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The age of father 10 years ago was thrice the age of his son. Ten years hence, father’s age will be twice that of his son. The ratio of their present ages is
  • a)
    5:2                           
  • b)
    7:3
  • c)
    9:2                           
  • d)
    13:4
  • e)
    None of these
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
The age of father 10 years ago was thrice the age of his son. Ten year...
The correct option ia B.
Let the ages of father and son 10 years ago be 3x and x years respectively.
Then, (3x + 10) + 10 = 2[(x + 10) + 10]
⇒ 3x + 20 = 2x + 40
⇒ x = 20
∴ Required ratio
= (3x + 10) : (x + 10)
= 70 : 30
= 7 : 3
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The age of father 10 years ago was thrice the age of his son. Ten year...
10 years ago = father : son = 3 : 1
10 years hence= father : son = 2 : 1.
Now 10 years ago= 3 : 1
10 years hence = 4 : 2.
so, difference 4-3= 1 = 20 years.
10 years hence age = 80:40.
present age- 70:30 Ans.
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