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UPSC Exam  >  UPSC Test  >  CSAT Preparation  >  Test: Speed, Time & Distance - 2 - UPSC MCQ

Speed, Time & Distance - 2 - Free MCQ Practice Test with solutions, UPSC


MCQ Practice Test & Solutions: Test: Speed, Time & Distance - 2 (10 Questions)

You can prepare effectively for UPSC CSAT Preparation with this dedicated MCQ Practice Test (available with solutions) on the important topic of "Test: Speed, Time & Distance - 2". These 10 questions have been designed by the experts with the latest curriculum of UPSC 2026, to help you master the concept.

Test Highlights:

  • - Format: Multiple Choice Questions (MCQ)
  • - Duration: 10 minutes
  • - Number of Questions: 10

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Test: Speed, Time & Distance - 2 - Question 1
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A Man travelled a distance of 61 km in 9 hours. He travelled partly on foot at 4 km/hr and partly on bicycle at 9 km/hr. What is the distance travelled on foot?

Detailed Solution: Question 1

Correct option: C - distance on foot = 16 km.

Let time on foot be x hours; then time by bicycle is 9 - x hours.

Distance = Speed × Time.

Distance on foot = 4x; distance by bicycle = 9(9 - x).

Using total distance 61 km, form the equation:

4x + 9(9 - x) = 61

Expand: 4x + 81 - 9x = 61

Simplify: -5x + 81 = 61 ⇒ -5x = -20 ⇒ x = 4 hours.

Distance on foot = 4 × 4 = 16 km. Therefore, option C is correct.

Test: Speed, Time & Distance - 2 - Question 2
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Walking 6/7th of his usual speed, a man is 12 minutes too late. What is the usual time taken by him to cover that distance?

Detailed Solution: Question 2

Let the distance be x
Let the original speed be y
Time originally taken = distance / speed
That means = x/y
Now the new speed is (6/7)y
And new time is distance /new speed
x/(6/7)y that can be written as 7x/6y
Now new time - original time = 12 min
7x/6y-x/y=12
After subtracting we get
x/y = 12×6
x/y = 72min

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Test: Speed, Time & Distance - 2 - Question 3
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A man goes to his office from his house at a speed of 3 km/hr and returns at a speed of 2 km/hr. If he takes 5 hours in going and coming, what is the distance between his house and office?

Detailed Solution: Question 3

If the distance between house and office is d km
Then time taken to go from home to office = d/3 hr (Time = Distance/Speed)
and Time taken to come back from office to home= d/2 hr
So total time taken = (d/3 +d/2) hour
But according to question , time taken = 5 hour
so we have
d/3+d/2=5
or (2d+3d)/6= 5
or 5d/6=5
or, d=5 x6/5= 6km
So distance between home and office = 6km

Test: Speed, Time & Distance - 2 - Question 4
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A man rides his bicycle 10 km at an average speed of 12 km/hr and again travels 12 km at an average speed of 10 km/hr. What is his average speed for the entire trip approximately?

Detailed Solution: Question 4

Total Distance = 10 +12 = 22 km
Total time = 10/12 + 12/10 = 5/6 + 6/5 = 25/30 + 36/30 = 61/30 hours
Average speed = 22 /(61/30) = 660/61 = 10.8 km/ hour

Test: Speed, Time & Distance - 2 - Question 5
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A train can travel 50% faster than a car. Both start from point A at the same time and reach point B 75 kms away from A at the same time. On the way, however, the train lost about 12.5 minutes while stopping at the stations. What is the speed of the car?

Detailed Solution: Question 5

Let the speed of the car be x km/h

So the speed of the train will be 1.5x km/h

According to the question

⇒ 75/x - 75/1.5x = 12.5/60

⇒ (112.5 - 75)/1.5x = 12.5/60

⇒ 37.5/1.5x = 12.5/60

⇒ 1.5x = 37.5 × (60/12.5)

⇒ x = 180/1.5

⇒ x = 120 km/h

∴ The speed of the car is 120 km/h

Test: Speed, Time & Distance - 2 - Question 6
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In a flight of 600 km, an aircraft was slowed down due to bad weather. Its average speed for the trip was reduced by 200 km/hr and the time of flight increased by 30 minutes. What is the duration of the flight ?

Detailed Solution: Question 6

option "D"

Test: Speed, Time & Distance - 2 - Question 7
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If a person walks at 14 km/hr instead of 10 km/hr, he would have walked 20 km more. What is the actual distance travelled by him?

Detailed Solution: Question 7

Distance he could travelled/speed diff.
= 20/(14-10)
= 20/4
= 5 hrs
Now his actual speed was 10 km/h
Total distance travelled by him = speed × time
= 10 × 5
= 50 km.
 

Test: Speed, Time & Distance - 2 - Question 8
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The ratio between the speeds of two trains is 7 : 8. If the second train runs 400 km in 4 hours, What is the the speed of the first train?

Detailed Solution: Question 8

Given 

The ratio of speed of two trains = 7 : 8 

Formula Used 

Distance = speed × time

Calculation 

Let the speed of trains be 7x and 8x respectively

Speed of 2nd train = 400/4 = 100 km/hr 

According to the question 

⇒ 8x = 100 

⇒ x = 12.5km/hr

So, speed of 1st train = 7x = 7 × 12.5 = 87.5 km/hr 

∴ The speed of 1st train is 87.5 km/hr

Test: Speed, Time & Distance - 2 - Question 9
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It takes eight hours for a 600 km journey, if 120 km is done by train and the rest by car. It takes 20 minutes more, if 200 km is done by train and the rest by car. What is the ratio of the speed of the train to that of the car?

Detailed Solution: Question 9

Eight hours for a 600 km journey, when 120 km is done by train and 480 km by car.

It takes 20 minutes more if 200 km is done by train and 400 km by car.

Formula used:

Speed = Distance/Time

Calculation:

Let the speed of the train be x km/h

And the speed of the car be y km/h

⇒ 120/x + 480/y = 8

⇒ 120(1/x + 4/y) = 8

⇒ 1/x + 4/y = 1/15     ...i)

In the second condition

⇒ Total time = 8 + 20/60 = 25/3 hr

∴  200/x + 400/y = 25/3

⇒ 200(1/x + 2/y) = 25/3

⇒ 1/x + 2/y = 1/24     ...ii)

After solving equation (i) and (ii)

(By substracting equation 2 from equation 1)

⇒ x = 60 km/h

⇒ y = 80 km/h

Ratio of the speed of train and car is

⇒ 60 : 80

⇒ 3 : 4

∴ The ratio of the speed of train and car is 3 : 4.

Test: Speed, Time & Distance - 2 - Question 10
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It takes eight hours for a 600 km journey, if 120 km is done by train and the rest by car. It takes 20 minutes more, if 200 km is done by train and the rest by car. What is the ratio of the speed of the train to that of the car?

Detailed Solution: Question 10

Let the speed of the train be x km/hr and that of the car be y km/hr.
It takes eight hours for a 600 km journey, if 120 km is done by train and the rest by car.
120/x + 480/y = 8 or 1/x + 4/y = 1/15
If 200 km is done by train and the rest by car, then 20 minutes more time is taken.
200/x + 400/y = 25/3 or 1/x + 2/y  = 1/24
Solving both the equations,
x = 60 and y = 80
Ratio is 3 : 4

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About this UPSC Practice Test

This test contains 10 MCQs on Speed, Time & Distance - 2 with detailed solutions for each question. It is part of the CSAT Preparation course on EduRev, designed to align with the current UPSC syllabus. Each solution explains not just the correct answer but also gives you an understanding of the topic — not just to attempt the question but also help you prepare for the exam with practice.

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