All Courses
Explore Courses UPSC Exam UPSC Test Series Free Notes EduRev Infinity Get the App Login Join for Free
Sign in Open App
Class 12 Exam  >  Class 12 Questions  >  An ac circuit resonates at a frequency of 10 ... Start Learning for Free
SaveJoin the Discussion on the App
An ac circuit resonates at a frequency of 10 kHz. If its frequency is increased to 11 kHz, then
  • a)
    Impedance will increase by 1.1 times
  • b)
    Impedance will remain remain unchanged
  • c)
    Impedance will increase and become inductive
  • d)
    Impedance will increase and become capacitive
Correct answer is option 'C'. Can you explain this answer?
Clear all your Class 12 doubts with EduRev
Most Upvoted Answer
An ac circuit resonates at a frequency of 10 kHz. If its frequency is ...
To understand why the impedance of an AC circuit increases and becomes inductive when the frequency is increased, we need to consider the behavior of inductors and capacitors at different frequencies.

1. Behavior of Inductors:
- An inductor is a device that stores energy in its magnetic field.
- At low frequencies, the reactance of an inductor (Xl) is small, and its impedance (Z) is primarily determined by its resistance (R).
- As the frequency increases, the reactance of the inductor also increases. The reactance of an inductor is given by the formula Xl = 2πfL, where f is the frequency and L is the inductance.
- When the frequency reaches a certain point, called the resonant frequency, the reactance of the inductor becomes equal to its resistance, resulting in a purely resistive impedance.

2. Behavior of Capacitors:
- A capacitor is a device that stores energy in its electric field.
- At low frequencies, the reactance of a capacitor (Xc) is large, and its impedance (Z) is primarily determined by its capacitance (C).
- As the frequency increases, the reactance of the capacitor decreases. The reactance of a capacitor is given by the formula Xc = 1/(2πfC), where f is the frequency and C is the capacitance.
- When the frequency reaches the resonant frequency, the reactance of the capacitor becomes equal to its resistance, resulting in a purely resistive impedance.

3. Impedance of an AC Circuit:
- The impedance of an AC circuit is the total opposition to the flow of alternating current, taking into account both the resistance and reactance.
- The impedance is given by the formula Z = √(R^2 + (Xl - Xc)^2), where R is the resistance, Xl is the reactance of the inductor, and Xc is the reactance of the capacitor.
- When the frequency is at the resonant frequency, Xl = Xc, and the impedance is purely resistive.
- When the frequency is increased beyond the resonant frequency, Xl > Xc, resulting in an increase in the reactance term in the impedance formula. This leads to an increase in the overall impedance.

Based on the above explanations, we can conclude that when the frequency of an AC circuit resonating at 10 kHz is increased to 11 kHz:
- The reactance of the inductor will increase.
- The reactance of the capacitor will decrease.
- The reactance term in the impedance formula will increase, resulting in an overall increase in impedance.
- Since the reactance of the inductor is greater than the reactance of the capacitor, the impedance will become more inductive.
Community Answer
An ac circuit resonates at a frequency of 10 kHz. If its frequency is ...
Z(impedance)=√R2+(XL)2=√R2+(2πf)2
so, As frequency increases for inductive reactance , the impedance increases
Explore Courses for Class 12 exam

Similar Class 12 Doubts

Read the following text and answer the following questions on the basis of the same: Tuning a radio set: In essence the simplest tuned radio frequency receiver is a simple crystal set. Desired frequency is tuned by a tuned coil / capacitor combination, and then the signal is presented to a simple crystal or diode detector where the amplitude modulated signal, is demodulated. This is then passed straight to the headphones or speaker. In radio set there is an LC oscillator comprising of a variable capacitor (or sometimes a variable coupling coil), with a knob on the front panel to tune the receiver. Capacitor used in old radio sets is gang capacitor. It consists of two sets of parallel circular plates one of which can rotate manually by means of a knob. The rotation causes overlapping areas of plates to change, thus changing its capacitance. Air gap between plates acts as dielectric. The capacitor has to be tuned in tandem corresponding to the frequency of a station so that the LC combination of the radio set resonates at the frequency of the desired station.When capacitive reactance (XC) is equal to the inductive reactance (XL), then the resonance occurs and the resonant frequency is given by ω0 = 1/√LCcurrent amplitude becomes maximum at the resonant frequency. It is important to note that resonance phenomenon is exhibited by a circuit only if both L and C are present in the circuit. Only then do the voltages across L and C cancel each other (both being out of phas e) and the Current amplitude is Vm/R the total source voltage appearing across R. This means that we cannot have resonance in a RL or RC circuit.Resonance frequency is equal to

Read the following text and answer the following questions on the basis of the same: Tuning a radio set: In essence the simplest tuned radio frequency receiver is a simple crystal set. Desired frequency is tuned by a tuned coil / capacitor combination, and then the signal is presented to a simple crystal or diode detector where the amplitude modulated signal, is demodulated. This is then passed straight to the headphones or speaker. In radio set there is an LC oscillator comprising of a variable capacitor (or sometimes a variable coupling coil), with a knob on the front panel to tune the receiver. Capacitor used in old radio sets is gang capacitor. It consists of two sets of parallel circular plates one of which can rotate manually by means of a knob. The rotation causes overlapping areas of plates to change, thus changing its capacitance. Air gap between plates acts as dielectric. The capacitor has to be tuned in tandem corresponding to the frequency of a station so that the LC combination of the radio set resonates at the frequency of the desired station.When capacitive reactance (XC) is equal to the inductive reactance (XL), then the resonance occurs and the resonant frequency is given by ω0 = 1/√LCcurrent amplitude becomes maximum at the resonant frequency. It is important to note that resonance phenomenon is exhibited by a circuit only if both L and C are present in the circuit. Only then do the voltages across L and C cancel each other (both being out of phas e) and the Current amplitude is Vm/R the total source voltage appearing across R. This means that we cannot have resonance in a RL or RC circuit.Capacitor used in radio set for tuning is a

Read the following text and answer the following questions on the basis of the same:Tuning a radio set: In essence the simplest tuned radio frequency receiver is a simple crystal set. Desired frequency is tuned by a tuned coil / capacitor combination, and then the signal is presented to a simple crystal or diode detector where the amplitude modulated signal, is demodulated. This is then passed straight to the headphones or speaker. In radio set there is an LC oscillator comprising of a variable capacitor (or sometimes a variable coupling coil), with a knob on the front panel to tune the receiver. Capacitor used in old radio sets is gang capacitor. It consists of two sets of parallel circular plates one of which can rotate manually by means of a knob. The rotation causes overlapping areas of plates to change, thus changing its capacitance. Air gap between plates acts as dielectric. The capacitor has to be tuned in tandem corresponding to the frequency of a station so that the LC combination of the radio set resonates at the frequency of the desired station.When capacitive reactance (XC) is equal to the inductive reactance (XL), then the resonance occurs and the resonant frequency is given by ω0 = 1/√LCcurrent amplitude becomes maximum at the resonant frequency. It is important to note that resonance phenomenon is exhibited by a circuit only if both L and C are present in the circuit. Only then do the voltages across L and C cancel each other (both being out of phas e) and the Current amplitude is Vm/R the total source voltage appearing across R. This means that we cannot have resonance in a RL or RC circuit.Name the phenomenon involved in tuning a radio set to a particular radio station.

Read the following text and answer the following questions on the basis of the same:Tuning a radio set: In essence the simplest tuned radio frequency receiver is a simple crystal set. Desired frequency is tuned by a tuned coil / capacitor combination, and then the signal is presented to a simple crystal or diode detector where the amplitude modulated signal, is demodulated. This is then passed straight to the headphones or speaker. In radio set there is an LC oscillator comprising of a variable capacitor (or sometimes a variable coupling coil), with a knob on the front panel to tune the receiver. Capacitor used in old radio sets is gang capacitor. It consists of two sets of parallel circular plates one of which can rotate manually by means of a knob. The rotation causes overlapping areas of plates to change, thus changing its capacitance. Air gap between plates acts as dielectric. The capacitor has to be tuned in tandem corresponding to the frequency of a station so that the LC combination of the radio set resonates at the frequency of the desired station.When capacitive reactance (XC) is equal to the inductive reactance (XL), then the resonance occurs and the resonant frequency is given by ω0 = 1/√LCcurrent amplitude becomes maximum at the resonant frequency. It is important to note that resonance phenomenon is exhibited by a circuit only if both L and C are present in the circuit. Only then do the voltages across L and C cancel each other (both being out of phas e) and the Current amplitude is Vm/R the total source voltage appearing across R. This means that we cannot have resonance in a RL or RC circuit.Resonance may occur in

An ac circuit resonates at a frequency of 10 kHz. If its frequency is increased to 11 kHz, thena)Impedance will increase by 1.1 timesb)Impedance will remain remain unchangedc)Impedance will increase and become inductived)Impedance will increase and become capacitiveCorrect answer is option 'C'. Can you explain this answer?
Question Description
An ac circuit resonates at a frequency of 10 kHz. If its frequency is increased to 11 kHz, thena)Impedance will increase by 1.1 timesb)Impedance will remain remain unchangedc)Impedance will increase and become inductived)Impedance will increase and become capacitiveCorrect answer is option 'C'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about An ac circuit resonates at a frequency of 10 kHz. If its frequency is increased to 11 kHz, thena)Impedance will increase by 1.1 timesb)Impedance will remain remain unchangedc)Impedance will increase and become inductived)Impedance will increase and become capacitiveCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An ac circuit resonates at a frequency of 10 kHz. If its frequency is increased to 11 kHz, thena)Impedance will increase by 1.1 timesb)Impedance will remain remain unchangedc)Impedance will increase and become inductived)Impedance will increase and become capacitiveCorrect answer is option 'C'. Can you explain this answer?.
Solutions for An ac circuit resonates at a frequency of 10 kHz. If its frequency is increased to 11 kHz, thena)Impedance will increase by 1.1 timesb)Impedance will remain remain unchangedc)Impedance will increase and become inductived)Impedance will increase and become capacitiveCorrect answer is option 'C'. Can you explain this answer? in English & in Hindi are available as part of our courses for Class 12. Download more important topics, notes, lectures and mock test series for Class 12 Exam by signing up for free.
Here you can find the meaning of An ac circuit resonates at a frequency of 10 kHz. If its frequency is increased to 11 kHz, thena)Impedance will increase by 1.1 timesb)Impedance will remain remain unchangedc)Impedance will increase and become inductived)Impedance will increase and become capacitiveCorrect answer is option 'C'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of An ac circuit resonates at a frequency of 10 kHz. If its frequency is increased to 11 kHz, thena)Impedance will increase by 1.1 timesb)Impedance will remain remain unchangedc)Impedance will increase and become inductived)Impedance will increase and become capacitiveCorrect answer is option 'C'. Can you explain this answer?, a detailed solution for An ac circuit resonates at a frequency of 10 kHz. If its frequency is increased to 11 kHz, thena)Impedance will increase by 1.1 timesb)Impedance will remain remain unchangedc)Impedance will increase and become inductived)Impedance will increase and become capacitiveCorrect answer is option 'C'. Can you explain this answer? has been provided alongside types of An ac circuit resonates at a frequency of 10 kHz. If its frequency is increased to 11 kHz, thena)Impedance will increase by 1.1 timesb)Impedance will remain remain unchangedc)Impedance will increase and become inductived)Impedance will increase and become capacitiveCorrect answer is option 'C'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice An ac circuit resonates at a frequency of 10 kHz. If its frequency is increased to 11 kHz, thena)Impedance will increase by 1.1 timesb)Impedance will remain remain unchangedc)Impedance will increase and become inductived)Impedance will increase and become capacitiveCorrect answer is option 'C'. Can you explain this answer? tests, examples and also practice Class 12 tests.
Explore Courses for Class 12 exam
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
10M+ students study on EduRev
Get App
© EduRev
Education Revolution
Signup to see your scores go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup