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Page 1
CBSE VI | Mathematics
Sample Paper 4 – Solution
CBSE Board
Class VI Mathematics
Term I
Sample Paper 4 – Solution
Time: 2 ½ hours Total Marks: 80
Section A
1. Correct answer: B
The number just before 1000000 is one less than 1000000.
The required number = 1000000 - 1 = 999999.
2. Correct answer: B
On a number line, –110 lies next to –111 on the right. Therefore, the successor of –111
is –110.
3. Correct answer: A
The given fraction is
15
18
Dividing the numerator and denominator by 3, we get,
15 3 5
18 3 6
?
?
?
Thus,
15
18
is equivalent to
5
6
.
4. Correct answer: D
The numbers 138 and 432 are divisible by both 2 and 3 and hence are divisible by 6.
The number 653 is neither divisible by 3 nor by 2 and hence is not divisible by 6.
Now, consider the number 531.
The sum of the digits of the number 531 is divisible by 3, so 531 is divisible by 3.
However, it is not an even number, so it is not divisible by 2.
Thus, 531 is divisible by 3 but not by 6.
5. Correct answer: B
1 1 4 ( 1) 3 1
3 12 12 12 4
? ? ? ??
? ? ? ?
??
??
Page 2
CBSE VI | Mathematics
Sample Paper 4 – Solution
CBSE Board
Class VI Mathematics
Term I
Sample Paper 4 – Solution
Time: 2 ½ hours Total Marks: 80
Section A
1. Correct answer: B
The number just before 1000000 is one less than 1000000.
The required number = 1000000 - 1 = 999999.
2. Correct answer: B
On a number line, –110 lies next to –111 on the right. Therefore, the successor of –111
is –110.
3. Correct answer: A
The given fraction is
15
18
Dividing the numerator and denominator by 3, we get,
15 3 5
18 3 6
?
?
?
Thus,
15
18
is equivalent to
5
6
.
4. Correct answer: D
The numbers 138 and 432 are divisible by both 2 and 3 and hence are divisible by 6.
The number 653 is neither divisible by 3 nor by 2 and hence is not divisible by 6.
Now, consider the number 531.
The sum of the digits of the number 531 is divisible by 3, so 531 is divisible by 3.
However, it is not an even number, so it is not divisible by 2.
Thus, 531 is divisible by 3 but not by 6.
5. Correct answer: B
1 1 4 ( 1) 3 1
3 12 12 12 4
? ? ? ??
? ? ? ?
??
??
CBSE VI | Mathematics
Sample Paper 4 – Solution
6. Correct answer: C
Every quadrilateral has four pairs of adjacent angles.
Example: For the quadrilateral ABCD, the pairs of adjacent angles are
(i) ? A, ? B (ii) ? B, ? C (iii) ? C, ? D (iv) ? D, ? A.
7. Correct answer: A
Starting from zero, a jump of 4 units is made to the right to reach 4. Then, 3 jumps
(each of 1 unit) are taken to the right to reach 7. So, this number line represents 4 + 3.
8. Correct Answer: A
If the number can be divided by the numbers 2 and 3, then that number is divisible by
6.
9. Correct answer: B
CCC stands for 300
And XL stands for 40
So, CCCXL stands for 300 + 40 = 340
10. Correct answer: A
When hour hand goes from 3 to 9 clockwise, it will rotate by 2 right angles or 180º.
Fraction =
180º 1
360º 2
?
11. Correct answer: A
1 + 0 = 1
? It does not represent zero
12. Correct answer: B
The given shape is cuboid.
Page 3
CBSE VI | Mathematics
Sample Paper 4 – Solution
CBSE Board
Class VI Mathematics
Term I
Sample Paper 4 – Solution
Time: 2 ½ hours Total Marks: 80
Section A
1. Correct answer: B
The number just before 1000000 is one less than 1000000.
The required number = 1000000 - 1 = 999999.
2. Correct answer: B
On a number line, –110 lies next to –111 on the right. Therefore, the successor of –111
is –110.
3. Correct answer: A
The given fraction is
15
18
Dividing the numerator and denominator by 3, we get,
15 3 5
18 3 6
?
?
?
Thus,
15
18
is equivalent to
5
6
.
4. Correct answer: D
The numbers 138 and 432 are divisible by both 2 and 3 and hence are divisible by 6.
The number 653 is neither divisible by 3 nor by 2 and hence is not divisible by 6.
Now, consider the number 531.
The sum of the digits of the number 531 is divisible by 3, so 531 is divisible by 3.
However, it is not an even number, so it is not divisible by 2.
Thus, 531 is divisible by 3 but not by 6.
5. Correct answer: B
1 1 4 ( 1) 3 1
3 12 12 12 4
? ? ? ??
? ? ? ?
??
??
CBSE VI | Mathematics
Sample Paper 4 – Solution
6. Correct answer: C
Every quadrilateral has four pairs of adjacent angles.
Example: For the quadrilateral ABCD, the pairs of adjacent angles are
(i) ? A, ? B (ii) ? B, ? C (iii) ? C, ? D (iv) ? D, ? A.
7. Correct answer: A
Starting from zero, a jump of 4 units is made to the right to reach 4. Then, 3 jumps
(each of 1 unit) are taken to the right to reach 7. So, this number line represents 4 + 3.
8. Correct Answer: A
If the number can be divided by the numbers 2 and 3, then that number is divisible by
6.
9. Correct answer: B
CCC stands for 300
And XL stands for 40
So, CCCXL stands for 300 + 40 = 340
10. Correct answer: A
When hour hand goes from 3 to 9 clockwise, it will rotate by 2 right angles or 180º.
Fraction =
180º 1
360º 2
?
11. Correct answer: A
1 + 0 = 1
? It does not represent zero
12. Correct answer: B
The given shape is cuboid.
CBSE VI | Mathematics
Sample Paper 4 – Solution
Section B
13. Using distributive property of multiplication over addition, we have:
101 × 33 = (100 + 1) × 33 = 3300 +33 = 3333
101 × 333 = (100 + 1) × 333 = 33300 + 333 = 33633
101 × 3333 = (100 + 1) × 3333 = 333300 + 3333 = 336633
101 × 33333 = (100 + 1) × 33333 = 3333300 + 33333 = 3366633
14. (74 × 126) – (74 × 32) + (74 × 16)
= 74 × (126 – 32 + 16)
= 74 × 110
= 8140
15. 21397 can be estimated as 21000
27807 can be estimated as 28000.
42305 can be estimated as 42000.
On adding, we get 21000 + 28000 + 42000 = 91000.
16. 4 × [10 + (-12)] = 4 × (-2) = -8
17. The arcs which can be formed in the given circle are as follows:
arc LMN, arc MNP, arc LNP and arc LMP.
18. There are unlimited number of integers both to the left and the right of zero, hence we
cannot determine the biggest or the smallest integer.
19. Angles which are neither angles of the triangle nor its exterior angles are ?AXB, ?EYF
and ?CZD.
20. A triangle with all three sides of different lengths is called a scalene triangle.
? ?DEF is a scalene triangle.
21. Line segments QR and ST are the chords of the circle.
Page 4
CBSE VI | Mathematics
Sample Paper 4 – Solution
CBSE Board
Class VI Mathematics
Term I
Sample Paper 4 – Solution
Time: 2 ½ hours Total Marks: 80
Section A
1. Correct answer: B
The number just before 1000000 is one less than 1000000.
The required number = 1000000 - 1 = 999999.
2. Correct answer: B
On a number line, –110 lies next to –111 on the right. Therefore, the successor of –111
is –110.
3. Correct answer: A
The given fraction is
15
18
Dividing the numerator and denominator by 3, we get,
15 3 5
18 3 6
?
?
?
Thus,
15
18
is equivalent to
5
6
.
4. Correct answer: D
The numbers 138 and 432 are divisible by both 2 and 3 and hence are divisible by 6.
The number 653 is neither divisible by 3 nor by 2 and hence is not divisible by 6.
Now, consider the number 531.
The sum of the digits of the number 531 is divisible by 3, so 531 is divisible by 3.
However, it is not an even number, so it is not divisible by 2.
Thus, 531 is divisible by 3 but not by 6.
5. Correct answer: B
1 1 4 ( 1) 3 1
3 12 12 12 4
? ? ? ??
? ? ? ?
??
??
CBSE VI | Mathematics
Sample Paper 4 – Solution
6. Correct answer: C
Every quadrilateral has four pairs of adjacent angles.
Example: For the quadrilateral ABCD, the pairs of adjacent angles are
(i) ? A, ? B (ii) ? B, ? C (iii) ? C, ? D (iv) ? D, ? A.
7. Correct answer: A
Starting from zero, a jump of 4 units is made to the right to reach 4. Then, 3 jumps
(each of 1 unit) are taken to the right to reach 7. So, this number line represents 4 + 3.
8. Correct Answer: A
If the number can be divided by the numbers 2 and 3, then that number is divisible by
6.
9. Correct answer: B
CCC stands for 300
And XL stands for 40
So, CCCXL stands for 300 + 40 = 340
10. Correct answer: A
When hour hand goes from 3 to 9 clockwise, it will rotate by 2 right angles or 180º.
Fraction =
180º 1
360º 2
?
11. Correct answer: A
1 + 0 = 1
? It does not represent zero
12. Correct answer: B
The given shape is cuboid.
CBSE VI | Mathematics
Sample Paper 4 – Solution
Section B
13. Using distributive property of multiplication over addition, we have:
101 × 33 = (100 + 1) × 33 = 3300 +33 = 3333
101 × 333 = (100 + 1) × 333 = 33300 + 333 = 33633
101 × 3333 = (100 + 1) × 3333 = 333300 + 3333 = 336633
101 × 33333 = (100 + 1) × 33333 = 3333300 + 33333 = 3366633
14. (74 × 126) – (74 × 32) + (74 × 16)
= 74 × (126 – 32 + 16)
= 74 × 110
= 8140
15. 21397 can be estimated as 21000
27807 can be estimated as 28000.
42305 can be estimated as 42000.
On adding, we get 21000 + 28000 + 42000 = 91000.
16. 4 × [10 + (-12)] = 4 × (-2) = -8
17. The arcs which can be formed in the given circle are as follows:
arc LMN, arc MNP, arc LNP and arc LMP.
18. There are unlimited number of integers both to the left and the right of zero, hence we
cannot determine the biggest or the smallest integer.
19. Angles which are neither angles of the triangle nor its exterior angles are ?AXB, ?EYF
and ?CZD.
20. A triangle with all three sides of different lengths is called a scalene triangle.
? ?DEF is a scalene triangle.
21. Line segments QR and ST are the chords of the circle.
CBSE VI | Mathematics
Sample Paper 4 – Solution
22.
? ? ? ? 3 4 2 3 4 1
21
43
3 4 3 4
? ? ? ?
? ? ?
? ? ? ?
14 13
34
14 4 13 3
12
56 39
12
95
12
??
? ? ?
?
?
?
?
23. (a) It is not a polygon as it is not a closed figure
(b) Yes it is a polygon made of 6 sides.
(c) No it is not made of line segments.
(d) No it is not made of only line segments.
24. Since the number is divisible by 12, it will also be divisible by its factors i.e. 1, 2, 3, 4, 6,
12. Clearly, 1, 2, 3, 4, and 6 are the numbers other than 12 by which this number is
also divisible.
Section C
25. Number of circles in step 1 = 3 = 1 × 2 + 1
Number of circles in step 2 = 5 = 2 × 2 + 1
Thus, we can observe that the number of circles is obtained by multiplying the step
number by 2 and then adding 1.
Therefore, the number of circles in the 100
th
step = (100 × 2) + 1 = 201
26. (a) (-52) + (-36) + 42 + 8 + (-22) + 46
= -(52 + 36+22) + (42 + 8+46)
= -110 + 96
= -14
(b) The largest 4-digit positive integer is 9999 and the smallest 3-digit negative
integer is -999.
? 9999 + (-999) = 9999 – 999 = 9000
(c) Two integers between 2 and -5 that are inverses of each other are -1 and 1.
The sum of 1 and -1 is 0.
Page 5
CBSE VI | Mathematics
Sample Paper 4 – Solution
CBSE Board
Class VI Mathematics
Term I
Sample Paper 4 – Solution
Time: 2 ½ hours Total Marks: 80
Section A
1. Correct answer: B
The number just before 1000000 is one less than 1000000.
The required number = 1000000 - 1 = 999999.
2. Correct answer: B
On a number line, –110 lies next to –111 on the right. Therefore, the successor of –111
is –110.
3. Correct answer: A
The given fraction is
15
18
Dividing the numerator and denominator by 3, we get,
15 3 5
18 3 6
?
?
?
Thus,
15
18
is equivalent to
5
6
.
4. Correct answer: D
The numbers 138 and 432 are divisible by both 2 and 3 and hence are divisible by 6.
The number 653 is neither divisible by 3 nor by 2 and hence is not divisible by 6.
Now, consider the number 531.
The sum of the digits of the number 531 is divisible by 3, so 531 is divisible by 3.
However, it is not an even number, so it is not divisible by 2.
Thus, 531 is divisible by 3 but not by 6.
5. Correct answer: B
1 1 4 ( 1) 3 1
3 12 12 12 4
? ? ? ??
? ? ? ?
??
??
CBSE VI | Mathematics
Sample Paper 4 – Solution
6. Correct answer: C
Every quadrilateral has four pairs of adjacent angles.
Example: For the quadrilateral ABCD, the pairs of adjacent angles are
(i) ? A, ? B (ii) ? B, ? C (iii) ? C, ? D (iv) ? D, ? A.
7. Correct answer: A
Starting from zero, a jump of 4 units is made to the right to reach 4. Then, 3 jumps
(each of 1 unit) are taken to the right to reach 7. So, this number line represents 4 + 3.
8. Correct Answer: A
If the number can be divided by the numbers 2 and 3, then that number is divisible by
6.
9. Correct answer: B
CCC stands for 300
And XL stands for 40
So, CCCXL stands for 300 + 40 = 340
10. Correct answer: A
When hour hand goes from 3 to 9 clockwise, it will rotate by 2 right angles or 180º.
Fraction =
180º 1
360º 2
?
11. Correct answer: A
1 + 0 = 1
? It does not represent zero
12. Correct answer: B
The given shape is cuboid.
CBSE VI | Mathematics
Sample Paper 4 – Solution
Section B
13. Using distributive property of multiplication over addition, we have:
101 × 33 = (100 + 1) × 33 = 3300 +33 = 3333
101 × 333 = (100 + 1) × 333 = 33300 + 333 = 33633
101 × 3333 = (100 + 1) × 3333 = 333300 + 3333 = 336633
101 × 33333 = (100 + 1) × 33333 = 3333300 + 33333 = 3366633
14. (74 × 126) – (74 × 32) + (74 × 16)
= 74 × (126 – 32 + 16)
= 74 × 110
= 8140
15. 21397 can be estimated as 21000
27807 can be estimated as 28000.
42305 can be estimated as 42000.
On adding, we get 21000 + 28000 + 42000 = 91000.
16. 4 × [10 + (-12)] = 4 × (-2) = -8
17. The arcs which can be formed in the given circle are as follows:
arc LMN, arc MNP, arc LNP and arc LMP.
18. There are unlimited number of integers both to the left and the right of zero, hence we
cannot determine the biggest or the smallest integer.
19. Angles which are neither angles of the triangle nor its exterior angles are ?AXB, ?EYF
and ?CZD.
20. A triangle with all three sides of different lengths is called a scalene triangle.
? ?DEF is a scalene triangle.
21. Line segments QR and ST are the chords of the circle.
CBSE VI | Mathematics
Sample Paper 4 – Solution
22.
? ? ? ? 3 4 2 3 4 1
21
43
3 4 3 4
? ? ? ?
? ? ?
? ? ? ?
14 13
34
14 4 13 3
12
56 39
12
95
12
??
? ? ?
?
?
?
?
23. (a) It is not a polygon as it is not a closed figure
(b) Yes it is a polygon made of 6 sides.
(c) No it is not made of line segments.
(d) No it is not made of only line segments.
24. Since the number is divisible by 12, it will also be divisible by its factors i.e. 1, 2, 3, 4, 6,
12. Clearly, 1, 2, 3, 4, and 6 are the numbers other than 12 by which this number is
also divisible.
Section C
25. Number of circles in step 1 = 3 = 1 × 2 + 1
Number of circles in step 2 = 5 = 2 × 2 + 1
Thus, we can observe that the number of circles is obtained by multiplying the step
number by 2 and then adding 1.
Therefore, the number of circles in the 100
th
step = (100 × 2) + 1 = 201
26. (a) (-52) + (-36) + 42 + 8 + (-22) + 46
= -(52 + 36+22) + (42 + 8+46)
= -110 + 96
= -14
(b) The largest 4-digit positive integer is 9999 and the smallest 3-digit negative
integer is -999.
? 9999 + (-999) = 9999 – 999 = 9000
(c) Two integers between 2 and -5 that are inverses of each other are -1 and 1.
The sum of 1 and -1 is 0.
CBSE VI | Mathematics
Sample Paper 4 – Solution
27. To solve using the number line start with -8, move 12 steps right and then back 2
steps as shown below:
So, we reach at 2; therefore, (-8 + 12 - 2) = 2
28. We have:
2 (9 3) 2 29 19 19 3 57
9 and 19
3 3 3 1 1 3 3
? ? ?
? ? ? ? ?
?
The required number can be calculated by subtracting
29 57
from
33
.
57 29 57 29
3 3 3
28
3
1
9
3
?
??
?
?
Hence,
1
9
3
should be added to
2
9
3
to get 19.
29. Mark point A. Take point A as the centre and draw a circle with radius 3 cm using a
compass.
The radius is the distance between the centre and any point on the circumference.
? AB is the radius of the circle.
The diameter is the chord which divides the circle into two halves.
? XY is the diameter of the circle.
A line segment which joins any two points on the circumference of a circle is called a
chord.
? XZ is a chord of the circle.
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FAQs on Class 6 Math: CBSE Sample Question Paper Solutions Term I – 4 - Mathematics (Maths) Class 6
| 1. What is the format of the CBSE Class 6 Math Sample Question Paper for Term I? |  |
Ans. The CBSE Class 6 Math Sample Question Paper for Term I typically follows a format that includes multiple-choice questions, short answer questions, and long answer questions. This format helps to assess the students' understanding of various concepts and their ability to apply them.
| 2. How can I prepare for the Class 6 Math Term I exam effectively? | |
Ans. To prepare effectively for the Class 6 Math Term I exam, you can follow these steps:
1. Understand the syllabus and exam pattern thoroughly.
2. Create a study schedule and allocate specific time for each topic.
3. Practice solving sample question papers and previous year's question papers.
4. Clarify doubts by seeking help from teachers or classmates.
5. Revise regularly and make concise notes for quick revision.
| 3. What are some important topics that I should focus on for the Class 6 Math Term I exam? | |
Ans. Some important topics that you should focus on for the Class 6 Math Term I exam include:
1. Whole Numbers and their Operations.
2. Basic Geometrical Concepts.
3. Fractions and Decimals.
4. Data Handling.
5. Algebraic Expressions and Equations.
6. Ratio and Proportion.
7. Practical Geometry.
8. Mensuration.
| 4. Are there any online resources available to practice Class 6 Math questions for the Term I exam? | |
Ans. Yes, there are several online resources available to practice Class 6 Math questions for the Term I exam. Some popular websites include:
1. Khan Academy
2. TopperLearning
3. Vedantu
4. Meritnation
5. BYJU'S
These websites offer interactive lessons, practice questions, and mock tests to help students prepare effectively.
| 5. How can I manage my time effectively during the Class 6 Math Term I exam? | |
Ans. To manage your time effectively during the Class 6 Math Term I exam, you can follow these tips:
1. Read the entire question paper carefully before starting.
2. Allocate time for each section based on the marks assigned to it.
3. Start with the questions you are most confident about.
4. If you get stuck on a question, move on and come back to it later.
5. Keep an eye on the time and make sure you complete the paper within the given time frame.
6. Utilize the last few minutes to review your answers and make any necessary corrections.
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