Test: Mirror Formulae - UPSC MCQ

# Test: Mirror Formulae - UPSC MCQ

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## 10 Questions MCQ Test Science & Technology for UPSC CSE - Test: Mirror Formulae

Test: Mirror Formulae for UPSC 2024 is part of Science & Technology for UPSC CSE preparation. The Test: Mirror Formulae questions and answers have been prepared according to the UPSC exam syllabus.The Test: Mirror Formulae MCQs are made for UPSC 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Mirror Formulae below.
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Test: Mirror Formulae - Question 1

### When a mirror is rotated through an angle θ, the reflected ray from it turns through an angle of

Detailed Solution for Test: Mirror Formulae - Question 1

Consider a plane-mirror and a fixed incident ray of light reflecting from the surface at an angle θi. Before the mirror has rotated, the angle of incidence is θ as is the angle of reflection. If the mirror is rotated through an angle φ the normal is rotated by an angle &phi and thus the angle of incidence increases to θ+φ. Therefore, the angle of reflection must also increase by φ to θ+φ The difference between the final angle of reflection and the initial angle of reflection and is 2φ.
Hence, For a fixed incident ray, the angle of the reflection is twice the angle through which the mirror has rotated: thetaf= 2φ

Test: Mirror Formulae - Question 2

### A concave mirror of focal length ‘f’ produces an image ‘n’ times farther than the object. If the image is real, then the distance of the object from the mirror is:​

Detailed Solution for Test: Mirror Formulae - Question 2

The correct option is B.

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Test: Mirror Formulae - Question 3

### If the magnification has a negative sign, the image formed by the concave mirror must be

Detailed Solution for Test: Mirror Formulae - Question 3

We know that, if the magnification value is negative sign in the concave mirror, then the image will be real and inverted. Especially, when you come to concave mirror, the images are formed at the left of the mirror. So, it forms real and inverted.

Test: Mirror Formulae - Question 4

When the image is of double size as the object, the magnification is

Detailed Solution for Test: Mirror Formulae - Question 4

Magnification is the ratio of height of the image to the height of the object. If the image size is double of object size, then the magnification is equal to two.

Test: Mirror Formulae - Question 5

When the image is of the same size as the object, the magnification is

Detailed Solution for Test: Mirror Formulae - Question 5

Explanation:
Magnification Definition:
Magnification is the ratio of the size of the image to the size of the object.
When the image is of the same size as the object:

• The size of the image will be equal to the size of the object.
• Therefore, the ratio of the size of the image to the size of the object is 1:1.
• So, the magnification is equal to one (1).

Test: Mirror Formulae - Question 6

Which one is correct as the new cartesian sign conventions ?

Detailed Solution for Test: Mirror Formulae - Question 6

Object is always kept on the left side of the mirror therefore its distance is always negative when taken from left of pole.

Test: Mirror Formulae - Question 7

An object is placed on the principal axis of a spherical mirror. The object distance u is:

Detailed Solution for Test: Mirror Formulae - Question 7

Understanding the Object Distance:
The object distance, denoted by 'u', is the distance between the object and the mirror along the principal axis.
It is measured from the pole of the mirror to the object.

Sign Convention for Object Distance:
In the sign convention for spherical mirrors, distances measured in the direction of incident light are considered positive, while distances measured opposite to the incident light are considered negative.

Placement of Object on Principal Axis:
When an object is placed on the principal axis of a spherical mirror, the object distance 'u' is considered negative.
This is because the object is placed opposite to the direction of incident light, towards the left of the mirror's pole.

Conclusion:
Therefore, when an object is placed on the principal axis of a spherical mirror, the object distance 'u' is definitely negative.

Test: Mirror Formulae - Question 8

The unit of linear magnification is

Detailed Solution for Test: Mirror Formulae - Question 8

Magnification is thr ratio of size of image to size of object and since it is a ratio of tel similar quantities hence it is unitless.

Test: Mirror Formulae - Question 9

An object 2 cm high is placed at a distance of 16 cm from a concave mirror, which produces a real image 3 cm high. What is the focal length of the mirror ?

Detailed Solution for Test: Mirror Formulae - Question 9

Correct option is A.

Test: Mirror Formulae - Question 10

The magnification of a convex mirror is always:

Detailed Solution for Test: Mirror Formulae - Question 10

The image formed by a convex mirror is always smaller in size than the object; hence its magnification is less than 1.

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## Science & Technology for UPSC CSE

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