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Test: Problems On Ages - 1 - GMAT MCQ


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10 Questions MCQ Test Quantitative for GMAT - Test: Problems On Ages - 1

Test: Problems On Ages - 1 for GMAT 2024 is part of Quantitative for GMAT preparation. The Test: Problems On Ages - 1 questions and answers have been prepared according to the GMAT exam syllabus.The Test: Problems On Ages - 1 MCQs are made for GMAT 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Problems On Ages - 1 below.
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Test: Problems On Ages - 1 - Question 1

Ten years ago, P was half of Q's age. If the ratio of their present ages is 3:4, what will be the total of their present ages?

Detailed Solution for Test: Problems On Ages - 1 - Question 1

Let present age of P and Q be 3x
and  4x  respectively.
Ten years ago, P was half of Q's age

Total of their present ages
=3x+4x=7x=7×5=35

Test: Problems On Ages - 1 - Question 2

Father is aged three times more than his son Sunil. After 8 years, he would be two and a half times of Sunil's age. After further 8 years, how many times would he be of Sunil's age?

Detailed Solution for Test: Problems On Ages - 1 - Question 2

Assume that Sunil's present age 
= x.
Then, father's present age  =3x + x = 4x

After 8 years, father's age =  times of Sunils' age

After further  8  years,
Sunil's age  = x + 8 + 8 = 8 + 8 + 8 = 24
Father's age  = 4 x + 8 + 8 = 4 x 8 + 8 + 8 = 48

Father's age/Sunil's age = 48/24 = 2

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Test: Problems On Ages - 1 - Question 3

A man's age is 125% of what it was 10 years ago, but  of what it will be after 10years. What is his present age?

Detailed Solution for Test: Problems On Ages - 1 - Question 3
  • Let the present age of the man = y
  • Man's age 10 years ago = (y-10)
  • Man's age 10 years later = (y+10)

As mentioned in the question, 

  • 125% of (y-10) = 250/3% of (y+10)
  • 125/100 x (y - 10) = 250/3 x 1/100 x (y+10)

After Calculating, we get

  • 5/4x(y-10) = 5/6 x (y+10)
  • 6y - 60 = 4y +40
  • 2y = 100
  • y = 50
     
Test: Problems On Ages - 1 - Question 4

A man is 24 years older than his son. In two years, his age will be twice the age of his son. What is the present age of his son?

Detailed Solution for Test: Problems On Ages - 1 - Question 4

Let present age of the son = x years
Then, present age the man = ( x + 24 ) years

Given that, in 2 years, man's age will be twice the age of his son
⇒(x+24)+2=2(x+2)
⇒x=22

Test: Problems On Ages - 1 - Question 5

Present ages of Kiran and Syam are in the ratio of 5 : 4 respectively. Three years hence, the ratio of their ages will become 11 : 9 respectively. What is Syam's present age in years?

Detailed Solution for Test: Problems On Ages - 1 - Question 5

Ratio of the present age of Kiran and Syam = 5 : 4

Let present age of Kiran = 5x
Present age of Syam = 4x
After 3 years, ratio of their ages = 11 : 9
⇒ ( 5 x + 3 ) : ( 4 x + 3 ) = 11 : 9
⇒ 9 ( 5 x + 3 ) = 11 ( 4 x + 3 )
⇒ 45 x + 27 = 44 x + 33
⇒ x = 33 − 27 = 6
Syam's present age = 4 x = 4 × 6 = 24

Test: Problems On Ages - 1 - Question 6

The sum of ages of 5 children born at the intervals of 3 years each is 50 years. Find out the age of the youngest child?

Detailed Solution for Test: Problems On Ages - 1 - Question 6

Let the age of the youngest child = x
Then, the ages of 5 children can be written as x , ( x + 3 ) , ( x + 6 ) , ( x + 9 ) and ( x + 12 )
x + ( x + 3 ) + ( x + 6 ) + ( x + 9 ) + ( x + 12 ) = 50
⇒ 5 x + 30 = 50
⇒ 5 x = 20

Test: Problems On Ages - 1 - Question 7

A is two years older than B who is twice as old as C. The total of the ages of A, B and C is 27 . How old is B?

Detailed Solution for Test: Problems On Ages - 1 - Question 7

Let age of C = x .

Then, Age of B = 2x
Age of A = 2 + 2x
Total age of A,B and C =27

B's age =2x=2×5=10

Test: Problems On Ages - 1 - Question 8

The average age of a class of 22 students is 21 years. The average increased by 1 when the teacher's age also included. What is the age of the teacher?

Detailed Solution for Test: Problems On Ages - 1 - Question 8

Total age of all students 
= 22 × 21

Total age of all students + Age of the teacher  = 23 × 22

Test: Problems On Ages - 1 - Question 9

A father said to his son, "I was as old as you are at the present at the time of your birth". If the father's age is 38 years now, what was the son's age five years back?

Detailed Solution for Test: Problems On Ages - 1 - Question 9

Let son's present age be x years. Then,

Son's age 5  years back = 19 − 5 = 14

Test: Problems On Ages - 1 - Question 10

Ayisha's age is 1 / 6 th of her father's age. Ayisha's father's age will be twice Shankar's age after 10 years. If Shankar's eight birthdays was celebrated two years before, then what is Ayisha's present age.

Detailed Solution for Test: Problems On Ages - 1 - Question 10

Let Ayisha's present age = x
Then, her father's age = 6 x
Given that Ayisha's father's age will be twice Shankar's age after 10 years. Therefore, Shankar's age after 10 years

Also given that Shankar's eight birthdays was celebrated two years before. Therefore, Shankar's age after 10 years = 8 + 12 = 20

Therefore, Ayisha's present age =5 years

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