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An ac circuit resonates at a frequency of 10 kHz. If its frequency is increased to 11 kHz, then
  • a)
    Impedance will increase by 1.1 times
  • b)
    Impedance will remain remain unchanged
  • c)
    Impedance will increase and become inductive
  • d)
    Impedance will increase and become capacitive
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
An ac circuit resonates at a frequency of 10 kHz. If its frequency is ...
In an LCR ac circuit, 
Impedance, Z=R+j(XL​−XC​) . . . . . . ..  .(1)
At the resonance, inductive reactance is equal to the capacitive reactance. 
XL​=XC​
From equation (1),
Z=R
The impedance is independent of the frequency term.
On increasing the frequency, the impedance will remain unchanged.
The correct option is B.
 
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Most Upvoted Answer
An ac circuit resonates at a frequency of 10 kHz. If its frequency is ...
Explanation:

To understand why the impedance will remain unchanged when the frequency of an AC circuit is increased from 10 kHz to 11 kHz, we need to consider the behavior of the circuit components at different frequencies.

Resonance in an AC circuit:
When an AC circuit resonates at a certain frequency, it means that the inductive reactance (XL) and capacitive reactance (XC) in the circuit cancel each other out, resulting in a purely resistive impedance. This occurs at the resonant frequency (fr) of the circuit.

Reactance:
Reactance is the opposition offered by inductors and capacitors to the flow of alternating current. Inductive reactance (XL) increases with increasing frequency, while capacitive reactance (XC) decreases with increasing frequency.

Impedance:
Impedance (Z) is the total opposition offered by the circuit to the flow of alternating current. It is a combination of resistance (R) and reactance (X). In a purely resistive circuit, the impedance is equal to the resistance. In a reactive circuit, the impedance is given by the formula:

Z = √(R^2 + (XL - XC)^2)

Effect of frequency increase:
When the frequency of the AC circuit is increased from 10 kHz to 11 kHz, both the inductive reactance (XL) and capacitive reactance (XC) increase. However, since both reactances increase by the same factor, their difference (XL - XC) remains unchanged.

Conclusion:
Since the difference between the inductive and capacitive reactances (XL - XC) remains unchanged, the impedance of the circuit, calculated using the above formula, will also remain unchanged. Therefore, the correct answer is option 'B' - the impedance will remain unchanged.
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An ac circuit resonates at a frequency of 10 kHz. If its frequency is increased to 11 kHz, thena)Impedance will increase by 1.1 timesb)Impedance will remain remain unchangedc)Impedance will increase and become inductived)Impedance will increase and become capacitiveCorrect answer is option 'B'. Can you explain this answer?
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An ac circuit resonates at a frequency of 10 kHz. If its frequency is increased to 11 kHz, thena)Impedance will increase by 1.1 timesb)Impedance will remain remain unchangedc)Impedance will increase and become inductived)Impedance will increase and become capacitiveCorrect answer is option 'B'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about An ac circuit resonates at a frequency of 10 kHz. If its frequency is increased to 11 kHz, thena)Impedance will increase by 1.1 timesb)Impedance will remain remain unchangedc)Impedance will increase and become inductived)Impedance will increase and become capacitiveCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An ac circuit resonates at a frequency of 10 kHz. If its frequency is increased to 11 kHz, thena)Impedance will increase by 1.1 timesb)Impedance will remain remain unchangedc)Impedance will increase and become inductived)Impedance will increase and become capacitiveCorrect answer is option 'B'. Can you explain this answer?.
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