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Mechanical Engineering Exam  >  Mechanical Engineering Tests  >  GATE Mechanical (ME) Mock Test Series 2025  >  GATE Mock Test Mechanical Engineering (ME) - 5 - Mechanical Engineering MCQ

GATE Mock Test Mechanical Engineering (ME) - 5 - Mechanical Engineering MCQ


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30 Questions MCQ Test GATE Mechanical (ME) Mock Test Series 2025 - GATE Mock Test Mechanical Engineering (ME) - 5

GATE Mock Test Mechanical Engineering (ME) - 5 for Mechanical Engineering 2024 is part of GATE Mechanical (ME) Mock Test Series 2025 preparation. The GATE Mock Test Mechanical Engineering (ME) - 5 questions and answers have been prepared according to the Mechanical Engineering exam syllabus.The GATE Mock Test Mechanical Engineering (ME) - 5 MCQs are made for Mechanical Engineering 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for GATE Mock Test Mechanical Engineering (ME) - 5 below.
Solutions of GATE Mock Test Mechanical Engineering (ME) - 5 questions in English are available as part of our GATE Mechanical (ME) Mock Test Series 2025 for Mechanical Engineering & GATE Mock Test Mechanical Engineering (ME) - 5 solutions in Hindi for GATE Mechanical (ME) Mock Test Series 2025 course. Download more important topics, notes, lectures and mock test series for Mechanical Engineering Exam by signing up for free. Attempt GATE Mock Test Mechanical Engineering (ME) - 5 | 65 questions in 180 minutes | Mock test for Mechanical Engineering preparation | Free important questions MCQ to study GATE Mechanical (ME) Mock Test Series 2025 for Mechanical Engineering Exam | Download free PDF with solutions
GATE Mock Test Mechanical Engineering (ME) - 5 - Question 1
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Fill in the blank with the correct word.

Unfortunately, the commentaries in the guidebook sometimes hinder rather than_____ the visitors' appreciation of the paintings in the gallery

Detailed Solution for GATE Mock Test Mechanical Engineering (ME) - 5 - Question 1
There are two negative indicators in this sentence-'unfortunately' and `rather than'-both of which imply contrast in ideas. If the author of the sentence finds it unfortunate that the commentaries in the guidebook to the art gallery sometimes hinder the visitors' appreciation of the paintings in it, what will he consider to be the legitimate function of the commentaries? Obviously, `to help', `to increase', `to assist' or `to aid' the visitor appreciation. Among the choices, 'enhance' has the same meaning as 'increase', and is the answer.
GATE Mock Test Mechanical Engineering (ME) - 5 - Question 2
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Which of the following is the antonym of the word SILENCE?

Detailed Solution for GATE Mock Test Mechanical Engineering (ME) - 5 - Question 2
Silence refers to 'no speech'. Babble means continuous, and sometimes incoherent speech.
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GATE Mock Test Mechanical Engineering (ME) - 5 - Question 3
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Choose the pair which best expresses the relationship similar to that expressed in the capitalized pair.

DRILL : BORING ∷

Detailed Solution for GATE Mock Test Mechanical Engineering (ME) - 5 - Question 3
(THING AND PURPOSE) A drill is a tool used for boring ; a die is tool for shaping.
GATE Mock Test Mechanical Engineering (ME) - 5 - Question 4
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Directions: In the following question, from amongst the figures marked (1), (2), (3) and (4), select the one which satisfies the same conditions of placement of the dots as in figure (X)
Detailed Solution for GATE Mock Test Mechanical Engineering (ME) - 5 - Question 4

In figure (X), one of the dots lies in the region common to the square and the triangle only, another dot lies in the region common to the circle and the triangle only and the third dot lies in the region common to the triangle and the rectangle only. In figure (2), there is no region common to the square and the triangle only. In figure (3), there is no region common to the circle and the triangle only. In figure (4), there is no region common to the triangle and the rectangle only. Only figure (1) consists of all the three types of regions.

GATE Mock Test Mechanical Engineering (ME) - 5 - Question 5
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Directions: In the following question, a square transparent sheet with a pattern is given. Figure out from among the four alternatives as to how the pattern will appear when the transparent sheet is folded along the dotted line.
Detailed Solution for GATE Mock Test Mechanical Engineering (ME) - 5 - Question 5

The above transparent figure, when folded along the dotted line, becomes

GATE Mock Test Mechanical Engineering (ME) - 5 - Question 6
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Which of the following statements cannot be inferred from the passage?

Not stagnating moment to moment is called achievement. Inward humility is achievement, outward courtesy is virtue. Establishing myriad truth in your nature is achievement; the mind being essentially detached from thoughts is virtue. Not departing from one's essential nature is achievement; acting adaptively without being affected is virtue. Continuity moment to moment is achievement; balance and directness of mental activity are virtue. Refining your own nature is achievement. Refining your own person is virtue.
Detailed Solution for GATE Mock Test Mechanical Engineering (ME) - 5 - Question 6

Going through the passage,

(1) is eliminated as it is true as per line,' Inward humility is achievement, outward courtesy is virtue' of the passage.

(2) is true as per the line ,'Refining your own nature is achievement. Refining your own person is virtue'. Hence, eliminated.

(3) can also be inferred in the last lines.

(4) is the only statement that can not be inferred, hence the Answer: (4)

GATE Mock Test Mechanical Engineering (ME) - 5 - Question 7
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In a chess competition involving some boys and girls of a school, every student had to play exactly one game with every other student. It was found that in 45 games both the players were girls and in 190 games both were boys. The number of games in which one player was a boy and the other was a girl is
Detailed Solution for GATE Mock Test Mechanical Engineering (ME) - 5 - Question 7

Number of games two girls = g C2

Number of games two boys = b C2

b2 - b - 380 = 0

( b - 20 ) ( b + 190 ) = 0

∴ b = 20 as b ≠ - 19

∴ Number of games in which one player is a boy and the other is a girl = 435 - 45 - 190 = 200

GATE Mock Test Mechanical Engineering (ME) - 5 - Question 8
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1/38 + 1/39 + 1/39 + 1/39 is equal to
Detailed Solution for GATE Mock Test Mechanical Engineering (ME) - 5 - Question 8

Remember that you can only add fractions with the same denominator.

Rearrange 1/38 so that it can be added to 1/39. That is, try and turn 1/38 into a fraction with 39 in the denominator.

Multiply 1/38 by 3/3 to get

1/38 x 3/3 = 3/38 x 3 = 3/39

solving,

Canceling out a factor of 3 gives

GATE Mock Test Mechanical Engineering (ME) - 5 - Question 9
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In a right angle triangle ABC with vertex B being the right angle, the mutually perpendicular sides AB and BC are p cm and q cm long respectively. If the length of the hypotenuse is (p + q — 6)cm, the radius of the largest possible circle that can be inscribed in the triangle is
Detailed Solution for GATE Mock Test Mechanical Engineering (ME) - 5 - Question 9

The largest possible circle that can be inscribed in the triangle is the one which touches the 3 sides. Since A is an external point from where AN and AM are tangents to this circle, we have AM = AN = a (say)

CN=CL=b (say)

If O is the centre of the circle, then OM = OL = r (radius of this circle)

BC = q = b + r and AB = p = a + r

We are given the hypotenuse CA = AN + NC

=p + q - 6 = a + b

Or using the values of p and q.

We get

b + r + a + r - 6 = a + b

r=3 cm

GATE Mock Test Mechanical Engineering (ME) - 5 - Question 10
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What will be the sum of the factors of 3129?
Detailed Solution for GATE Mock Test Mechanical Engineering (ME) - 5 - Question 10
N is a number such that N = ap bq cr ... where a, b, c are prime number and p, q, r are positive integers.

Here a = 3, p = 129,

so required sum = (3130 - 1) / 2 .

GATE Mock Test Mechanical Engineering (ME) - 5 - Question 11
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In a Go/No - go -gage, which one of the describes the function of the Go —gage?
Detailed Solution for GATE Mock Test Mechanical Engineering (ME) - 5 - Question 11
The Go limit is used to check the dimension at its maximum material condition. This is the minimum size for an internal feature such as a hole and it is the maximum size for an external feature such as an outside diameter. The No - Go limit is used to inspect the minimum material condition of the dimension in question.
GATE Mock Test Mechanical Engineering (ME) - 5 - Question 12
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Which of the following machines does not require a flywheel?
Detailed Solution for GATE Mock Test Mechanical Engineering (ME) - 5 - Question 12
A gas turbine does not require a flywheel. A flywheel is a device which is used to control the variation in speed, during each cycle of an engine or it acts as an energy reservoir for storing and releasing the mechanical energy of an engine.
GATE Mock Test Mechanical Engineering (ME) - 5 - Question 13
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Quality screw threads are produced by
Detailed Solution for GATE Mock Test Mechanical Engineering (ME) - 5 - Question 13

Quality screw threads are produced by only thread casting.
Quality screw threads are made by die-casting and permanent mould casting are very accurate and of high finish, if properly made.

GATE Mock Test Mechanical Engineering (ME) - 5 - Question 14
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Identify the Newton-Raphson iteration scheme for finding the square root of 2.
Detailed Solution for GATE Mock Test Mechanical Engineering (ME) - 5 - Question 14
We have, x = √2 or x2 – 2 = 0

or f(x) = x2 – 2

From the Newton – Raphson iteration,

GATE Mock Test Mechanical Engineering (ME) - 5 - Question 15
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Considering the variation of static pressure and absolute velocity in an impulse stream turbine across one row of moving blades,
Detailed Solution for GATE Mock Test Mechanical Engineering (ME) - 5 - Question 15


The diagram shows that static pressure remains constant, while velocity decreases.

GATE Mock Test Mechanical Engineering (ME) - 5 - Question 16
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A rectangular channel 6.0 m wide carries a discharge of 16.0 m3/s under uniform condition with normal depth of 1.60 m. Manning's n is 0.015.

The channel width is to be contracted. The minimum width to which the channel can be contracted without affecting the upstream flow condition is
Detailed Solution for GATE Mock Test Mechanical Engineering (ME) - 5 - Question 16
At sub-critical flow, when width of the channel is contracted, there will be decrease in depth of flow at the contracted section and depth of contracted section will decrease till it reaches the depth at contracted section equal to critical depth and flow at contracted section will be critical flow means minimum specific energy.

B2/3 = 2.557

∴ B = 4.088 m ≃ 4.1 m

GATE Mock Test Mechanical Engineering (ME) - 5 - Question 17
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Match the following :
Detailed Solution for GATE Mock Test Mechanical Engineering (ME) - 5 - Question 17
Face centred cubic —Ca, Ni, Cu, Ag, Pt, Pb, Al

Hexagonal close packed —Be, Mg, Zn, Cd, Te

Body centred cubic —Na, K, V, Mo, Ta, W

Simple cubic —Po

GATE Mock Test Mechanical Engineering (ME) - 5 - Question 18
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Match List - I (Measuring instruments) with List - II (Measuring/testing parameters) and select the correct answer using the codes given below the list:
Detailed Solution for GATE Mock Test Mechanical Engineering (ME) - 5 - Question 18
The Try square is used to check the external squareness of a workpiece. To do this, butt the stock of the square up to the edge of the workpiece with the inside edge of the blade sitting across the workpiece surface.

Surface plate is used as a measuring base or a datum surface for testing of flatness of surfaces.

A feeler gauge is a tool used to measure gap widths. Feeler gauges are mostly used in engineering to measure the clearance between two components.

Slip gauges are used to provide end standards of specific length by combining several individual slip gauges into a single gauge bar.

A micrometer, also called micrometer screw gauge, is a device incorporating a calibrated screw widely used for accurate measurement of components in mechanical engineering and machining as well as most mechanical trades, along with other metrological instruments such as dial, vernier, and digital calipers.

GATE Mock Test Mechanical Engineering (ME) - 5 - Question 19
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Minimum number of links require to make consisting of lower pairs only
Detailed Solution for GATE Mock Test Mechanical Engineering (ME) - 5 - Question 19
DOF = 3(n — 1) — 2j

n= number of links

j = number of lower pairs

For minimum number of links, DOF = 1

1 = 3(n — 1) — 2j

3n — 2j = 4

n = 4 + 2j /3

∵ j > 1, for minimum number of links

j can be taken as 4 to get integer value for n

⇒ n = 4+2x4 / 3 = 4

GATE Mock Test Mechanical Engineering (ME) - 5 - Question 20
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Consider the following parameters:

  1. Grinding wheel diameter

  2. Regulating wheel diameter

  3. Speed of grinding wheel

  4. Speed of regulating wheel

Which of the above parameters will influence the axial feed rate in centre-less grinding?
Detailed Solution for GATE Mock Test Mechanical Engineering (ME) - 5 - Question 20

In different from other cylindrical processes, where the work piece is held in the grinding machine, while grinding between centers, the workpiece is not mechanically constrained during centreless grinding. Therefore the parts to be ground on a centreless grinder do not need center holes, drivers or workhead fixtures at the ends

Axial feed rate in centreless grinding is,

f = πDNsinα

Where, N is speed of regulating wheel and

D is diameter of regulating wheel

α is angle between the axes of grinding and regulating wheels

GATE Mock Test Mechanical Engineering (ME) - 5 - Question 21
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A man wanted to sell an article with 33% profit but he actually sold at 16% loss for Rs. 504. At what price did he want to sell it to earn the profit?
Detailed Solution for GATE Mock Test Mechanical Engineering (ME) - 5 - Question 21

According to question:
Let CP = 100%
Loss = 16%
SP = 100% - 16% = 84%
84% correspond to 504.
1% correspond to 504/84
So, SP of article to earn a profit of 33% = 133 × 504/84 = 798.

GATE Mock Test Mechanical Engineering (ME) - 5 - Question 22
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A cylindrical resistor element on a circuit board dissipates 0.8 W of power. The resistor is 2 cm long and has a diameter of 0.4 cm. For heat to be transferred uniformly from all surfaces, the amount of heat this resistor dissipates during a 24-hour period and the heat flux, respectively, are
Detailed Solution for GATE Mock Test Mechanical Engineering (ME) - 5 - Question 22

The amount of heat this resistor dissipates during a 24-hour period is,

= 19.2 Wh = 69.1 kJ (since 1 Wh = 3600 Ws = 3.6 kJ)

= 0.251 + 2.513 = 2.764 cm2

The heat flux on the surface of the resistor is,

GATE Mock Test Mechanical Engineering (ME) - 5 - Question 23
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Evaluate where [ x ] denotes greatest integer
Detailed Solution for GATE Mock Test Mechanical Engineering (ME) - 5 - Question 23

= 13 / 2

GATE Mock Test Mechanical Engineering (ME) - 5 - Question 24
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Consider a refrigerator with a COP of 1.2. It removes heat from the refrigerated space at a rate of 60 kJ/min. What will be the electric power consumed by the refrigerator and the rate of heat transfer to the kitchen air, respectively?
Detailed Solution for GATE Mock Test Mechanical Engineering (ME) - 5 - Question 24

Using the definition of the coefficient of performance, the power z input to the refrigerator is determined to be

The heat transfer rate to the kitchen air is determined from the energy balance as

GATE Mock Test Mechanical Engineering (ME) - 5 - Question 25
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If f and g are differentiable function in [ 0,1] satisfying f (0) = 3 = g(1), g(0) = 0 and f (1) = 6, then for same C ∈ (0, 1)
Detailed Solution for GATE Mock Test Mechanical Engineering (ME) - 5 - Question 25

By Lagrange,s Mean Value Theorem,

= 6 - 3 / 3

= 1

GATE Mock Test Mechanical Engineering (ME) - 5 - Question 26
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The crystal structures that delta iron and gamma iron have, respectively, are
Detailed Solution for GATE Mock Test Mechanical Engineering (ME) - 5 - Question 26
As molten iron cools down, it crystallizes at 1538°C into its d-allotrope, which has a BCC crystal structure and the gamma iron which has a FCC crystal structure.
*Answer can only contain numeric values
GATE Mock Test Mechanical Engineering (ME) - 5 - Question 27
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Let p = . The product of eigen values of p-1 is

Detailed Solution for GATE Mock Test Mechanical Engineering (ME) - 5 - Question 27

det (p) = । p। = - 20 + 18 = - 2

Product of eigen values of p-1 = । p-1 ।

= - 1 / 2

= - 0.5

GATE Mock Test Mechanical Engineering (ME) - 5 - Question 28
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Earing in a drawn cup can be due to non-uniform

  1. Speed of the press

  2. Clearance between tools

  3. Material properties

  4. Blank holding

Detailed Solution for GATE Mock Test Mechanical Engineering (ME) - 5 - Question 28
Earing defect in a deep drawing is due to wavy projections (i.e. ears) formed as a result of directional properties or anisotropy of the strip. Earing is one of the major defects observed in a deep drawing process due to the anisotropic nature of the sheet material and due to non-uniform speed of the press and blank holding.
GATE Mock Test Mechanical Engineering (ME) - 5 - Question 29
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In electro chemical machining of an iron surface that is 20 mm x 20 mm in cross section using NaCl in water as electrolyte. The gap between the tool and the work piece is 0.2 mm. The supply voltage is 13 Vdc . The specific resistance of the electrolyte is 2Ωcm. Then material removal rate (in g /s) is Take Valency (Z) = 2, Atomic weight (A) = 55.85, Density (pa) = 7860 kg /m3, Faraday constant = 96540 coulombs
Detailed Solution for GATE Mock Test Mechanical Engineering (ME) - 5 - Question 29

Given data

Cross sectional area of the gap , Agap = 20 x 20 = mm2

Gap between the tool and work piece , H = 0.2 mm

Voltage , V = 13 V

ρ = 2 Ωcm = 2 x 10 Ωmm

Material removal rate in ECM by considering 100% current efficiency, MRR = AI / ZF

= 72605 / 193080

= 0.376 g / s

*Answer can only contain numeric values
GATE Mock Test Mechanical Engineering (ME) - 5 - Question 30
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In the figure shown, what will be the moment (kN-m) at the fixed support? (Answer up to the nearest integer)

Detailed Solution for GATE Mock Test Mechanical Engineering (ME) - 5 - Question 30

In an equilibrium condition,

Now taking the moment about the fixed support A,

MA = 16 kN - m

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