Test: Compound Interest- 2
10 Questions MCQ Test CSAT Preparation for UPSC CSE | Test: Compound Interest- 2
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The compound interest on a certain sum for 2 years at 10% per annum is Rs. 525. The simple interest on the same sum for double the time at half the rate percent per annum is:
Let the sum be Rs. P
The effective annual rate of interest corresponding to a nominal rate of 6% per annum payable half-yearly is:
The Simple interest on a certain sum for 2 years at 20% per annum is Rs. 80. The corresponding compound interest is
P = (100×80)/(20×2) = 200
20%(200)= 40
20%(40) = 8
Required compound interest = 2(40)+ 8
= 88
A sum put out at 4% compound interest payable half-yearly amounts to Rs. 13265.10 in 1 1/2 years. The sum is:
Arun invested an amount of Rs. 20000 in a fixed deposit scheme for 2 years at compound interest rate 4 p.c.p.a. How much amount will Arun get on maturity of the fixed deposit?
The compound interest on Rs. 20,480 at 6 1/4 % per annum for 2 years 73 days, is:
A sum amounts to Rs. 882 in 2 years at 5% compound interest. The sum is
Compound interest = Amount -Principal
Amount = P(1 + R/100)N
882 = P(1+5/100)2
= 882 × 20/21 × 20/21
P = 800
Simple interest on a certain sum of money for 4 years at 5% per annum is half the compound interest on Rs. 3000 for 2 years at 10% per annum. The sum placed on simple interest is:
C.I = P[(1 + r/100)n - 1]
C.I = 3000[(1 + 0.10)2 - 1]
= 3000(1.21 - 1)
⇒ 3000 * 0.21
⇒ 630
S.I = 630/2
⇒ 315
As we know that, P = (SI * 100)/(R * T)
⇒ (315 * 100)/(4 * 5)
⇒ 1575
The least number of complete years in which a sum of money put out at 20% compound interest will be more than doubled is
P [1 + (r/100)]n > 2P
⇒ P [1 + (20/100)]n > 2P
[1 + (2/10) ]n > 2
[12 / 10]n > 2
[6/5]n > 2
{6/5 * 6/5 * 6/5 * 6/5} > 2
∴ n = 4
The difference between simple interest and compound on Rs. 2400 for one year at 10% per annum reckoned half-yearly is:
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