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Test: Simplification- 1 - CUET Commerce MCQ


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20 Questions MCQ Test General Test Preparation for CUET - Test: Simplification- 1

Test: Simplification- 1 for CUET Commerce 2024 is part of General Test Preparation for CUET preparation. The Test: Simplification- 1 questions and answers have been prepared according to the CUET Commerce exam syllabus.The Test: Simplification- 1 MCQs are made for CUET Commerce 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Simplification- 1 below.
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Test: Simplification- 1 - Question 1

7.8 + 5.4 x 8.2 = ?

Test: Simplification- 1 - Question 2

8% of 800 x ? = 224

Detailed Solution for Test: Simplification- 1 - Question 2
  • First, calculate 8% of 800: 8/100 * 800 = 64.
  • Now, the equation is 64 * ? = 224.
  • To solve for ?, divide both sides by 64: ? = 224 / 64.
  • This simplifies to ? = 3.5.
  • So, the correct answer is 3.5, which corresponds to option 2.
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Test: Simplification- 1 - Question 3

∛185193 = ?

Test: Simplification- 1 - Question 4

What will come in the place of question mark (?) in the following question?

=

Detailed Solution for Test: Simplification- 1 - Question 4

Correct option is D. 9

Test: Simplification- 1 - Question 5

√7921 x √? = 6942

Test: Simplification- 1 - Question 6

856 x 567 = ?

Detailed Solution for Test: Simplification- 1 - Question 6
- Step 1: Multiply 856 by 500
    856 × 500 = 428,000
- Step 2: Multiply 856 by 60
    856 × 60 = 51,360
- Step 3: Multiply 856 by 7
    856 × 7 = 5,992
- Total: Add all results
    428,000 + 51,360 + 5,992 = 485,352

Therefore, the correct answer is option d: 485352.
Test: Simplification- 1 - Question 7

(?)3 x (55) ÷ 225 = 3000

Test: Simplification- 1 - Question 8

4/439 + ? + 354 = 865

Test: Simplification- 1 - Question 9

Test: Simplification- 1 - Question 10

Detailed Solution for Test: Simplification- 1 - Question 10

On solving, we will get x = 3 or x = -2
Ignoring the negative value answer is 3.

Test: Simplification- 1 - Question 11

82/3 is equal to  

Test: Simplification- 1 - Question 12

√8 - √4 - √2 = ?

Detailed Solution for Test: Simplification- 1 - Question 12

√8-√4-√2=√2×4-√4-√2 =√4-√2=√2-2 ans

Test: Simplification- 1 - Question 13

Detailed Solution for Test: Simplification- 1 - Question 13

 5.5 x 6.4 / 0.4 =  35.2 / 0.4 = 88 

Test: Simplification- 1 - Question 14

(764 x ?) ÷ 250 = 382

Detailed Solution for Test: Simplification- 1 - Question 14

Solution:

Given equation:

(764 x ?) ÷ 250 = 382

Solving for ?:

(764 x ?) = 382 x 250

? = (382 x 250) / 764

? = 125

Therefore, the value of ? is 125.

So, the correct answer is B: 125.

Test: Simplification- 1 - Question 15

6156 / √? x 53 = 4028

Detailed Solution for Test: Simplification- 1 - Question 15

C is the correct option. Solution- 
4028÷53=76
6156÷76=81
So the value needed is a square of 81 which is 6561.

Test: Simplification- 1 - Question 16

[(7 x 9) + (2 x 12) + 3] / [(12 x 3) + (81/9)] = ?

Detailed Solution for Test: Simplification- 1 - Question 16

[(7 x 9) + (2 x 12) + 3] / [(12 x 3) + (81 / 9)]
= (63 + 24 + 3) / (36 + 9)
= 90/45
= 2

Test: Simplification- 1 - Question 17

(169 – 144)½ ÷ (64 + 36)½ = ?

Detailed Solution for Test: Simplification- 1 - Question 17

To solve the given expression:

1. Calculate the values inside the parentheses first: √(169 - 144 = 25) and √(64 + 36 = 100).
2. Now simplify the expression further: √25/√100 .
3. Calculate the square roots: 5/10
4. Finally, divide the two results: 0.5

Therefore, the correct answer is A: 0.5.

Test: Simplification- 1 - Question 18

–224 + (–314) x (–9) = ?

Detailed Solution for Test: Simplification- 1 - Question 18

Option (a) 2602 is correct. 

Explanation:- 
 

{ Given,   

-224 + ( - 314) * (-9) 

 According to BODMASS ; 

=>  -224 -314  * -9

=>  -224 +  2826
=>   2602

Test: Simplification- 1 - Question 19

(?)² / 4 + √1521 = 1063

Test: Simplification- 1 - Question 20

4/7 x 2/3 x ? = 1008

Detailed Solution for Test: Simplification- 1 - Question 20

8/21 * x = 1008

x = 21168 / 8

x = 2646

 

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