Page 1
MARKING SCHEME
2024 -25
Class X Science (086)
Section-A
1
A. 2,2,4
1
2
B. a – (iii), b – (i), c – (iv), d – (ii)
1
3
A. C2H5OH
Alternate question for VI
A. Dilute acid
1
4
C. A has a pH greater than 7 and B has a pH less than 7
1
5
C. Displacement reaction
1
6
C. X is a non-metal and Y is a metal.
1
7
B. Cooking of food
1
8
D. carbon dioxide in human cells
1
9
B. contraction of left ventricle.
1
10
D. Longer small intestine.
1
11
C. Posture and balance.
1
12
D. sex is not genetically determined in snails.
1
13
B. A ray passing through the centre of curvature and incident obliquely.
1
14
C. Red Violet
1
15
C. It utilizes 10% of light energy and transfers the rest to the next trophic
level.
1
16
B. Enrichment of oxygen in the atmosphere.
1
17
A. A is true but R is false
1
18
B. Both A and R are true, and R is not the correct explanation of A
1
19
B. Both A and R are true, and R is not the correct explanation of A
1
20
D. A is false but R is true.
1
Page 2
MARKING SCHEME
2024 -25
Class X Science (086)
Section-A
1
A. 2,2,4
1
2
B. a – (iii), b – (i), c – (iv), d – (ii)
1
3
A. C2H5OH
Alternate question for VI
A. Dilute acid
1
4
C. A has a pH greater than 7 and B has a pH less than 7
1
5
C. Displacement reaction
1
6
C. X is a non-metal and Y is a metal.
1
7
B. Cooking of food
1
8
D. carbon dioxide in human cells
1
9
B. contraction of left ventricle.
1
10
D. Longer small intestine.
1
11
C. Posture and balance.
1
12
D. sex is not genetically determined in snails.
1
13
B. A ray passing through the centre of curvature and incident obliquely.
1
14
C. Red Violet
1
15
C. It utilizes 10% of light energy and transfers the rest to the next trophic
level.
1
16
B. Enrichment of oxygen in the atmosphere.
1
17
A. A is true but R is false
1
18
B. Both A and R are true, and R is not the correct explanation of A
1
19
B. Both A and R are true, and R is not the correct explanation of A
1
20
D. A is false but R is true.
1
Section-B
21 A. Exothermic/Displacement reaction/Redox reaction. (0.5)
Heat is evolved or a More reactive element displaces a less reactive
element or aluminium reduces iron (II) oxide to iron (0.5)
B. Double displacement / Precipitation reaction (0.5)
As there is an exchange of ions between reactants and products /
(Yellow) precipitate (of Lead iodide) is formed (0.5)
2
22 S.
No.
Feature Alveoli Nephron
1 Structure
and location
Balloon like structures
present at the terminal ends
of bronchioles in lungs
Tubular structure
present in kidneys
2 Function Exchange of gases Filtration of blood
to form urine
2
23
Students to attempt either option A or B.
A. Steps of synthesis of glucose in plants:
? Absorption of light energy by chlorophyll
? Conversion of light energy to chemical energy and splitting of water
molecules into hydrogen and oxygen
? Reduction of carbon dioxide into carbohydrates.
? Desert plants take up carbon dioxide at night and prepare an
intermediate which is acted upon by the energy absorbed by the
chlorophyll during the day. (0.5 x 4)
OR
B.
? Salivary amylase – breaks down starch which is a complex
molecule to sugar.
? Pepsin – Helps to digest proteins in stomach.
? Trypsin – It helps in digesting proteins to amino acids.
? Lipase – Breaking down of emulsified fats to fatty acids and
glycerol. (0.5 x 4)
2
24 A. The lens is a convex lens.
B. The image is virtual.
C. Magnification for lens =
?? ?? =
h
?? h
?? = 2.
-30????
?? = 2
Hence u = -15 cm
- - - - - - - - - - - -
For visually impaired students
A. concave lens (1)
B. correction of myopia and peepholes of doors or any other correct
alternative. (1)
2
Page 3
MARKING SCHEME
2024 -25
Class X Science (086)
Section-A
1
A. 2,2,4
1
2
B. a – (iii), b – (i), c – (iv), d – (ii)
1
3
A. C2H5OH
Alternate question for VI
A. Dilute acid
1
4
C. A has a pH greater than 7 and B has a pH less than 7
1
5
C. Displacement reaction
1
6
C. X is a non-metal and Y is a metal.
1
7
B. Cooking of food
1
8
D. carbon dioxide in human cells
1
9
B. contraction of left ventricle.
1
10
D. Longer small intestine.
1
11
C. Posture and balance.
1
12
D. sex is not genetically determined in snails.
1
13
B. A ray passing through the centre of curvature and incident obliquely.
1
14
C. Red Violet
1
15
C. It utilizes 10% of light energy and transfers the rest to the next trophic
level.
1
16
B. Enrichment of oxygen in the atmosphere.
1
17
A. A is true but R is false
1
18
B. Both A and R are true, and R is not the correct explanation of A
1
19
B. Both A and R are true, and R is not the correct explanation of A
1
20
D. A is false but R is true.
1
Section-B
21 A. Exothermic/Displacement reaction/Redox reaction. (0.5)
Heat is evolved or a More reactive element displaces a less reactive
element or aluminium reduces iron (II) oxide to iron (0.5)
B. Double displacement / Precipitation reaction (0.5)
As there is an exchange of ions between reactants and products /
(Yellow) precipitate (of Lead iodide) is formed (0.5)
2
22 S.
No.
Feature Alveoli Nephron
1 Structure
and location
Balloon like structures
present at the terminal ends
of bronchioles in lungs
Tubular structure
present in kidneys
2 Function Exchange of gases Filtration of blood
to form urine
2
23
Students to attempt either option A or B.
A. Steps of synthesis of glucose in plants:
? Absorption of light energy by chlorophyll
? Conversion of light energy to chemical energy and splitting of water
molecules into hydrogen and oxygen
? Reduction of carbon dioxide into carbohydrates.
? Desert plants take up carbon dioxide at night and prepare an
intermediate which is acted upon by the energy absorbed by the
chlorophyll during the day. (0.5 x 4)
OR
B.
? Salivary amylase – breaks down starch which is a complex
molecule to sugar.
? Pepsin – Helps to digest proteins in stomach.
? Trypsin – It helps in digesting proteins to amino acids.
? Lipase – Breaking down of emulsified fats to fatty acids and
glycerol. (0.5 x 4)
2
24 A. The lens is a convex lens.
B. The image is virtual.
C. Magnification for lens =
?? ?? =
h
?? h
?? = 2.
-30????
?? = 2
Hence u = -15 cm
- - - - - - - - - - - -
For visually impaired students
A. concave lens (1)
B. correction of myopia and peepholes of doors or any other correct
alternative. (1)
2
25 Student to attempt either A or B.
A. P = VI (1)
= 230 × 3.5 = 805 W
I ?
1
?? , so half the resistance means double the current.
Therefore, current in Y = 7.0 A. (1)
OR
B. For series total resistance is R+2R = 3R (0.5)
P1 =
?? 2
3?? . (0.5)
For parallel total Resistance is
2?? 3
. (0.5)
P2 =
?? 2
2?? /3
=
3?? 2
2?? .
?? 1
?? 2
=
2
9
. (0.5)
- - - - - - - - - - - -
For visually impaired students
A. The resistance will be lowest/minimum if all the resistors are
connected in parallel.
The equivalent resistance in parallel combination is given by (0.5)
1
?? ?????? =
1
?? 1
+
1
?? 2
+
1
?? 3
+
1
?? 4
(0.5)
Substituting the values, we get
1
?? ??????
=
1
3
+
1
6
+
1
9
+
1
12
(0.5)
=
12 + 6 + 4 + 2
36
=
24
36
=
2
3
?? ??????
=
3
2
= 1.5 ??
(0.5)
OR
B. ?? = ?? × ?? (0.5)
?? =
?? ?? =
1000
220
= 4.54 ?? (0.5)
We will be using fuse B with is rated as 5A. This is because it will be
able to sustain the current (4.54 A) passing through it. Whereas fuse
A will melt and break the circuit as the current exceeds its rating. (1)
2
26 Pesticides are non-biodegradable/ keep getting accumulated at each trophic
level, / persist for longer time/ and thus last trophic level has highest
concentration/ humans will have the highest concentration of pesticides/
leads to bio-magnification. (any 2 points)
- - - - - - - - - - - -
For visually impaired students
2
Page 4
MARKING SCHEME
2024 -25
Class X Science (086)
Section-A
1
A. 2,2,4
1
2
B. a – (iii), b – (i), c – (iv), d – (ii)
1
3
A. C2H5OH
Alternate question for VI
A. Dilute acid
1
4
C. A has a pH greater than 7 and B has a pH less than 7
1
5
C. Displacement reaction
1
6
C. X is a non-metal and Y is a metal.
1
7
B. Cooking of food
1
8
D. carbon dioxide in human cells
1
9
B. contraction of left ventricle.
1
10
D. Longer small intestine.
1
11
C. Posture and balance.
1
12
D. sex is not genetically determined in snails.
1
13
B. A ray passing through the centre of curvature and incident obliquely.
1
14
C. Red Violet
1
15
C. It utilizes 10% of light energy and transfers the rest to the next trophic
level.
1
16
B. Enrichment of oxygen in the atmosphere.
1
17
A. A is true but R is false
1
18
B. Both A and R are true, and R is not the correct explanation of A
1
19
B. Both A and R are true, and R is not the correct explanation of A
1
20
D. A is false but R is true.
1
Section-B
21 A. Exothermic/Displacement reaction/Redox reaction. (0.5)
Heat is evolved or a More reactive element displaces a less reactive
element or aluminium reduces iron (II) oxide to iron (0.5)
B. Double displacement / Precipitation reaction (0.5)
As there is an exchange of ions between reactants and products /
(Yellow) precipitate (of Lead iodide) is formed (0.5)
2
22 S.
No.
Feature Alveoli Nephron
1 Structure
and location
Balloon like structures
present at the terminal ends
of bronchioles in lungs
Tubular structure
present in kidneys
2 Function Exchange of gases Filtration of blood
to form urine
2
23
Students to attempt either option A or B.
A. Steps of synthesis of glucose in plants:
? Absorption of light energy by chlorophyll
? Conversion of light energy to chemical energy and splitting of water
molecules into hydrogen and oxygen
? Reduction of carbon dioxide into carbohydrates.
? Desert plants take up carbon dioxide at night and prepare an
intermediate which is acted upon by the energy absorbed by the
chlorophyll during the day. (0.5 x 4)
OR
B.
? Salivary amylase – breaks down starch which is a complex
molecule to sugar.
? Pepsin – Helps to digest proteins in stomach.
? Trypsin – It helps in digesting proteins to amino acids.
? Lipase – Breaking down of emulsified fats to fatty acids and
glycerol. (0.5 x 4)
2
24 A. The lens is a convex lens.
B. The image is virtual.
C. Magnification for lens =
?? ?? =
h
?? h
?? = 2.
-30????
?? = 2
Hence u = -15 cm
- - - - - - - - - - - -
For visually impaired students
A. concave lens (1)
B. correction of myopia and peepholes of doors or any other correct
alternative. (1)
2
25 Student to attempt either A or B.
A. P = VI (1)
= 230 × 3.5 = 805 W
I ?
1
?? , so half the resistance means double the current.
Therefore, current in Y = 7.0 A. (1)
OR
B. For series total resistance is R+2R = 3R (0.5)
P1 =
?? 2
3?? . (0.5)
For parallel total Resistance is
2?? 3
. (0.5)
P2 =
?? 2
2?? /3
=
3?? 2
2?? .
?? 1
?? 2
=
2
9
. (0.5)
- - - - - - - - - - - -
For visually impaired students
A. The resistance will be lowest/minimum if all the resistors are
connected in parallel.
The equivalent resistance in parallel combination is given by (0.5)
1
?? ?????? =
1
?? 1
+
1
?? 2
+
1
?? 3
+
1
?? 4
(0.5)
Substituting the values, we get
1
?? ??????
=
1
3
+
1
6
+
1
9
+
1
12
(0.5)
=
12 + 6 + 4 + 2
36
=
24
36
=
2
3
?? ??????
=
3
2
= 1.5 ??
(0.5)
OR
B. ?? = ?? × ?? (0.5)
?? =
?? ?? =
1000
220
= 4.54 ?? (0.5)
We will be using fuse B with is rated as 5A. This is because it will be
able to sustain the current (4.54 A) passing through it. Whereas fuse
A will melt and break the circuit as the current exceeds its rating. (1)
2
26 Pesticides are non-biodegradable/ keep getting accumulated at each trophic
level, / persist for longer time/ and thus last trophic level has highest
concentration/ humans will have the highest concentration of pesticides/
leads to bio-magnification. (any 2 points)
- - - - - - - - - - - -
For visually impaired students
2
Cabbage/plant-> rabbit-> snake-> owl (Any other relevant food chain) (1)
Pesticides are non-biodegradable and persist for long. So when humans
consume plants or any animal that consume this plant, the pesticide enters
the food chain and keeps getting accumulated at each trophic level, thus the
organism in the last trophic level-human being has the highest concentration
of pesticide and this is called biological magnification. (1)
Section-C
27 A. Aqueous solution of magnesium oxide turns red litmus to blue.
Aluminium oxide is amphoteric and insoluble in water. Thus, it does
not change the colour of either blue or red litmus.
OR
Magnesium oxide reacts with acid only whereas Aluminium oxide reacts
with acids and bases, which are amphoteric. (1)
B.
(1+1)
- -- - - - - - - - -
For visually impaired students
A. Certain metals (like aluminium/ copper) are used for making cooking
utensils as they are good conductors of heat and have high melting
points. (0.5 + 0.5)
B. Hydrogen gas is not evolved when a metal reacts with nitric acid. This
is because HNO3 is a strong oxidising agent. It oxidises the H2
produced to water and itself gets reduced to any of the nitrogen oxides
(N2O, NO, NO2). But magnesium (Mg) and manganese (Mn) react
with very dilute HNO3 to evolve H2 gas. (1+1)
3
28 Students to attempt either A or B.
A.
(i) X = NaHCO3; Z = Na2CO3 (0.5+0.5)
(ii) Decomposition reaction (0.5)
(iii) Solution A (0.5)
(iv) Increasing order or H+ ions C<B<A (1)
OR
B.
(i) As bee sting is acidic and wasp sting is basic. (1)
(ii) To change the nature of soil to (neutral or basic). (1)
(iii) To protect sculptures from the effects of certain gases present in
environment and acid rain. (1)
3
29 ? In plants, the water is absorbed by the plants from the soil through the
roots. Xylem tissue of the roots, stems and leaves are interconnected
to form a continuous system of water conducting channels. (1)
? During the day, when stomata are open, the transpiration pull becomes
3
Page 5
MARKING SCHEME
2024 -25
Class X Science (086)
Section-A
1
A. 2,2,4
1
2
B. a – (iii), b – (i), c – (iv), d – (ii)
1
3
A. C2H5OH
Alternate question for VI
A. Dilute acid
1
4
C. A has a pH greater than 7 and B has a pH less than 7
1
5
C. Displacement reaction
1
6
C. X is a non-metal and Y is a metal.
1
7
B. Cooking of food
1
8
D. carbon dioxide in human cells
1
9
B. contraction of left ventricle.
1
10
D. Longer small intestine.
1
11
C. Posture and balance.
1
12
D. sex is not genetically determined in snails.
1
13
B. A ray passing through the centre of curvature and incident obliquely.
1
14
C. Red Violet
1
15
C. It utilizes 10% of light energy and transfers the rest to the next trophic
level.
1
16
B. Enrichment of oxygen in the atmosphere.
1
17
A. A is true but R is false
1
18
B. Both A and R are true, and R is not the correct explanation of A
1
19
B. Both A and R are true, and R is not the correct explanation of A
1
20
D. A is false but R is true.
1
Section-B
21 A. Exothermic/Displacement reaction/Redox reaction. (0.5)
Heat is evolved or a More reactive element displaces a less reactive
element or aluminium reduces iron (II) oxide to iron (0.5)
B. Double displacement / Precipitation reaction (0.5)
As there is an exchange of ions between reactants and products /
(Yellow) precipitate (of Lead iodide) is formed (0.5)
2
22 S.
No.
Feature Alveoli Nephron
1 Structure
and location
Balloon like structures
present at the terminal ends
of bronchioles in lungs
Tubular structure
present in kidneys
2 Function Exchange of gases Filtration of blood
to form urine
2
23
Students to attempt either option A or B.
A. Steps of synthesis of glucose in plants:
? Absorption of light energy by chlorophyll
? Conversion of light energy to chemical energy and splitting of water
molecules into hydrogen and oxygen
? Reduction of carbon dioxide into carbohydrates.
? Desert plants take up carbon dioxide at night and prepare an
intermediate which is acted upon by the energy absorbed by the
chlorophyll during the day. (0.5 x 4)
OR
B.
? Salivary amylase – breaks down starch which is a complex
molecule to sugar.
? Pepsin – Helps to digest proteins in stomach.
? Trypsin – It helps in digesting proteins to amino acids.
? Lipase – Breaking down of emulsified fats to fatty acids and
glycerol. (0.5 x 4)
2
24 A. The lens is a convex lens.
B. The image is virtual.
C. Magnification for lens =
?? ?? =
h
?? h
?? = 2.
-30????
?? = 2
Hence u = -15 cm
- - - - - - - - - - - -
For visually impaired students
A. concave lens (1)
B. correction of myopia and peepholes of doors or any other correct
alternative. (1)
2
25 Student to attempt either A or B.
A. P = VI (1)
= 230 × 3.5 = 805 W
I ?
1
?? , so half the resistance means double the current.
Therefore, current in Y = 7.0 A. (1)
OR
B. For series total resistance is R+2R = 3R (0.5)
P1 =
?? 2
3?? . (0.5)
For parallel total Resistance is
2?? 3
. (0.5)
P2 =
?? 2
2?? /3
=
3?? 2
2?? .
?? 1
?? 2
=
2
9
. (0.5)
- - - - - - - - - - - -
For visually impaired students
A. The resistance will be lowest/minimum if all the resistors are
connected in parallel.
The equivalent resistance in parallel combination is given by (0.5)
1
?? ?????? =
1
?? 1
+
1
?? 2
+
1
?? 3
+
1
?? 4
(0.5)
Substituting the values, we get
1
?? ??????
=
1
3
+
1
6
+
1
9
+
1
12
(0.5)
=
12 + 6 + 4 + 2
36
=
24
36
=
2
3
?? ??????
=
3
2
= 1.5 ??
(0.5)
OR
B. ?? = ?? × ?? (0.5)
?? =
?? ?? =
1000
220
= 4.54 ?? (0.5)
We will be using fuse B with is rated as 5A. This is because it will be
able to sustain the current (4.54 A) passing through it. Whereas fuse
A will melt and break the circuit as the current exceeds its rating. (1)
2
26 Pesticides are non-biodegradable/ keep getting accumulated at each trophic
level, / persist for longer time/ and thus last trophic level has highest
concentration/ humans will have the highest concentration of pesticides/
leads to bio-magnification. (any 2 points)
- - - - - - - - - - - -
For visually impaired students
2
Cabbage/plant-> rabbit-> snake-> owl (Any other relevant food chain) (1)
Pesticides are non-biodegradable and persist for long. So when humans
consume plants or any animal that consume this plant, the pesticide enters
the food chain and keeps getting accumulated at each trophic level, thus the
organism in the last trophic level-human being has the highest concentration
of pesticide and this is called biological magnification. (1)
Section-C
27 A. Aqueous solution of magnesium oxide turns red litmus to blue.
Aluminium oxide is amphoteric and insoluble in water. Thus, it does
not change the colour of either blue or red litmus.
OR
Magnesium oxide reacts with acid only whereas Aluminium oxide reacts
with acids and bases, which are amphoteric. (1)
B.
(1+1)
- -- - - - - - - - -
For visually impaired students
A. Certain metals (like aluminium/ copper) are used for making cooking
utensils as they are good conductors of heat and have high melting
points. (0.5 + 0.5)
B. Hydrogen gas is not evolved when a metal reacts with nitric acid. This
is because HNO3 is a strong oxidising agent. It oxidises the H2
produced to water and itself gets reduced to any of the nitrogen oxides
(N2O, NO, NO2). But magnesium (Mg) and manganese (Mn) react
with very dilute HNO3 to evolve H2 gas. (1+1)
3
28 Students to attempt either A or B.
A.
(i) X = NaHCO3; Z = Na2CO3 (0.5+0.5)
(ii) Decomposition reaction (0.5)
(iii) Solution A (0.5)
(iv) Increasing order or H+ ions C<B<A (1)
OR
B.
(i) As bee sting is acidic and wasp sting is basic. (1)
(ii) To change the nature of soil to (neutral or basic). (1)
(iii) To protect sculptures from the effects of certain gases present in
environment and acid rain. (1)
3
29 ? In plants, the water is absorbed by the plants from the soil through the
roots. Xylem tissue of the roots, stems and leaves are interconnected
to form a continuous system of water conducting channels. (1)
? During the day, when stomata are open, the transpiration pull becomes
3
the major driving force for the movement of water in the xylem. (1)
? Evaporation of water molecules from the stomata creates a suction
which pulls water from the xylem cells of roots to the stem and then to
the leaves. (1)
30 (Any letter which clearly indicated dominant and recessive ears, example, L
or E or any other)
A. LL × ll
F1= Ll
Ll X Ll
1LL:2Ll:1ll. (2)
B. No change in ratio/the ratio of F2 generation will still be 1LL:2Ll:1ll/ ratio
will be the same.
As the cross is still between a pure dominant and recessive allele/
genes/ traits/characters /as shown in the cross above. (1)
3
31 A. Hypermetropia is a defect that causes difficulty in focusing on near
objects, with clearer vision observed for distant objects. In Myopia
distant objects appear blurry while near objects are seen clearly. (1)
B.
(i) The image shows a case of hypermetropia. (0.5)
(ii) shortening of the eyeball or focal length of the eye lens becomes
too long. (0.5)
(iii) No the concave lens would diverge the rays coming to the eyeball
and will push the image even further, but a convex lens should be
used which will help to converge the rays and create the image at
the exact place on the retina. (1)
- - - - - - - - - - - -
For visually impaired students
A. Hypermetropia is a defect that causes difficulty in focusing on near
objects, with clearer vision observed for distant objects. In Myopia
distant objects appear blurry while near objects are seen
clearly. (1)
B. High converging power of eye lens, elongation of eye-ball. (2)
3
32 A.
R ? ??
R ?
?? ??
R = ?? ?? ?? . (1.5)
B.
R = ?? ?? ??
?? = R
?? ?? for A =1m
2
and l =1m, we have
?? = R
Hence resistivity is the resistance offered by a wire of length 1 m having a
cross sectional area of 1 m
2
. (1.5)
3
33 A. Magnetic field strength is inversely proportional to the distance from the 3
Read More