10 Questions MCQ Test CSAT Preparation - Test: Probability- 2
Test: Probability- 2 for UPSC 2023 is part of CSAT Preparation preparation. The Test: Probability- 2 questions and answers have been
prepared according to the UPSC exam syllabus.The Test: Probability- 2 MCQs are made for UPSC 2023 Exam. Find important
definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Probability- 2 below.
Solutions of Test: Probability- 2 questions in English are available as part of our CSAT Preparation for UPSC & Test: Probability- 2 solutions in
Hindi for CSAT Preparation course. Download more important topics, notes, lectures and mock
test series for UPSC Exam by signing up for free. Attempt Test: Probability- 2 | 10 questions in 10 minutes | Mock test for UPSC preparation | Free important questions MCQ to study CSAT Preparation for UPSC Exam | Download free PDF with solutions
A card is randomly drawn from a deck of 52 cards. What is the probability getting either a King or a Diamond?
Detailed Solution for Test: Probability- 2 - Question 8
Total number of cards = 52
Total Number of King Cards = 4
Total Number of Diamond Cards = 13
Total Number of Cards which are both King and Diamond = 1
Here a card can be both a Diamond card and a King. Hence these are not mutually exclusive events. (Reference : mutually exclusive events) . By Addition Theorem of Probability, we have P(King or a Diamond) = P(King) + P(Diamond) – P(King and Diamond)
John and Dani go for an interview for two vacancies. The probability for the selection of John is 1/3 and whereas the probability for the selection of Dani is 1/5. What is the probability that none of them are selected?
Detailed Solution for Test: Probability- 2 - Question 9
John and Dani go for an interview for two vacancies. The probability for the selection of John is 1/3 and whereas the probability for the selection of Dani is 1/5. What is the probability that only one of them is selected?
Detailed Solution for Test: Probability- 2 - Question 10
The correct answer is B as
probability of one of them being selected, imply either John must be selected and Dani must not or Dani must be selected and John must not.
The probability of John's selection is 1/3, so that of his disselection is (1-1/3) = 2/3.
The probability of Dani's selection is 1/5, so that of his disselection is (1-1/5) = 4/5.
The probability of John's selection and Dani's disselection is 1/3 x 4/5 = 4/15.
The probability of Dani's selection and John's disselection is 2/3 x 1/5 = 2/15.
So the required probability is 4/15 + 2/15 = 6/15 = 2/5.
In this test you can find the Exam questions for Test: Probability- 2 solved & explained in the simplest way possible.
Besides giving Questions and answers for Test: Probability- 2, EduRev gives you an ample number of Online tests for practice
Find all the important questions for Probability- 2 at EduRev.Get fully prepared for Probability- 2 with EduRev's comprehensive question bank and test resources.
Our platform offers a diverse range of question papers covering various topics within the Probability- 2 syllabus.
Whether you need to review specific subjects or assess your overall readiness, EduRev has you covered.
The questions are designed to challenge you and help you gain confidence in tackling the actual exam.
Maximize your chances of success by utilizing EduRev's extensive collection of Probability- 2 resources.
Probability- 2 MCQs with Answers
Prepare for the Probability- 2 within the UPSC exam with comprehensive MCQs and answers at EduRev.
Our platform offers a wide range of practice papers, question papers, and mock tests to familiarize you with the exam pattern and syllabus.
Access the best books, study materials, and notes curated by toppers to enhance your preparation.
Stay updated with the exam date and receive expert preparation tips and paper analysis.
Visit EduRev's official website today and access a wealth of videos and coaching resources to excel in your exam.
Online Tests for Probability- 2 CSAT Preparation
Practice with a wide array of question papers that follow the exam pattern and syllabus.
Our platform offers a user-friendly interface, allowing you to track your progress and identify areas for improvement.
Access detailed solutions and explanations for each test to enhance your understanding of concepts.
With EduRev's Online Tests, you can build confidence, boost your performance, and ace Probability- 2 with ease.
Join thousands of successful students who have benefited from our trusted online resources.