10 Questions MCQ Test Science & Technology for UPSC CSE - MCQ : Work And Energy - 1
MCQ : Work And Energy - 1 for UPSC 2023 is part of Science & Technology for UPSC CSE preparation. The MCQ : Work And Energy - 1 questions and answers have been
prepared according to the UPSC exam syllabus.The MCQ : Work And Energy - 1 MCQs are made for UPSC 2023 Exam. Find important
definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for MCQ : Work And Energy - 1 below.
Solutions of MCQ : Work And Energy - 1 questions in English are available as part of our Science & Technology for UPSC CSE for UPSC & MCQ : Work And Energy - 1 solutions in
Hindi for Science & Technology for UPSC CSE course. Download more important topics, notes, lectures and mock
test series for UPSC Exam by signing up for free. Attempt MCQ : Work And Energy - 1 | 10 questions in 10 minutes | Mock test for UPSC preparation | Free important questions MCQ to study Science & Technology for UPSC CSE for UPSC Exam | Download free PDF with solutions
If 1 newton of force displaces a body by 1 m, the work done is
Detailed Solution for MCQ : Work And Energy - 1 - Question 1
One joule equals the work done ( or energy expended) by a force of One Newton (N) acting over a distance of one meter (m). One Newton equals a force that produces an acceleration of one meter per second (s) per second on a one Kilogram (Kg) mass. Therefore, one joule equals one Newton meter.
An object of mass 1kg has a PE of 1J relative to the ground when it is at a height of:
Detailed Solution for MCQ : Work And Energy - 1 - Question 4
Mass of the Body (m) = 1 Kg.
Potential energy (E) = 1 Joule.
Acceleration Due to Gravity (g) = 9.8 m/s²
Potential energy is the energy which a body posses due to virtue of Position.
Formula of Potential energy
P.E = Mgh
M denotes Mass of the Body.
g denotes Acceleration Due to Gravity.
h Denotes the Height to which the body is raisen.
From Potential energy Formula,
⇒ P.E = Mgh
⇒ E = M x g x h
⇒ E = 1 kg x 9.8 m/s² x h meters
⇒ E = 1 x 9.8 x h
⇒ E = 9.8 x h
∵ [ Potential Energy = 1 joule.]
⇒ 1 = 9.8 x h
⇒ h = 1/9.8
⇒ h = 10/98
⇒ h = 0.102 Meters.
So, The Height at which Potential Energy is 1 joule is 0.102 meters.
A bullet entering a metal block of 30 cm length stops on reaching 25 cm. The energy with the bullet will be lost
Detailed Solution for MCQ : Work And Energy - 1 - Question 5
To determine where the energy of the bullet is lost, we need to consider the different forms of energy transfer involved. 1. Kinetic Energy: The bullet initially possesses kinetic energy as it moves towards the metal block. 2. Momentum Transfer: When the bullet collides with the metal block, it imparts momentum to the block. 3. Heat Energy: Some of the kinetic energy of the bullet is also converted into heat energy during the collision. Given that the bullet stops on reaching 25 cm inside the metal block, we can conclude that the bullet loses all its kinetic energy and comes to rest. Therefore, the energy with the bullet is lost in both imparting momentum to the block and in the form of heat. Hence, the correct answer is option C: Both (a) and (b). To summarize: - The bullet loses its kinetic energy upon colliding with the metal block. - The momentum of the bullet is transferred to the block, causing the block to move. - Some of the kinetic energy is converted into heat energy during the collision. Note: It is important to note that this solution assumes an idealized scenario where no other external factors, such as friction or air resistance, are present.
Detailed Solution for MCQ : Work And Energy - 1 - Question 6
When a flying airplane is in motion, it possesses both potential and kinetic energy. Here's a detailed explanation of why it has both types of energy: Potential Energy: - Potential energy is the energy an object possesses due to its position or state. - In the case of a flying airplane, it has potential energy due to its altitude or height from the ground. - The higher the airplane is above the ground, the greater its potential energy. Kinetic Energy: - Kinetic energy is the energy an object possesses due to its motion. - In the case of a flying airplane, it has kinetic energy due to its forward motion. - The faster the airplane is moving, the greater its kinetic energy. Combination of Potential and Kinetic Energy: - As the airplane flies, it converts potential energy into kinetic energy and vice versa. - When the airplane gains altitude, it increases its potential energy while decreasing its kinetic energy. - When the airplane descends, it decreases its potential energy while increasing its kinetic energy. - At any given moment during flight, the airplane has a combination of both potential and kinetic energy. Conclusion: - A flying airplane possesses both potential and kinetic energy simultaneously. - Therefore, the correct answer is option C: both potential and kinetic energy.
Two particles of masses 1 g and 4 g have equal kinetic energies. What is the ratio between their momenta?
Detailed Solution for MCQ : Work And Energy - 1 - Question 8
Given: Mass of particle 1 (m1) = 1 g = 0.001 kg Mass of particle 2 (m2) = 4 g = 0.004 kg Kinetic energy of both particles is equal. We know that the kinetic energy of a particle is given by the formula: Kinetic Energy = (1/2) * (mass of the particle) * (velocity of the particle)^2 Let the velocities of the two particles be v1 and v2 respectively. Since the kinetic energy of both particles is equal, we have: (1/2) * m1 * v1^2 = (1/2) * m2 * v2^2 Simplifying the equation: m1 * v1^2 = m2 * v2^2 Taking the square root of both sides of the equation: v1 = sqrt((m2 * v2^2) / m1) The momentum of a particle is given by the formula: Momentum = mass * velocity Therefore, the momentum of particle 1 (p1) is given by: p1 = m1 * v1 Similarly, the momentum of particle 2 (p2) is given by: p2 = m2 * v2 To find the ratio between their momenta, we can divide the equation for p1 by the equation for p2: (p1 / p2) = (m1 * v1) / (m2 * v2) Substituting the value of v1 from the equation derived earlier: (p1 / p2) = (m1 * sqrt((m2 * v2^2) / m1)) / (m2 * v2) Simplifying the equation: (p1 / p2) = sqrt((m1 / m2) * (v2 / v2)) Since v2 / v2 is equal to 1, we have: (p1 / p2) = sqrt(m1 / m2) Substituting the given values: (p1 / p2) = sqrt(0.001 / 0.004) Simplifying the equation: (p1 / p2) = sqrt(1/4) Taking the square root, we get: (p1 / p2) = 1/2 Therefore, the ratio between the momenta of the two particles is 1 : 2. Answer: C. 1 : 2
Detailed Solution for MCQ : Work And Energy - 1 - Question 9
To determine the correct answer, we need to convert 1 kWh (kilowatt-hour) to joules. 1. Understand the conversion: - 1 kilowatt-hour (kWh) is a unit of energy equal to 1 kilowatt (kW) of power used for 1 hour. - To convert kWh to joules, we need to multiply the number of kilowatt-hours by the conversion factor. 2. Conversion factor: - 1 kilowatt-hour (kWh) is equal to 3.6 x 10^6 joules. - The conversion factor is derived from the relationship between kilowatts (kW) and joules (J). 3. Calculate the conversion: - Multiply 1 kWh by the conversion factor of 3.6 x 10^6 joules/kWh. - 1 kWh * 3.6 x 10^6 joules/kWh = 3.6 x 10^6 joules. 4. Compare the options: - Option A: 3.6 x 10^6 joule - This matches the calculation above, so it is the correct answer. - Option B: 3.6 x 10^3 joule - This is incorrect. The correct conversion factor is 3.6 x 10^6 joules. - Option C: 3 x 19^8 joule - This is incorrect. The conversion factor does not involve the number 19. - Option D: 300 joule - This is incorrect. The correct conversion is much larger than 300 joules. Therefore, the correct answer is A: 3.6 x 10^6 joule.
In this test you can find the Exam questions for MCQ : Work And Energy - 1 solved & explained in the simplest way possible.
Besides giving Questions and answers for MCQ : Work And Energy - 1, EduRev gives you an ample number of Online tests for practice
Find all the important questions for MCQ : Work And Energy - 1 at EduRev.Get fully prepared for MCQ : Work And Energy - 1 with EduRev's comprehensive question bank and test resources.
Our platform offers a diverse range of question papers covering various topics within the MCQ : Work And Energy - 1 syllabus.
Whether you need to review specific subjects or assess your overall readiness, EduRev has you covered.
The questions are designed to challenge you and help you gain confidence in tackling the actual exam.
Maximize your chances of success by utilizing EduRev's extensive collection of MCQ : Work And Energy - 1 resources.
MCQ : Work And Energy - 1
Prepare for the MCQ : Work And Energy - 1 within the UPSC exam with comprehensive MCQs and answers at EduRev.
Our platform offers a wide range of practice papers, question papers, and mock tests to familiarize you with the exam pattern and syllabus.
Access the best books, study materials, and notes curated by toppers to enhance your preparation.
Stay updated with the exam date and receive expert preparation tips and paper analysis.
Visit EduRev's official website today and access a wealth of videos and coaching resources to excel in your exam.
Online Tests for MCQ : Work And Energy - 1 Science & Technology for UPSC CSE
Practice with a wide array of question papers that follow the exam pattern and syllabus.
Our platform offers a user-friendly interface, allowing you to track your progress and identify areas for improvement.
Access detailed solutions and explanations for each test to enhance your understanding of concepts.
With EduRev's Online Tests, you can build confidence, boost your performance, and ace MCQ : Work And Energy - 1 with ease.
Join thousands of successful students who have benefited from our trusted online resources.