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In a throw of a dice,find the probability of not getting 4 or 5?
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In a throw of a dice,find the probability of not getting 4 or 5?
Probability of not getting 4 or 5 in a dice throw


Introduction: In a dice throw, there are six possible outcomes, which are numbers from 1 to 6. The probability of getting any one of these outcomes is 1/6 or approximately 0.1667. In this question, we need to find the probability of not getting 4 or 5, which means we need to find the probability of getting any one of the remaining four outcomes, which are 1, 2, 3, and 6.


Solution:


Step 1: Find the total number of possible outcomes


  • There are six possible outcomes in a dice throw, which are numbers from 1 to 6.

  • Therefore, the total number of possible outcomes is 6.



Step 2: Find the number of outcomes that are not 4 or 5


  • There are four outcomes that are not 4 or 5, which are 1, 2, 3, and 6.

  • Therefore, the number of outcomes that are not 4 or 5 is 4.



Step 3: Find the probability of not getting 4 or 5


  • The probability of not getting 4 or 5 is the number of outcomes that are not 4 or 5 divided by the total number of possible outcomes.

  • The probability of not getting 4 or 5 = number of outcomes that are not 4 or 5 / total number of possible outcomes

  • The probability of not getting 4 or 5 = 4/6

  • The probability of not getting 4 or 5 = 0.6667 or approximately 0.67



Conclusion:


The probability of not getting 4 or 5 in a dice throw is 0.6667 or approximately 0.67. This means that if we throw a dice multiple times, we can expect to get a number that is not 4 or 5 about 67% of the time.
Community Answer
In a throw of a dice,find the probability of not getting 4 or 5?
4/6 divided by 2 equal to 2/3
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