Test: Quadratic Equations- 1


10 Questions MCQ Test IBPS PO Mains - Study Material, Online Tests, Previous Year | Test: Quadratic Equations- 1


Description
This mock test of Test: Quadratic Equations- 1 for Quant helps you for every Quant entrance exam. This contains 10 Multiple Choice Questions for Quant Test: Quadratic Equations- 1 (mcq) to study with solutions a complete question bank. The solved questions answers in this Test: Quadratic Equations- 1 quiz give you a good mix of easy questions and tough questions. Quant students definitely take this Test: Quadratic Equations- 1 exercise for a better result in the exam. You can find other Test: Quadratic Equations- 1 extra questions, long questions & short questions for Quant on EduRev as well by searching above.
QUESTION: 1

Find the roots of the quadratic equation: x2 + 2x - 15 = 0?

Solution:

x2 + 5x - 3x - 15 = 0
x(x + 5) - 3(x + 5) = 0
(x - 3)(x + 5) = 0
⇒ x = 3 or x = -5.

QUESTION: 2

Find the roots of the quadratic equation: 2x2 + 3x - 9 = 0?

Solution:

2x2 + 6x - 3x - 9 = 0
2x(x + 3) - 3(x + 3) = 0
(x + 3)(2x - 3) = 0
⇒ x = -3 or x = 3/2.

QUESTION: 3

The roots of the equation 3x2 - 12x + 10 = 0 are?

Solution:

Explanation:

The discriminant of the quadratic equation is (-12)2 - 4(3)(10) i.e., 24. As this is positive but not a perfect square, the roots are irrational and unequal.

QUESTION: 4

If the roots of a quadratic equation are 20 and -7, then find the equation?

Solution:

Explanation:

Any quadratic equation is of the form
x2 - (sum of the roots)x + (product of the roots) = 0 ---- (1)
where x is a real variable. As sum of the roots is 13 and product of the roots is -140, the quadratic equation with roots as 20 and -7 is: x2 - 13x - 140 = 0.

QUESTION: 5

The sum and the product of the roots of the quadratic equation x2 + 20x + 3 = 0 are?

Solution:

Explanation:

Sum of the roots and the product of the roots are -20 and 3 respectively.

QUESTION: 6

If the roots of the equation 2x2 - 5x + b = 0 are in the ratio of 2:3, then find the value of b?

Solution:

Explanation:

Let the roots of the equation 2a and 3a respectively.
2a + 3a = 5a = -(- 5/2) = 5/2 => a = 1/2
Product of the roots: 6a2 = b/2 => b = 12a2
a = 1/2, b = 3.

QUESTION: 7

The sum of the squares of two consecutive positive integers exceeds their product by 91. Find the integers?

Solution:

Explanation:

Let the two consecutive positive integers be x and x + 1
x2 + (x + 1)2 - x(x + 1) = 91
x2 + x - 90 = 0
(x + 10)(x - 9) = 0 => x = -10 or 9.
As x is positive x = 9
Hence the two consecutive positive integers are 9 and 10.

QUESTION: 8

One root of the quadratic equation x2 - 12x + a = 0, is thrice the other. Find the value of a?

Solution:

Explanation:

Let the roots of the quadratic equation be x and 3x.
Sum of roots = -(-12) = 12
a + 3a = 4a = 12 => a = 3
Product of the roots = 3a2 = 3(3)2 = 27.

QUESTION: 9

The sum of the square of the three consecutive even natural numbers is 1460. Find the numbers?

Solution:

Explanation:

Three consecutive even natural numbers be 2x - 2, 2x and 2x + 2.
(2x - 2)2 + (2x)2 + (2x + 2)2 = 1460
4x2 - 8x + 4 + 4x2 + 8x + 4 = 1460
12x2 = 1452 => x2 = 121 => x = ± 11
As the numbers are positive, 2x > 0. Hence x > 0. Hence x = 11.
Required numbers are 20, 22, 24.

QUESTION: 10

If a and b are the roots of the equation x2 - 9x + 20 = 0, find the value of a2 + b2 + ab?

Solution:

Explanation:

a2 + b2 + ab = a2 + b2 + 2ab - ab
i.e., (a + b)2 - ab
from x2 - 9x + 20 = 0, we have
a + b = 9 and ab = 20. Hence the value of required expression (9)2 - 20 = 61.

Similar Content

Related tests