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Light: Reflection & Refraction - 1 - Class 10 MCQ


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10 Questions MCQ Test Science Class 10 - Light: Reflection & Refraction - 1

Light: Reflection & Refraction - 1 for Class 10 2024 is part of Science Class 10 preparation. The Light: Reflection & Refraction - 1 questions and answers have been prepared according to the Class 10 exam syllabus.The Light: Reflection & Refraction - 1 MCQs are made for Class 10 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Light: Reflection & Refraction - 1 below.
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Light: Reflection & Refraction - 1 - Question 1

A concave mirror is used to form an image of the sun on a white screen. If the lower half of the mirror is covered with a black paper, the effect on the image formed on the screen would be:

Detailed Solution for Light: Reflection & Refraction - 1 - Question 1

If the lower half (or a part) of a mirror is covered with a black paper then a complete image of the object will be formed as before. However, the image will be less bright now.

Light: Reflection & Refraction - 1 - Question 2

Figure shows a ray of light as it travels from medium A to medium B. Refractive index of the medium B relative to medium A is

Detailed Solution for Light: Reflection & Refraction - 1 - Question 2

Here, ∠i = 60°, ∠r = 45°
Using Snell’s law of refraction, refractive index of medium B with respect to medium A.

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Light: Reflection & Refraction - 1 - Question 3

A full length image of a distant tall building can definitely be seen by using:

Detailed Solution for Light: Reflection & Refraction - 1 - Question 3

A full length image of a distant tall building can definitely be seen by using a convex mirror because a convex mirror always forms a virtual, erect and highly diminished image.

Light: Reflection & Refraction - 1 - Question 4

The angle of incidence of any light ray passing through the centre of curvature of a spherical mirror is:

Detailed Solution for Light: Reflection & Refraction - 1 - Question 4

The angle of incidence of any light ray passing through the centre of curvature of a spherical mirror is 0°, because a line joining centre of curvature to any point on the mirror is a normal drawn at that point of the mirror.

Light: Reflection & Refraction - 1 - Question 5

A 10 mm long awl pin is placed vertically in front of a concave mirror. A 5 mm long image of the awl pin is formed at 30 cm in front of the mirror. The focal length of this mirror is:

Detailed Solution for Light: Reflection & Refraction - 1 - Question 5

Given h0 = +10 mm - + 0.1 cm 
h2 = - 5 mm = -0 .5 cm
for real image, v = - 30 cm                       

Now magnification,



∴ f = -20 cm

Light: Reflection & Refraction - 1 - Question 6

In case of a real and inverted image the magnification of a mirror is:

Detailed Solution for Light: Reflection & Refraction - 1 - Question 6

Magnification is negative for a real and inverted image formed by a mirror.

Light: Reflection & Refraction - 1 - Question 7

The distance between the optical centre and point of convergence is called focal length in which of the following cases?

Detailed Solution for Light: Reflection & Refraction - 1 - Question 7

Parallel rays after refracting meet at the focus of a convex lens.

Light: Reflection & Refraction - 1 - Question 8

Rays from sun converge at a point 15 cm in front of a concave mirror. Where should an object be placed so that size of the image is exactly equal to the size of the object ?

Detailed Solution for Light: Reflection & Refraction - 1 - Question 8

As light rays from sun (u = ) converge at a point 15 cm in front of a concave mirror, hence focal length of concave mirror f = - 15 cm.
To form an image of exactly same size as that of an object, the object should be placed at the centre of curvature (u = R = 2f) of mirror. Hence, the object should be placed at 30 cm in front of mirror.

Light: Reflection & Refraction - 1 - Question 9

A magnified real image is formed by a convex lens when the obiect is at:

Detailed Solution for Light: Reflection & Refraction - 1 - Question 9

To get the real and magnified image for a convex lens, the object is placed in between F and 2F.

Light: Reflection & Refraction - 1 - Question 10

A virtual, erect and magnified image of an object is to be produced with a concave mirror of focal length 12 cm. Object may be placed at a distance of:

Detailed Solution for Light: Reflection & Refraction - 1 - Question 10

A concave mirror forms a virtual, erect and magnified image when an object is placed between pole and focus point of the mirror. As focal length of given concave mirror, hence object must be placed at a distance less than 12 cm i.e., u < 12 cm. Thus, the object may be placed at a distance of 10 cm from the mirror.

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