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The current amplitude in a pure inductor in a radio receiver is to be 250 μA when the voltage amplitude is 3.60 V at a frequency of 1.60 MHz (at the upper end of the AM broadcast band). If the voltage amplitude is kept constant, what will be the current amplitude through this inductor at 16.0 MHz?
  • a)
    20.0 μA
  • b)
    33.0 μA
  • c)
    .35.0 μA
  • d)
    25.0 μA
Correct answer is option 'D'. Can you explain this answer?
Most Upvoted Answer
The current amplitude in a pure inductor in a radio receiver is to be ...
I0=250μA, v0=3.6v .  v=1.6x106 Hz
Here,
(Reactance of inductance) XL=ωL
XL=2πv X L
v0/I0=2πv x L
3.6/2.5x10-4=2πx1.6x10-6 x L
0.14x104-6=L
L=0.14x10-2H
Now for v=16.0x106Hz
XL=2πv X L
=2πx16x106x14x10-4
XL=1407x102Ω
Now,
v0=I0 x XL
3.6/1407x102=I0   [∵v0=kept constant.]
I0=0.00256x10-2
I0=25.6μA
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The current amplitude in a pure inductor in a radio receiver is to be 250μAwhen the voltage amplitude is 3.60 V at a frequency of 1.60 MHz (at the upper end of the AM broadcast band). If the voltage amplitude is kept constant, what will be the current amplitude through this inductor at 16.0 MHz?a)20.0μAb)33.0μAc).35.0μAd)25.0μACorrect answer is option 'D'. Can you explain this answer? for Class 12 2025 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about The current amplitude in a pure inductor in a radio receiver is to be 250μAwhen the voltage amplitude is 3.60 V at a frequency of 1.60 MHz (at the upper end of the AM broadcast band). If the voltage amplitude is kept constant, what will be the current amplitude through this inductor at 16.0 MHz?a)20.0μAb)33.0μAc).35.0μAd)25.0μACorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for Class 12 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The current amplitude in a pure inductor in a radio receiver is to be 250μAwhen the voltage amplitude is 3.60 V at a frequency of 1.60 MHz (at the upper end of the AM broadcast band). If the voltage amplitude is kept constant, what will be the current amplitude through this inductor at 16.0 MHz?a)20.0μAb)33.0μAc).35.0μAd)25.0μACorrect answer is option 'D'. Can you explain this answer?.
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