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Page 1
CBSE VII | Mathematics
Sample Paper 1 – Solution
CBSE Board
Class VII Mathematics
Term II
Sample Paper 1 – Solution
Time: 2 ½ hours Total Marks: 80
Section A
1. Correct answer: B
Discount = 40% on Rs 7000 = ??
4
7000 Rs 2800
100
Therefore, SP = Rs (7000 - 2800) = Rs 4200.
2. Correct answer: A
Since the numerators are equal, so the rational number with the least denominator
is the greatest.
3. Correct answer: B
Measure of one side.
4. Correct answer: C
5. Correct answer: A
a ? a ? a ? a ? y ? y ? y ? y ? z ? z = a
4
y
4
z
2
6. Correct answer: C
Number of lines of symmetry of a regular polygon is equal to its number of sides.
Since, regular heptagon has 7 sides, it has 7 lines of symmetry.
Page 2
CBSE VII | Mathematics
Sample Paper 1 – Solution
CBSE Board
Class VII Mathematics
Term II
Sample Paper 1 – Solution
Time: 2 ½ hours Total Marks: 80
Section A
1. Correct answer: B
Discount = 40% on Rs 7000 = ??
4
7000 Rs 2800
100
Therefore, SP = Rs (7000 - 2800) = Rs 4200.
2. Correct answer: A
Since the numerators are equal, so the rational number with the least denominator
is the greatest.
3. Correct answer: B
Measure of one side.
4. Correct answer: C
5. Correct answer: A
a ? a ? a ? a ? y ? y ? y ? y ? z ? z = a
4
y
4
z
2
6. Correct answer: C
Number of lines of symmetry of a regular polygon is equal to its number of sides.
Since, regular heptagon has 7 sides, it has 7 lines of symmetry.
CBSE VII | Mathematics
Sample Paper 1 – Solution
7. Correct answer: B
A number is chosen from numbers 1 to 5.
Odd numbers are 1, 3 and 5.
Required probability= ?
Number of ways to choose an odd number 3
Total number of numbers 5
8. Correct answer: A
A regular hexagon has 1 centre of rotation.
9. Correct answer: C
10. Correct answer: B
Substituting the value of x in the given expression, we get:
7 × (-2)
2
-5 × (-2) + k = -4
28 + 10 + k = -4
38 + k = -4
Thus, k = -42
11. Correct answer: D
Since, the angle measuring 150
o
and y are corresponding angles. Therefore, y = 150
o
.
(As the lines are parallel, corresponding angles are equal)
12. Correct answer: C
-5 + 9 + (-5) + (-10) + (1)
-5 + 9 = 4
4 + (-5) = -1
-1 + (-10) = -1 - 10 = -11
-11 + 1 = -10
So, -5 + 9 + (-5) + (-10) + (1) = -10
Page 3
CBSE VII | Mathematics
Sample Paper 1 – Solution
CBSE Board
Class VII Mathematics
Term II
Sample Paper 1 – Solution
Time: 2 ½ hours Total Marks: 80
Section A
1. Correct answer: B
Discount = 40% on Rs 7000 = ??
4
7000 Rs 2800
100
Therefore, SP = Rs (7000 - 2800) = Rs 4200.
2. Correct answer: A
Since the numerators are equal, so the rational number with the least denominator
is the greatest.
3. Correct answer: B
Measure of one side.
4. Correct answer: C
5. Correct answer: A
a ? a ? a ? a ? y ? y ? y ? y ? z ? z = a
4
y
4
z
2
6. Correct answer: C
Number of lines of symmetry of a regular polygon is equal to its number of sides.
Since, regular heptagon has 7 sides, it has 7 lines of symmetry.
CBSE VII | Mathematics
Sample Paper 1 – Solution
7. Correct answer: B
A number is chosen from numbers 1 to 5.
Odd numbers are 1, 3 and 5.
Required probability= ?
Number of ways to choose an odd number 3
Total number of numbers 5
8. Correct answer: A
A regular hexagon has 1 centre of rotation.
9. Correct answer: C
10. Correct answer: B
Substituting the value of x in the given expression, we get:
7 × (-2)
2
-5 × (-2) + k = -4
28 + 10 + k = -4
38 + k = -4
Thus, k = -42
11. Correct answer: D
Since, the angle measuring 150
o
and y are corresponding angles. Therefore, y = 150
o
.
(As the lines are parallel, corresponding angles are equal)
12. Correct answer: C
-5 + 9 + (-5) + (-10) + (1)
-5 + 9 = 4
4 + (-5) = -1
-1 + (-10) = -1 - 10 = -11
-11 + 1 = -10
So, -5 + 9 + (-5) + (-10) + (1) = -10
CBSE VII | Mathematics
Sample Paper 1 – Solution
Section B
13.
2x-1 x+2
=
32
Multiply both sides by 6 (L.C.M of 3 and 2)
2 (2x -1) = 3 (x + 2)
4x - 2 = 3x + 6
Transpose 3x to L.H.S and -2 to R.H.S
4x -3x = 6 + 2
x = 8
14. Decrease in consumption = 10 - 8 = 2 kg
Therefore,
= ??
2
100 20
10
%
15. The rational form of the given decimals are:
The rational numbers obtained above can be represented as follows:
16. Area of the triangle ABC = 48 m
2
Height, CD = 12 m
Area =
1
2
x base x height
48 =
1
2
x AB x 12
6 x AB = 48
AB = 8 m
Thus, base AB = 8 m
Page 4
CBSE VII | Mathematics
Sample Paper 1 – Solution
CBSE Board
Class VII Mathematics
Term II
Sample Paper 1 – Solution
Time: 2 ½ hours Total Marks: 80
Section A
1. Correct answer: B
Discount = 40% on Rs 7000 = ??
4
7000 Rs 2800
100
Therefore, SP = Rs (7000 - 2800) = Rs 4200.
2. Correct answer: A
Since the numerators are equal, so the rational number with the least denominator
is the greatest.
3. Correct answer: B
Measure of one side.
4. Correct answer: C
5. Correct answer: A
a ? a ? a ? a ? y ? y ? y ? y ? z ? z = a
4
y
4
z
2
6. Correct answer: C
Number of lines of symmetry of a regular polygon is equal to its number of sides.
Since, regular heptagon has 7 sides, it has 7 lines of symmetry.
CBSE VII | Mathematics
Sample Paper 1 – Solution
7. Correct answer: B
A number is chosen from numbers 1 to 5.
Odd numbers are 1, 3 and 5.
Required probability= ?
Number of ways to choose an odd number 3
Total number of numbers 5
8. Correct answer: A
A regular hexagon has 1 centre of rotation.
9. Correct answer: C
10. Correct answer: B
Substituting the value of x in the given expression, we get:
7 × (-2)
2
-5 × (-2) + k = -4
28 + 10 + k = -4
38 + k = -4
Thus, k = -42
11. Correct answer: D
Since, the angle measuring 150
o
and y are corresponding angles. Therefore, y = 150
o
.
(As the lines are parallel, corresponding angles are equal)
12. Correct answer: C
-5 + 9 + (-5) + (-10) + (1)
-5 + 9 = 4
4 + (-5) = -1
-1 + (-10) = -1 - 10 = -11
-11 + 1 = -10
So, -5 + 9 + (-5) + (-10) + (1) = -10
CBSE VII | Mathematics
Sample Paper 1 – Solution
Section B
13.
2x-1 x+2
=
32
Multiply both sides by 6 (L.C.M of 3 and 2)
2 (2x -1) = 3 (x + 2)
4x - 2 = 3x + 6
Transpose 3x to L.H.S and -2 to R.H.S
4x -3x = 6 + 2
x = 8
14. Decrease in consumption = 10 - 8 = 2 kg
Therefore,
= ??
2
100 20
10
%
15. The rational form of the given decimals are:
The rational numbers obtained above can be represented as follows:
16. Area of the triangle ABC = 48 m
2
Height, CD = 12 m
Area =
1
2
x base x height
48 =
1
2
x AB x 12
6 x AB = 48
AB = 8 m
Thus, base AB = 8 m
CBSE VII | Mathematics
Sample Paper 1 – Solution
17. Consider:
3(a + b) - 2(2a - b) + 4a - 7
= 3a + 3b - 4a + 2b + 4a - 7
= (3a - 4a + 4a) + (2b + 3b) - 7
= 3a + 5b - 7
18. We have,
Since bases are equal, powers are also equal.
19. The alphabet is H
It has 2 lines of symmetry as shown below:
After rotating the letter H through 180
o
, we find that the image remains same. So the
order of rotational symmetry is 2.
20. Number of cubes in the first layer = 5 x 5 = 25
Number of cubes in the second layer = 13 + 4 = 17
Number of cubes in third layer = 4
Hence, total number of cubes = 25 + 17 + 4 = 46
Page 5
CBSE VII | Mathematics
Sample Paper 1 – Solution
CBSE Board
Class VII Mathematics
Term II
Sample Paper 1 – Solution
Time: 2 ½ hours Total Marks: 80
Section A
1. Correct answer: B
Discount = 40% on Rs 7000 = ??
4
7000 Rs 2800
100
Therefore, SP = Rs (7000 - 2800) = Rs 4200.
2. Correct answer: A
Since the numerators are equal, so the rational number with the least denominator
is the greatest.
3. Correct answer: B
Measure of one side.
4. Correct answer: C
5. Correct answer: A
a ? a ? a ? a ? y ? y ? y ? y ? z ? z = a
4
y
4
z
2
6. Correct answer: C
Number of lines of symmetry of a regular polygon is equal to its number of sides.
Since, regular heptagon has 7 sides, it has 7 lines of symmetry.
CBSE VII | Mathematics
Sample Paper 1 – Solution
7. Correct answer: B
A number is chosen from numbers 1 to 5.
Odd numbers are 1, 3 and 5.
Required probability= ?
Number of ways to choose an odd number 3
Total number of numbers 5
8. Correct answer: A
A regular hexagon has 1 centre of rotation.
9. Correct answer: C
10. Correct answer: B
Substituting the value of x in the given expression, we get:
7 × (-2)
2
-5 × (-2) + k = -4
28 + 10 + k = -4
38 + k = -4
Thus, k = -42
11. Correct answer: D
Since, the angle measuring 150
o
and y are corresponding angles. Therefore, y = 150
o
.
(As the lines are parallel, corresponding angles are equal)
12. Correct answer: C
-5 + 9 + (-5) + (-10) + (1)
-5 + 9 = 4
4 + (-5) = -1
-1 + (-10) = -1 - 10 = -11
-11 + 1 = -10
So, -5 + 9 + (-5) + (-10) + (1) = -10
CBSE VII | Mathematics
Sample Paper 1 – Solution
Section B
13.
2x-1 x+2
=
32
Multiply both sides by 6 (L.C.M of 3 and 2)
2 (2x -1) = 3 (x + 2)
4x - 2 = 3x + 6
Transpose 3x to L.H.S and -2 to R.H.S
4x -3x = 6 + 2
x = 8
14. Decrease in consumption = 10 - 8 = 2 kg
Therefore,
= ??
2
100 20
10
%
15. The rational form of the given decimals are:
The rational numbers obtained above can be represented as follows:
16. Area of the triangle ABC = 48 m
2
Height, CD = 12 m
Area =
1
2
x base x height
48 =
1
2
x AB x 12
6 x AB = 48
AB = 8 m
Thus, base AB = 8 m
CBSE VII | Mathematics
Sample Paper 1 – Solution
17. Consider:
3(a + b) - 2(2a - b) + 4a - 7
= 3a + 3b - 4a + 2b + 4a - 7
= (3a - 4a + 4a) + (2b + 3b) - 7
= 3a + 5b - 7
18. We have,
Since bases are equal, powers are also equal.
19. The alphabet is H
It has 2 lines of symmetry as shown below:
After rotating the letter H through 180
o
, we find that the image remains same. So the
order of rotational symmetry is 2.
20. Number of cubes in the first layer = 5 x 5 = 25
Number of cubes in the second layer = 13 + 4 = 17
Number of cubes in third layer = 4
Hence, total number of cubes = 25 + 17 + 4 = 46
CBSE VII | Mathematics
Sample Paper 1 – Solution
21. Drawing the relational part, the images become as follows:
22.
i. 343000 = 343 × 1000
= 7 × 7 × 7 × 10 × 10 × 10
= 7
3
×10
3
ii. 2048 = 2 × 1024
= 2 × 2 × 512
= 2 × 2 × 2 × 256
= 2 × 2 × 2 × 2 × 128
= 2 × 2 × 2 × 2 × 2 × 64
= 2 × 2 × 2 × 2 × 2 × 2 × 32
= 2 × 2 × 2 × 2 × 2 × 2 × 2 × 16
= 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 × 8
= 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2 × 2
= 2
11
23. Total tons of hay owned by the farmer =
1
56
2
tons
Amount of hay sold by him =
3
5
of
1
56
2
tons
i.e.
3
5
×
1
56
2
['of' means multiplication]
3 113
=×
52
3×113
=
5×2
339
=
10
9
=33
10
Thus, the farmer sold
9
33
10
tons of hay.
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FAQs on Class 7 Math: CBSE Sample Question Paper Solutions Term II – 1 - Mathematics (Maths) Class 7
| 1. What is the format of the CBSE Class 7 Math Sample Question Paper for Term II? |  |
Ans. The CBSE Class 7 Math Sample Question Paper for Term II follows the format specified by the CBSE board. It consists of a combination of multiple-choice questions, short answer questions, and long answer questions. The paper is divided into different sections, each focusing on a specific topic or concept.
| 2. How can I use the CBSE Class 7 Math Sample Question Paper for Term II to prepare for my exams? | |
Ans. The CBSE Class 7 Math Sample Question Paper for Term II is a valuable resource for exam preparation. By solving the sample paper, you can familiarize yourself with the question format, time management, and gain a better understanding of the important topics. It is recommended to solve the sample paper under exam-like conditions to assess your preparation level and identify areas that need improvement.
| 3. Are the questions in the CBSE Class 7 Math Sample Question Paper for Term II similar to the ones asked in the actual exam? | |
Ans. The CBSE Class 7 Math Sample Question Paper for Term II is designed to provide students with an idea of the type and difficulty level of questions that can be expected in the actual exam. While the questions may not be exactly the same, they are formulated to assess the students' understanding of the concepts covered in the syllabus. It is advisable to practice with the sample paper to get a good grasp of the exam pattern.
| 4. Can I rely solely on the CBSE Class 7 Math Sample Question Paper for Term II for my exam preparation? | |
Ans. While the CBSE Class 7 Math Sample Question Paper for Term II is a useful resource for exam preparation, it should not be the sole source of study material. It is important to thoroughly study the textbook, understand the concepts, and practice additional problems to strengthen your understanding of the subject. The sample paper should be used as a supplement to your regular study routine.
| 5. Are there any specific tips for solving the CBSE Class 7 Math Sample Question Paper for Term II effectively? | |
Ans. Yes, here are a few tips for solving the CBSE Class 7 Math Sample Question Paper for Term II effectively:
- Read the instructions carefully before attempting each question.
- Manage your time wisely and allocate specific time for each section.
- Start with the questions you are most confident about to build momentum.
- Show all the necessary steps and workings while solving numerical problems.
- Revise your answers and check for any errors or omissions before submitting the paper.
- Analyze your performance and identify areas that need improvement.
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