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Test: Simplification- 2 - CUET Commerce MCQ


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21 Questions MCQ Test General Test Preparation for CUET - Test: Simplification- 2

Test: Simplification- 2 for CUET Commerce 2024 is part of General Test Preparation for CUET preparation. The Test: Simplification- 2 questions and answers have been prepared according to the CUET Commerce exam syllabus.The Test: Simplification- 2 MCQs are made for CUET Commerce 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Simplification- 2 below.
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Test: Simplification- 2 - Question 1

47.932 + 56 + 97.168 – 67 – 78.3 – 22.7

Detailed Solution for Test: Simplification- 2 - Question 1

Expression:

( 47.932 + 56 + 97.168 - 67 - 78.3 - 22.7 )

Step 1: Add the positive terms:

( 47.932 + 56 + 97.168 = 201.1 )

Step 2: Add the negative terms:

( 67 + 78.3 + 22.7 = 168 )

Step 3: Subtract the sum of negative terms from the sum of positive terms:

( 201.1 - 168 = 33.1 )

Final Answer: The result of the expression is 33.1.

Test: Simplification- 2 - Question 2

4789300 x 11

Detailed Solution for Test: Simplification- 2 - Question 2
  • To solve 4789300 x 11, we can break it down.
  • First, multiply 4789300 by 10, which gives 47893000.
  • Next, add 4789300 to that result (because 11 is 10 + 1).
  • So, 47893000 + 4789300 = 52682300.
  • The correct answer is 52682300, which is option 1.
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Test: Simplification- 2 - Question 3

Detailed Solution for Test: Simplification- 2 - Question 3

To solve the expression:

Step 1: Convert the mixed fraction to a decimal.

14   = 6.25)

Now, substitute (6.25) into the expression:

Expression: (6.25 + 0.25 + 0.75 - 0.3125)

Step 2: Calculate each operation:

  • (6.25 + 0.25 = 6.5)
  • (6.5 + 0.75 = 7.25)
  • (7.25 - 0.3125 = 6.9375)

Answer: a) 6.9375

Test: Simplification- 2 - Question 4

Detailed Solution for Test: Simplification- 2 - Question 4

Test: Simplification- 2 - Question 5

Test: Simplification- 2 - Question 6

Detailed Solution for Test: Simplification- 2 - Question 6

Given equation:
√169 × 256 = (?)² × 13

Step 1: Calculate the square root of 169
√169 = 13
Substitute this value back into the equation:
13 × 256 = (?)² × 13

Step 2: Divide both sides by 13
256 = (?)²

Step 3: Solve for ( ? )
Taking the square root of both sides:
? = √256 = 16

The answer is: d) 16

Test: Simplification- 2 - Question 7

What should come in the place of question mark (?) in the following equation? 

Detailed Solution for Test: Simplification- 2 - Question 7

The correct option is C.
(7*x)2/49 = _/81
⇒ 49*x2/49 = _/81
⇒ x2 = _/81
⇒ x2 = 9
⇒ x = 3

Test: Simplification- 2 - Question 8

Simplify:

Detailed Solution for Test: Simplification- 2 - Question 8

Given expression = 10 1/2 -[8 1/2+{6-(7–2)}]

= 10 1/2 -[8 1/2+{6–5}]

= 10 1/2 -[8 1/2+1]

= 10 1/2 -9 1/2

= 1

Test: Simplification- 2 - Question 9

What approximate value should come in place of the question mark (?) in the given questions?

14.998% of 619.999 =?

Detailed Solution for Test: Simplification- 2 - Question 9

Given,

14.998% of 619.999 =?

It can also be approximated as

15% of 600=?

= ×600

= 90 ≈ 95

Test: Simplification- 2 - Question 10

Find the value of x:

Detailed Solution for Test: Simplification- 2 - Question 10

Given,

23 × 34 × 1080 ÷ 15 = 6x

⇒ 23 × 34 × 72 = 6x

⇒ 23 × 34 × (2 × 62) = 6x

⇒ 24 × 34 × 62 = 6x

⇒ (2 × 3)4 × 62 = 6x           [∵ xm × ym = (xy)m]

⇒ 64 × 62 = 6x

⇒ 6(4 + 2) = 6x

⇒ x = 6

Test: Simplification- 2 - Question 11

Detailed Solution for Test: Simplification- 2 - Question 11
  1. Start with the innermost part: 111 + 111 × 111

    111×111=12321
    111+12321=12432
  2. Next, calculate 111÷12432, which is approximately 0 since 12432 is much larger than 111.

  3. Substitute back into the expression:

    111−[111+{111×0}] = 111−[111+0] = 111−111 = 0

Answer: 0 (Option a)

Test: Simplification- 2 - Question 12

Find the value of 

Detailed Solution for Test: Simplification- 2 - Question 12

x=
x2=380+x
x2-x-380=0
(x-20)(x+19)
 

Test: Simplification- 2 - Question 13

Which one of the following fractions is the greatest?

Test: Simplification- 2 - Question 14

The sum of the digits of a two-digit number is 9. If the digits are reversed, the number is decreased by 45. Find the number.

Detailed Solution for Test: Simplification- 2 - Question 14



Test: Simplification- 2 - Question 15

The sum of the digits of a two-digit number is 8. If the digits are reversed, the number is decreased by 54. Find the number.

Test: Simplification- 2 - Question 16

If the sum of a number and its square is 156, what is the number?

Detailed Solution for Test: Simplification- 2 - Question 16

Let the number be x.
x+x2=156
x2+x−156=0
(x−12)(x+13)=0

x+13=0
x=−13 (Since x is a natural number)
x−12=0
x=12

Test: Simplification- 2 - Question 17

What is the number in the unit place in (5427)641?

Detailed Solution for Test: Simplification- 2 - Question 17

The correct answer is B as the unit place will be 7 only .

Test: Simplification- 2 - Question 18

A number when divided by 1092 gives a remainder 60. What remainder would be obtained by dividing the same number by 28?

Detailed Solution for Test: Simplification- 2 - Question 18
In these type of of questions we apply a trick by just dividing the given remainder by given no.
60÷28
remainder will come( 4)
Test: Simplification- 2 - Question 19

The sum of squares of two numbers is 85 and the square of first number is 77 more than by the square of second number. The product of the two numbers is

Detailed Solution for Test: Simplification- 2 - Question 19

Test: Simplification- 2 - Question 20

Find the number in the unit place in (321)321 x (325)326.

Detailed Solution for Test: Simplification- 2 - Question 20

321 raised to 321=1 in unit digit and any number ending in 5 raised to any number has always 5 as unit digit, so 1×5=5

Test: Simplification- 2 - Question 21

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