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A coil of inductance 0.1 H is connected to an alternating voltage generator of voltage E = 100 sin (100t) volt. The current flowing through the coil will be
- a)I = 10
sin (100t) A - b)I = 10
cos (100t) A - c)I = _10 sin (100t) A
- d)I = _10 cos (100t) A
Correct answer is option 'D'. Can you explain this answer?
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Verified Answer
A coil of inductance 0.1 H is connected to an alternating voltage gene...
L =0.14
E=100sin(100t)
⇒XL=wL=100×0.1
=10Ω
⇒io=Eo/XL=100/10=10A
⇒i=iosin(100t− π/2)
⇒i=−iosin[(π/2)−100]
So we get
⇒i=−10cos(100t)A
therefore, option D is correct.
E=100sin(100t)
⇒XL=wL=100×0.1
=10Ω
⇒io=Eo/XL=100/10=10A
⇒i=iosin(100t− π/2)
⇒i=−iosin[(π/2)−100]
So we get
⇒i=−10cos(100t)A
therefore, option D is correct.
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A coil of inductance 0.1 H is connected to an alternating voltage gene...
L =0.14
E=100sin(100t)
⇒XL=wL=100×0.1
=10Ω
⇒io=Eo/XL=100/10=10A
⇒i=iosin(100t− π/2)
⇒i=−iosin[(π/2)−100]
So we get
⇒i=−10cos(100t)A
therefore, option D is correct.
E=100sin(100t)
⇒XL=wL=100×0.1
=10Ω
⇒io=Eo/XL=100/10=10A
⇒i=iosin(100t− π/2)
⇒i=−iosin[(π/2)−100]
So we get
⇒i=−10cos(100t)A
therefore, option D is correct.
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A coil of inductance 0.1 H is connected to an alternating voltage generator of voltage E = 100 sin (100t) volt. The current flowing through the coil will bea)I = 10 sin (100t) Ab)I = 10 cos (100t) Ac)I = _10 sin (100t) Ad)I = _10 cos (100t) ACorrect answer is option 'D'. Can you explain this answer?
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A coil of inductance 0.1 H is connected to an alternating voltage generator of voltage E = 100 sin (100t) volt. The current flowing through the coil will bea)I = 10 sin (100t) Ab)I = 10 cos (100t) Ac)I = _10 sin (100t) Ad)I = _10 cos (100t) ACorrect answer is option 'D'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about A coil of inductance 0.1 H is connected to an alternating voltage generator of voltage E = 100 sin (100t) volt. The current flowing through the coil will bea)I = 10 sin (100t) Ab)I = 10 cos (100t) Ac)I = _10 sin (100t) Ad)I = _10 cos (100t) ACorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A coil of inductance 0.1 H is connected to an alternating voltage generator of voltage E = 100 sin (100t) volt. The current flowing through the coil will bea)I = 10 sin (100t) Ab)I = 10 cos (100t) Ac)I = _10 sin (100t) Ad)I = _10 cos (100t) ACorrect answer is option 'D'. Can you explain this answer?.
A coil of inductance 0.1 H is connected to an alternating voltage generator of voltage E = 100 sin (100t) volt. The current flowing through the coil will bea)I = 10 sin (100t) Ab)I = 10 cos (100t) Ac)I = _10 sin (100t) Ad)I = _10 cos (100t) ACorrect answer is option 'D'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about A coil of inductance 0.1 H is connected to an alternating voltage generator of voltage E = 100 sin (100t) volt. The current flowing through the coil will bea)I = 10 sin (100t) Ab)I = 10 cos (100t) Ac)I = _10 sin (100t) Ad)I = _10 cos (100t) ACorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A coil of inductance 0.1 H is connected to an alternating voltage generator of voltage E = 100 sin (100t) volt. The current flowing through the coil will bea)I = 10 sin (100t) Ab)I = 10 cos (100t) Ac)I = _10 sin (100t) Ad)I = _10 cos (100t) ACorrect answer is option 'D'. Can you explain this answer?.
Solutions for A coil of inductance 0.1 H is connected to an alternating voltage generator of voltage E = 100 sin (100t) volt. The current flowing through the coil will bea)I = 10 sin (100t) Ab)I = 10 cos (100t) Ac)I = _10 sin (100t) Ad)I = _10 cos (100t) ACorrect answer is option 'D'. Can you explain this answer? in English & in Hindi are available as part of our courses for Class 12.
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A coil of inductance 0.1 H is connected to an alternating voltage generator of voltage E = 100 sin (100t) volt. The current flowing through the coil will bea)I = 10 sin (100t) Ab)I = 10 cos (100t) Ac)I = _10 sin (100t) Ad)I = _10 cos (100t) ACorrect answer is option 'D'. Can you explain this answer?, a detailed solution for A coil of inductance 0.1 H is connected to an alternating voltage generator of voltage E = 100 sin (100t) volt. The current flowing through the coil will bea)I = 10 sin (100t) Ab)I = 10 cos (100t) Ac)I = _10 sin (100t) Ad)I = _10 cos (100t) ACorrect answer is option 'D'. Can you explain this answer? has been provided alongside types of A coil of inductance 0.1 H is connected to an alternating voltage generator of voltage E = 100 sin (100t) volt. The current flowing through the coil will bea)I = 10 sin (100t) Ab)I = 10 cos (100t) Ac)I = _10 sin (100t) Ad)I = _10 cos (100t) ACorrect answer is option 'D'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice A coil of inductance 0.1 H is connected to an alternating voltage generator of voltage E = 100 sin (100t) volt. The current flowing through the coil will bea)I = 10 sin (100t) Ab)I = 10 cos (100t) Ac)I = _10 sin (100t) Ad)I = _10 cos (100t) ACorrect answer is option 'D'. Can you explain this answer? tests, examples and also practice Class 12 tests.
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