full Test 3 - EKT EEE - Question 23

SCR is a unidirectional switch since the gate current can only be positive and it operates in only one quadrant of I-V characteristics.

Full Test 3 - EKT EEE - Question 24

The purpose of blades in a squirrel cage induction motor is

Detailed Solution for Full Test 3 - EKT EEE - Question 24

In induction motor, the rotor has fan blades to circulate cooling air through the motor frame.

Full Test 3 - EKT EEE - Question 25

An step – up transformer increases

Detailed Solution for Full Test 3 - EKT EEE - Question 25

A step up transformer is one in which the voltage in secondary side is more than that of primary side. However, the KVA remains the same.

Full Test 3 - EKT EEE - Question 26

Why holes are not created in a metal?

Detailed Solution for Full Test 3 - EKT EEE - Question 26

In a conductor, the forbidden band is missing and the conduction band and valance band are overlapped. Therefore, no holes can be created in a metal.

Full Test 3 - EKT EEE - Question 27

In a material, the Fermi level is located between the center of the valence band and the conduction band the material is

Detailed Solution for Full Test 3 - EKT EEE - Question 27

In a P-type semiconductor the Fermi level is close to valence band while in n-type the Fermi level is closer to conduction band. Only in intrinsic semiconductor it is at center of conduction and valence band.

Full Test 3 - EKT EEE - Question 28

MOSFET requires

Detailed Solution for Full Test 3 - EKT EEE - Question 28

A MOSFET is a voltage controlled device and requires only a small input current. This is because of the fact that gate circuit impedance in MOSFET is extremely high, of the order of 109 ohm.

Full Test 3 - EKT EEE - Question 29

The current gain of a pnp transistor is

Detailed Solution for Full Test 3 - EKT EEE - Question 29

Typically for a pnp or npn transistor, the current gain (α) is the ratio of the DC collector current to the DC emitter current. It is near to unity.

Full Test 3 - EKT EEE - Question 30

The switching speed of p + n junction (having a heavily doped P region) depends primarily on 

Detailed Solution for Full Test 3 - EKT EEE - Question 30

The P + N diode has heavily doped P- region. Under forward bias electrons are injected from N region to P region and holes are injected form P region into the N region. These injected carries become minority carriers in the other region and recombine with the majority carriers there and decay exponentially with distance. The switching speed of P + N (heavily doped P – region) junction depends on the life time (τ) of the majority carriers (i.e. electrons) in the N – region which is lightly doped region.

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