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2 g of calcium carbonate was added to 10 g of dilute hydrochloric acid in a beaker. when whole of CaCO3 had reacted away and no more effervescence took place; the solution left in the beaker weighed 11.1 g .Which gas was evolved and how much?
Most Upvoted Answer
2 g of calcium carbonate was added to 10 g of dilute hydrochloric acid...
Gas Evolved: Carbon Dioxide (CO2)
Explanation:
Given:
Mass of calcium carbonate (CaCO3) = 2 g
Mass of dilute hydrochloric acid = 10 g
Mass of solution after reaction = 11.1 g
Step 1: Calculate the mass of calcium carbonate reacted
Mass of calcium carbonate reacted = Initial mass of calcium carbonate - Final mass of solution
= 2 g - 11.1 g
= -9.1 g
Since the mass cannot be negative, we can conclude that all of the calcium carbonate reacted.
Step 2: Calculate the mass of carbon dioxide evolved
The equation for the reaction between calcium carbonate and hydrochloric acid is as follows:
CaCO3 + 2HCl → CaCl2 + H2O + CO2
From the balanced equation, we can see that 1 mole of calcium carbonate reacts to produce 1 mole of carbon dioxide. The molar mass of calcium carbonate is 100.1 g/mol, so the number of moles of calcium carbonate reacted can be calculated as follows:
Number of moles of calcium carbonate = Mass of calcium carbonate / Molar mass of calcium carbonate
= 2 g / 100.1 g/mol
= 0.01998 mol
Since the ratio of calcium carbonate to carbon dioxide is 1:1, the number of moles of carbon dioxide evolved is also 0.01998 mol.
Step 3: Convert moles of carbon dioxide to grams
The molar mass of carbon dioxide is 44.01 g/mol, so the mass of carbon dioxide evolved can be calculated as follows:
Mass of carbon dioxide = Number of moles of carbon dioxide * Molar mass of carbon dioxide
= 0.01998 mol * 44.01 g/mol
= 0.879 g
Conclusion:
The gas evolved during the reaction between calcium carbonate and hydrochloric acid is carbon dioxide (CO2), and the mass of carbon dioxide evolved is 0.879 g.
Explanation:
Given:
Mass of calcium carbonate (CaCO3) = 2 g
Mass of dilute hydrochloric acid = 10 g
Mass of solution after reaction = 11.1 g
Step 1: Calculate the mass of calcium carbonate reacted
Mass of calcium carbonate reacted = Initial mass of calcium carbonate - Final mass of solution
= 2 g - 11.1 g
= -9.1 g
Since the mass cannot be negative, we can conclude that all of the calcium carbonate reacted.
Step 2: Calculate the mass of carbon dioxide evolved
The equation for the reaction between calcium carbonate and hydrochloric acid is as follows:
CaCO3 + 2HCl → CaCl2 + H2O + CO2
From the balanced equation, we can see that 1 mole of calcium carbonate reacts to produce 1 mole of carbon dioxide. The molar mass of calcium carbonate is 100.1 g/mol, so the number of moles of calcium carbonate reacted can be calculated as follows:
Number of moles of calcium carbonate = Mass of calcium carbonate / Molar mass of calcium carbonate
= 2 g / 100.1 g/mol
= 0.01998 mol
Since the ratio of calcium carbonate to carbon dioxide is 1:1, the number of moles of carbon dioxide evolved is also 0.01998 mol.
Step 3: Convert moles of carbon dioxide to grams
The molar mass of carbon dioxide is 44.01 g/mol, so the mass of carbon dioxide evolved can be calculated as follows:
Mass of carbon dioxide = Number of moles of carbon dioxide * Molar mass of carbon dioxide
= 0.01998 mol * 44.01 g/mol
= 0.879 g
Conclusion:
The gas evolved during the reaction between calcium carbonate and hydrochloric acid is carbon dioxide (CO2), and the mass of carbon dioxide evolved is 0.879 g.
Community Answer
2 g of calcium carbonate was added to 10 g of dilute hydrochloric acid...
Co2
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2 g of calcium carbonate was added to 10 g of dilute hydrochloric acid in a beaker. when whole of CaCO3 had reacted away and no more effervescence took place; the solution left in the beaker weighed 11.1 g .Which gas was evolved and how much?
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2 g of calcium carbonate was added to 10 g of dilute hydrochloric acid in a beaker. when whole of CaCO3 had reacted away and no more effervescence took place; the solution left in the beaker weighed 11.1 g .Which gas was evolved and how much? for Class 9 2024 is part of Class 9 preparation. The Question and answers have been prepared according to the Class 9 exam syllabus. Information about 2 g of calcium carbonate was added to 10 g of dilute hydrochloric acid in a beaker. when whole of CaCO3 had reacted away and no more effervescence took place; the solution left in the beaker weighed 11.1 g .Which gas was evolved and how much? covers all topics & solutions for Class 9 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 2 g of calcium carbonate was added to 10 g of dilute hydrochloric acid in a beaker. when whole of CaCO3 had reacted away and no more effervescence took place; the solution left in the beaker weighed 11.1 g .Which gas was evolved and how much?.
2 g of calcium carbonate was added to 10 g of dilute hydrochloric acid in a beaker. when whole of CaCO3 had reacted away and no more effervescence took place; the solution left in the beaker weighed 11.1 g .Which gas was evolved and how much? for Class 9 2024 is part of Class 9 preparation. The Question and answers have been prepared according to the Class 9 exam syllabus. Information about 2 g of calcium carbonate was added to 10 g of dilute hydrochloric acid in a beaker. when whole of CaCO3 had reacted away and no more effervescence took place; the solution left in the beaker weighed 11.1 g .Which gas was evolved and how much? covers all topics & solutions for Class 9 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 2 g of calcium carbonate was added to 10 g of dilute hydrochloric acid in a beaker. when whole of CaCO3 had reacted away and no more effervescence took place; the solution left in the beaker weighed 11.1 g .Which gas was evolved and how much?.
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