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Page 1
CBSE VII | Mathematics
Sample Paper 2 – Solution
CBSE Board
Class VII Mathematics
Term II
Sample Paper 2 – Solution
Time: 2 ½ hours Total Marks: 80
Section A
1. Correct answer: B
2. Correct answer: B
For the option (B), 1 is the only common factor between numerator and
denominator and the denominator is a positive integer, hence it is in the standard
form.
3. Correct answer: D
6 components - three angles and three sides
4. Correct answer: A
Cylinder
5. Correct answer: B
-x + 1 is an example of binomial as it contains two terms.
6. Correct answer: C
7. Correct answer: A
Hence, order of rotational symmetry is 2.
Page 2
CBSE VII | Mathematics
Sample Paper 2 – Solution
CBSE Board
Class VII Mathematics
Term II
Sample Paper 2 – Solution
Time: 2 ½ hours Total Marks: 80
Section A
1. Correct answer: B
2. Correct answer: B
For the option (B), 1 is the only common factor between numerator and
denominator and the denominator is a positive integer, hence it is in the standard
form.
3. Correct answer: D
6 components - three angles and three sides
4. Correct answer: A
Cylinder
5. Correct answer: B
-x + 1 is an example of binomial as it contains two terms.
6. Correct answer: C
7. Correct answer: A
Hence, order of rotational symmetry is 2.
CBSE VII | Mathematics
Sample Paper 2 – Solution
8. Correct answer: C
The length of given cuboid is 6 units.
9. Correct answer: D
10. Correct answer: A
Perimeter of rhombus = 28 cm
Thus, 4 x (side) = 28 cm
Side =
28
4
= 7 cm
11. Correct answer: A
(128 ÷32) ÷ (-4) = 4 ÷ (-4) = -1
12. Correct answer: A
2x + 3 = 7
If we transpose 3 to RHS, then the term with variable will remain on one side and
the constants will be on the other side.
So, the first step is to transpose 3 to RHS.
i.e. 2x = 7 – 3
Section B
13. Percentage of marks scored by Rahul =
40
100 80%
50
??
Percentage of marks scored by Rohan =
75
100 75%
100
??
Hence, Rahul scored more marks than Rohan.
Page 3
CBSE VII | Mathematics
Sample Paper 2 – Solution
CBSE Board
Class VII Mathematics
Term II
Sample Paper 2 – Solution
Time: 2 ½ hours Total Marks: 80
Section A
1. Correct answer: B
2. Correct answer: B
For the option (B), 1 is the only common factor between numerator and
denominator and the denominator is a positive integer, hence it is in the standard
form.
3. Correct answer: D
6 components - three angles and three sides
4. Correct answer: A
Cylinder
5. Correct answer: B
-x + 1 is an example of binomial as it contains two terms.
6. Correct answer: C
7. Correct answer: A
Hence, order of rotational symmetry is 2.
CBSE VII | Mathematics
Sample Paper 2 – Solution
8. Correct answer: C
The length of given cuboid is 6 units.
9. Correct answer: D
10. Correct answer: A
Perimeter of rhombus = 28 cm
Thus, 4 x (side) = 28 cm
Side =
28
4
= 7 cm
11. Correct answer: A
(128 ÷32) ÷ (-4) = 4 ÷ (-4) = -1
12. Correct answer: A
2x + 3 = 7
If we transpose 3 to RHS, then the term with variable will remain on one side and
the constants will be on the other side.
So, the first step is to transpose 3 to RHS.
i.e. 2x = 7 – 3
Section B
13. Percentage of marks scored by Rahul =
40
100 80%
50
??
Percentage of marks scored by Rohan =
75
100 75%
100
??
Hence, Rahul scored more marks than Rohan.
CBSE VII | Mathematics
Sample Paper 2 – Solution
14. In the given number line, the rational number between 0 and -1 would be
1
2
?
.
Rational number between 1 and 2 is
3
2
as 1 can be written as
2
2
.
So, the next point would be
3
2
and 2 can be written as
4
2
, which is the same.
Thus, the number line representing the missing values is as follows:
15.
(a) ?A = 120
o
, ?B = 90
o
and AB = 8 cm
Since, ?A + ?B = 120
o
+ 90
o
= 210
o
That is the sum of two angles is more than 180
o
.
Hence, the triangle is not possible.
(b) ?P = 90
o
, ?Q = 90
o
and PQ = 9 cm
Since, ?P + ?Q = 90
o
+ 90
o
= 180
o
That is the sum of two angles is equal to 180
o
.
And the measure of third angle is zero.
Hence, the triangle is not possible.
16.
Page 4
CBSE VII | Mathematics
Sample Paper 2 – Solution
CBSE Board
Class VII Mathematics
Term II
Sample Paper 2 – Solution
Time: 2 ½ hours Total Marks: 80
Section A
1. Correct answer: B
2. Correct answer: B
For the option (B), 1 is the only common factor between numerator and
denominator and the denominator is a positive integer, hence it is in the standard
form.
3. Correct answer: D
6 components - three angles and three sides
4. Correct answer: A
Cylinder
5. Correct answer: B
-x + 1 is an example of binomial as it contains two terms.
6. Correct answer: C
7. Correct answer: A
Hence, order of rotational symmetry is 2.
CBSE VII | Mathematics
Sample Paper 2 – Solution
8. Correct answer: C
The length of given cuboid is 6 units.
9. Correct answer: D
10. Correct answer: A
Perimeter of rhombus = 28 cm
Thus, 4 x (side) = 28 cm
Side =
28
4
= 7 cm
11. Correct answer: A
(128 ÷32) ÷ (-4) = 4 ÷ (-4) = -1
12. Correct answer: A
2x + 3 = 7
If we transpose 3 to RHS, then the term with variable will remain on one side and
the constants will be on the other side.
So, the first step is to transpose 3 to RHS.
i.e. 2x = 7 – 3
Section B
13. Percentage of marks scored by Rahul =
40
100 80%
50
??
Percentage of marks scored by Rohan =
75
100 75%
100
??
Hence, Rahul scored more marks than Rohan.
CBSE VII | Mathematics
Sample Paper 2 – Solution
14. In the given number line, the rational number between 0 and -1 would be
1
2
?
.
Rational number between 1 and 2 is
3
2
as 1 can be written as
2
2
.
So, the next point would be
3
2
and 2 can be written as
4
2
, which is the same.
Thus, the number line representing the missing values is as follows:
15.
(a) ?A = 120
o
, ?B = 90
o
and AB = 8 cm
Since, ?A + ?B = 120
o
+ 90
o
= 210
o
That is the sum of two angles is more than 180
o
.
Hence, the triangle is not possible.
(b) ?P = 90
o
, ?Q = 90
o
and PQ = 9 cm
Since, ?P + ?Q = 90
o
+ 90
o
= 180
o
That is the sum of two angles is equal to 180
o
.
And the measure of third angle is zero.
Hence, the triangle is not possible.
16.
CBSE VII | Mathematics
Sample Paper 2 – Solution
17. Required sum:
(6m - 7n - 5p) + (-4m - 9n + 6p) + (-4m - 9n + 6p)
= 6m - 7n - 5p - 4m - 9n + 6p - 4m - 9n + 6p
= (6m - 4m - 4m) + (-7n - 9n - 9n) + (-5p + 6p + 6p)
= (6 - 4 - 4)m + (-7 - 9 - 9)n + (-5 + 6 + 6)p
= -2m - 25n + 7p
18.
19. The other holes are as below:
i.
ii.
Page 5
CBSE VII | Mathematics
Sample Paper 2 – Solution
CBSE Board
Class VII Mathematics
Term II
Sample Paper 2 – Solution
Time: 2 ½ hours Total Marks: 80
Section A
1. Correct answer: B
2. Correct answer: B
For the option (B), 1 is the only common factor between numerator and
denominator and the denominator is a positive integer, hence it is in the standard
form.
3. Correct answer: D
6 components - three angles and three sides
4. Correct answer: A
Cylinder
5. Correct answer: B
-x + 1 is an example of binomial as it contains two terms.
6. Correct answer: C
7. Correct answer: A
Hence, order of rotational symmetry is 2.
CBSE VII | Mathematics
Sample Paper 2 – Solution
8. Correct answer: C
The length of given cuboid is 6 units.
9. Correct answer: D
10. Correct answer: A
Perimeter of rhombus = 28 cm
Thus, 4 x (side) = 28 cm
Side =
28
4
= 7 cm
11. Correct answer: A
(128 ÷32) ÷ (-4) = 4 ÷ (-4) = -1
12. Correct answer: A
2x + 3 = 7
If we transpose 3 to RHS, then the term with variable will remain on one side and
the constants will be on the other side.
So, the first step is to transpose 3 to RHS.
i.e. 2x = 7 – 3
Section B
13. Percentage of marks scored by Rahul =
40
100 80%
50
??
Percentage of marks scored by Rohan =
75
100 75%
100
??
Hence, Rahul scored more marks than Rohan.
CBSE VII | Mathematics
Sample Paper 2 – Solution
14. In the given number line, the rational number between 0 and -1 would be
1
2
?
.
Rational number between 1 and 2 is
3
2
as 1 can be written as
2
2
.
So, the next point would be
3
2
and 2 can be written as
4
2
, which is the same.
Thus, the number line representing the missing values is as follows:
15.
(a) ?A = 120
o
, ?B = 90
o
and AB = 8 cm
Since, ?A + ?B = 120
o
+ 90
o
= 210
o
That is the sum of two angles is more than 180
o
.
Hence, the triangle is not possible.
(b) ?P = 90
o
, ?Q = 90
o
and PQ = 9 cm
Since, ?P + ?Q = 90
o
+ 90
o
= 180
o
That is the sum of two angles is equal to 180
o
.
And the measure of third angle is zero.
Hence, the triangle is not possible.
16.
CBSE VII | Mathematics
Sample Paper 2 – Solution
17. Required sum:
(6m - 7n - 5p) + (-4m - 9n + 6p) + (-4m - 9n + 6p)
= 6m - 7n - 5p - 4m - 9n + 6p - 4m - 9n + 6p
= (6m - 4m - 4m) + (-7n - 9n - 9n) + (-5p + 6p + 6p)
= (6 - 4 - 4)m + (-7 - 9 - 9)n + (-5 + 6 + 6)p
= -2m - 25n + 7p
18.
19. The other holes are as below:
i.
ii.
CBSE VII | Mathematics
Sample Paper 2 – Solution
20.
1. 1. First take an isometric dot sheet.
2. Draw the line segment AB and AD of length 5 units and 3 units respectively.
3. For the height draw the line segment AG, BC and DE of 6 units each.
4. Join EG and GC.
5. Again draw EF and CF of 5 units and 3 units respectively.
21. Mass of earth = 5,970,000,000,000,000,000,000,000 kg
= 597 × 10000000000000000000000 kg
= 597 × 10
22
kg
= 5.97 × 10
24
kg
22. Number of cubes in first layer = 7
Number of cubes in second layer = 2
Hence, total number of cubes = 7 + 2 = 9
23. Average score = mean score
? ? ? ? ? ? ? ? ? ?
?
?
?
Sum of all observations
Mean=
Total number of observations
12 23 10 77 15 78 90 54 23 10 1
11
393
11
35.7
24. 725 × (-35) + (-725) × 65
= 725 × (-35) - 725 × 65
= 725 x (-35 - 65) [Using distributive property]
= 725 × (-100)
= -72500
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FAQs on Class 7 Math: CBSE Sample Question Paper Solutions Term II – 2 - Mathematics (Maths) Class 7
| 1. What is the CBSE Sample Question Paper for Class 7 Math? |  |
Ans. The CBSE Sample Question Paper for Class 7 Math is a set of practice questions designed by the Central Board of Secondary Education (CBSE) to help students prepare for their term II exams. It includes a variety of questions covering different topics from the class 7 math syllabus.
| 2. How can I access the CBSE Sample Question Paper for Class 7 Math? | |
Ans. The CBSE Sample Question Paper for Class 7 Math can be accessed through various sources. It is usually available on the official website of CBSE (cbse.nic.in) or can be obtained from your school. Additionally, there are several online platforms and educational websites that provide these sample papers for free download.
| 3. Are the CBSE Sample Question Papers for Class 7 Math similar to the actual exam papers? | |
Ans. Yes, the CBSE Sample Question Papers for Class 7 Math are designed to be similar to the actual exam papers. They are created by experts and follow the same format and marking scheme as the real exams. Practicing these sample papers will give students a good idea of the exam pattern and help them familiarize themselves with the types of questions that can be asked.
| 4. How can solving CBSE Sample Question Papers help me in my Class 7 Math exams? | |
Ans. Solving CBSE Sample Question Papers can be extremely helpful in preparing for Class 7 Math exams. It allows students to assess their knowledge and understanding of the subject, identify their strengths and weaknesses, and practice time management. By solving these papers, students can also get familiar with the question paper pattern, improve their problem-solving skills, and gain confidence in tackling different types of questions.
| 5. Can I rely solely on CBSE Sample Question Papers for Class 7 Math preparation? | |
Ans. While CBSE Sample Question Papers are a valuable resource for exam preparation, it is recommended not to rely solely on them. It is important to thoroughly study the textbook, understand the concepts, and practice additional problems from other sources as well. This will provide a more comprehensive understanding of the subject and improve your chances of scoring well in the exams.
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Nov 22, 2024 Last updated |
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