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A particle moves in straight line with a constant acceleration.It changes its velocity from 10 ms-1 to 20ms-1 while passing through a distance 135 m in t sec.The value of t is....
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A particle moves in straight line with a constant acceleration.It chan...
U=10m/s
V=20m/s
S=135m
We know,
2as=v2-u2
2×a×135=(20×20)-(10×1₩)
270a=400-100
a=300/270
a=10/9m/s2
V=u+at
20=10+10/9×t
10=10/9×t
T=10×9/10
T=9 seconds
if wrong then explain me please
V=20m/s
S=135m
We know,
2as=v2-u2
2×a×135=(20×20)-(10×1₩)
270a=400-100
a=300/270
a=10/9m/s2
V=u+at
20=10+10/9×t
10=10/9×t
T=10×9/10
T=9 seconds
if wrong then explain me please
Community Answer
A particle moves in straight line with a constant acceleration.It chan...
Given:
- Initial velocity (u): 10 m/s
- Final velocity (v): 20 m/s
- Distance (s): 135 m
Formula:
- Final velocity (v) = Initial velocity (u) + Acceleration (a) * Time (t)
- Distance (s) = Initial velocity (u) * Time (t) + 0.5 * Acceleration (a) * Time (t)^2
Calculating the acceleration:
Using the first formula, we can calculate the acceleration (a).
- 20 m/s = 10 m/s + a * t
- a * t = 20 m/s - 10 m/s
- a * t = 10 m/s
- a = 10 m/s / t
Substituting the values in the second formula:
Now, we can substitute the known values in the second formula to find the time (t).
- 135 m = 10 m/s * t + 0.5 * a * t^2
- 135 m = 10 m/s * t + 0.5 * (10 m/s / t) * t^2
- 135 m = 10 m/s * t + 5 m/s * t
- 135 m = 15 m/s * t
- t = 135 m / 15 m/s
- t = 9 seconds
Conclusion:
The value of time (t) taken by the particle to change its velocity from 10 m/s to 20 m/s while passing through a distance of 135 m is 9 seconds.
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A particle moves in straight line with a constant acceleration.It changes its velocity from 10 ms-1 to 20ms-1 while passing through a distance 135 m in t sec.The value of t is....
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A particle moves in straight line with a constant acceleration.It changes its velocity from 10 ms-1 to 20ms-1 while passing through a distance 135 m in t sec.The value of t is.... for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about A particle moves in straight line with a constant acceleration.It changes its velocity from 10 ms-1 to 20ms-1 while passing through a distance 135 m in t sec.The value of t is.... covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A particle moves in straight line with a constant acceleration.It changes its velocity from 10 ms-1 to 20ms-1 while passing through a distance 135 m in t sec.The value of t is.....
A particle moves in straight line with a constant acceleration.It changes its velocity from 10 ms-1 to 20ms-1 while passing through a distance 135 m in t sec.The value of t is.... for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about A particle moves in straight line with a constant acceleration.It changes its velocity from 10 ms-1 to 20ms-1 while passing through a distance 135 m in t sec.The value of t is.... covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A particle moves in straight line with a constant acceleration.It changes its velocity from 10 ms-1 to 20ms-1 while passing through a distance 135 m in t sec.The value of t is.....
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