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This discussion on The concentration of a reactant undergoing decomposition was 0.1, 0.08 and 0.067 mol L1 after 1.0, 2.0 and 3.0 hr respectively. The order of the reaction is:a)0b)1c)2d)3?
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**Solution:**
To determine the order of the reaction, we need to analyze the concentration-time data given in the question. The order of the reaction can be determined by comparing the changes in the concentration of the reactant over time.
Let's calculate the initial rate of reaction for each time interval:
**Time interval 1 (0 - 1.0 hr):**
Initial concentration of the reactant = 0.1 mol/L
Final concentration of the reactant = 0.08 mol/L
Change in concentration = 0.1 - 0.08 = 0.02 mol/L
Time taken = 1.0 hr
Rate of reaction in the first time interval = Change in concentration / Time taken = 0.02 mol/L / 1.0 hr = 0.02 mol/L.hr
**Time interval 2 (1.0 - 2.0 hr):**
Initial concentration of the reactant = 0.08 mol/L
Final concentration of the reactant = 0.067 mol/L
Change in concentration = 0.08 - 0.067 = 0.013 mol/L
Time taken = 1.0 hr
Rate of reaction in the second time interval = Change in concentration / Time taken = 0.013 mol/L / 1.0 hr = 0.013 mol/L.hr
**Time interval 3 (2.0 - 3.0 hr):**
Initial concentration of the reactant = 0.067 mol/L
Final concentration of the reactant = 0 (complete decomposition)
Change in concentration = 0.067 - 0 = 0.067 mol/L
Time taken = 1.0 hr
Rate of reaction in the third time interval = Change in concentration / Time taken = 0.067 mol/L / 1.0 hr = 0.067 mol/L.hr
By comparing the rates of reaction in the three time intervals, we can determine the order of the reaction.
If the rate of reaction remains constant over time, the reaction is zero order.
If the rate of reaction decreases over time, the reaction is first order.
If the rate of reaction decreases exponentially over time, the reaction is second order.
If the rate of reaction decreases exponentially and then levels off, the reaction is third order.
**Comparing the rates of reaction:**
Rate of reaction in the first time interval = 0.02 mol/L.hr
Rate of reaction in the second time interval = 0.013 mol/L.hr
Rate of reaction in the third time interval = 0.067 mol/L.hr
From the given data, we can observe that the rate of reaction decreases over time. Therefore, we can conclude that the reaction is first order.
Hence, the correct answer is (b) 1.
To determine the order of the reaction, we need to analyze the concentration-time data given in the question. The order of the reaction can be determined by comparing the changes in the concentration of the reactant over time.
Let's calculate the initial rate of reaction for each time interval:
**Time interval 1 (0 - 1.0 hr):**
Initial concentration of the reactant = 0.1 mol/L
Final concentration of the reactant = 0.08 mol/L
Change in concentration = 0.1 - 0.08 = 0.02 mol/L
Time taken = 1.0 hr
Rate of reaction in the first time interval = Change in concentration / Time taken = 0.02 mol/L / 1.0 hr = 0.02 mol/L.hr
**Time interval 2 (1.0 - 2.0 hr):**
Initial concentration of the reactant = 0.08 mol/L
Final concentration of the reactant = 0.067 mol/L
Change in concentration = 0.08 - 0.067 = 0.013 mol/L
Time taken = 1.0 hr
Rate of reaction in the second time interval = Change in concentration / Time taken = 0.013 mol/L / 1.0 hr = 0.013 mol/L.hr
**Time interval 3 (2.0 - 3.0 hr):**
Initial concentration of the reactant = 0.067 mol/L
Final concentration of the reactant = 0 (complete decomposition)
Change in concentration = 0.067 - 0 = 0.067 mol/L
Time taken = 1.0 hr
Rate of reaction in the third time interval = Change in concentration / Time taken = 0.067 mol/L / 1.0 hr = 0.067 mol/L.hr
By comparing the rates of reaction in the three time intervals, we can determine the order of the reaction.
If the rate of reaction remains constant over time, the reaction is zero order.
If the rate of reaction decreases over time, the reaction is first order.
If the rate of reaction decreases exponentially over time, the reaction is second order.
If the rate of reaction decreases exponentially and then levels off, the reaction is third order.
**Comparing the rates of reaction:**
Rate of reaction in the first time interval = 0.02 mol/L.hr
Rate of reaction in the second time interval = 0.013 mol/L.hr
Rate of reaction in the third time interval = 0.067 mol/L.hr
From the given data, we can observe that the rate of reaction decreases over time. Therefore, we can conclude that the reaction is first order.
Hence, the correct answer is (b) 1.
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This discussion on The concentration of a reactant undergoing decomposition was 0.1, 0.08 and 0.067 mol L1 after 1.0, 2.0 and 3.0 hr respectively. The order of the reaction is:a)0b)1c)2d)3? for IIT JAM 2024 is part of IIT JAM preparation. The Question and answers have been prepared according to the IIT JAM exam syllabus. Information about This discussion on The concentration of a reactant undergoing decomposition was 0.1, 0.08 and 0.067 mol L1 after 1.0, 2.0 and 3.0 hr respectively. The order of the reaction is:a)0b)1c)2d)3? covers all topics & solutions for IIT JAM 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for This discussion on The concentration of a reactant undergoing decomposition was 0.1, 0.08 and 0.067 mol L1 after 1.0, 2.0 and 3.0 hr respectively. The order of the reaction is:a)0b)1c)2d)3?.
This discussion on The concentration of a reactant undergoing decomposition was 0.1, 0.08 and 0.067 mol L1 after 1.0, 2.0 and 3.0 hr respectively. The order of the reaction is:a)0b)1c)2d)3? for IIT JAM 2024 is part of IIT JAM preparation. The Question and answers have been prepared according to the IIT JAM exam syllabus. Information about This discussion on The concentration of a reactant undergoing decomposition was 0.1, 0.08 and 0.067 mol L1 after 1.0, 2.0 and 3.0 hr respectively. The order of the reaction is:a)0b)1c)2d)3? covers all topics & solutions for IIT JAM 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for This discussion on The concentration of a reactant undergoing decomposition was 0.1, 0.08 and 0.067 mol L1 after 1.0, 2.0 and 3.0 hr respectively. The order of the reaction is:a)0b)1c)2d)3?.
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