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QUESTION: 1

The compound interest on a certain sum for 2 years at 10% per annum is Rs. 525. The simple interest on the same sum for double the time at half the rate percent per annum is:

Solution:

Let the sum be Rs. P

QUESTION: 2

The effective annual rate of interest corresponding to a nominal rate of 6% per annum payable half-yearly is:

Solution:

QUESTION: 3

The Simple interest on a certain sum for 2 years at 20% per annum is Rs. 80. The corresponding compound interest is

Solution:

P = (100×80)/(20×2) = 200

20%(200)= 40

20%(40) = 8

Required compound interest = 2(40)+ 8

= 88

QUESTION: 4

A sum put out at 4% compound interest payable half-yearly amounts to Rs. 13265.10 in 1 1/2 years. The sum is:

Solution:

QUESTION: 5

Arun invested an amount of Rs. 20000 in a fixed deposit scheme for 2 years at compound interest rate 4 p.c.p.a. How much amount will Arun get on maturity of the fixed deposit?

Solution:

QUESTION: 6

The compound interest on Rs. 20,480 at 6 1/4 % per annum for 2 years 73 days, is:

Solution:

QUESTION: 7

A sum amounts to Rs. 882 in 2 years at 5% compound interest. The sum is

Solution:

Compound interest = Amount -Principal

Amount = P(1 + R/100)^{N}

882 = P(1+5/100)2

= 882 × 20/21 × 20/21

P = 800

QUESTION: 8

Simple interest on a certain sum of money for 4 years at 5% per annum is half the compound interest on Rs. 3000 for 2 years at 10% per annum. The sum placed on simple interest is:

Solution:

C.I = P[(1 + r/100)n - 1]

C.I = 3000[(1 + 0.10)2 - 1]

= 3000(1.21 - 1)

⇒ 3000 * 0.21

⇒ 630

S.I = 630/2

⇒ 315

As we know that, P = (SI * 100)/(R * T)

⇒ (315 * 100)/(4 * 5)

⇒ 1575

QUESTION: 9

The least number of complete years in which a sum of money put out at 20% compound interest will be more than doubled is

Solution:

P [1 + (r/100)]^{n }> 2P

⇒ P [1 + (20/100)]^{n} > 2P

[1 + (2/10) ]^{n} > 2

[12 / 10]n > 2

[6/5]n > 2

{6/5 * 6/5 * 6/5 * 6/5} > 2

∴ n = 4

QUESTION: 10

The difference between simple interest and compound on Rs. 2400 for one year at 10% per annum reckoned half-yearly is:

Solution:

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