Test: Arithmetical Reasoning - 1 - UPSC MCQ

# Test: Arithmetical Reasoning - 1 - UPSC MCQ

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## 10 Questions MCQ Test CSAT Preparation - Test: Arithmetical Reasoning - 1

Test: Arithmetical Reasoning - 1 for UPSC 2024 is part of CSAT Preparation preparation. The Test: Arithmetical Reasoning - 1 questions and answers have been prepared according to the UPSC exam syllabus.The Test: Arithmetical Reasoning - 1 MCQs are made for UPSC 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Arithmetical Reasoning - 1 below.
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Test: Arithmetical Reasoning - 1 - Question 1

### A is 3 years older to B and 3 years younger to C, while B and D are twins. How many years older is C to D?

Detailed Solution for Test: Arithmetical Reasoning - 1 - Question 1

Since B and D are twins, so B = D.
Now, A = B + 3 and A = C - 3.
Thus, B + 3 = C - 3  D + 3 = C - 3  C - D = 6.

Test: Arithmetical Reasoning - 1 - Question 2

### The 30 members of a club decided to play a badminton singles tournament. Every time a member loses a game he is out of the tournament. There are no ties. What is the minimum number of matches that must be played to determine the winner?

Detailed Solution for Test: Arithmetical Reasoning - 1 - Question 2

Clearly, every member except one (i.e. the winner) must lose one game to decide the winner. Thus, minimum number of matches to be played = 30 - 1 = 29.

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Test: Arithmetical Reasoning - 1 - Question 3

### In a garden, there are 10 rows and 12 columns of mango trees. The distance between the two trees is 2 metres and a distance of one metre is left from all sides of the boundary of the garden. The length of the garden is

Detailed Solution for Test: Arithmetical Reasoning - 1 - Question 3

Each row contains 12 plants.
There are 11 gapes between the two corner trees (11 x 2) metres and 1 metre on each side is left.
Therefore, Length = (22 + 2) m = 24 m.

Test: Arithmetical Reasoning - 1 - Question 4

12 year old Manick is three times as old as his brother Rahul. How old will Manick be when he is twice as old as Rahul?

Detailed Solution for Test: Arithmetical Reasoning - 1 - Question 4

Manick's present age = 12 years, Rahul's present age = 4 years.
Let Manick be twice as old as Rahul after x years from now.
Then, 12 + x = 2 (4 + x)  12 + x = 8 + 2x  x = 4.
Hence, Manick's required age = 12 + x = 16 years.

Test: Arithmetical Reasoning - 1 - Question 5

A tailor had a number of shirt pieces to cut from a roll of fabric. He cut each roll of equal length into 10 pieces. He cut at the rate of 45 cuts a minute. How many rolls would be cut in 24 minutes?

Detailed Solution for Test: Arithmetical Reasoning - 1 - Question 5

Number of cuts made to cut a roll into 10 pieces = 9.
Therefore Required number of rolls = (45 x 24)/9 = 120.

Test: Arithmetical Reasoning - 1 - Question 6

In a class of 60 students, the number of boys and girls participating in the annual sports is in the ratio 3 : 2 respectively. The number of girls not participating in the sports is 5 more than the number of boys not participating in the sports. If the number of boys participating in the sports is 15, then how many girls are there in the class?

Detailed Solution for Test: Arithmetical Reasoning - 1 - Question 6

Let the number of boys and girls participating in sports be 3x and 2x respectively.
Then, 3x = 15 or x = 5.
So, number of girls participating in sports = 2x = 10.
Number of students not participating in sports = 60 - (15 + 10) = 35.
Let number of boys not participating in sports be y.
Then, number of girls not participating in sports = (35 -y).
Therefore (35 - y) = y + 5  2y  30  y = 15.
So, number of girls not participating in sports = (35 - 15) = 20.
Hence, total number of girls in the class = (10 + 20) = 30.

Test: Arithmetical Reasoning - 1 - Question 7

There are deer and peacocks in a zoo. By counting heads they are 80. The number of their legs is 200. How many peacocks are there?

Detailed Solution for Test: Arithmetical Reasoning - 1 - Question 7

Let x and y be the number of deer and peacocks in the zoo respectively. Then,
x + y = 80 ...(i) and
4x + 2y = 200 or 2x + y = 100 ...(ii)
Solving (i) and (ii), we get) x = 20, y = 60.

Test: Arithmetical Reasoning - 1 - Question 8

A man wears socks of two colours - Black and brown. He has altogether 20 black socks and 20 brown socks in a drawer. Supposing he has to take out the socks in the dark, how many must he take out to be sure that he has a matching pair?

Detailed Solution for Test: Arithmetical Reasoning - 1 - Question 8

Since there are socks of only two colours, so two out of any three socks must always be of the same colour.

Test: Arithmetical Reasoning - 1 - Question 9

A motorist knows four different routes from Bristol to Birmingham. From Birmingham to Sheffield he knows three different routes and from Sheffield to Carlisle he knows two different routes. How many routes does he know from Bristol to Carlisle?

Detailed Solution for Test: Arithmetical Reasoning - 1 - Question 9

Total number of routes from Bristol to Carlisle = (4 x 3 x 2) = 24.

Test: Arithmetical Reasoning - 1 - Question 10

Mac has £ 3 more than Ken, but then Ken wins on the horses and trebles his money, so that he now has £ 2 more than the original amount of money that the two boys had between them. How much money did Mac and Ken have between them before Ken's win?

Detailed Solution for Test: Arithmetical Reasoning - 1 - Question 10

Let money with Ken = x. Then, money with Mac = x + £ 3.
Now, 3x = (x + x + £ 3) + £ 2  x = £ 5.
Therefore Total money with Mac and Ken = 2x + £ 3 = £ 13.

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