IIT JAM Exam  >  IIT JAM Questions  >  The concentration of reactant undergoing deco... Start Learning for Free
The concentration of reactant undergoing decomposition was o.1 ,0.08 and 0.067mol/L after 1.0,2.0,and 3.0 hr respectively.the order of reaction.?
Most Upvoted Answer
The concentration of reactant undergoing decomposition was o.1 ,0.08 a...
Analyzing the Reaction Order
To determine the order of the reaction, we can use the concentration data provided at various time intervals. The concentrations of the reactant are:
- At 1.0 hr: 0.1 mol/L
- At 2.0 hr: 0.08 mol/L
- At 3.0 hr: 0.067 mol/L
Calculating the Change in Concentration
- From 1.0 hr to 2.0 hr:
- Change = 0.1 - 0.08 = 0.02 mol/L
- From 2.0 hr to 3.0 hr:
- Change = 0.08 - 0.067 = 0.013 mol/L
Determining the Rate of Change
- Average rate from 1.0 hr to 2.0 hr:
- Rate = Change in concentration / Change in time = 0.02 / 1 = 0.02 mol/L/hr
- Average rate from 2.0 hr to 3.0 hr:
- Rate = Change in concentration / Change in time = 0.013 / 1 = 0.013 mol/L/hr
Order of Reaction Calculation
To find the order of the reaction, we can compare the rates of change with respect to the concentration.
If we assume a first-order reaction:
- The rate of reaction is proportional to the concentration of the reactant.
- A decrease in concentration will yield a corresponding decrease in the rate.
Since the rate decrease is not constant and appears to diminish over time, it suggests the reaction is not first-order.
Conclusion
The observed data indicates that the reaction follows a second-order kinetics:
- The rate decreases more significantly as the reaction progresses, suggesting that the reaction order is higher than one.
In summary, the reaction is likely a second-order reaction based on the concentration changes over time.
Explore Courses for IIT JAM exam
The concentration of reactant undergoing decomposition was o.1 ,0.08 and 0.067mol/L after 1.0,2.0,and 3.0 hr respectively.the order of reaction.?
Question Description
The concentration of reactant undergoing decomposition was o.1 ,0.08 and 0.067mol/L after 1.0,2.0,and 3.0 hr respectively.the order of reaction.? for IIT JAM 2024 is part of IIT JAM preparation. The Question and answers have been prepared according to the IIT JAM exam syllabus. Information about The concentration of reactant undergoing decomposition was o.1 ,0.08 and 0.067mol/L after 1.0,2.0,and 3.0 hr respectively.the order of reaction.? covers all topics & solutions for IIT JAM 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The concentration of reactant undergoing decomposition was o.1 ,0.08 and 0.067mol/L after 1.0,2.0,and 3.0 hr respectively.the order of reaction.?.
Solutions for The concentration of reactant undergoing decomposition was o.1 ,0.08 and 0.067mol/L after 1.0,2.0,and 3.0 hr respectively.the order of reaction.? in English & in Hindi are available as part of our courses for IIT JAM. Download more important topics, notes, lectures and mock test series for IIT JAM Exam by signing up for free.
Here you can find the meaning of The concentration of reactant undergoing decomposition was o.1 ,0.08 and 0.067mol/L after 1.0,2.0,and 3.0 hr respectively.the order of reaction.? defined & explained in the simplest way possible. Besides giving the explanation of The concentration of reactant undergoing decomposition was o.1 ,0.08 and 0.067mol/L after 1.0,2.0,and 3.0 hr respectively.the order of reaction.?, a detailed solution for The concentration of reactant undergoing decomposition was o.1 ,0.08 and 0.067mol/L after 1.0,2.0,and 3.0 hr respectively.the order of reaction.? has been provided alongside types of The concentration of reactant undergoing decomposition was o.1 ,0.08 and 0.067mol/L after 1.0,2.0,and 3.0 hr respectively.the order of reaction.? theory, EduRev gives you an ample number of questions to practice The concentration of reactant undergoing decomposition was o.1 ,0.08 and 0.067mol/L after 1.0,2.0,and 3.0 hr respectively.the order of reaction.? tests, examples and also practice IIT JAM tests.
Explore Courses for IIT JAM exam

Suggested Free Tests

Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
10M+ students study on EduRev